Introduction
A loss record can be correct on its own terms and still be unusable beside another record. A ground-up claim count includes losses that produce no policy payment; a count of paid claims does not. Likewise, a treaty may apply to the policy’s covered payment rather than to the original loss. Combining these quantities without first aligning their bases can distort both estimated frequency and expected cost.
This workshop follows hypothetical claims from ground-up loss through a policy deductible and limit to a per-claim reinsurance layer. The central discipline is to label every count and amount by the event or payment it represents. The calculations use an exponential severity model to make the conversions explicit; the same basis checks matter with other severity models. This approach is aligned with the SOA Exam ASTAM (Advanced Short-Term Actuarial Mathematics) syllabus.
State the Basis Before Calculating
For a simple model, suppose ground-up losses are independent and identically distributed, and each has the same policy terms. Write \(q=P(Y^L>0)\) for the probability that one ground-up loss produces a positive policy payment. If there are \(m\) ground-up claims, the expected number of positive policy payments is \(mq\). This is an expectation, not a claim that the realized count must equal \(mq\).
If \(N\) is a random ground-up claim count with \(E[N]=\lambda\), and the loss distribution and policy terms are the same for each claim, the expected number of positive policy payments is \(\lambda q\). Independence between claims’ payment indicators is not needed for this expected-count relation: conditional on \(N\), linearity of expectation gives \(E[\sum_{j=1}^{N} I_j\mid N]=Nq\) when each indicator \(I_j\) has probability \(q\). If claim probabilities differ, sum the individual probabilities instead. Independence assumptions may matter for the distribution or variance of the paid count, but not for this mean.
The amounts also need a basis label. \(E[Y^L]\) is the average policy payment per ground-up claim, including zero payments. \(E[Y^P]\) is the average amount among claims that do produce a payment. They satisfy \(E[Y^L]=qE[Y^P]\). Multiplying a paid-claim count by \(E[Y^L]\), or a ground-up count by \(E[Y^P]\), mixes bases.
Policy Payments Under an Exponential Model
Assume \(X\) has an exponential distribution with mean \(\theta>0\), so \(P(X>x)=e^{-x/\theta}\) for \(x\geq 0\). For a positive deductible \(d\) and payment limit \(u>0\), the policy pays only when \(X>d\), giving \(q=e^{-d/\theta}\). The formula below is for a per-claim payment cap \(u\), not a cap on the original loss.
The integral follows from the tail-integral identity for a nonnegative random variable: its expectation is the integral of its survival probability. For \(0\leq t<u\), a policy payment exceeds \(t\) exactly when \(X>d+t\); beyond \(u\), it cannot exceed \(t\). Integrating \(e^{-(d+t)/\theta}\) from \(0\) to \(u\) gives the stated mean. Dividing by \(q\) conditions on a positive payment. Equivalently, given \(X>d\), the exponential memoryless property says that \(X-d\) is again exponential with mean \(\theta\), and the policy payment is \(\min(X-d,u)\).
Worked Example: Convert Policy Severity to Both Bases
A hypothetical policy has deductible \(d=\$2{,}000\) and per-claim payment limit \(u=\$12{,}000\). Ground-up loss \(X\) is exponential with mean \(\theta=\$10{,}000\). Calculate the probability of a positive payment, the expected payment per ground-up claim, and the expected payment conditional on a positive payment.
Method. First calculate the exceedance probability, then calculate the unconditional payment mean and divide by that probability to obtain the conditional mean.
The positive-payment probability is \(q=e^{-2000/10000}=e^{-0.2}=0.8187307531\), or \(0.8187\) to four decimals.
The payment per ground-up claim, which includes zero payments, has mean
The payment per positive payment has mean
Check. Multiplying the conditional mean by the probability of payment gives \(0.8187307531\times \$6{,}988.0579=\$5{,}721.3379\), which agrees with \(E[Y^L]\). Amounts are rounded to the nearest cent only in the displayed dollar results.
Convert Paid-Claim Frequency to Ground-Up Frequency
When an exposure record reports only claims that generated a positive payment, it cannot be used directly as a ground-up frequency. If the model gives a positive-payment probability \(q\), then an expected positive-payment count \(m_P\) corresponds to a ground-up expected count \(m_P/q\), provided the same severity and coverage assumptions apply to the claims in question. This conversion is about expected counts. For realized data, the observed counts need not match their expectations exactly.
Worked Example: Infer Ground-Up Frequency From Paid Claims
A hypothetical annual report gives an expected count of 800 claims with positive policy payments. The policy and exponential severity assumptions are those in the preceding example: \(d=\$2{,}000\), \(u=\$12{,}000\), and \(\theta=\$10{,}000\). Infer the corresponding expected ground-up count and calculate the expected annual policy payments.
Step 1: Convert the frequency basis. The positive-payment probability is \(q=0.8187307531\). Therefore the expected ground-up count is
or approximately 977.1 ground-up claims. The non-integer result is an expected count, not a possible realized count.
Step 2: Calculate the annual payment total using the paid-claim basis. There are 800 expected positive payments, each with conditional mean \(\$6{,}988.0579\):
Step 3: Check using the ground-up basis. The unconditional mean payment per ground-up claim is \(\$5{,}721.3379\), so the same expected annual total is
The two methods agree because \((800/q)(qE[Y^P])=800E[Y^P]\). Calculations use unrounded values internally; displayed dollar amounts are rounded to the nearest cent.
Apply the Treaty to the Covered Payment
A per-claim excess-of-loss treaty may attach above the policy’s payment, not above \(X\). Let \(a\) be the treaty attachment and \(w\) its maximum recovery per claim. If it covers the policy payment \(Y^L\), its recovery per ground-up claim is \(R=\min((Y^L-a)_+,w)\). A recovery count, like a paid-claim count, refers only to claims with positive recovery unless explicitly stated otherwise.
