Tutorials › CAS Exam 8 - Advanced Ratemaking › Choosing Count, Rate, or Binary Likelihoods

CAS Exam 8 · Bayesian Credibility Foundations · Tutorial 437 of 989

Choosing Count, Rate, or Binary Likelihoods

Learn to match claim data to its sampling process, use exposure correctly, and avoid treating claim counts, rates, and binary outcomes as interchangeable.

Intermediate 11 min read

What You'll Learn

  • Identify when claims should be modeled as Poisson counts and how exposure enters the likelihood.
  • Explain why an exposure-adjusted rate is not a separate sampling model.
  • Calculate exposure-weighted claim rates and distinguish them from unweighted averages.
  • Choose a binomial likelihood when each trial records one binary outcome.
  • Update Gamma-Poisson and Beta-Binomial models under stated assumptions.
  • Recognize when a binary outcome loses information about claim frequency.

Choosing a Likelihood From the Data-Generating Process

A claim dataset may be presented as counts, rates, or indicators such as “at least one claim.” Those summaries are not interchangeable. The correct likelihood depends on what was observed, what the denominator represents, and what outcomes a trial can produce. A count records how many events occurred over exposure; a binary indicator records only whether an event occurred at least once during a defined trial.

The choice matters in credibility calculations because the likelihood determines how exposure and observations update the unknown risk parameter. A rate can be a useful way to report experience, but it does not automatically define a new probability model. The first question is always how the underlying data were generated.

Definition: A Poisson count likelihood models the number of events observed over a known exposure when, conditional on a constant event rate, events occur independently at that rate. An exposure-adjusted claim rate is the observed count divided by its exposure. A binomial likelihood models the number of successes among a fixed number of independent trials, each with the same success probability.

Counts and Exposure-Adjusted Rates

Suppose \(N_j\) is the claim count for observation \(j\), \(e_j\) is its exposure, and \(\lambda\) is the claim rate per unit of exposure. Under a common-rate Poisson model, the conditional distribution is \(N_j\mid\lambda\sim\operatorname{Poisson}(e_j\lambda)\). Its probability mass function is

$$ P(N_j=n_j\mid\lambda) = \frac{\exp(-e_j\lambda)(e_j\lambda)^{n_j}}{n_j!}, \qquad n_j=0,1,2,\ldots $$

The exposure unit must be specified: it might be policy-years, vehicle-years, or another appropriate measure. The model assumes the rate is constant over the exposure being combined, the counts are conditionally independent, and the exposure is known. If risk varies materially across observations, a single common \(\lambda\) may not be appropriate without further adjustment or a different model.

For independent observations sharing \(\lambda\), write \(N=\sum_j n_j\) and \(E=\sum_j e_j\). Multiplying their likelihoods gives

$$ L(\lambda) \propto \exp(-E\lambda)\lambda^N. $$

Thus the count and total exposure enter through their sums. The maximum-likelihood estimate of the common rate is \(N/E\), the total count divided by total exposure. This is also the exposure-weighted average of the observation-specific rates \(n_j/e_j\).

Key distinction: The observed rate \(n_j/e_j\) is calculated from a count and its exposure; it is not, by itself, a Poisson-distributed count. If counts and exact exposures are available, use the count likelihood. If only a rounded rate is reported, the original count may not be recoverable, and the exact count likelihood cannot be reconstructed from that rounded value alone.

Worked Example: Updating a Claim Rate From Counts and Exposure

A hypothetical specialty insurer observes 4 claims over 2 policy-years and 7 claims over 5 policy-years. Assume both observations share a constant claim rate \(\lambda\) per policy-year and are conditionally independent given \(\lambda\). The prior is Gamma with shape \(\alpha=3\) and rate \(\beta=2\), so its density is proportional to \(\lambda^{\alpha-1}\exp(-\beta\lambda)\) and its mean is \(\alpha/\beta\). No interest rate or mortality assumption applies. Find the posterior mean claim rate.

Method and assumptions. Use the Gamma-Poisson update. The model is \(N_j\mid\lambda\sim\operatorname{Poisson}(e_j\lambda)\), and the prior is Gamma(shape 3, rate 2). The exposures and counts are assumed exact.

Combine the data. The total count is \(N=4+7=11\) claims. The total exposure is \(E=2+5=7\) policy-years. The observed exposure-adjusted rate is \(11/7=1.5714\) claims per policy-year.

Update the parameters. The likelihood contributes 11 to the shape and 7 to the rate. The posterior is Gamma with shape \(3+11=14\) and rate \(2+7=9\). Its mean is \(14/9=1.5556\) claims per policy-year.

