Tutorials › CAS Exam 8 - Advanced Ratemaking › Choosing The Exposure Basis For Claim Frequency

CAS Exam 8 · Frequency Model Specification · Tutorial 101 of 989

Choosing The Exposure Basis For Claim Frequency

Choose an exposure basis that matches the insured risk and claim count, then calculate and interpret frequency rates without mixing denominators.

Intermediate 11 min read

What You'll Learn

  • Define policy-year and vehicle-year exposure and distinguish the risk units they measure
  • Select a denominator that is consistent with the coverage, claims, and rating question
  • Calculate frequency using alternative exposure bases and state the units of each rate
  • Explain why changing the denominator can change comparisons between groups
  • Pool claim counts and exposures correctly when estimating a common Poisson rate
  • Identify common exposure-basis errors, including inconsistent periods and double counting

Why the Exposure Basis Matters

A claim frequency is a count divided by an amount of exposure. The denominator is not just a convenient scaling factor: it defines the unit of risk to which the claim rate refers. For an automobile portfolio, a claim rate per policy-year answers a different question from a rate per vehicle-year when policies cover different numbers of vehicles. A sound frequency analysis therefore starts by deciding what one unit of exposure represents.

The exposure basis should fit the insured object, the way claims are counted, and the purpose of the analysis. Once the basis is chosen, the frequency model must use the corresponding exposure consistently. The earlier material on offsets explains how a known exposure amount enters a frequency model; here the focus is what that amount should measure.

Definition: An exposure basis is the defined unit or quantity of insured risk used as the denominator for a claim frequency. If \(N\) is the claim count and \(E\) is exposure measured on a specified basis, the observed frequency is \(N/E\), with units of claims per unit of that exposure.

Common Exposure Bases

A policy-year is one policy in force for one year. Partial periods contribute fractional policy-years: for example, one policy in force for six months contributes \(0.5\) policy-years, assuming the period is measured on a year basis. Vehicle-years count insured vehicles over time. One vehicle insured for one year contributes one vehicle-year; two vehicles insured for six months each also contribute one vehicle-year in total.

The two measures are related but not identical. A policy covering several vehicles contributes one policy-year for a full year, but several vehicle-years. Other lines may use exposure measures such as payroll, sales, passenger miles, or machine-hours when those quantities are suitable measures of the risk being insured. The appropriate choice depends on the coverage and how the exposure data and claims are defined.

Exposure basisOne unit representsExample question answered
Policy-yearOne policy in force for one yearHow many claims occur per policy-year?
Vehicle-yearOne insured vehicle for one yearHow many claims occur per vehicle-year?
PayrollA stated amount of payroll, such as $1,000How many claims occur per $1,000 of payroll?
Machine-hoursOne hour of operation of insured equipmentHow many claims occur per machine-hour?

There is no universally best basis. Policy-years may be appropriate when the insured risk and claim count are fundamentally policy-level. Vehicle-years can be more informative when each insured vehicle is a distinct source of claim exposure and policy sizes vary. A denominator should not be selected just because it is available or produces a preferred rate.

Key condition: The claim count and exposure must refer to the same coverage, risk population, and observation period. The exposure should measure the quantity of insured risk consistently; it should not be a quantity changed by the claims being counted.

Worked Rates on Different Bases

Worked Example: Converting the Denominator, Not the Claim Count

A hypothetical commercial auto portfolio has 36 policy-years, 90 vehicle-years, and 18 reported claims for a specified coverage. Calculate the observed frequency per policy-year and per vehicle-year, and explain why the results differ.

Method. Divide the same claim count by each exposure total, and attach the exposure unit to each rate.

Per policy-year:

$$ \frac{18\text{ claims}}{36\text{ policy-years}} =0.5\text{ claims per policy-year}. $$

Per vehicle-year:

$$ \frac{18\text{ claims}}{90\text{ vehicle-years}} =0.2\text{ claims per vehicle-year}. $$

The rate per policy-year is \(0.5\), while the rate per vehicle-year is \(0.2\). These are not conflicting estimates expressed in the same units; they answer different questions. The portfolio has \(90/36=2.5\) vehicle-years per policy-year on average, and \(0.5/2.5=0.2\) claims per vehicle-year. This conversion describes the portfolio totals, not a universal relationship that must hold for every group or policy.

