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AP Calculus AB & BC Intermediate

Determining Absolute (Global) Extrema on a Closed Interval

A systematic method for finding the absolute maximum and absolute minimum values of a function on a closed interval using critical points and endpoints.

What Absolute Extrema Are

An absolute maximum, also called a global maximum, is the largest function value attained on a specified domain. An absolute minimum, or global minimum, is the smallest function value attained on that domain.

For a function restricted to a closed interval , the key question is not simply where the derivative is zero. You must compare the function values at all critical points in the interval and both endpoints.

This procedure is sometimes called the closed-interval method. It is one of the most important applications of derivatives in AP Calculus.

The Extreme Value Theorem

The reason closed intervals are so important comes from the Extreme Value Theorem.

If a function is continuous on a closed interval , then the function is guaranteed to have both an absolute maximum and an absolute minimum somewhere on that interval.

This theorem tells you that the extrema exist. The derivative-based closed-interval method tells you how to find them.

The Closed-Interval Method

To determine the absolute maximum and minimum of a continuous function on a closed interval, use these steps:

  1. Find the derivative .
  2. Find all critical numbers in the interval by solving and finding where does not exist.
  3. Keep only the critical numbers that lie inside the interval.
  4. Evaluate the original function at every critical number and at both endpoints.
  5. Compare all resulting function values.
  6. The largest value is the absolute maximum; the smallest value is the absolute minimum.

Worked Examples

Example 1: A Quadratic Function

Find the absolute maximum and minimum of on .

Step 1: Differentiate:
Step 2: Find critical numbers by setting the derivative equal to zero: . Thus the critical number is , which lies in the interval.
Step 3: Evaluate the function at the critical number and both endpoints:
Step 4: Compare the values:
Result: The absolute maximum is , occurring at . The absolute minimum is , occurring at .
Example 2: A Cubic Function with Two Critical Points

Find the absolute maximum and minimum of on .

Step 1: Differentiate:
Step 2: Solve . The critical numbers are . Both lie inside the interval.
Step 3: Evaluate the original function at the two critical numbers and both endpoints:
Step 4: Compare all four values:
Result: The absolute maximum is , occurring at . The absolute minimum is , occurring at .
Example 3: A Critical Number Where the Derivative Does Not Exist

Find the absolute maximum and minimum of on .

Step 1: Differentiate:
Step 2: The derivative is undefined at . Because is in the domain of the original function, it is a critical number.
Step 3: Evaluate the original function at the critical number and both endpoints:
Step 4: Compare the values. The largest is and the smallest is .
Result: The absolute maximum is , occurring at . The absolute minimum is , occurring at .
Example 4: An AP-Style Function with a Nontrivial Critical Point

Find the absolute maximum and minimum of on .

Step 1: Differentiate:
Step 2: Set the derivative equal to zero: . Thus the critical number is .
Step 3: Evaluate the original function at :
Step 4: Compare the values:
Result: The absolute maximum is , occurring at . The absolute minimum is , occurring at .

Why You Must Check the Endpoints

A common mistake is to find the critical points and stop. That does not guarantee the absolute extrema on a closed interval.

An absolute maximum or minimum can occur at an endpoint even when the derivative is not zero there. Endpoints are not interior points, so the usual critical-number condition does not apply to them.

Critical points are not the whole answer

Finding only identifies possible interior extrema. For an absolute-extrema problem on , you must also evaluate and .

Absolute vs. Local Extrema

It is important to distinguish between local and absolute extrema.

A function can have several local extrema but only one absolute maximum value and one absolute minimum value, although the same absolute value can sometimes occur at multiple x-values.

Do not confuse a local maximum with the absolute maximum

A critical point can produce a local maximum without producing the largest value on the entire interval. Always compare its function value with every other candidate, including the endpoints.

A Fast AP Calculus Strategy

For a closed-interval absolute-extrema problem, you can use this compact checklist:

Think of the process as building a short list of candidates. Critical numbers inside the interval are candidates, and the two endpoints are candidates. Once every candidate has been evaluated using the original function, the largest and smallest values settle the problem.

Common Mistakes

Forgetting the endpoints

This is the most common error. The endpoints are always candidates for absolute extrema on a closed interval, even though they are not critical numbers.

Using the derivative instead of the original function

After finding critical numbers, evaluate the original function at each candidate. Do not plug the candidates into and call those the function values.

Keeping critical numbers outside the interval

A critical number matters for the problem only if it belongs to the specified domain. If the interval is and a critical number is , that critical number is not a candidate.

Finding a critical number but not checking whether it belongs to the domain

A point where does not exist is a critical number only when the original function is defined there. Always check the original function's domain.

Practice Problems

Question 1

Find the absolute maximum and minimum of on .

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Question 2

Find the absolute maximum and minimum of on .

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Question 3

Find the absolute maximum and minimum of on .

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Question 4 (Critical Point Where Derivative Is Undefined)

Find the absolute maximum and minimum of on .

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