Why Exponential Models Matter
Many quantities change at a rate that is proportional to their current size. Populations, bacteria, money in an interest-bearing account, and radioactive substances can all be modeled this way.
The key idea is simple: the larger the quantity becomes, the faster it changes. For a growing population, a population of 1,000 might add 50 individuals per year, while a population of 10,000 growing at the same proportional rate might add 500.
This leads to the differential equation
where is the quantity being modeled, is time, and is the constant proportional growth or decay rate.
The solution is an exponential function:
Here, represents the initial amount at .
Population Growth
A population that grows at a constant percentage rate is naturally modeled exponentially. The continuous-growth model is
If , the population grows. If , the population decreases.
Percentage Rate vs. Number of Individuals
This distinction is important on the AP exam. A statement such as "the population increases by 4% per year" describes a relative rate of change:
It does not mean that exactly 4 individuals are added each year. The actual number being added depends on the current population.
Worked Example 1: Modeling a Growing Population
A town has a population of 12,000. The population grows continuously at a rate of 3% per year. Let represent the population years after the initial measurement.
Using the Derivative to Interpret Population Growth
The derivative of an exponential model tells you the instantaneous rate at which the population is changing.
If
then
So the rate of population growth is proportional to the population itself. This gives an important interpretation:
If is measured in people per year, then tells you how many people per year the population is increasing at that instant.
Radioactive Decay
Radioactive substances provide the same mathematical model, but with a negative rate constant. As radioactive material decays, the amount remaining decreases at a rate proportional to the amount currently present.
The model is
where is negative.
Because the exponent becomes increasingly negative as time passes, the quantity decreases toward zero.
Half-Life
Radioactive decay problems frequently give a substance's half-life: the amount of time required for half of the material to remain.
If the initial amount is and the half-life is , then
More generally, if the initial amount is , the amount remaining after time can be written as
This form is often easier to use than first solving for .
Worked Example 2: Radioactive Decay
A radioactive isotope has a half-life of 8 years. A sample initially contains 500 grams. How much remains after 20 years?
Finding a Time from a Population or Decay Model
AP Calculus problems often reverse the question. Instead of asking how much remains after a certain amount of time, they ask when a quantity reaches a specified value.
Suppose
and we want to find the time when the quantity equals . Set the model equal to the target and use logarithms:
Worked Example 3: Finding When a Population Reaches a Target
A population is modeled by , where is measured in years. How long will it take the population to reach 20,000?
Finding the Rate Constant from Two Data Points
Sometimes the growth or decay constant is not given directly. Instead, you receive two measurements. The strategy is to substitute both measurements into the exponential model and solve for the unknown constant.
For a model of the form
if the initial value is known and a later value is given, then
Taking the natural logarithm isolates .
Worked Example 4: Building a Decay Model from Data
A sample contains 800 milligrams of a radioactive substance initially. After 6 hours, 500 milligrams remain. Find the continuous decay constant and write an exponential model.
Population Growth vs. Radioactive Decay
The mathematics is almost identical. The main difference is the sign of the constant.
- Population growth: , so the exponential function increases.
- Radioactive decay: , so the exponential function decreases.
- In both cases, the instantaneous rate of change is proportional to the current amount.
- The derivative gives the actual rate of change at a particular time.
Common Mistakes
A 5% growth rate means the population changes by 5% of its current size, not by a fixed number of people. Exponential models describe proportional change.
For radioactive decay, the continuous rate constant must be negative. A positive exponent produces growth rather than decay.
The half-life is a time interval. The continuous decay constant has units of inverse time. They are related by .
Always track the units of . If time is measured in years, the rate constant has units of per year. Your final answer should match the units requested in the problem.
AP Calculus Strategy
When you see a population or radioactive-decay problem, identify the mathematical structure before doing any calculations.
- Identify the initial amount. This is the value of the model at the chosen starting time.
- Determine whether the quantity grows or decays. This tells you whether the exponential constant should be positive or negative.
- Write the exponential model. Use the continuous model when the problem describes continuous proportional change.
- Use the derivative when the question asks for a rate. The model gives the amount; its derivative gives the instantaneous rate.
- Use logarithms when solving for time or a rate constant.
- Check the answer against the context. A decay model should decrease over time; a growth model should increase.
Practice Problems
A population of 4,000 grows continuously at a rate of 6% per year. Write an exponential model for the population.
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A population is modeled by . Find the instantaneous rate of population growth at .
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A radioactive isotope has a half-life of 12 years. If a sample initially contains 240 grams, how much remains after 30 years?
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A population is modeled by . At what time will the population reach 30,000?
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