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CAS Exam 8 · Credibility in Experience Rating · Tutorial 469 of 989

Deriving The Bühlmann Experience Modification

See why the Bühlmann premium is the best linear estimate of a risk’s hypothetical mean, and convert it into a multiplicative experience modification relative to the collective premium.

Advanced 12 min read

What You'll Learn

  • State the conditional independence and equal-exposure assumptions behind the Bühlmann premium.
  • Derive the least-squares linear predictor of a risk’s hypothetical mean.
  • Interpret the Bühlmann credibility factor through EPV and VHM.
  • Calculate a credibility premium and its multiplicative experience modification.
  • Distinguish an experience modification factor from its percentage adjustment.
  • Identify when the Bühlmann derivation does not apply.

Why Derive an Experience Modification?

An experience-rated premium combines a risk’s own observed experience with a collective benchmark. The Bühlmann formula is often introduced as a weighted average, but its weights have a precise justification: among linear estimates based on the observed experience, it minimizes expected squared error in estimating the risk’s hypothetical mean. Writing the premium relative to the collective premium then gives a multiplicative experience modification, which is convenient when the starting rate is expressed as a dollar premium or loss cost.

The derivation concerns equal-exposure observations under the classical Bühlmann model. It does not by itself establish a nonlinear posterior mean, handle unequal exposures, or specify operational rating constraints. Those distinctions matter when deciding whether the formula fits a particular rating problem.

Definition: Let \(\Theta\) denote a risk’s latent risk characteristic. Its hypothetical mean is \(m(\Theta)=E[X_j\mid\Theta]\), the conditional expected outcome for one observation. The collective mean is \(\mu=E[m(\Theta)]=E[X_j]\). The expected process variance is \(\mathrm{EPV}=E[\operatorname{Var}(X_j\mid\Theta)]\), and the variance of hypothetical means is \(\mathrm{VHM}=\operatorname{Var}(m(\Theta))\).

Model and Assumptions

Suppose a risk has \(n\) observations \(X_1,\ldots,X_n\). Conditional on \(\Theta\), assume these observations are independent and identically distributed, with finite second moments, conditional mean \(m(\Theta)\), and conditional variance that may depend on \(\Theta\). Assume also that \(0<\mathrm{VHM}<\infty\) and \(0\leq\mathrm{EPV}<\infty\). Equal exposure and a common measurement basis across observations are implicit in this setup.

The target is \(m(\Theta)\), not the next random observation itself. The distinction is important: an observation has both risk-level variation and process variation, while the hypothetical mean describes the risk level without the new observation’s process noise.

Definition: The Bühlmann credibility parameter is \(K=\mathrm{EPV}/\mathrm{VHM}\). For \(n\) equal-exposure observations, the Bühlmann credibility factor is \(Z=n/(n+K)\), and the Bühlmann premium is \(P=Z\bar X+(1-Z)\mu\), where \(\bar X=(X_1+\cdots+X_n)/n\).

Here, \(\mathrm{EPV}\) measures the average variability of observations around their own risk’s hypothetical mean; \(\mathrm{VHM}\) measures the variability of those hypothetical means across risks. Greater process noise relative to between-risk variation makes individual experience less informative, while more observations increase its weight.

Least-Squares Derivation

Consider a linear predictor of the hypothetical mean of the form \(a+\sum_{j=1}^n b_jX_j\). Choose the coefficients to minimize the unconditional expected squared prediction error \(E[(m(\Theta)-a-\sum_j b_jX_j)^2]\). This is a best linear predictor: it minimizes squared error within the class of linear functions of the observations. Without additional distributional assumptions, it need not equal the full conditional expectation \(E[m(\Theta)\mid X_1,\ldots,X_n]\).

