Why Cash-Flow Timing Matters
A premium may be deferred until a specified policy duration, cease after a fixed date, or stop when the insured enters another state. A benefit may be payable only after the insured has remained in a state for a waiting period. In each case, the reserve depends not just on the amount of each cash flow, but on when it is payable and what must have happened for it to be payable.
A calendar-based start or stop date can usually be represented by a time-dependent cash-flow rate in the Thiele equation. A waiting period that starts when a transition occurs is different: eligibility depends on the history, or duration, of the current state. The model must retain enough information to know whether the waiting period has been completed.
The indicator \(\mathbf{1}_{[a,b)}(t)\) equals 1 on the interval \([a,b)\) and 0 otherwise. For continuous cash flows, whether an endpoint is included does not change a present value, since a single instant has zero duration. For a lump-sum premium due at a particular time, the contract must specify whether it is payable at that instant and which state condition applies.
Valuing a Deferred Cash-Flow Stream
The prospective-value approach is often the clearest way to check a Thiele calculation. If the insured is alive at time 0, has constant death intensity \(\mu\), and a continuous premium rate \(P\) is payable only while alive from time \(a\) to time \(b\), then the premium present value is $$ P\int_a^b e^{-\delta t}e^{-\mu t}\,dt =P\int_a^b e^{-(\delta+\mu)t}\,dt. $$ The two exponential factors have different roles: \(e^{-\delta t}\) discounts the payment, while \(e^{-\mu t}\) is the probability of surviving to receive or pay it.
More generally, with time-varying death intensity \(\mu(s)\), the probability of remaining alive from time 0 to time \(t\) is \(\exp(-\int_0^t\mu(s)\,ds)\). For a benefit paid on death, the expected discounted value over an interval \([a,b)\) is the integral of the benefit amount times the discounted probability of survival to \(t\) times the death intensity at \(t\).
Worked Example: Premiums Deferred and Stopped at Fixed Durations
A hypothetical policy pays \$1,000 immediately on death before duration 4. Death intensity is constant at \(0.04\) per year, and the force of interest is \(0.03\) per year. A continuous premium of \$60 per year is payable while the insured is alive from duration 1 to duration 3, and no premium is payable otherwise. Find the reserve at duration 0.
Method. Calculate the expected present value of the death benefit and subtract the expected present value of premiums. The death benefit is payable only if death occurs, and the premiums are payable only while the insured is alive.
The discount-and-survival exponent for a continuous premium is \(\delta+\mu=0.03+0.04=0.07\). The premium present value is $$ 60\int_1^3 e^{-0.07t}\,dt =60\frac{e^{-0.07}-e^{-0.21}}{0.07}. $$ Using \(e^{-0.07}=0.9323938\) and \(e^{-0.21}=0.8105842\), the integral is \((0.9323938-0.8105842)/0.07=1.740137\). Therefore the premium present value is \(60(1.740137)=\$104.41\), to the nearest cent.
For death at time \(t\), the density of death is \(0.04e^{-0.04t}\). Including discounting, the death-benefit present value is $$ 1{,}000\int_0^4 0.04e^{-0.07t}\,dt =1{,}000\frac{0.04}{0.07}(1-e^{-0.28}). $$ Since \(e^{-0.28}=0.7557837\), this is \(1{,}000(0.5714286)(0.2442163)=\$139.55\), to the nearest cent.
The reserve is therefore \(139.55-104.41=\$35.14\), with the subtraction performed using the unrounded values. The result is positive because the expected present value of the death benefit exceeds the expected present value of premiums.
Check and common mistake avoided. If survival were omitted when valuing premiums, the premium value would incorrectly be \(60\int_1^3e^{-0.03t}\,dt=\$113.03\), giving a reserve of \$26.52. That calculation treats premiums as payable even after death. Including survival gives the correct reserve of \$35.14.
