Why Deferral Changes a Reserve
A deferred whole-life policy does not insure death from its issue date. It pays a death benefit only after a specified waiting period. Consequently, a prospective reserve during that period cannot value the benefit as though whole-life coverage were already active. It must value only the deaths that would generate a payment under the contract. The premium side must be treated just as carefully: include future premiums only for as long as the policy requires them.
The calculations below use a discrete annual model. Interest is at effective annual rate \(i\), with \(v=1/(1+i)\). A death benefit is paid at the end of the policy year of death. Unless a problem states otherwise, a premium is payable at the beginning of a policy year if the insured is alive. We value reserves immediately after any premium due at the valuation duration.
Write \({}_kp_x\) for the probability of surviving \(k\) years from age \(x\), and \(q_{x+k}\) for the probability of dying in the following year given survival to age \(x+k\). The whole-life insurance value \(A_x\) is the expected present value of a unit benefit paid at the end of the year of death. The annuity-due value \(\ddot{a}_x\) is the expected present value of unit premiums paid at the beginnings of years while alive, including a payment at time 0. The annuity-immediate value \(a_x\) counts future payments at the ends of years while alive.
Value Only Deaths That Are Covered
At duration \(k<n\), the policy is still in its waiting period. A death during the next \(n-k\) years is not covered. The first covered death year, measured from the valuation date, is year \(n-k+1\). Thus the benefit value is the sum over covered death years only. At duration \(k\ge n\), the deferral has ended and every future death is covered, so the benefit value is \(A_{x+k}\).
Here \(B_k\) is the expected present value, at duration \(k\), of future benefits per unit insured. The summation uses \(j\), the number of years from the valuation date until the benefit payment. Its survival term requires the insured to reach the start of that death year; its \(q\) term then gives the conditional probability of dying in that year. The lower limit excludes deaths before coverage begins.
For a level annual premium \(P\) payable while alive for life, the expected present value of future premiums immediately after the premium at duration \(k\) is \(P a_{x+k}\). The next possible payment is one year later, conditional on surviving to that payment date. The prospective net reserve is therefore:
This is the prospective policy value: expected present value of future benefits minus expected present value of future premiums, conditional on being alive at the valuation duration. If premiums stop at the end of the deferral period, the premium annuity must instead include only the remaining scheduled payments. If the valuation is immediately before a premium date, that due premium must be included; the timing convention changes the premium value.
Why the Deferral Factor Appears
A useful simplification applies when the mortality law from age \(x+n\) onward is the same law used to calculate \(A_{x+n}\). To receive a deferred whole-life benefit, the insured must first survive \(n\) years. Conditional on doing so, the remaining insurance has value \(A_{x+n}\), discounted \(n\) years to the issue date. Therefore the issue-date benefit value is:
This identity follows by conditioning on survival to time \(n\). If the insured does not survive the waiting period, the contract pays nothing. If the insured does survive, future deaths are valued as whole-life deaths from age \(x+n\). The factor \(v^n{}_np_x\) accounts for both discounting and the probability of reaching the start of active coverage. At a later duration \(k<n\), the same reasoning gives \(v^{n-k}{}_{n-k}p_{x+k}A_{x+n}\), provided \(A_{x+n}\) represents the post-deferral insurance under the stated mortality model.
If premiums are payable for life, the net level premium at issue follows from equivalence: the expected present value of premiums equals the expected present value of benefits. In this discrete model, \(P\ddot{a}_x={}_nE_xA_{x+n}\). The issue-date premium annuity is due because a premium is payable at time 0.
Worked Example: Reserve Halfway Through the Waiting Period
A hypothetical policy provides a unit death benefit after a two-year deferral. Mortality is constant by year, with \(q=0.10\) and \(p=0.90\), and the effective annual interest rate is \(i=25\%\), so \(v=0.80\). Annual net premiums are due while the insured is alive for life. Calculate the reserve immediately after the premium at duration 1.