The observations are exchangeable under the model, so the minimizing coefficients on the observations are equal. Write their common value as \(b\). The least-squares residual must have zero covariance with each \(X_j\). This condition follows by differentiating the expected squared error with respect to its coefficient: the derivative is minus twice the covariance of the residual with \(X_j\), so at an interior minimum that covariance is zero.

$$ \operatorname{Cov}(m(\Theta),X_j)=\mathrm{VHM},\qquad \operatorname{Var}(X_j)=\mathrm{VHM}+\mathrm{EPV},\qquad \operatorname{Cov}(X_j,X_k)=\mathrm{VHM}\quad(j\ne k). $$

To see these identities, condition on \(\Theta\). Since \(E[X_j\mid\Theta]=m(\Theta)\), the covariance of \(m(\Theta)\) and \(X_j\) is \(\operatorname{Var}(m(\Theta))\). The law of total variance gives \(\operatorname{Var}(X_j)=E[\operatorname{Var}(X_j\mid\Theta)]+\operatorname{Var}(m(\Theta))\). For two distinct observations, conditional independence makes their conditional covariance zero, leaving only the covariance of their shared conditional mean across risks.

Apply the zero-covariance condition to the residual \(m(\Theta)-a-b\sum_{k=1}^nX_k\) and any \(X_j\). There is one own-observation covariance and \(n-1\) cross-observation covariances:

$$ 0=\operatorname{Cov}\left(m(\Theta)-a-b\sum_{k=1}^nX_k,X_j\right) =\mathrm{VHM}-b\left(\mathrm{EPV}+n\mathrm{VHM}\right). $$

Thus \(b=\mathrm{VHM}/(\mathrm{EPV}+n\mathrm{VHM})=1/(n+K)\). The least-squares predictor’s intercept makes its expected value equal to \(E[m(\Theta)]=\mu\), because \(E[X_j]=\mu\). Therefore \(a=\mu-bn\mu\). Substituting the value of \(b\) gives the Bühlmann form:

$$ a+b\sum_{j=1}^nX_j =\left(1-\frac{n}{n+K}\right)\mu+\frac{n}{n+K}\bar X =(1-Z)\mu+Z\bar X. $$

This derivation explains both the weight and the collective complement. It also gives a useful check: if process variance is zero, \(K=0\) and \(Z=1\) for positive \(n\); if process variance is large relative to VHM, \(Z\) is smaller. If VHM is zero, all risks have the same hypothetical mean under the model, \(K\) is not a finite ratio, and the appropriate predictor is the collective mean rather than this formula.

From Premium to Experience Modification

When the collective premium \(\mu\) is positive, divide the Bühlmann premium by it to obtain the multiplicative experience modification \(M\). A modification of \(1.08\) means a premium 8% above the collective benchmark; it is not itself an 8% adjustment.

$$ M=\frac{P}{\mu} =\frac{Z\bar X+(1-Z)\mu}{\mu} =1+Z\left(\frac{\bar X-\mu}{\mu}\right). $$

The percentage adjustment from the collective premium is \(M-1=Z(\bar X-\mu)/\mu\). The experience deviation from the collective is therefore scaled by credibility. If \(\bar X=\mu\), the modification is 1. If experience is above the collective, the modification exceeds 1, provided the model quantities and \(\mu\) are positive as assumed for this interpretation. If \(\mu=0\), the ratio is undefined, although the additive Bühlmann premium may still be defined.

Worked Example: Converting a Credibility Premium to a Factor

A hypothetical coverage has annual loss costs with \(\mu=\$90\), \(\mathrm{EPV}=900\) dollars squared, and \(\mathrm{VHM}=300\) dollars squared. A risk’s five equal-exposure annual observations are \(\$80,\$100,\$100,\$120,\$100\). Find its Bühlmann premium and experience modification. Assume the observations satisfy the equal-exposure Bühlmann model; no interest or mortality assumption is involved.

