Why Expected Exposure Matters
In a multiple-decrement model, a member of a group can leave during an interval through one of several competing causes. Expected exposure measures the total time, in person-years, that the group is expected to remain under observation or at risk during that interval. It is not generally equal to the number of people present at the beginning or end of the interval: some members may exit partway through it.
The calculation depends on how exits are distributed within the interval. Under the uniform distribution of decrements (UDD) assumption, exits are spread uniformly through the interval. Under a constant-force assumption, the total force of exit is constant, so the expected number remaining declines exponentially. These assumptions can give different expected exposures even when they produce the same annual exit probabilities.
For one life entering a one-year interval, the corresponding quantity is the expected fraction of a year spent in the group. For a cohort of \(N_0\) lives entering together, multiply that per-life exposure by \(N_0\). If the starting number is itself an expected number of lives from a table, the same multiplication gives expected person-years.
Exposure Under UDD
Suppose the interval is one year and the mutually exclusive causes have multiple-decrement probabilities \(q_1,\ldots,q_m\). Each \(q_j\) is the probability, for a life in the group at the start of the year, of exiting through cause \(j\) during that year. Assume all exits are included, so the probability of remaining in the group for the full year is \(p=1-q\), where \(q=\sum_{j=1}^m q_j\). Under UDD, the expected proportion remaining at time \(t\), for \(0\leq t\leq1\), is \(1-tq\).
The cause-specific probabilities are added to obtain the total probability of exit; the exposure formula uses that total. For successive years, calculate exposure separately in each year using that year’s total exit probability and the number expected to be present at its start. Then add the yearly exposures.
Worked Example: UDD Exposure Across Two Years
A hypothetical decrement group has 250 members at the start of year 1. In that year, the cause-specific exit probabilities are 0.06 and 0.10. Under UDD, 210 members are expected to enter year 2, when the total exit probability is 0.12. Find expected exposure over the two years.
Method. Apply the UDD formula in each year, using the total exit probability and the population entering that year.
In year 1, the total exit probability is \(q_1=0.06+0.10=0.16\). Thus the exposure per entering member is \(1-0.16/2=0.92\) years, and expected year 1 exposure is \(250(0.92)=230\) person-years. As a check, the expected number surviving to year 2 is \(250(1-0.16)=210\), consistent with the stated number.
In year 2, the total exit probability is \(0.12\). Expected exposure is \(210(1-0.12/2)=210(0.94)=197.4\) person-years.
Adding the year-specific exposures gives \(230+197.4=427.4\) person-years. The answer is 427.40 person-years. The common mistake this method avoids is adding the two cause-specific probabilities as if each cause had a separate full-year population at risk.
Exposure Under Constant Competing Forces
Now suppose each cause has a constant force of exit during the year. Write \(\lambda_j\) for the constant force for cause \(j\), and let \(\lambda=\sum_{j=1}^m\lambda_j\) be the total force. The probability of remaining in the group to time \(t\) is \(e^{-\lambda t}\), and the one-year total exit probability is \(q=1-e^{-\lambda}\). Therefore, expected exposure per life entering the interval is the integral of this survival probability.
If \(q=0\), then \(\lambda=0\): no one exits during the interval, so exposure is exactly one year per entering life. The ratio \(q/[-\ln(1-q)]\) is not defined at \(q=0\), although its limit as \(q\) approaches zero is 1. State this zero-exit case separately when using the ratio form.
Under constant competing forces, the cause-specific annual probabilities are linked to the forces by \(q_j=(\lambda_j/\lambda)(1-e^{-\lambda})\) when \(\lambda>0\). Their sum is \(q\). Thus total exposure depends on the total force, or equivalently the total annual exit probability, rather than on the allocation among causes.
Worked Example: Constant Forces With Two Competing Causes
A hypothetical group of 160 lives is subject during the coming year to two constant exit forces, \(\lambda_1=(\ln 2)/4\) and \(\lambda_2=3(\ln 2)/4\), measured per year. Find the expected exposure during the year and verify the annual cause-specific probabilities.
Method. Add the cause-specific forces to get the total force, integrate the resulting survival function, and then calculate the cause probabilities from their force shares.
The total force is \(\lambda=(\ln 2)/4+3(\ln 2)/4=\ln 2\). The probability of remaining for the full year is \(e^{-\ln 2}=1/2\), so the total annual exit probability is \(q=1-1/2=0.5\).
The exposure per entering life is \((1-e^{-\ln 2})/\ln 2=0.5/\ln 2\) years. For 160 lives, expected exposure is \(160(0.5/\ln 2)=80/\ln 2=115.415\ldots\) person-years, or 115.42 person-years to two decimal places.
