Tutorials › CAS Exam 8 - Advanced Ratemaking › Derive Expected Limited Losses Under A Claim Cap

CAS Exam 8 · Retrospective Plan Parameters · Tutorial 623 of 989

Derive Expected Limited Losses Under A Claim Cap

Learn to calculate expected per-claim capped losses from a severity distribution and determine the expected converted loss for a portfolio.

Advanced 10 min read

What You'll Learn

  • Define the per-claim capped loss and state the assumptions behind its expected value.
  • Derive expected limited loss as an integral of the severity survival function.
  • Calculate capped expectations for exponential, uniform, and discrete severity distributions.
  • Apply a fixed loss conversion factor to expected capped losses.
  • Extend a per-claim expectation to a fixed or random number of claims.
  • Identify common errors involving losses above the cap and conversion factors.

Why Derive Expected Losses Under a Claim Cap?

In a retrospective rating calculation, a per-claim cap limits how much of any one loss enters the loss total used in the plan. When the individual claim amounts are uncertain, calculating an expected capped total requires more than multiplying the expected uncapped loss by a factor. The cap changes the expected amount contributed by each claim, and the size of that change depends on the claim severity distribution.

The calculation has two distinct stages: first cap each claim, then apply any loss conversion factor to the capped amount. This tutorial derives the expected capped amount from the severity survival function and shows how to extend that expectation to several claims. The cap discussed here applies separately to each claim, not to the portfolio total.

Definition: Let \(X\) be a nonnegative claim severity, with finite expected value, and let \(u\geq 0\) be a per-claim cap. The limited loss is \(Z=\min(X,u)\). If a fixed loss conversion factor \(c\geq 0\) is applied to that limited loss, the converted limited loss is \(cZ=c\min(X,u)\). The expected converted limited loss per claim is \(cE[\min(X,u)]\).

The factor \(c\) is assumed to be a deterministic multiplier applied to the capped loss. For example, \(c=1.08\) means the capped loss is multiplied by 1.08. This calculation does not automatically include fixed expenses or other amounts that are not multiplied by \(c\); those require separate treatment.

Deriving the Survival-Function Formula

Write the severity survival function as \(S_X(x)=P(X>x)\). For any nonnegative severity and cap \(u\), the expected limited loss is

$$ E[\min(X,u)]=\int_0^u S_X(x)\,dx. $$

This identity works for continuous, discrete, and mixed severity distributions. To see why, fix a realized claim amount \(X\). For each \(x\) between 0 and \(u\), the indicator of the event \(X>x\) is 1 exactly over a length \(\min(X,u)\). Therefore,

$$ \min(X,u)=\int_0^u \mathbf{1}_{\{X>x\}}\,dx. $$

Taking expectations and interchanging expectation and integration for this nonnegative integrand gives

$$ E[\min(X,u)] =\int_0^u E[\mathbf{1}_{\{X>x\}}]\,dx =\int_0^u P(X>x)\,dx =\int_0^u S_X(x)\,dx. $$

The formula can also be understood by splitting the loss at the cap. Since \(\min(X,u)=X-(X-u)_+\), where \((X-u)_+=\max(X-u,0)\), the cap removes the expected amount of loss above \(u\):

$$ E[\min(X,u)]=E[X]-E[(X-u)_+] =E[X]-\int_u^\infty S_X(x)\,dx. $$

The two integral forms are equivalent when \(E[X]\) is finite. The first form is often convenient when the survival function is simple below the cap; the second emphasizes the expected excess removed by the cap.

From One Claim to a Portfolio

Suppose there are \(n\) claims, each with capped amount \(Z_j=\min(X_j,u)\). Linearity of expectation gives

$$ E\left[\sum_{j=1}^n cZ_j\right] =c\sum_{j=1}^n E[Z_j]. $$

If the claims have the same severity distribution, this becomes \(ncE[\min(X,u)]\). Independence is not required for this expected-value result; the claim expectations must exist, and the same fixed factor \(c\) must apply to each claim. If claim severities differ, calculate the limited expectation for each severity distribution and add them.

If the number of claims \(N\) is random, independent of identically distributed severities, then conditioning on \(N\) gives \(E[\sum_{j=1}^N cZ_j]=E[N]cE[Z]\), provided the expectations are finite. This is an expected total, not an aggregate cap: each individual claim is limited before the amounts are summed.

Worked Calculations

Worked Example: Exponential Severity With a Per-Claim Cap

A hypothetical account has four claims. Each claim severity is exponentially distributed with mean $10,000, so its survival function is \(S_X(x)=e^{-x/10000}\) for \(x\geq 0\). The per-claim cap is $15,000, and the loss conversion factor is \(c=1.08\). Find the expected total converted limited loss, to the nearest cent.

Method. Integrate the survival function up to the cap, multiply the per-claim expected limited loss by the factor, and then multiply by four. The given mean is the exponential scale parameter, and the exponent uses the ratio \(u/10000\).

Step 1: Expected limited loss per claim.

$$ E[\min(X,15000)] =\int_0^{15000}e^{-x/10000}\,dx =10000(1-e^{-15000/10000}) =10000(1-e^{-1.5}). $$

Using \(e^{-1.5}=0.2231301601\), the expectation is \(10000(1-0.2231301601)=10000(0.7768698399)=\$7,768.6984\), or $7,768.70 to the nearest cent.

Step 2: Apply the conversion factor. The expected converted limited loss per claim is \(1.08(\$7,768.6984)=\$8,390.1943\).

Step 3: Sum over the four claims. \(4(\$8,390.1943)=\$33,560.7771\), which rounds to $33,560.78.

Check. The factor is applied once to each capped claim: equivalently, \(4(1.08)(\$7,768.6984)=\$33,560.7771\), giving the same final amount. A common mistake is to multiply the intermediate values inaccurately or to apply the factor to the wrong amount.

