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AP Calculus AB & BC Intermediate

Exponential Growth and Decay Models

Learn how to recognize, build, interpret, and use exponential growth and decay models—and how differential equations explain why these models work.

What Exponential Growth and Decay Models Are For

Many real-world quantities change at a rate that is proportional to the amount currently present. Population growth, radioactive decay, continuously compounded interest, medication concentration, and the spread of certain quantities can all be modeled this way.

The key idea is simple: the more you have, the faster the quantity changes. If a quantity grows, its rate of change is positive and proportional to its current amount. If it decays, its rate of change is negative and proportional to its current amount.

That relationship is represented by the differential equation:

Here, is the quantity being modeled, is time, and is the proportionality constant. The sign of determines whether the model represents growth or decay.

The Exponential Model

The differential equation has a general solution of the form:

The constant represents the initial amount when . The constant controls how quickly the quantity changes.

If , the model represents exponential growth. If , the model represents exponential decay.

When an initial value is known, the model can be written especially conveniently as:

This form is extremely useful on the AP exam because it automatically incorporates the initial condition.

How to Recognize an Exponential Model

Look for a statement that says the rate of change is proportional to the current amount. Typical wording includes:

Mathematically, all of these statements point toward the same structure:

The word proportional is the major clue. It tells you that the quantity itself belongs on the right-hand side of the differential equation.

A Step-by-Step Method

  1. Define the quantity. Identify what represents and what represents.
  2. Translate the wording into a differential equation. If the rate is proportional to the amount, write .
  3. Use the initial condition to determine the constant in the exponential model.
  4. Use another data point, if one is provided, to determine the proportionality constant.
  5. Answer the question. Substitute the requested time or quantity into the completed model.
  6. Interpret the result in context. Include appropriate units and make sure the answer makes sense.

Worked Examples

Example 1: Building a Growth Model

A population grows at a rate proportional to its current size. At time , the population is 500. After 3 years, the population is 800. Find a model for the population.

Step 1: Let represent the population at time .
Step 2: Since the growth rate is proportional to the population:
Step 3: The general model is:
Step 4: Use the initial condition . This gives , so:
Step 5: Use the second data point, :
Step 6: Solve for :
Result: The population model is:
Example 2: Exponential Decay

A radioactive substance has an initial mass of 200 grams. Its mass decreases at a rate proportional to the amount remaining. After 5 years, 120 grams remain. Find the amount remaining after 10 years.

Step 1: Let be the mass, in grams, at time .
Step 2: Because the substance is decaying:
Step 3: The exponential model is:
Step 4: Since , the initial amount is 200 grams:
Step 5: Use the fact that :
Step 6: Solve for :
Step 7: Evaluate the model at :
Result: Approximately 72 grams remain after 10 years.
Example 3: Finding the Growth Rate from a Differential Equation

A population satisfies . Initially, the population is 1,200. Find the population after 4 years.

Step 1: The proportionality constant is already given: .
Step 2: Use the exponential model:
Step 3: Use to find the initial-value constant:
Step 4: Evaluate at :
Result: The population is approximately 1,463 after 4 years.
Example 4: Half-Life

A radioactive substance has a half-life of 8 hours. If the initial amount is 500 milligrams, how much remains after 20 hours?

Step 1: Because the quantity is decaying, use an exponential decay model:
Step 2: A half-life of 8 hours means that after 8 hours, half the original amount remains:
Step 3: Substitute the initial amount and the half-life condition:
Step 4: Divide by 500:
Step 5: Solve for the decay constant:
Step 6: Evaluate the model at 20 hours:
Result: Approximately 89 milligrams remain after 20 hours.

Growth and Decay Rates

The constant tells you more than whether the quantity is growing or shrinking. Its magnitude controls how quickly the quantity changes.

For the model :

Because the derivative is:

the rate of change is itself proportional to the current amount. This is why exponential growth gets increasingly steep and exponential decay gradually flattens toward zero.

Continuous Growth vs. Discrete Growth

Be careful not to confuse continuous exponential growth with models based on a fixed number of compounding periods.

A discrete model often looks like:

whereas continuous growth is modeled by:

In AP Calculus, a statement involving a differential equation such as points directly toward the continuous exponential model.

Common Mistakes

Using the wrong sign for decay

For decay, the proportionality constant is negative. If the quantity is decreasing, . A model such as represents growth, not decay.

Forgetting that the rate is proportional to the current amount

"The rate is proportional to the amount" means , not a constant-rate equation such as . A constant rate produces linear behavior, not exponential behavior.

Confusing the initial amount with the growth constant

In , the constant is the initial amount when . The constant controls the growth or decay rate.

Ignoring units

If is measured in years, then the proportionality constant has units of inverse years. Always check that your final answer has the correct units.

Rounding too early

Keep the exact value of as long as possible. For example, if you obtain , do not immediately replace it with a decimal approximation. Early rounding can noticeably change the final answer.

Practice Problems

Question 1

A population grows at a rate proportional to its current size. If the population is 400 at time and 600 at time , find the population model.

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Question 2

A substance decays according to . If the initial amount is 800 grams, how much remains after 5 hours?

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Question 3

A radioactive isotope has a half-life of 12 years. If the initial amount is 300 grams, find the amount remaining after 30 years.

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Question 4 (Model Interpretation)

A quantity is modeled by . Is the quantity increasing or decreasing? What is its initial value, and what is its relative rate of change?

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