For the exponential model and policy limit \(u>a\), define the effective treaty width \(b=\min(w,u-a)\). The treaty can pay only after the policy payment exceeds \(a\), and the maximum payable amount is \(b\). Applying the same tail-integral argument to the recovery gives the result below. If \(u\leq a\), there is no recovery. The formula does not apply unchanged if the treaty attaches to a different base, such as ground-up loss.
The threshold for any recovery is \(X>d+a\), because the policy first subtracts \(d\) and the treaty then requires the policy payment to exceed \(a\). For \(0\leq t<b\), \(R>t\) exactly when \(X>d+a+t\). Integrating \(P(R>t)=e^{-(d+a+t)/\theta}\) from zero to \(b\) yields the expected recovery. This derivation also shows why applying the attachment directly to \(X\) changes the threshold.
Worked Example: Reconcile a Per-Claim Treaty Layer
A hypothetical insurer has 1,200 expected ground-up claims in a year. Each loss is exponential with mean \(\theta=\$10{,}000\). The policy has deductible \(d=\$2{,}000\) and payment limit \(u=\$12{,}000\). A per-claim treaty reimburses the insurer for \(\$5{,}000\) excess of \(\$3{,}000\) of the policy payment. Calculate the expected paid-claim count, expected recovery count, total expected policy payments, total expected treaty recovery, and retained expected amount.
Step 1: Find the policy payment frequency and mean. From the policy model, \(q=e^{-0.2}=0.8187307531\) and \(E[Y^L]=\$5{,}721.3379\). Thus the expected count with positive policy payments is
The expected total policy payment is
Step 2: Find the treaty recovery probability and mean. Here \(a=\$3{,}000\), \(w=\$5{,}000\), and \(u-a=\$9{,}000\), so \(b=\min(5000,9000)=\$5{,}000\). A recovery is possible when \(X>\$5{,}000\), giving \(P(R>0)=e^{-0.5}=0.6065306597\). The expected count with a positive treaty recovery is therefore
The expected recovery per ground-up claim is
Thus the total expected recovery is
Step 3: Calculate the retained amount and check the basis. The expected amount retained after treaty recovery is \(\$6{,}865{,}605.47-\$2{,}863{,}814.62=\$4{,}001{,}790.85\), approximately. As an independent recovery check, the conditional mean recovery given \(R>0\) is \(E[R]/P(R>0)=10000(1-e^{-0.5})=\$3{,}934.69\). Multiplying this by 727.8368 expected recovery claims gives approximately \(\$2{,}863{,}814.62\), as required. All aggregate amounts are rounded to the nearest cent.
Common Basis Errors and When the Formulas Need Adjustment
A frequent error is to pair a positive-payment count with an average that includes zero payments. In the frequency example, multiplying 800 positive payments by \(E[Y^L]=\$5{,}721.3379\) gives only \(800(5721.3379)=\$4{,}577{,}070.31\). That is not the expected annual payment total for 800 positive claims. The correction is to use the conditional mean \(E[Y^P]=\$6{,}988.0579\), giving \(\$5{,}590{,}446.32\). Alternatively, convert 800 positive claims to 977.1222 expected ground-up claims and use \(E[Y^L]\).
Another common error is to apply the treaty attachment to ground-up loss when its contract says it attaches to covered policy payment. In the treaty example, a \(\$3{,}000\) attachment above the policy payment requires \(X>\$2{,}000+\$3{,}000=\$5{,}000\). Treating the attachment as \(\$3{,}000\) above \(X\) would instead use the wrong threshold and overstate expected recovery. Always translate contract wording into the quantity to which the attachment applies before calculating a layer.
The exponential formulas rely on the stated exponential severity model and identical policy terms. Different deductibles, limits, or severity distributions require claim-specific probabilities and expectations or an appropriately modified model. If claim counts are random, the expected aggregate amount can be calculated as expected count times the mean amount per claim when the claim severity and count are independent, as in the usual compound frequency-severity model. For non-identical claims, use the corresponding sum of expectations rather than a single common mean. Do not infer that a paid count must be Poisson merely from its expected value; Poisson thinning requires additional distributional and independence assumptions.
Check Your Understanding
For each problem, identify the count and payment basis before calculating. Dollar answers are rounded to the nearest cent where applicable.
- Ground-up losses are exponential with mean \(\$5{,}000\). A policy has a \(\$1{,}000\) deductible and no payment limit. Find the positive-payment probability and the expected payment per ground-up claim. (Answer: \(0.8187\); \(\$4{,}093.65\))
- There are 400 expected ground-up claims, and each has probability \(0.75\) of producing a positive policy payment. Find the expected number of positive payments. (Answer: 300)
- Ground-up loss is exponential with mean \(\$8{,}000\); the deductible is \(\$2{,}000\), and the per-claim payment limit is \(\$8{,}000\). Find the expected policy payment per ground-up claim. (Answer: \(\$3{,}938.37\))
- Ground-up loss is exponential with mean \(\$5{,}000\). A policy has deductible \(\$1{,}000\) and a payment limit of at least \(\$6{,}000\). A treaty pays \(\$4{,}000\) excess of \(\$2{,}000\) of policy payment. Find expected treaty recovery per ground-up claim. (Answer: \(\$1{,}511.07\))
- A report gives 600 expected positive policy payments. Under the applicable policy terms, the positive-payment probability is \(0.80\), and the mean payment conditional on a positive payment is \(\$1{,}200\). Infer the expected ground-up count and expected aggregate policy payment. (Answer: 750 ground-up claims; \(\$720{,}000.00\))