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AP Calculus AB & BC Intermediate

Behavior of Implicit Relations Using Derivatives

How to use implicit differentiation to determine where an implicitly defined relation is increasing, decreasing, or changing direction—and how derivatives reveal the geometry of curves that aren't written as explicit functions.

Why Implicit Relations Need a Different Approach

In many calculus problems, a function is written explicitly as . That makes it easy to calculate and use its sign to determine whether the function is increasing or decreasing.

But not every curve is given that way. A circle, for example, is naturally written as . Solving for gives two separate functions, so treating the equation as a single explicit function can be awkward.

Implicit differentiation lets us work directly with the relation. Once we find , we can analyze the behavior of the curve just as we would analyze an ordinary function.

The key idea is simple: the sign of tells us the direction in which the curve is moving as increases.

What "Increasing" and "Decreasing" Mean for an Implicit Curve

For an explicitly defined function , we say the function is increasing on an interval when throughout that interval. Likewise, it is decreasing when .

The same idea applies locally to an implicitly defined relation. At a point where the curve has a well-defined vertical change with respect to horizontal change:

So the sign chart is interpreted exactly as you already know:

Step 1: Find the Implicit Derivative

The first step is always to differentiate the entire relation with respect to . Remember that is a function of , even if the equation doesn't explicitly write .

For example, consider:

Differentiate both sides with respect to . The derivative of is , while the derivative of requires the chain rule.

Now solve algebraically for :

Once this expression is available, we can determine where the curve is increasing or decreasing by analyzing its sign.

Step 2: Find Critical Points

For an implicitly defined relation, horizontal tangent points occur when , provided the derivative exists there.

For a derivative written as a fraction, such as , there are two especially important possibilities:

  1. The numerator is zero, giving .
  2. The denominator is zero, making undefined and potentially indicating a vertical tangent.

These are not automatically maxima or minima. They are candidate points that must be analyzed using the behavior of the derivative on either side.

Critical point does not automatically mean maximum or minimum

A point where is zero or undefined is only a candidate for a local extremum. You still need to determine what happens to the sign of on either side of the point.

Worked Example 1: Increasing and Decreasing on a Circle

Example 1: An Implicit Circle

Consider the circle:

Determine where the upper portion of the circle is increasing and decreasing.

Step 1: Differentiate implicitly:
Step 2: Solve for the derivative:
Step 3: On the upper semicircle, , so the denominator is positive. Therefore the sign of is determined by .
Step 4: When , we have . When , we have .
Result: The upper semicircle is decreasing for and increasing for .

Step 3: Use a Sign Chart

A sign chart is one of the most reliable ways to analyze the behavior of an implicitly defined curve.

Suppose your derivative has the form:

Find the values of where the numerator or denominator is zero. These values divide the domain into intervals. Then test the sign of in each interval.

Sign Chart Strategy
1. Find all relevant values.
2. Place them on a number line.
3. Test one point in each interval.
4. Record whether is positive or negative.
5. Translate the signs into increasing and decreasing behavior.

Worked Example 2: Finding a Local Maximum and Minimum

Example 2: An Implicit Relation with Extrema

Consider the relation:

Determine the points where the curve has horizontal tangents and classify the corresponding extrema.

Step 1: Differentiate implicitly:
Step 2: Solve for :
Step 3: Horizontal tangents occur when the numerator is zero:
Step 4: The corresponding values can be found from the original relation. This gives the candidate points:
Step 5: A sign analysis of shows that the curve changes from increasing to decreasing at the first point and from decreasing to increasing at the second.
Result: The first point is a local maximum and the second point is a local minimum.

Horizontal Tangents vs. Vertical Tangents

Implicit differentiation is especially useful because it can reveal tangent behavior that is difficult to see from an explicit equation.

If:

then a horizontal tangent is possible because the slope is zero.

If:

then the slope is undefined. If the numerator is nonzero and the denominator approaches zero, this can correspond to a vertical tangent.

Do not confuse undefined derivative with vertical tangent automatically

An undefined derivative does not automatically guarantee a vertical tangent. You should check the behavior of the curve and verify that the tangent direction is actually vertical. A cusp, corner, or other singular behavior can also produce an undefined derivative.

Worked Example 3: Identifying a Vertical Tangent

Example 3: Horizontal and Vertical Tangents

Consider:

Find the horizontal tangent points and identify the vertical tangent points.

Step 1: Differentiate:
Step 2: Solve for the derivative:
Step 3: Horizontal tangents require the numerator to equal zero:
Step 4: Vertical tangents occur where the denominator is zero while the numerator is nonzero:
Result: The derivative gives a direct algebraic way to locate both horizontal and vertical tangent behavior without solving the relation explicitly for .

How Derivatives Describe the Shape of an Implicit Curve

The derivative contains much more information than just the slope at one point. By studying its sign, you can describe how an implicit curve behaves across an interval.

This means that the familiar first-derivative analysis from explicit functions still works. The only additional step is that you must first obtain using implicit differentiation.

Second Derivatives and Concavity

You can also use implicit differentiation to study concavity. Once you have an expression for , differentiate it again with respect to .

The sign of can then be used to determine concavity, just as it is for an explicitly defined function:

Be careful: for implicit relations, the algebra involved in finding can be substantially more complicated because itself appears inside the expression.

AP Calculus Problem-Solving Workflow

When an AP Calculus question asks you to analyze the behavior of an implicitly defined relation, use this workflow:

  1. Differentiate implicitly. Treat as a function of .
  2. Solve for if the problem asks for a derivative or requires sign analysis.
  3. Find candidate critical values. Look for where is zero or undefined.
  4. Use the original relation to determine the corresponding points on the curve.
  5. Build a sign chart for .
  6. Classify behavior. Identify increasing/decreasing intervals, local extrema, and possible vertical tangents.
  7. State your answer in terms of the requested variable and interval.

Common Mistakes

Forgetting the chain rule on y terms

When differentiating with respect to , the derivative is not simply . Because depends on , you must include .

Solving for y unnecessarily

An implicit relation often does not need to be rewritten as . In fact, solving for can create multiple branches and make the problem harder. Implicit differentiation lets you work directly with the original equation.

Calling every critical point an extremum

A point where is zero or undefined is only a candidate. You need a sign analysis or another valid argument to determine whether the point is actually a local maximum or minimum.

Using only the derivative equation and ignoring the original relation

After finding a critical value, substitute it back into the original relation when the problem asks for a point. The derivative equation alone may not contain enough information to determine the corresponding coordinate.

Practice Problems

Question 1

For the relation , find and determine where the curve is increasing.

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Question 2

For the relation , find the points where the curve has horizontal tangents.

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Question 3

For the relation , determine where the curve is increasing and decreasing.

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Question 4 (Tangents)

For the relation , determine the locations of the horizontal and vertical tangents.

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Question 5 (Extrema)

For the relation , use the first derivative to classify the horizontal-tangent points.

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