Worked Example: Uniform Severity and a Cap Below the Maximum

For a hypothetical equipment policy, a claim severity \(X\) is uniform on the interval from $0 to $20,000. The per-claim cap is $12,000. There are three claims, and the loss conversion factor is \(c=1.05\). Find the expected total converted limited loss to the nearest cent.

Method. For a uniform severity on \([0,b]\), the survival function is \(1-x/b\) for \(0\leq x\leq b\). Here \(b=\$20,000\), and the cap falls within the severity range, so integrate that survival function only from zero to $12,000.

Step 1: Calculate the per-claim expected limited loss.

$$ \begin{aligned} E[\min(X,12000)] &=\int_0^{12000}\left(1-\frac{x}{20000}\right)\,dx\\ &=12000-\frac{12000^2}{2(20000)}\\ &=12000-\frac{144000000}{40000}\\ &=12000-3600=\$8,400. \end{aligned} $$

Step 2: Convert and aggregate. The expected converted limited loss per claim is \(1.05(\$8,400)=\$8,820\). For three claims, the expected total is \(3(\$8,820)=\mathbf{\$26,460.00}\).

Check. The limited expectation of $8,400 is below the cap of $12,000, as it must be. The factor increases that amount to $8,820 per claim, and three claims produce $26,460.00. The common mistake this method avoids is treating the cap as though every claim paid exactly $12,000.

Worked Example: Discrete Severity With Claims Above the Cap

A hypothetical machinery program has five claims. Each claim severity is $4,000 with probability 0.50, $10,000 with probability 0.30, and $25,000 with probability 0.20. The per-claim cap is $12,000, and the loss conversion factor is \(c=1.07\). Find the expected total converted limited loss to the nearest cent.

Method. For a discrete distribution, calculate the limited amount at each possible severity, multiply each by its probability, and add. The $25,000 outcome contributes only the capped amount of $12,000.

Step 1: Apply the cap to each possible severity. The limited amounts are \(\min(4000,12000)=\$4,000\), \(\min(10000,12000)=\$10,000\), and \(\min(25000,12000)=\$12,000\).

Step 2: Take the probability-weighted average.

$$ E[\min(X,12000)] =0.50(4000)+0.30(10000)+0.20(12000) =2000+3000+2400 =\$7,400. $$

Step 3: Convert and aggregate. The expected converted limited loss per claim is \(1.07(\$7,400)=\$7,918\). For five claims, the expected total is \(5(\$7,918)=\mathbf{\$39,590.00}\).

Check. The calculation includes the probability-weighted capped payment for the $25,000 outcome. Omitting that outcome because the original severity exceeds the cap would understate the expected limited loss.

Interpretation and Common Exam Traps

A cap reduces the expected loss whenever there is positive probability of a claim exceeding the cap. The exact reduction in expected loss per claim is \(E[(X-u)_+]\), the expected excess above the cap. With a fixed conversion factor, the reduction in expected converted loss is \(cE[(X-u)_+]\). If the cap is at least as large as every possible severity, it has no effect; if the cap is zero, the limited loss is zero.

The order of operations matters conceptually: cap each claim first, then apply the loss conversion factor to the amount subject to conversion. For a fixed multiplicative factor, multiplication and expectation commute, so \(E[c\min(X,u)]=cE[\min(X,u)]\). That does not mean every plan component should be multiplied by \(c\); fixed expenses, separately rated amounts, or amounts outside the capped-loss definition must be handled according to their own terms.

  • Trap: omit payments at or above the cap. The limited loss is not \(X\mathbf{1}_{\{X\leq u\}}\). Claims with \(X>u\) still contribute \(u\).
  • Trap: cap the portfolio total instead of each claim. A per-claim cap is applied to each severity before the capped amounts are summed.
  • Trap: use an uncapped mean as the capped mean. In general, \(E[\min(X,u)]\neq E[X]\); use the survival integral or calculate the limited severity distribution.
  • Trap: multiply by the conversion factor twice. Apply \(c\) once to each capped loss, or once to the already calculated expected limited loss.
Key takeaway: For nonnegative severity \(X\) and per-claim cap \(u\), \(E[\min(X,u)]=\int_0^u S_X(x)\,dx\). For a fixed loss conversion factor \(c\), multiply this expectation by \(c\) per claim, then sum across claims. This result is aligned with the CAS Exam 8 (Advanced Ratemaking) syllabus.

Check Your Understanding

For each problem, calculate the expected limited loss first, then apply any stated conversion factor and claim count.

  1. A hypothetical severity is uniform from $0 to $30,000, with a per-claim cap of $9,000. Find the expected limited loss per claim. (Answer: $7,650.00)
  2. Claim severities are exponential with mean $6,000. A hypothetical account has three claims, a $12,000 per-claim cap, and a loss conversion factor of 1.04. Find the expected total converted limited loss to the nearest cent. (Answer: $16,186.52)
  3. A severity is $2,000 with probability 0.40, $8,000 with probability 0.35, and $20,000 with probability 0.25. With a $10,000 cap, six claims, and conversion factor 1.10, find the expected total converted limited loss. (Answer: $40,260.00)
  4. Claim severity is exponential with mean $12,000. There are two claims, each capped at $6,000, and the conversion factor is 1.02. Find the expected total converted limited loss to the nearest cent. (Answer: $9,632.13)
  5. A hypothetical account has a Poisson-distributed claim count with mean 2.5, independent of identically distributed exponential severities with mean $8,000. Each claim is capped at $10,000, and the conversion factor is 1.06. Find the expected total converted limited loss to the nearest cent. (Answer: $15,126.10)
Clinical Biostats