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Finding the Slope of a Curve Defined Parametrically

How to find the slope of a parametrically defined curve without eliminating the parameter. Learn the AP Calculus formula for , evaluate it at a specific parameter value, and recognize horizontal and vertical tangents.

What Parametric Slope Means

When a curve is defined parametrically, you are given separate equations for and in terms of a third variable, usually . Instead of describing the curve directly as , the parameter tells you where you are on the curve as it changes.

The important idea is that the slope is still rise over run. The only difference is that both the vertical change and the horizontal change are expressed in terms of . So instead of differentiating directly with respect to , we calculate how quickly and are changing with respect to .

The Formula

Suppose a curve is defined parametrically by

Differentiate both equations with respect to :

Then use the fact that the slope of the curve is the rate of change of with respect to . Divide the two derivatives:

This is the central formula to memorize for parametrically defined curves:

In words: differentiate with respect to the parameter, differentiate with respect to the parameter, and divide.

A Step-by-Step Method

  1. Differentiate with respect to . This gives .
  2. Differentiate with respect to . This gives .
  3. Divide: .
  4. Substitute the given parameter value, if the problem asks for the slope at a particular point or parameter value.
  5. Simplify your answer and check whether the denominator is zero. A zero denominator means the tangent is vertical rather than giving an ordinary finite slope.

Worked Examples

Example 1: Basic Parametric Slope

Suppose

Find the slope of the curve at .

Step 1: Differentiate :
Step 2: Differentiate :
Step 3: Divide:
Step 4: Substitute :
Result: The slope is .
Example 2: Trigonometric Parametric Equations

Suppose

Find at .

Step 1: Differentiate :
Step 2: Differentiate :
Step 3: Apply the parametric slope formula:
Step 4: Evaluate at :
Result: The slope is .
Example 3: Finding the Slope at a Given Point

Consider the parametric equations

Find the slope of the curve at the point corresponding to .

Step 1: Differentiate both equations:
Step 2: Form :
Step 3: Substitute the parameter value:
Result: The slope at the specified point is .
Example 4: A More Complicated Parametric Derivative

Suppose

Find the slope when .

Step 1: Differentiate :
Step 2: Differentiate :
Step 3: Divide:
Step 4: Substitute :
Result: The slope is .

Horizontal Tangents

A horizontal tangent has slope zero. For a parametrically defined curve,

A fraction is zero when its numerator is zero, as long as the denominator is not also zero. Therefore, to find horizontal tangents:

  1. Set equal to zero.
  2. Solve for the parameter value or values.
  3. Check that is not zero at those values.
  4. Find the corresponding point if the problem asks for coordinates.
Example 5: Finding a Horizontal Tangent

Let

Find the parameter value where the curve has a horizontal tangent.

Step 1: Differentiate:
Step 2: Set the numerator equal to zero:
Step 3: Check the denominator:
Result: The horizontal tangent occurs when .

Vertical Tangents

A vertical tangent occurs when the horizontal rate of change is zero while the vertical rate of change is not zero. In parametric form, that means

So to find vertical tangents:

  1. Set equal to zero.
  2. Solve for the parameter value or values.
  3. Check that is not zero.
  4. Find the corresponding point if required.
Example 6: Recognizing a Vertical Tangent

Suppose

Find the parameter value where the curve has a vertical tangent.

Step 1: Differentiate:
Step 2: Set equal to zero:
Step 3: Check :
Result: The curve has a vertical tangent when .

Why the Formula Works

The formula for parametric slope is not a new rule that appears out of nowhere. It comes directly from the chain rule.

Since both and depend on , think of as a function of and as a function of .

Using the chain rule,

Now solve this equation for :

So the familiar parametric derivative formula is really a direct consequence of the chain rule. This is also why it is important to understand what the parameter represents: it is the variable through which both coordinates are changing.

Common Mistakes

Dividing in the wrong order

The slope is vertical change divided by horizontal change. Therefore the correct formula is , not . Think "dy over dx," so the derivative of goes on top and the derivative of goes on the bottom.

Forgetting that both equations must be differentiated with respect to the parameter

If the equations are written in terms of , you should calculate and . Do not differentiate one equation with respect to and the other with respect to .

Substituting the wrong variable

If a problem asks for the slope at , substitute the parameter value into your final expression for . Do not automatically substitute the x-coordinate unless the problem specifically gives you a way to determine the corresponding parameter value.

Missing a vertical tangent

If is zero, the slope formula has a zero denominator. That does not mean "the slope is zero." It means you should check whether is nonzero. If it is, the tangent is vertical.

Practice Problems

Question 1

The curve is defined by . Find at .

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Question 2

The curve is defined by . Find the slope at .

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Question 3

For , find the parameter value where the curve has a horizontal tangent.

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Question 4 (Vertical Tangent)

For , find the parameter value where the curve has a vertical tangent.

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