One Occurrence, One Deductible, One Maximum Payment
When one event causes several covered losses, a policy may treat them together as a single occurrence. If the contract specifies both a deductible per occurrence and a maximum payment per occurrence, the calculation uses the combined covered loss: the deductible is applied once, and the maximum payment is enforced once. The individual losses are still needed to determine which amounts are covered and belong to the occurrence, but they are not separate deductible or limit calculations.
The order matters. This tutorial assumes the policy wording makes the deductible the insured’s first portion of the combined loss and states a maximum amount the insurer will pay for that occurrence. In that arrangement, first subtract the deductible, but not below zero; then cap the resulting insurer payment at the maximum. Actual policy wording governs if it defines a limit differently.
Here, \(L\) is not necessarily every cost associated with an event. It is the total of the amounts that the policy terms classify as covered loss for the occurrence. For example, if a contract excludes a particular item, that item is not included in \(L\). Unless the policy says otherwise, this calculation also does not introduce separate expense treatment, coinsurance, sublimits, or a policy-period aggregate limit.
Payment Function and Breakpoints
The deductible creates the first breakpoint at \(L=d\): at or below that amount, the insured’s loss has not exceeded the deductible, so the insurer pays nothing. The maximum payment creates a second breakpoint at \(L=d+u\). Once the loss exceeds that amount, the amount remaining after the deductible is greater than \(u\), so the payment stays at \(u\).
The middle interval is the only interval in which an additional dollar of covered loss increases the insurer’s payment by one dollar. Before the deductible is exhausted, the additional loss remains with the insured. After the maximum payment is reached, additional loss also remains with the insured. The payment is continuous at both breakpoints: at \(L=d\), both adjacent expressions give zero, and at \(L=d+u\), the middle expression gives \(d+u-d=u\).
Why the Formula Holds
The formula follows directly from the two contract terms. The deductible leaves \(L-d\) after the insured’s first \(d\) dollars, but that amount cannot be negative. The insurer’s payment before considering the maximum is therefore \((L-d)^+\). The maximum payment then permits no more than \(u\), which is exactly what taking the minimum with \(u\) does.
Add the covered loss amounts assigned to the occurrence to obtain \(L\). Do not apply the per-occurrence deductible separately to each item.
Calculate \((L-d)^+\). If \(L\leq d\), this step gives zero.
Take the smaller of the amount after the deductible and \(u\). The result is the insurer payment for the occurrence.
The breakpoint \(d+u\) is useful as a quick check. If \(L\) is between \(d\) and \(d+u\), the payment must be \(L-d\). If \(L\) is at least \(d+u\), the payment must be exactly \(u\). If \(L\) is at most \(d\), the payment must be zero.
Worked Example: Combined Loss Below the Deductible
A hypothetical property policy covers two losses from one occurrence. The covered amounts are $2,800 and $5,700. The policy has a $10,000 deductible per occurrence and a maximum insurer payment of $20,000 per occurrence. Find the payment.
Method. Add the covered losses first, then apply the occurrence terms once. The common mistake avoided here is comparing each individual loss with the deductible as if each had its own deductible.
Step 1: Find the combined covered loss. $$ L=\$2{,}800+\$5{,}700=\$8{,}500. $$
Step 2: Apply the deductible. The amount after the deductible, floored at zero, is $$ (L-d)^+=(\$8{,}500-\$10{,}000)^+=(-\$1{,}500)^+=\$0. $$
Step 3: Apply the maximum payment. $$ P(L)=\min(\$0,\$20{,}000)=\$0. $$
Check. The combined loss of $8,500 is below the $10,000 deductible, so a zero payment is consistent with the piecewise rule. The insurer pays $0.00.
Worked Example: Payment Between the Two Breakpoints
A hypothetical commercial policy assigns three covered losses of $9,000, $7,000, and $6,000 to one occurrence. Its deductible is $10,000 per occurrence, and its maximum insurer payment is $18,000 per occurrence. Calculate the payment.
Method. Compare the combined loss with \(d\) and \(d+u\). This avoids both applying the deductible three times and treating the stated maximum as a cap on loss before the deductible.
Step 1: Add the covered amounts. $$ L=\$9{,}000+\$7{,}000+\$6{,}000=\$22{,}000. $$
Step 2: Locate the combined loss relative to the breakpoints. Here \(d=\$10{,}000\) and \(u=\$18{,}000\), so $$ d+u=\$10{,}000+\$18{,}000=\$28{,}000. $$ Because \(\$10{,}000<\$22{,}000<\$28{,}000\), the payment is in the middle interval.
Step 3: Subtract the deductible once. $$ L-d=\$22{,}000-\$10{,}000=\$12{,}000. $$
Step 4: Enforce the maximum payment. $$ P(L)=\min(\$12{,}000,\$18{,}000)=\$12{,}000. $$
Check. The result is positive because the loss exceeds the deductible, and it is below the $18,000 maximum because the loss has not reached \(d+u=\$28,000\). The insurer pays $12,000.00.