Check. Multiplying \(0.2\) claims per vehicle-year by 90 vehicle-years gives 18 claims. The numerator and denominator units have been kept consistent. A common mistake is to call both figures simply “the frequency” and compare them as if they used the same basis.

How the Choice Can Change Comparisons

When groups have different average numbers of vehicles per policy, dividing by policy-years and dividing by vehicle-years can produce different comparisons. This is a substantive consequence of changing the unit of exposure, not a rounding issue. Before interpreting a difference, state the denominator and check whether the groups have comparable exposure composition on that basis.

Worked Example: Group Ranking Depends on the Exposure Basis

Two hypothetical territories have the following results for the same coverage and period. Territory A has 35 claims, 100 policy-years, and 140 vehicle-years. Territory B has 24 claims, 80 policy-years, and 80 vehicle-years. Calculate each territory’s frequency on both bases and identify which territory has the higher rate under each definition.

Method. Calculate each group’s claim count divided by its policy-years, then separately divided by its vehicle-years.

For Territory A:

$$ \frac{35}{100}=0.35\text{ claims per policy-year}, \qquad \frac{35}{140}=0.25\text{ claims per vehicle-year}. $$

For Territory B:

$$ \frac{24}{80}=0.30\text{ claims per policy-year}, \qquad \frac{24}{80}=0.30\text{ claims per vehicle-year}. $$

On a policy-year basis, Territory A has the higher observed rate: \(0.35>0.30\). On a vehicle-year basis, Territory B has the higher observed rate: \(0.30>0.25\). Territory A has \(140/100=1.4\) vehicle-years per policy-year, whereas Territory B has \(80/80=1.0\). The different average number of vehicles per policy helps explain why the rankings change.

Check. The computed claim counts are recovered from either denominator: for A, \(0.35(100)=35\) and \(0.25(140)=35\); for B, \(0.30(80)=24\) on both bases. The common mistake is to compare A’s rate per policy-year with B’s rate per vehicle-year. That comparison is invalid because the units differ.

Exposure and a Common Poisson Frequency Rate

A standard frequency formulation assumes that, for a stated exposure basis, the count \(N_j\) in observation \(j\) has a Poisson distribution with mean \(e_j\lambda\). Here \(e_j\) is the known exposure on that basis and \(\lambda\) is a common claim rate per exposure unit. The model assumes a common rate across the observations being pooled, conditional on the model specification, and that the counts follow the stated Poisson model. If the observations have different underlying rates, one common rate is not an appropriate description without further modeling.

Under these assumptions, the maximum-likelihood estimate of the common rate is total claims divided by total exposure. This is an exposure-weighted rate, not generally the simple average of the individual observed rates.

Why Total Claims Divided by Total Exposure Works

For independent observations \(N_j\sim\operatorname{Poisson}(e_j\lambda)\), the likelihood, omitting factors that do not involve \(\lambda\), is proportional to \(\prod_j (e_j\lambda)^{N_j}\exp(-e_j\lambda)\). Taking its logarithm and differentiating gives the score equation below.

$$ \ell(\lambda) =\sum_j\left[N_j\log(e_j\lambda)-e_j\lambda-\log(N_j!)\right], \qquad \frac{d\ell}{d\lambda} =\frac{\sum_jN_j}{\lambda}-\sum_je_j. $$

Setting the derivative equal to zero gives the estimate. For positive total exposure, the log-likelihood is concave in \(\lambda\), since its second derivative is negative when there are claims. Thus this stationary point is the maximum. If total claims are zero, the likelihood is maximized at the boundary \(\hat{\lambda}=0\).

$$ \hat{\lambda}=\frac{\sum_jN_j}{\sum_je_j}. $$

This derivation also explains why exposure amounts, rather than observations counted equally, determine the pooling weights. Each observation contributes claims and its corresponding amount of exposure. A high-frequency estimate based on very little exposure should not receive the same weight as an estimate based on much more exposure when the model assumes one common rate.

Worked Example: Pooling Unequal Vehicle-Year Exposures

A hypothetical insurer observes 8 claims over 40 vehicle-years in one fleet segment and 18 claims over 60 vehicle-years in another. Assume, for this calculation, that both segments share one Poisson claim rate per vehicle-year. Estimate that rate and calculate the fitted expected claim count for a future 25 vehicle-years at the same rate.