Method and calculation. First, \(\bar X=(80+100+100+120+100)/5=500/5=\$100\). The credibility parameter is \(K=900/300=3\), so \(Z=5/(5+3)=5/8=0.625\). The premium is

$$ P=0.625(\$100)+0.375(\$90)=\$62.50+\$33.75=\$96.25. $$

The modification factor is \(M=\$96.25/\$90=1.069444\ldots\). Rounded only at the final step to four decimal places, \(M=1.0694\), or a \(6.94\%\) adjustment when expressed as a percentage to two decimals. Check: the risk’s observed mean is \(\$10\) above the collective, and credibility applies \(62.5\%\) of that difference: \(\$90+0.625(\$10)=\$96.25\). This calculation avoids treating the full observed excess as the premium adjustment.

Worked Example: Building EPV and VHM From Risk Types

A hypothetical book has two equally likely risk types. Their conditional annual loss-cost means are \(\$70\) and \(\$130\), and each type has conditional variance \(400\) dollars squared. A risk of one type has three annual observations, \(\$90,\$110,\$130\). Estimate its premium and modification. Assume conditional independence and equal exposure; interest and mortality are not relevant.

Method and calculation. The collective mean is \(\mu=(70+130)/2=\$100\). The deviations of the two hypothetical means from \(\$100\) are \(-\$30\) and \(+\$30\), so \(\mathrm{VHM}=[(-30)^2+(30)^2]/2=900\) dollars squared. The conditional variance is 400 for either type, hence \(\mathrm{EPV}=400\) dollars squared. Therefore \(K=400/900=4/9\).

The observations average \(\bar X=(90+110+130)/3=\$110\). Thus \(Z=3/(3+4/9)=3/(31/9)=27/31\). The premium is

$$ P=\frac{27}{31}(\$110)+\frac{4}{31}(\$100) =\frac{\$2{,}970+\$400}{31} =\frac{\$3{,}370}{31} =\$108.709677\ldots. $$

Rounded to the nearest cent, \(P=\$108.71\). The modification is \(M=\$3{,}370/(\$3{,}100)=1.087096\ldots\), or 1.0871 to four decimals; its percentage adjustment is 8.71% to two decimals. Check: the observed mean is 10% above the collective, and the credibility factor \(27/31\) applies about 87.10% of that relative difference, giving a factor about 1.0871. The common mistake avoided here is using the variance of the two risk-type means as EPV; it is VHM, while the within-type variance is EPV.

Worked Example: Least-Squares Weights and a Below-Collective Risk

For a hypothetical line, let \(\mu=\$120\), \(\mathrm{EPV}=200\) dollars squared, and \(\mathrm{VHM}=800\) dollars squared. A risk has two equal-exposure observations, \(\$165\) and \(\$135\). Calculate the linear predictor’s coefficient on each observation, the premium, and the experience modification. Assume the Bühlmann model; interest and mortality are not relevant.

Method and calculation. First \(K=200/800=0.25\). The coefficient on each observation in the least-squares form is \(b=1/(n+K)=1/2.25=4/9\). The total coefficient on the observations is \(2b=8/9\), which is \(Z=n/(n+K)=2/2.25=8/9\). The sample mean is \(\bar X=(165+135)/2=\$150\). Hence

$$ P=\frac{8}{9}(\$150)+\frac{1}{9}(\$120) =\frac{\$1{,}200+\$120}{9} =\$146.6666\ldots. $$

Rounded to the nearest cent, \(P=\$146.67\). The factor is \(M=\$1{,}320/\$1{,}080=1.222222\ldots\), or 1.2222 to four decimals; the corresponding increase is 22.22% to two decimals. Check: the mean experience is \(\$30\) above the collective, and \(8/9\) of that difference is \(\$26.6666\ldots\), giving \(\$146.6666\ldots\). The individual-observation coefficient \(b=4/9\) is not the same quantity as the total credibility \(Z=8/9\); confusing them would underweight the two observations.

