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AP Calculus BC Intermediate

Total Distance Traveled by a Particle in the Plane

How to find the actual distance a particle travels along its path in the plane using the magnitude of its velocity vector and a definite integral. The key distinction: total distance measures the entire path, not just the particle's net displacement.

Distance Is Not the Same as Displacement

When a particle moves in the plane, its position can be described by a vector-valued function , where gives the particle's horizontal position and gives its vertical position at time .

The displacement of the particle over an interval is the change in its position. It tells you where the particle ended up relative to where it started. But displacement does not tell you how much ground the particle actually covered.

If a particle moves forward, turns around, and then comes back toward its starting point, its displacement may be small even though it traveled a substantial distance.

Key Distinction

Displacement is a vector and depends only on the starting and ending positions. Total distance traveled is a scalar and accounts for every part of the path.

Velocity Gives Us the Direction and Speed

The velocity vector is the derivative of the position vector:

Therefore, if , then:

The velocity vector tells us both how the particle is moving horizontally and how it is moving vertically. But for total distance, we need the particle's speed.

Speed Is the Magnitude of the Velocity Vector

If the velocity vector is , its magnitude is:

This is the particle's speed. Speed is always nonnegative because it represents how quickly the particle is moving, regardless of its direction.

Notice the squares under the square root. The horizontal and vertical velocity components contribute together to the particle's instantaneous speed.

The Total Distance Formula

Once we know the speed as a function of time, we can accumulate that speed over the entire time interval. If the particle moves from time to time , the total distance traveled is:

In other words:

This is one of the most important formulas for vector-valued motion in AP Calculus BC.

Why We Integrate Speed

Think about what happens during a very small time interval . If the particle's speed is approximately , then the small amount of distance traveled is approximately:

Adding all of those tiny distances over the entire interval produces a definite integral:

So the distance formula is really just the continuous version of the familiar relationship distance = rate × time.

A Step-by-Step Method

  1. Start with the position function. Identify and .
  2. Differentiate to find velocity. Calculate and .
  3. Find speed. Take the magnitude of the velocity vector: .
  4. Set up the distance integral. Integrate speed over the requested time interval.
  5. Evaluate the integral. Use an antiderivative when possible or a calculator when the integral does not have a convenient elementary antiderivative.

Worked Examples

Example 1: Polynomial Motion

A particle moves in the plane according to , for . Find the total distance traveled.

Step 1: Identify the position components: and .
Step 2: Differentiate to find velocity:
Step 3: Find speed by taking the magnitude:
Step 4: Integrate speed from to :
Result:
Example 2: Trigonometric Motion

A particle has position for . Find the total distance traveled.

Step 1: The position components are and .
Step 2: Differentiate:
Step 3: Calculate speed:
Step 4: Integrate speed:
Result:
Example 3: Calculator-Based Distance Integral

A particle moves according to for . Find the total distance traveled, rounded to three decimal places.

Step 1: Differentiate the position function:
Step 2: Find the speed:
Step 3: Set up the distance integral:
Step 4: Evaluate numerically:
Result:
Example 4: Distance Versus Displacement

A particle moves along a straight line with position for . Find both the displacement and the total distance traveled.

Step 1: Find the displacement:
Step 2: Find velocity:
Step 3: Because this is one-dimensional motion, speed is the absolute value of velocity:
Step 4: The velocity changes sign, so the particle reverses direction. Find the total distance by integrating speed:
Result:

The Most Important AP Calculus Distinction

Students frequently confuse net displacement with total distance traveled. The formulas look similar, but there is a critical difference.

The displacement integral uses the velocity vector itself. The distance integral uses the magnitude of the velocity vector.

In one-dimensional motion, this distinction appears as the difference between integrating velocity and integrating the absolute value of velocity:

In two-dimensional motion, the same idea applies, except the absolute value is replaced by the magnitude of the velocity vector.

Why You Cannot Usually Just Integrate the Velocity Components

Suppose . It is tempting to calculate and add the two integrals.

That does not give total distance. The two components describe movement in perpendicular directions, so their contributions must be combined using the Pythagorean theorem at each instant.

Only after finding this magnitude do we integrate over time.

Mistake: Integrating velocity instead of speed

The integral of velocity gives displacement, not total distance. For total distance, first calculate the magnitude of the velocity vector and then integrate that nonnegative quantity.

Mistake: Adding the horizontal and vertical distances

Do not integrate and separately and add them. Horizontal and vertical motion combine according to the Pythagorean theorem, producing the speed .

Mistake: Forgetting that speed is nonnegative

Speed cannot be negative. If your proposed speed function can become negative, you have not correctly calculated the magnitude of the velocity vector.

Mistake: Reporting displacement as distance

A particle can travel around a complicated path and finish close to its starting point. A small displacement does not mean a small total distance.

When the Particle Changes Direction

In two-dimensional motion, a particle can change direction even when neither velocity component individually becomes zero. The direction of the velocity vector is determined by both components together.

For total distance, this does not create the same absolute-value issue that occurs in one-dimensional motion. The speed is already a magnitude:

Because a square root of a sum of squares is nonnegative, the speed automatically measures the amount of motion regardless of direction.

AP Exam Tip

If an AP Calculus BC question asks for the total distance traveled, look for the magnitude of velocity inside the integral. If it asks for displacement, integrate the velocity components directly.

Using a Calculator for Distance

Many AP Calculus BC distance problems lead to an integral that does not have a convenient elementary antiderivative. That is completely normal.

For example, if the speed is , you can set up:

Then use your calculator's numerical integration function to evaluate the integral. On the AP exam, the setup is often just as important as the numerical value.

A Reliable AP Calculus Workflow

  1. Write the position vector.
  2. Differentiate to get the velocity vector.
  3. Take the magnitude of velocity.
  4. Put the speed inside a definite integral.
  5. Use the stated time interval as the limits.
  6. Evaluate exactly or numerically.
  7. Include units when the problem gives them.

A useful memory shortcut is:

Practice Problems

Question 1

A particle has position for . Find the total distance traveled.

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Question 2

A particle has position . Find the speed of the particle at .

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Question 3

A particle moves according to for . Set up, but do not evaluate, an integral representing the total distance traveled.

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Question 4

A particle has velocity . Find the total distance traveled from to .

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Question 5 (Conceptual)

Explain why integrating the velocity vector over a time interval does not generally give the total distance traveled.

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