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Defining the Definite Integral as a Limit of Riemann Sums

See how an approximation made from rectangles becomes an exact definite integral as the number of subintervals approaches infinity—and learn how to translate between Riemann-sum notation and integral notation.

Why the Definite Integral Needs a Limit

Suppose we want the exact signed area between a function and the on the interval . If the graph is curved, we cannot usually find the exact area by using one rectangle. Instead, we divide the interval into many smaller pieces and approximate the area with rectangles.

With a finite number of rectangles, we get an approximation. But what happens if we keep increasing the number of rectangles? The rectangles become narrower, the approximation becomes more accurate, and in the limit the approximation approaches the exact area.

This limiting process is the foundation of the definite integral.

The important idea is that the definite integral is not merely a convenient symbol for area. It is defined as the limit of these increasingly fine Riemann-sum approximations.

Step 1: Divide the Interval into Subintervals

Start with the interval . Divide it into equal subintervals.

The width of each subinterval is:

As becomes larger, becomes smaller. This is what allows the rectangles to fit the curve more closely.

Step 2: Choose a Sample Point

For each subinterval, choose a point at which to evaluate the function. A general sample point in the subinterval can be written as .

Different choices produce different types of Riemann sums:

For the definition of the definite integral, the particular choice of sample points does not matter as the subintervals become arbitrarily small, provided the function is sufficiently well-behaved.

Step 3: Build the Riemann Sum

The approximate signed area of one rectangle is:

Adding all rectangles gives a Riemann sum:

This is still an approximation because there are only finitely many rectangles.

Step 4: Let the Number of Rectangles Approach Infinity

Now comes the key step. Let the number of subintervals increase without bound:

As , the width . The rectangles become infinitely thin in the limiting process, and the Riemann sum approaches the exact value of the area.

That limit is what we call the definite integral.

The Definition of the Definite Integral

For a continuous function on , the definite integral is defined by:

This formula is worth recognizing in several equivalent forms. The most common version uses right endpoints:

Here, because the right endpoint of the subinterval is .

Worked Examples

Example 1: Write an Integral as a Riemann-Sum Limit

Write as a limit of Riemann sums using right endpoints.

Step 1: Identify the interval: , so and .
Step 2: Find the width:
Step 3: The right endpoint of the subinterval is .
Step 4: Substitute into the definition:
Result:
Example 2: Evaluate a Riemann-Sum Limit

Evaluate .

Step 1: Recognize the function and interval. The expression has and , so it represents .
Step 2: Evaluate the integral:
Step 3: Therefore, the limit is .
Example 3: Identify the Integral from Sigma Notation

Write the following limit as a definite integral:

Step 1: Compare the expression with . Since , the interval begins at 1.
Step 2: Since , the interval ends at 3.
Step 3: The function being evaluated is .
Result:
Example 4: Using Left Endpoints

Express as a limit of left-endpoint Riemann sums.

Step 1: The interval is , so and .
Step 2: The width is .
Step 3: For a left-endpoint sum, use .
Result:

What the Limit Is Really Doing

It is easy to look at the notation and think that the limit is just a technical trick. It is more useful to understand what is happening geometrically.

So the definite integral can be thought of as the result of taking the idea of "adding infinitely many infinitely thin pieces" and defining it precisely through a limit.

Riemann Sum Notation vs. Integral Notation

AP Calculus often asks you to move between these two forms. The correspondence is:

A useful way to read the Riemann sum is:

Common Mistakes

Confusing the number of rectangles with their width

The number of rectangles is , while their width is . As , the width approaches zero.

Using the wrong endpoint

For a right-endpoint sum, the sample point is . For a left-endpoint sum, it is . Mixing these up changes the Riemann sum.

Forgetting the Δx factor

A function value alone is not an area. Each rectangle contributes , so the width factor must appear in the Riemann sum.

Thinking the Riemann sum is already exact

A finite Riemann sum is an approximation. The exact definite integral is obtained only after taking the limit as .

Confusing signed area with total geometric area

A definite integral measures signed area. Regions below the contribute negatively. If a problem asks for total geometric area, you may need to split the interval or use absolute values.

Practice Problems

Question 1

Write as a limit of right-endpoint Riemann sums.

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Question 2

Write the limit as a definite integral.

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Question 3

Evaluate .

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Question 4 (Conceptual)

Explain what happens to as .

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