Cause 1 has force share \(\lambda_1/\lambda=1/4\), so its annual exit probability is \((1/4)(0.5)=0.125\). Cause 2 has force share \(3/4\), so its annual exit probability is \((3/4)(0.5)=0.375\). Their sum is \(0.125+0.375=0.500\), which checks the total exit probability used in the exposure calculation.
Why the Formulas Hold
A member who exits at time \(T\) contributes \(\min(T,1)\) years of exposure during a one-year interval. For any nonnegative time-to-exit \(T\), the identity \(\min(T,1)=\int_0^1 I(T>t)\,dt\) expresses that time as the accumulated indicator of still being present. Taking expectations gives the integral of the probability of remaining at each time. For \(N_0\) entering lives, summing their indicators gives the expected number remaining at each time, so integrating that expected number gives cohort exposure.
Under UDD, \(P(T>t)=1-tq\), and integrating gives \(\int_0^1(1-tq)\,dt=1-q/2\). Under a constant total force, \(P(T>t)=e^{-\lambda t}\), and integrating gives \((1-e^{-\lambda})/\lambda\) for \(\lambda>0\). The formulas therefore use the same underlying principle; the difference is the assumed pattern of survival within the year.
Worked Example: Comparing UDD and Constant Force
A hypothetical cohort of 500 lives faces two competing causes with annual multiple-decrement probabilities 0.08 and 0.12. Calculate its one-year expected exposure under UDD and under constant forces calibrated to reproduce the same cause-specific annual probabilities.
Method. First calculate exposure using the UDD total exit probability. Then use the constant-force exposure formula with the same total annual exit probability.
The total annual exit probability is \(q=0.08+0.12=0.20\). Under UDD, exposure is \(500(1-0.20/2)=500(0.90)=450\) person-years.
For constant forces, \(\lambda=-\ln(1-q)=-\ln(0.80)=0.22314355\ldots\). To preserve the annual cause probabilities, assign force shares \(0.08/0.20=0.4\) and \(0.12/0.20=0.6\). The resulting cause probabilities are \(0.4(0.20)=0.08\) and \(0.6(0.20)=0.12\), as required.
Constant-force exposure is \(500(0.20/0.22314355\ldots)=448.141\ldots\) person-years, or 448.14 person-years to two decimal places. The two answers differ because matching annual probabilities does not make the within-year survival patterns the same. The common mistake is to use the UDD exposure formula after adopting constant forces, or to assume that the same annual probabilities imply the same exposure.
Multiple Intervals and Common Traps
For a sequence of intervals, let \(N_k\) be the expected number present at the start of interval \(k\). Calculate exposure in that interval using its own decrement probabilities and interpolation assumption, then add the results. Under UDD the one-year contribution is \(N_k(1-q_k/2)\); under constant force it is \(N_k(1-e^{-\lambda_k})/\lambda_k\) if \(\lambda_k>0\), and \(N_k\) if \(\lambda_k=0\). The starting population for the next interval must reflect survival through the preceding interval.
- Do not count a full year for everyone. Members who exit during the interval contribute only their time in the group before exit, on average less than a full year.
- Do not apply the single-cause exposure formula separately and add the results. That would count the same starting population more than once. First use the total exit probability or total force to describe whether a member remains in the group.
- Keep the model assumption consistent. UDD and constant force specify different survival curves within the year, even when their annual exit probabilities agree.
- Handle a zero total exit probability directly. Under either model, exposure is one year per entering life if there is no possibility of exit. In the constant-force ratio, do not substitute zero into a \(0/0\) expression.
Expected exposure is a person-time measure, not an exit probability or an expected count of exits. It is useful wherever calculations require the amount of time a group is at risk or subject to a rate during an interval. The key steps are to identify who is present at the interval’s start, combine competing exits into a total, and then integrate the appropriate within-interval survival pattern.
Check Your Understanding
For each problem, identify the applicable within-interval assumption and calculate expected exposure before rounding.
- A hypothetical group of 400 enters a year with cause-specific UDD exit probabilities 0.05 and 0.15. Find expected exposure for the year. (Answer: 360.00 person-years)
- A group of 100 is subject to two constant forces, 0.20 and 0.30 per year. Find expected exposure during the next year. Give the result to two decimal places. (Answer: 78.69 person-years)
- Under UDD, 1,200 lives enter year 1, when total exit probability is 0.10. The expected number entering year 2 is 1,080, and the year 2 total exit probability is 0.25. Find total expected exposure over both years. (Answer: 2,085 person-years)
- Under UDD, a cohort of 200 enters a year with total exit probability 0.40. Find the expected exposure contributed during the middle half of that year, from time 0.25 to time 0.75. (Answer: 80.00 person-years)
- A cohort of 500 has annual cause-specific probabilities 0.08 and 0.12. Assuming constant competing forces calibrated to those probabilities, find one-year expected exposure to two decimal places. (Answer: 448.14 person-years)