Check and trap avoided. The result is slightly below the observed rate because the prior mean is \(3/2=1.5\). Adding the prior rate 2 to the count, or adding the prior shape 3 to the exposure, would mix unlike quantities. The update uses shape plus claims and rate plus exposure.

Why Exposure Weights Rates

An observation based on more exposure represents more opportunities for claims. This is why the combined rate is not generally the simple average of individual rates. The justification follows directly from the likelihood: all count contributions contain \(\lambda^{n_j}\), while all exposure contributions contain \(\exp(-e_j\lambda)\). Multiplying these factors adds counts and exposures separately.

$$ L(\lambda) \propto \prod_j \exp(-e_j\lambda)\lambda^{n_j} = \exp\!\left(-\lambda\sum_j e_j\right) \lambda^{\sum_j n_j}. $$

The log-likelihood, ignoring terms that do not depend on \(\lambda\), is \(N\log\lambda-E\lambda\). Differentiating gives \(N/\lambda-E\); setting this equal to zero yields \(\hat{\lambda}=N/E\) when \(N>0\). If \(N=0\), the likelihood is maximized at the boundary \(\hat{\lambda}=0\). This derivation explains why counts and exposures, rather than an unweighted average of rates, determine the estimate.

Worked Example: Combining Rates With Unequal Exposure

A hypothetical program reports a rate of 2 claims per policy-year from 2 claims over 1 policy-year in one segment, and a rate of 0.75 claims per policy-year from 6 claims over 8 policy-years in another. Assume a shared underlying rate after any needed risk adjustment. A Gamma prior has shape 2 and rate 2. Find the observed combined rate and posterior mean. No interest rate or mortality assumption applies.

Method. Treat each reported rate as a summary of its underlying count and exposure, then use the Poisson likelihood with total count and total exposure. The prior distribution is Gamma(shape 2, rate 2), with mean \(2/2=1\).

Combine the observations. The total count is \(2+6=8\). The total exposure is \(1+8=9\) policy-years. Therefore, the combined observed rate is \(8/9=0.8889\) claims per policy-year.

Update. The posterior is Gamma with shape \(2+8=10\) and rate \(2+9=11\). Its mean is \(10/11=0.9091\) claims per policy-year.

Check and trap avoided. The posterior mean lies between the prior mean 1 and the observed rate 0.8889. The unweighted average of the two segment rates is \((2+0.75)/2=1.375\), which is not the pooled rate: it gives the one-year segment the same weight as the eight-year segment. The exposure-weighted rate is \(8/9\), not 1.375.

When the Observation Is Binary

A different data structure arises when each trial has a fixed definition and can be classified as either a success or a failure. For example, a trial might be one policy-year, with success defined as “at least one claim during the year.” If there are \(n\) independent trials, each with the same probability \(q\) of success, then the number \(X\) of successes has a binomial distribution:

$$ X\mid q\sim\operatorname{Binomial}(n,q), \qquad P(X=x\mid q) = \binom{n}{x}q^x(1-q)^{n-x}. $$

This model assumes a fixed number of trials, independent outcomes, and a common success probability. A Beta prior with parameters \(a,b\) has density proportional to \(q^{a-1}(1-q)^{b-1}\). Combining it with the binomial likelihood gives a Beta posterior with parameters \(a+x\) and \(b+n-x\); the posterior mean is \((a+x)/(a+b+n)\). This update is appropriate for a probability of a binary outcome, not automatically for a claim count rate.

A binary “any claim” indicator discards information about the number of claims on a trial that had at least one. If a policy-year can have several claims, the indicator treats one claim and several claims alike. Use the binomial model when the target is the probability of at least one claim under the defined trial, or when the data truly consist of one binary outcome per trial. Use count data when the number of claims is observed and claim frequency is the target.

Worked Example: Updating an Any-Claim Probability

A hypothetical warranty portfolio contains 80 completed one-year contracts. Each contract is recorded only as having at least one claim or no claim; 9 contracts had at least one claim. Assume independent contracts with a common annual any-claim probability \(q\). The prior is Beta with \(a=2\) and \(b=18\). No interest rate or mortality assumption applies. Find the posterior mean of \(q\).

Method and assumptions. Use the Beta-Binomial update because there are 80 fixed binary outcomes. The observed success count is \(x=9\), and the failure count is \(80-9=71\). The prior mean is \(2/(2+18)=0.1\).

