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AP Calculus BC Intermediate

Differentiating Vector-Valued Functions

Learn how to differentiate vector-valued functions component by component, interpret the derivative as velocity, and use higher derivatives to analyze motion in the plane.

What a Vector-Valued Function Is

A vector-valued function describes a point whose position depends on time. Instead of giving one output for each input, it gives a vector containing the point's horizontal and vertical coordinates.

For a particle moving in the plane, we commonly write its position as:

Here, gives the particle's horizontal position and gives its vertical position at time .

Key Idea

A vector-valued function is really two ordinary functions working together. That means differentiation is much less mysterious than it may initially look: differentiate each component separately.

How to Differentiate a Vector-Valued Function

Suppose:

Then the derivative is obtained by differentiating the component and the component independently:

The same rule works for vector-valued functions written using unit vectors:

Differentiate the coefficient of and the coefficient of separately. The unit vectors themselves do not change because they are constant.

The First Derivative: Velocity

In AP Calculus BC, vector-valued functions are often used to describe motion. If represents the position of a particle at time , then its derivative is the velocity vector.

The horizontal component of velocity tells you how quickly the particle's position is changing. The vertical component tells you how quickly its position is changing.

The particle's speed is the magnitude of its velocity vector:

Notice the distinction: velocity is a vector, while speed is a scalar. Velocity tells you both how fast the particle is moving and the direction in which it is moving.

The Second Derivative: Acceleration

Differentiate the velocity vector one more time and you obtain the acceleration vector.

Just as with the first derivative, differentiate each component separately:

So the standard motion framework is:

Worked Examples

Example 1: Basic Vector Differentiation

Let . Find .

Step 1: Differentiate the horizontal component:
Step 2: Differentiate the vertical component:
Result:
Example 2: Trigonometric Components

Let . Find the velocity vector and the speed at .

Step 1: Differentiate each component:
Step 2: Evaluate the velocity at :
Step 3: Take the magnitude to find speed:
Result: The particle's speed at is units per unit time.
Example 3: Velocity and Acceleration

The position of a particle is . Find its velocity and acceleration vectors.

Step 1: Differentiate the position function:
Step 2: Differentiate again:
Result:
Example 4: Using the Chain Rule Inside a Vector Function

Let . Find the velocity vector.

Step 1: Differentiate the first component using the chain rule:
Step 2: Differentiate the second component using the chain rule:
Result:

Position, Velocity, and Acceleration

It helps to think of the three vectors as a chain:

For example, if you are given a position function, differentiate once to get velocity and twice to get acceleration. If you are given velocity, integrate to recover position only when enough initial information is supplied.

What Does a Velocity Component Tell You?

Suppose the velocity is . Then:

The signs of the velocity components therefore tell you the direction of motion in the coordinate plane.

Common Mistakes

Differentiating the vector as if it were a single scalar expression

A vector-valued function has multiple components. Differentiate each component separately. Do not try to apply one derivative rule to the entire vector at once.

Confusing velocity with speed

Velocity is the vector . Speed is its magnitude, . If an AP question asks for speed, you must take the magnitude.

Forgetting the chain rule inside a component

Each component is an ordinary function. If one component contains something like , you still need the chain rule when differentiating that component.

Using the position vector when the question asks for velocity

Read the wording carefully. Position is , velocity is its first derivative, and acceleration is its second derivative.

Practice Problems

Question 1

Let . Find .

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Question 2

A particle has position . Find its velocity at .

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Question 3

For the particle in Question 2, find its speed at .

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Question 4 (Higher Derivatives)

Let . Find the acceleration vector .

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