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AP Calculus AB & BC Intermediate

Extreme Value Theorem and Candidates Test

Learn when a function is guaranteed to have an absolute maximum and minimum, and use the Candidates Test to find the absolute extrema efficiently and correctly.

What the Extreme Value Theorem Is For

The Extreme Value Theorem (EVT) tells you when a continuous function is guaranteed to have both an absolute maximum and an absolute minimum on an interval. This is one of the most important ideas behind the Candidates Test.

The key conditions are simple: the function must be continuous, and the interval must be closed and bounded. If those conditions are satisfied, the function cannot avoid attaining its highest and lowest values somewhere on the interval.

Notice that the theorem guarantees that the extrema exist. It does not tell you where they occur. That's where the Candidates Test comes in.

The Extreme Value Theorem

If is continuous on the closed interval , then has both an absolute maximum and an absolute minimum on .

In practical AP Calculus problems, think:

Example: Does the EVT Apply?

Consider on .

Continuity: is a polynomial, so it is continuous everywhere.
Interval: is a closed and bounded interval.
Conclusion: By the Extreme Value Theorem, must have both an absolute maximum and an absolute minimum on .

Why the Endpoints Matter

One of the biggest AP Calculus mistakes is checking only where the derivative equals zero. That is not enough when you're looking for absolute extrema on a closed interval.

For a function on , the endpoints are always candidates. Even if the derivative does not equal zero there, the function can still achieve its absolute maximum or minimum at an endpoint.

Example: An Endpoint Can Be the Absolute Maximum

Consider on .

Derivative:
Critical number:
Candidates: The critical number and both endpoints:
Evaluate:
Conclusion: The absolute maximum occurs at , while the absolute minimum occurs at .

The Candidates Test

The Candidates Test is the standard procedure for finding absolute maximum and minimum values of a continuous function on a closed interval.

  1. Find the derivative .
  2. Find all critical numbers in the interval. These occur where or where does not exist, provided the original function is defined there.
  3. Evaluate the original function at every critical number in the interval.
  4. Evaluate the original function at both endpoints.
  5. Compare all candidate values. The largest output is the absolute maximum; the smallest output is the absolute minimum.

The crucial word is candidates. A critical number is not automatically a maximum or minimum. It is simply a point that might produce an absolute extremum.

Worked Example 1: Polynomial on a Closed Interval

Example 1: Full Candidates Test

Find the absolute maximum and minimum values of on .

Step 1 — Differentiate:
Step 2 — Find critical numbers: Set the derivative equal to zero: . Thus .
Step 3 — List all candidates: The critical number inside the interval plus the two endpoints gives .
Step 4 — Evaluate:
Step 5 — Compare: The largest value is , and the smallest value is .
Conclusion: The absolute maximum is , occurring at . The absolute minimum is , occurring at .

Worked Example 2: A Critical Number That Is Not an Absolute Extremum

Example 2: Critical Does Not Mean Maximum or Minimum

Find the absolute maximum and minimum values of on .

Derivative:
Critical number:
Candidates:
Evaluate:
Comparison:

The critical number is a candidate, but it does not produce either absolute extremum. This is why you must compare all candidate values rather than stopping at the first critical point you find.

Critical Numbers: What Counts?

A critical number is a value in the domain of where either:

For the Candidates Test, only critical numbers inside the interval are included as critical-number candidates. The endpoints are handled separately and must always be checked.

Critical numbers are not the same as endpoints

Endpoints are candidates because the interval ends there. They do not need to satisfy . In fact, the derivative may not even be defined at an endpoint. Always evaluate both endpoints separately.

Worked Example 3: Derivative Undefined at a Critical Number

Example 3: A Corner Can Be a Candidate

Find the absolute maximum and minimum values of on .

Derivative:
Critical number: The derivative is undefined at , and the original function is defined there, so is a critical number.
Candidates:
Evaluate:
Conclusion: The absolute maximum and minimum are determined by comparing these candidate values.

When the Extreme Value Theorem Does Not Apply

The EVT requires continuity on a closed interval. If either condition fails, the theorem does not guarantee absolute extrema.

Open interval

Consider on . The function is continuous, but the interval is open. The function approaches its largest possible value as , but that value is never actually attained.

Discontinuous function

A function with a hole or vertical asymptote on the interval is not continuous there. Therefore, the EVT cannot guarantee an absolute maximum or minimum.

Example: Why the Closed Interval Matters

Consider on .

Continuity: The function is continuous on the interval.
But: The interval is not closed.
Result: The Extreme Value Theorem does not apply, so we cannot conclude from the theorem that an absolute maximum and minimum exist.

Absolute vs. Local Extrema

Do not confuse an absolute maximum with a local maximum.

A function can have several local extrema but only one absolute maximum value and one absolute minimum value on a given interval, although multiple points can sometimes share the same absolute value.

A Fast AP Exam Strategy

When an AP Calculus question asks for the absolute maximum or minimum of a function on a closed interval, use this checklist:

  1. Write down the interval endpoints.
  2. Differentiate the function.
  3. Find every critical number in the interval.
  4. Evaluate the original function at every critical number and both endpoints.
  5. Compare the resulting function values.
  6. State the answer clearly, including both the value and where it occurs when requested.

This method is reliable because every possible absolute extremum of a continuous function on a closed interval must occur at one of these candidates.

Common Mistakes

Checking only where f′(x) = 0

This misses endpoints and can miss critical numbers where the derivative does not exist. The complete candidate list includes critical numbers plus both endpoints.

Forgetting the original function

Once you find critical numbers, plug them into , not into . You are comparing function values, not derivative values.

Assuming every critical number is an extremum

A critical number is only a candidate. It might produce the absolute maximum, the absolute minimum, neither, or—in some cases—share an absolute value with another candidate.

Ignoring the interval

A critical number outside the specified interval is irrelevant to the Candidates Test for that problem. Find the critical numbers, then keep only those that lie in the interval.

Practice Problems

Question 1

Find the absolute maximum and minimum values of on .

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Question 2

Find the absolute maximum and minimum values of on .

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Question 3

Find the absolute maximum and minimum values of on .

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Question 4 (Conceptual)

Does the Extreme Value Theorem guarantee that has an absolute maximum and minimum on ?

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