Method. Use the common-rate Poisson estimate, total claims divided by total exposure. First add the counts and exposures:

$$ N_{\text{total}}=8+18=26, \qquad E_{\text{total}}=40+60=100\text{ vehicle-years}. $$

The estimated frequency is:

$$ \hat{\lambda}=\frac{26}{100}=0.26\text{ claims per vehicle-year}. $$

For 25 vehicle-years, the fitted mean count is:

$$ 25(0.26)=6.5\text{ claims}. $$

As a check, the segment rates are \(8/40=0.20\) and \(18/60=0.30\). Their exposure-weighted average is \(\bigl(40(0.20)+60(0.30)\bigr)/100=(8+18)/100=0.26\). The unweighted average, \((0.20+0.30)/2=0.25\), is not the common-rate maximum-likelihood estimate because the segments have unequal exposures. The assumption of a common rate is important: if the segments have genuinely different rates, the pooled estimate is only an overall exposure-weighted summary, not a rate that describes each segment separately.

Choosing and Auditing a Basis

A practical choice follows from the intended interpretation and the data definition. Ask which object or quantity is exposed to the covered peril, whether the claims are counted on that same basis, and whether the exposure can be measured consistently across risks and periods. For example, a policy-level coverage may naturally be analyzed per policy-year, whereas vehicle-level claim frequency may be better expressed per vehicle-year if vehicle counts and insured periods are known.

For any selected basis, verify that:

  • Exposure includes only the period during which the relevant coverage was in force.
  • The unit is consistent across policies, groups, and time periods, including partial periods.
  • Claims and exposure refer to the same coverage and risk population.
  • A multi-item policy contributes the appropriate number of units when the chosen basis counts items separately.
  • The chosen denominator is not confused with premium, which is a price rather than a direct measure of exposure.

A policy-year and a vehicle-year can both be valid for the same portfolio, but their rates should not be interchanged without an explicit conversion and a clear statement of assumptions. In particular, a portfolio-wide average number of vehicles per policy does not guarantee that every rating group has the same mix. A single conversion factor can therefore obscure differences in composition.

Common exam trap: If a problem asks for claims per vehicle-year, dividing claims by policy-years is wrong even when the policy data are easier to obtain. For example, 12 claims over 30 policy-years is \(0.40\) claims per policy-year, not \(0.40\) claims per vehicle-year. If those policies represent 60 vehicle-years, the vehicle-year rate is \(12/60=0.20\) claims per vehicle-year.

Check Your Understanding

For each problem, state the exposure basis and retain its units in the final rate.

  1. A hypothetical book has 42 claims, 120 policy-years, and 180 vehicle-years. Calculate the observed rates per policy-year and per vehicle-year. (Answer: \(0.35\) claims per policy-year and \(0.2333\) claims per vehicle-year.)
  2. A policy covers three vehicles for four months, with all coverage in force throughout that period. Calculate the policy-year and vehicle-year exposures. (Answer: \(1/3\) policy-year and \(1\) vehicle-year.)
  3. Territory C has 16 claims, 40 policy-years, and 80 vehicle-years. Territory D has 15 claims, 60 policy-years, and 60 vehicle-years. Which has the higher rate on each basis? (Answer: C is higher per policy-year, \(0.40\) versus \(0.25\); D is higher per vehicle-year, \(0.25\) versus \(0.20\).)
  4. Two hypothetical segments have 9 claims over 30 vehicle-years and 21 claims over 70 vehicle-years. Under a common Poisson rate per vehicle-year, estimate the rate and the fitted mean count for 20 vehicle-years. (Answer: \(30/100=0.30\) claims per vehicle-year; fitted mean \(20(0.30)=6\) claims.)
  5. A portfolio has 10 claims over 25 policy-years and 20 claims over 100 vehicle-years. Is the comparison of the two raw rates valid as a ranking of frequency? State each rate and explain. (Answer: The rates are \(0.40\) claims per policy-year and \(0.20\) claims per vehicle-year; they cannot be ranked directly because they use different exposure units.)
Clinical Biostats