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Radius and Interval of Convergence of a Power Series

A practical method for finding where a power series converges, including the crucial endpoint checks that turn a radius into a complete interval of convergence.

What Convergence Means

A power series is an infinite series whose terms contain powers of a variable. A common form is:

The important question is not simply whether the series converges or diverges. Instead, we want to know:

For most power series, there is a central interval where the series converges and values outside that interval where it diverges. The two quantities you need to find are the radius of convergence and the interval of convergence.

Radius vs. Interval of Convergence

The radius of convergence, \(R\), tells you how far the convergence extends from the center of the power series.

If the series is centered at \(x=c\), then:

This gives the key distinction:

The radius tells you the distance from the center. The interval tells you the actual \(x\)-values for which the series converges.

The Standard AP Calculus Method

When you are asked to find the radius and interval of convergence, use this four-step process:

  1. Apply a convergence test, usually the Ratio Test.
  2. Solve the resulting inequality to find the values where the series converges absolutely.
  3. Identify the radius and candidate endpoints.
  4. Test each endpoint separately. The endpoint tests determine whether the interval uses parentheses or brackets.

The most important habit is this: never stop after finding the radius. The endpoints are separate problems.

Using the Ratio Test

For a series \(\sum a_n\), the Ratio Test examines:

For a power series, the goal is to simplify this limit until it produces an inequality involving \(x\).

If the limit is less than 1, the series converges. If it is greater than 1, the series diverges. When the limit equals 1, the Ratio Test is inconclusive.

Worked Example 1: Finding the Radius and Interval

Example 1: Basic Power Series

Find the radius and interval of convergence of:

Step 1: Apply the Ratio Test. Let the \(n\)-th term be \(a_n=\dfrac{(x-2)^n}{n}\). Then:
Step 2: Simplify the limit.
Step 3: Require the limit to be less than 1.

Therefore:

Step 4: Identify the radius and candidate endpoints.

The center is \(2\), so the radius is:

The candidate endpoints are:

Step 5: Test the left endpoint.

Substitute \(x=-1\):

This is the harmonic series with negative terms, so it diverges.

Step 6: Test the right endpoint.

Substitute \(x=5\):

This is the harmonic series, so it diverges.

Result:

The series converges for \(-1

Worked Example 2: One Endpoint Converges

Example 2: Endpoint Testing Matters

Find the radius and interval of convergence of:

Step 1: Apply the Ratio Test.
Step 2: Solve the inequality.
Step 3: Find the candidate endpoints.

The center is \(1\) and the radius is \(2\), so:

Step 4: Test \(x=-1\).

This is a \(p\)-series with \(p=2\), so it converges.

Step 5: Test \(x=3\).

This is the harmonic series, so it diverges.

Result:

Notice what happened: the radius alone was \(2\), but the interval of convergence is \([-1,3)\). The endpoint tests supplied the missing information.

Worked Example 3: Alternating Endpoint

Example 3: Using the Alternating Series Test

Find the radius and interval of convergence of:

Step 1: Apply the Ratio Test.
Step 2: Determine the radius.

The center is \(0\), so the candidate endpoints are \(-1\) and \(1\).

Step 3: Test \(x=-1\).

This is the alternating harmonic series, which converges by the Alternating Series Test.

Step 4: Test \(x=1\).

This is the harmonic series, which diverges.

Result:

How to Read the Endpoint Results

Once you have the candidate interval, each endpoint gets its own convergence test.

The radius is always the distance from the center to either candidate endpoint. The interval is the more precise answer because it tells you exactly which endpoints are included.

Why the Endpoints Are Special

The Ratio Test typically gives you an inequality such as:

But when \(x\) is exactly an endpoint, the ratio-test limit becomes \(1\). That means the Ratio Test is inconclusive.

This does not mean that the series necessarily diverges. It means you need another test.

At the endpoints, you may encounter familiar series such as:

Common Mistakes

Stopping after finding the radius

Finding \(R\) does not finish the problem. You still need to test both endpoints. Two power series can have the same radius but different intervals of convergence.

Assuming the endpoints are automatically included

The interval \(|x-c|

Using the Ratio Test at an endpoint and stopping when the limit is 1

A ratio-test limit of 1 means the test is inconclusive. Switch to another convergence test that matches the resulting series.

Confusing radius with interval

The radius is a single positive number. The interval is a set of \(x\)-values. For example, \(R=3\) does not mean the interval is automatically \((-3,3)\); the endpoints still need to be checked.

A Fast AP Exam Strategy

When you see "find the radius and interval of convergence", think:

  1. Find the Ratio Test limit.
  2. Make the limit less than 1.
  3. Solve for \(x\).
  4. Read off the radius and candidate endpoints.
  5. Plug in the left endpoint.
  6. Plug in the right endpoint.
  7. State the final interval using brackets or parentheses.

That workflow is reliable because it separates the problem into two parts: the Ratio Test finds the interior, and endpoint tests finish the job.

Practice Problems

Question 1

Find the radius and interval of convergence of:

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Question 2

Find the radius and interval of convergence of:

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Question 3

Find the radius and interval of convergence of:

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Question 4 (Endpoint Testing)

Find the radius and interval of convergence of:

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