Exam Traps and Model Boundaries

A frequent error is to reverse the variance ratio and use \(\mathrm{VHM}/\mathrm{EPV}\) as \(K\). That makes more process noise increase credibility, which contradicts the model’s interpretation. For example, with \(\mathrm{EPV}=900\), \(\mathrm{VHM}=300\), and \(n=5\), the correct calculation is \(K=900/300=3\) and \(Z=5/(5+3)=0.625\). The reversed ratio gives \(K=1/3\), and the incorrect factor is \(5/(5+1/3)=15/16=0.9375\). The correction is to define \(K\) as process variance divided by between-risk variance before calculating \(Z\).

Other checks help prevent interpretation errors:

  • Use the arithmetic mean of the equal-exposure observations, not their total, in \(P=Z\bar X+(1-Z)\mu\).
  • Report \(M=P/\mu\) as a factor, and \(M-1\) as the proportional adjustment. Do not label a factor of 1.08 as an 8% factor.
  • Keep the target clear: the derivation estimates \(m(\Theta)\), the hypothetical mean. It is not a promise that the next observed loss cost will equal the premium.
  • Do not apply the equal-exposure formula unchanged when exposure differs by period or observation. The assumptions used in the covariance derivation would need to be replaced by a model that accounts for the differing exposures.

The premium is a least-squares linear estimate, so its quality depends on the model and its variance components. If a rating application requires bounds, credibility adjustments, or additional constraints, those are separate decisions and do not follow from the unconstrained least-squares derivation.

Key takeaway: Under the equal-exposure Bühlmann assumptions, \(Z=n/(n+\mathrm{EPV}/\mathrm{VHM})\) is the total weight on the observed mean in the best linear predictor of the hypothetical mean. For a positive collective premium, \(M=P/\mu=1+Z(\bar X-\mu)/\mu\) expresses that estimate as a relative experience modification.

Check Your Understanding

For each hypothetical problem, use the stated equal-exposure Bühlmann assumptions. No interest or mortality assumption is involved.

  1. A risk has four annual observations averaging \(\$84\). Given \(\mu=\$80\), \(\mathrm{EPV}=600\), and \(\mathrm{VHM}=200\), calculate \(K\), \(Z\), the premium, and the modification factor. (Answer: \(K=3\), \(Z=4/7\), premium \(\$82.29\), factor \(1.0286\) to four decimals.)
  2. Two equally likely hypothetical risk types have conditional means \(\$50\) and \(\$90\), each with conditional variance \(100\). A risk’s two observations are \(\$70\) and \(\$90\). Find \(\mu\), EPV, VHM, \(Z\), and the premium. (Answer: \(\mu=\$70\), EPV \(=100\), VHM \(=400\), \(Z=8/9\), premium \(=\$78.89\) to the nearest cent.)
  3. A portfolio has \(\mu=\$200\), \(\mathrm{EPV}=1{,}200\), \(\mathrm{VHM}=300\), and a risk’s six observations average \(\$230\). Find the premium and the percentage adjustment. (Answer: \(K=4\), \(Z=0.6\), premium \(=\$218\), adjustment \(=9.00\%\).)
  4. For \(n=3\), \(\mathrm{EPV}=500\), and \(\mathrm{VHM}=500\), calculate the coefficient on each observation in the least-squares predictor and the total credibility. If \(\mu=\$150\) and \(\bar X=\$120\), find the premium and factor. (Answer: coefficient per observation \(=1/4\), total \(Z=3/4\), premium \(=\$127.50\), factor \(=0.8500\).)
  5. A hypothetical portfolio has two equally likely types with conditional means \(\$60\) and \(\$100\), and conditional variances \(225\) and \(225\). A risk’s four equal-exposure observations average \(\$95\). Calculate the collective mean, EPV, VHM, credibility, premium, and factor. (Answer: \(\mu=\$80\), EPV \(=225\), VHM \(=400\), \(K=0.5625\), \(Z=64/73\), premium \(=\$93.15\) to the nearest cent, factor \(=1.1644\) to four decimals.)
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