Worked Example: Combined Loss Reaches the Maximum Payment
A hypothetical liability policy covers two losses from one occurrence: $31,000 and $25,000. The deductible is $8,000 per occurrence, and the maximum insurer payment is $35,000 per occurrence. Find the insurer payment and the portion of the combined covered loss not paid by the insurer.
Method. Apply the deductible to the total, then cap the payment. The common mistake avoided is assuming that the insurer pays every dollar above the deductible even after its maximum payment has been reached.
Step 1: Find the combined covered loss. $$ L=\$31{,}000+\$25{,}000=\$56{,}000. $$
Step 2: Calculate the loss after the deductible. $$ L-d=\$56{,}000-\$8{,}000=\$48{,}000. $$
Step 3: Cap the insurer payment. $$ P(L)=\min(\$48{,}000,\$35{,}000)=\$35{,}000. $$
Step 4: Find the amount not paid by the insurer. Under these assumptions, subtract the insurer payment from the combined covered loss: $$ \$56{,}000-\$35{,}000=\$21{,}000. $$ This consists of the $8,000 deductible plus $13,000 above the maximum insurer payment.
Check. The upper breakpoint is \(d+u=\$8{,}000+\$35{,}000=\$43{,}000\). Since $56,000 is above it, the payment must equal the maximum, $35,000. The insurer pays $35,000.00, and $21,000.00 of the covered loss is not paid by the insurer.
Reading the Limit Wording Carefully
A maximum insurer payment and a maximum covered loss are not interchangeable descriptions. The formula in this tutorial applies when \(u\) is the maximum amount the insurer pays after the deductible has been applied. If a contract instead says that no more than \(u\) of loss is considered before the deductible, the payment rule would need to reflect that wording. For instance, under such a different definition, the insurer payment might be \((\min(L,u)-d)^+\), not \(\min((L-d)^+,u)\). Do not choose between these formulas from the word “limit” alone; identify what amount the contract says is limited.
For the second worked example, the specified maximum is an insurer-payment maximum, so the correct calculation is \(\min(\$22{,}000-\$10{,}000,\$18{,}000)=\$12{,}000\). If one incorrectly capped the loss first and then subtracted the deductible, the result would be \(\min(\$22{,}000,\$18{,}000)-\$10{,}000=\$8{,}000\). That calculation uses a different limit definition and does not match the stated contract.
Common Errors and a Reliable Check
- Applying the deductible to each loss. A deductible per occurrence is applied to the combined covered loss once, not separately to every claim or damaged item assigned to that occurrence.
- Applying the maximum to each loss. A maximum payment per occurrence caps the payment for the combined occurrence, not each component loss separately.
- Reversing the contract order. For a maximum insurer payment after the deductible, use \(\min((L-d)^+,u)\). Do not substitute \((\min(L,u)-d)^+\) unless the policy specifies a cap on the loss before the deductible.
- Forgetting the zero floor. When \(L<d\), subtracting \(d\) produces a negative number, but an insurer payment cannot be negative. Use \((L-d)^+\).
- Stopping after the deductible. A positive amount after the deductible is not automatically the payment; it still must be compared with the maximum \(u\).
A final reasonableness check uses the three regions. The payment cannot be negative or exceed \(u\). It is zero for \(L\leq d\), equals \(L-d\) between \(d\) and \(d+u\), and equals \(u\) at or above \(d+u\). These checks often reveal an omitted deductible, a repeated deductible, or a limit applied to the wrong quantity.
Check Your Understanding
For each hypothetical policy, treat the stated amounts as covered losses assigned to one occurrence. Assume the maximum is a cap on insurer payment after the deductible.
- A wind event produces covered losses of $3,600 and $4,900. The per-occurrence deductible is $7,000 and the maximum payment is $12,000. What does the insurer pay? (Answer: $1,500.00)
- One occurrence produces covered losses of $14,000 and $11,000. The deductible is $9,000 and the maximum payment is $20,000. Find the payment and identify which interval contains the combined loss. (Answer: $16,000.00; \(d<L<d+u\))
- A single event produces three covered losses of $18,000, $22,000, and $15,000. The occurrence deductible is $10,000 and the maximum payment is $40,000. Calculate the payment and the amount of covered loss not paid by the insurer. (Answer: payment $40,000.00; not paid $15,000.00)
- A policy covers a combined occurrence loss of $52,000, with a $12,000 deductible and a $30,000 maximum insurer payment. A proposed calculation caps the $52,000 loss at $30,000 and then subtracts the deductible. Explain why that is incorrect under the stated definition and give the correct payment. (Answer: the $30,000 is a maximum payment after the deductible, so the correct payment is \(\min(\$52,000-\$12,000,\$30,000)=\$30,000.00\); the proposed order incorrectly treats the limit as a cap on loss before the deductible.)
- A covered occurrence loss totals $27,500. The deductible is $7,500 and the maximum insurer payment is $25,000. Calculate the payment and verify it by comparing the loss with \(d+u\). (Answer: \(d+u=\$32,500\), so the loss is between the breakpoints and the payment is \(\$27,500-\$7,500=\$20,000.00\).)