Waiting Periods After a State Transition
Suppose a benefit starts only after the insured has been continuously disabled for a specified period. If disability begins at a varying time, the policy duration alone does not tell us how long the insured has been disabled. Two insureds can both be disabled at policy duration 5, but one may have entered disability at duration 4.9 and the other at duration 3. A benefit requiring six months of continuous disability is not payable to both.
There are two standard representations. One is to add a waiting state, such as “disabled, waiting,” and a benefit-eligible state, such as “disabled, eligible.” The other is to track time since disability onset explicitly. In either representation, recovery or death during the waiting period prevents eligibility if the contract requires continuous disability. A fixed wait after policy inception, by contrast, can be represented directly as a time-dependent benefit rate because its start time is known from policy duration.
Worked Example: Benefit After a Disability Waiting Period
A hypothetical insured has just entered a disability waiting state at time 0. While waiting, recovery occurs at constant intensity \(0.10\) per year and death at constant intensity \(0.03\) per year. If the insured is still disabled and alive at 0.5 years, a continuous benefit of \$80 per year is payable from duration 0.5 through duration 2.0, provided disability continues. The force of interest is \(0.02\) per year. Find the benefit’s expected present value at the start of the waiting period. Assume no other cash flows.
Method. During the eligible payment interval, continued disability and survival have combined exit intensity \(0.10+0.03=0.13\). Including interest, the exponent for a payment at time \(t\) is \(0.13+0.02=0.15\). The benefit is payable only from \(t=0.5\) to \(t=2.0\), measured from the start of the waiting period.
The expected present value is $$ 80\int_{0.5}^{2.0}e^{-0.15t}\,dt =80\frac{e^{-0.075}-e^{-0.30}}{0.15}. $$ Using \(e^{-0.075}=0.9277435\) and \(e^{-0.30}=0.7408182\), the integral is \(0.1869253/0.15=1.2461687\). Multiplying by \$80 gives \$99.6935, or \$99.69 to the nearest cent.
As a check, the value at time 0.5 conditional on being eligible then is \(80(1-e^{-0.225})/0.15=\$107.46\) (to the nearest cent). The probability of remaining in the waiting state to time 0.5 is \(e^{-0.13(0.5)}=e^{-0.065}\), while discounting to time 0.5 contributes \(e^{-0.02(0.5)}\). Their product is \(e^{-0.075}\). Multiplying the unrounded conditional value by that product gives the same present value, approximately \$99.69.
Common mistake avoided. Starting the benefit at disability onset would value \(80\int_0^2e^{-0.15t}\,dt\), which includes payments during the waiting period and overstates the benefit value. The correct lower integration limit is 0.5, and a recovery or death before that time also prevents any benefit.
Using the Thiele Equation Across Cash-Flow Boundaries
When a premium starts or stops at a fixed duration, the premium term in the relevant state’s Thiele equation changes at that duration. The reserve itself is normally continuous at such a time if no lump sum is paid there; its derivative may change because the instantaneous cash-flow rate has changed. At a transition into another state, the reserve is the reserve for the new state, with any transition benefit included according to the contract.
A useful workflow is to split the time line wherever a cash-flow rule changes. On each interval, specify the state-dependent income rate, transition benefits, and terminal or boundary values. Then solve or integrate the Thiele system on each interval, matching reserve values at a boundary where no lump sum is payable. For a waiting-period product, include a state boundary when eligibility changes, or use a duration-dependent formulation that records the waiting time.
List premium start and stop times, benefit commencement times, and any policy termination time. Distinguish policy duration from time since a state transition.
For each cash flow, state whether it is payable in the healthy, waiting, eligible, or another defined state. Do not treat a payment as payable after a transition that ends eligibility.
Enter continuous premiums as positive income in \(c_i(t)\), continuous outgo as negative income, and transition benefits as \(B_{ij}(t)\). Apply the specified timing interval to each term.
Where feasible, value each future stream using its payment probability and discount factor. Confirm the sign: premiums reduce the reserve, while benefits increase it.