Update. The posterior is Beta with parameters \(a+x=2+9=11\) and \(b+n-x=18+71=89\). The posterior mean is \(11/(11+89)=11/100=0.1100\), or 11.00%.

Check and trap avoided. There are 9 positive indicators among 80 contracts, so the raw observed proportion is \(9/80=0.1125\); the posterior mean is slightly closer to the prior mean of 0.1. This calculation estimates the probability of at least one claim, not the expected number of claims per contract. If a contract could have multiple claims, those additional claims are not represented in these binary data.

A Practical Selection Process

Before selecting a likelihood, describe the observation mechanism in words. The same portfolio can support different models depending on how experience was recorded and what quantity is being estimated.

1
Identify the observational unit.
Determine whether each record is a policy-year, a contract, a vehicle-year, or another defined trial or exposure unit.
2
Ask what the data record.
If the data give the number of events, consider a count model. If each trial gives only yes or no, consider a binary model.
3
Check the denominator.
For counts, identify exposure and its units. For binary outcomes, identify the fixed number of trials and the event defining success.
4
Match the parameter to the question.
A Poisson rate is expected claims per exposure unit; a binomial parameter is the probability of the specified success on one trial.
5
Verify the assumptions.
Check whether the common-rate or common-probability and conditional independence assumptions are defensible. If not, the basic likelihood may be inadequate.
Data structureNatural likelihoodParameter interpreted as
Number of claims with known exposurePoisson count likelihoodClaim rate per exposure unit
Count divided by its exposureUnderlying count likelihood, if count and exposure are availableObserved rate is a summary; pooled rate weights by exposure
Number of trials with an event indicator for eachBinomial likelihoodProbability of the defined event per trial

Common Mistakes and Model Limits

The most frequent error is to focus on the column label—“frequency,” “rate,” or “claim incidence”—instead of how the observations were produced. A rate may be a count divided by exposure, while an incidence measure may be a count of trials with any event divided by the number of trials. These have different denominators and different interpretations.

  • Averaging rates without exposure weights. If exposures differ, use total claims divided by total exposure. An ordinary average gives equal weight to observations with unequal amounts of experience.
  • Using a binomial model for a claim count. Binomial outcomes allow only success or failure per trial. If multiple claims can occur and are observed, a count likelihood preserves that information.
  • Using a Poisson model for a binary record without checking the target. A binary record may support an any-claim probability, but it does not reveal the number of claims on positive trials.
  • Ignoring units or changing denominators. A rate per policy-year is not numerically interchangeable with a rate per vehicle-year unless the exposure definition is consistent.

The basic models also have limits. A Poisson model with a common rate implies conditional variance equal to the conditional mean for a given exposure. A binomial model with a common probability assumes independent trials with the same success probability. Strong dependence, changing risks, or unexplained variation can undermine these assumptions. Model choice is not settled by arithmetic alone: the likelihood must represent the sampling process sufficiently well for the intended estimate.

Key takeaway: Choose the likelihood from the observed outcome and its denominator. Use counts with exposure to estimate a claim rate; use fixed binary trials to estimate an event probability. A reported rate is usually a summary of counts, while a binary indicator may discard claim-count information.

Check Your Understanding

For each problem, identify the appropriate data structure and carry out the requested calculation.

  1. A hypothetical portfolio has 6 claims over 3.5 policy-years. A Gamma prior has shape 2 and rate 1. Find the posterior mean claim rate under a common-rate Poisson model. (Answer: 1.7778 claims per policy-year)
  2. One segment has 3 claims over 2 exposure units, and another has 10 claims over 8 exposure units. Find the pooled rate and the unweighted average of the two segment rates. (Answer: pooled rate \(13/10=1.3000\); unweighted average \(1.3750\))
  3. Among 90 independent one-year contracts, 12 have at least one claim. With a Beta prior having \(a=1\) and \(b=9\), find the posterior mean any-claim probability. (Answer: \(13/100=0.1300\))
  4. A risk group has no claims over 3 policy-years. Its prior is Gamma with shape 4 and rate 2. Under the Poisson model, find the posterior mean claim rate and state why the zero count does not make the posterior mean zero. (Answer: \(4/5=0.8000\) claims per policy-year; the prior shape remains positive.)
  5. For 150 hypothetical contracts, records show 14 contracts with at least one claim and 18 total claims. If the target is the annual probability of any claim, which count should enter the binomial update? If the target is claims per contract-year, which observation is needed for a Poisson rate estimate? (Answer: use 14 successes out of 150 for the binomial any-claim probability; use 18 claims and the total contract-year exposure for the Poisson rate.)
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