Worked Example: Reserve with a Deferred Premium Stream
A hypothetical policy pays \$5,000 immediately on death before duration 3. Death intensity is constant at \(0.05\) per year, and the force of interest is \(0.03\) per year. A continuous premium of \$40 per year is payable while alive from duration 1 to duration 2. Find the reserve at duration 1, conditional on being alive then.
Method. At duration 1, value death benefits over the next two years and subtract premiums over the next one year. The combined exponent for each future payment is \(0.05+0.03=0.08\).
The death-benefit value at duration 1 is $$ 5{,}000\int_0^2 0.05e^{-0.08s}\,ds =3{,}125(1-e^{-0.16}). $$ Since \(e^{-0.16}=0.8521438\), this is \(3{,}125(0.1478562)=\$462.05\), to the nearest cent.
The premium value at duration 1 is $$ 40\int_0^1e^{-0.08s}\,ds =40\frac{1-e^{-0.08}}{0.08}. $$ Using \(e^{-0.08}=0.9231163\), the annuity factor is \(0.0768837/0.08=0.961046\), so the premium value is \(40(0.961046)=\$38.44\), to the nearest cent.
Thus the reserve at duration 1 is \(462.05-38.44=\$423.61\), using unrounded values before rounding the final result. As a boundary check, at duration 2 the premium stream has ended; the reserve there is \(3{,}125(1-e^{-0.08})=\$240.26\). The duration-1 reserve includes both the value at duration 2 and the expected discounted cash flows over the intervening year, including premiums only during that year.
Common mistake avoided. Valuing the premium as though it began at duration 0 would use the wrong interval. Since this reserve is conditional on being alive at duration 1, the premium integral starts at elapsed time 0 from that valuation date and ends at elapsed time 1.
Common Timing and Modeling Traps
- Using the wrong clock. A premium deferred to policy duration 1 starts one year after issue. A benefit delayed six months after disability starts six months after the transition, not necessarily at a fixed policy duration.
- Discounting without conditioning on payment. A premium payable only while alive must be weighted by survival; a disability benefit payable only while disabled must be weighted by the probability of remaining eligible.
- Paying benefits during the waiting period. The payment interval begins only after the required period of continuous eligibility has elapsed.
- Using an artificial waiting-state intensity. A deterministic wait of length \(w\) means eligibility begins after exactly \(w\) years if the insured remains eligible. It does not mean an exponential transition with intensity \(1/w\), which would allow eligibility at random times before \(w\).
- Changing the premium sign. In the stated Thiele convention, premiums received enter \(c_i(t)\) positively and appear as \(-c_i(t)\) in the reserve derivative. In prospective values they are subtracted from benefits.
Check Your Understanding
For each problem, state the relevant timing or state condition before calculating. Round dollar answers to the nearest cent.
- A hypothetical policy pays \$900 at death before duration 2. Death intensity is \(0.04\) per year and the force of interest is \(0.02\) per year. A continuous premium of \$30 per year is payable while alive from duration 0.5 to 1.5. Find the reserve at duration 0. (Answer: \$39.59)
- A newly disabled insured has recovery intensity \(0.08\) per year and death intensity \(0.02\) per year. At a force of interest of \(0.04\), a benefit of \$100 per year is payable continuously from 0.25 years after disability onset through 1.25 years after onset, only while disability continues. Find its expected present value at onset. (Answer: \$90.11)
- A hypothetical policy pays \$2,000 on death before duration 3, with constant death intensity \(0.02\) and force of interest \(0.03\). A continuous premium of \$50 per year is payable while alive from duration 1 to 2. Find the reserve at duration 0. (Answer: \$65.04)
- A newly disabled insured has recovery intensity \(0.10\) per year, death intensity 0, and force of interest \(0.02\). A continuous benefit of \$120 per year is payable only after a 0.5-year waiting period, and only until 1.5 years after disability onset. Find its expected present value at onset. (Answer: \$106.49)