Method and assumptions. With constant \(q\), the value of whole-life insurance and the annuity values are geometric sums:
At issue, the benefit value for a two-year deferral is \((vp)^2A_x\). Since \(vp=0.72\), this is \(0.72^2(2/7)=0.5184(2/7)=0.1481143\). Equivalence gives the annual premium:
At duration 1, one year of deferral remains. The conditional benefit value is \(vpA_{x+1}=0.72(2/7)=0.2057143\). Because premiums continue for life, the future premium value is \(Pa_{x+1}=0.041472(18/7)=0.1066423\). Therefore:
The result is positive: the value of the benefit still available exceeds the value of the remaining premiums. The calculation also checks the deferral correctly: it values only deaths after the one remaining waiting year, not all future deaths as immediately covered. The most common error here is to use \(A_{x+1}\) alone for benefits at duration 1, which includes deaths during the remaining waiting year.
Reserves Once Coverage Has Begun
After duration \(n\), the benefit side is the ordinary whole-life insurance value at the attained age. The premium side still depends on the contract. For premiums payable for life, it is \(Pa_{x+k}\) immediately after a premium date. A change in benefit status at the end of the waiting period does not, by itself, mean that premiums stop or continue; their schedule must be read from the policy terms.
Worked Example: Reserve at the Start of Active Coverage
A hypothetical policy has a two-year deferral and a unit death benefit. Its conditional annual death probabilities are \(q_1=0.10\), \(q_2=0.20\), \(q_3=0.25\), and \(q_4=1\); death is certain by the end of year 4. The effective annual interest rate is \(i=5\%\). Net annual premiums are payable at times 0, 1, 2, and 3 if alive, with no premium after time 3. Find the reserve immediately after the premium at time 2.
Method and assumptions. Deaths in years 1 and 2 are not covered; deaths in years 3 and 4 are covered. Put \(v=1/1.05=0.952381\). The issue-date benefit value is:
The expected present value of the four possible premiums is the annuity-due value \(1+0.9v+0.72v^2+0.54v^3\):
Thus the net annual premium is \(P=0.599750/2.976676=0.201483\), to six decimals. At time 2, the insured has survived the first two years. Death in year 3 has conditional probability \(0.25\); if that year is survived, death in year 4 is certain. The future benefit value is:
Immediately after the premium at time 2, the only possible future premium is at time 3, if the insured survives year 3. Its expected present value per dollar of premium is \(0.75v=0.714286\). Hence the reserve is:
The reserve is calculated to six decimals. It checks against the contract schedule: the premium at time 2 has already been paid, and no premium after time 3 is due. Treating premiums as payable for life would subtract payments that this policy does not require.
Premiums That Stop at the End of Deferral
A deferred policy may instead charge premiums only during its waiting period. That arrangement changes the premium value, not the definition of which deaths are covered. For an \(n\)-year deferral with premiums due at times \(0,\ldots,n-1\) while alive, the issue-date premium annuity is the expected present value of precisely those scheduled payments. At a later duration, subtract only the payments still scheduled after the valuation time.
Worked Example: A Fixed Number of Deferral-Period Premiums
A hypothetical policy pays a unit benefit on death after a three-year deferral and pays no benefit for earlier death. It charges three annual premiums, due at times 0, 1, and 2 if alive; premiums stop after time 2. Mortality is constant with \(q=0.10\), and the effective annual interest rate is \(i=0\%\). Calculate the net premium and the reserve immediately after the premium at time 1.
Method and assumptions. With zero interest and eventual death probability 1 under the constant-\(q\) model, a unit whole-life benefit after the waiting period has value 1 conditional on surviving to that period. At issue, the deferred benefit value is the probability of surviving three years: \(0.9^3=0.729\). The expected number of premiums is \(1+0.9+0.9^2=1+0.9+0.81=2.71\). Therefore:
At time 1, two more years of survival are required to reach active coverage, so the benefit value is \(0.9^2=0.81\). Only one premium remains, due at time 2 if the insured survives the next year. Its expected value per dollar is \(0.9\). The reserve is:
The answer is rounded to six decimals. This reserve is not found by subtracting a lifetime annuity of premiums: the contract has only one premium remaining. The calculation also excludes any benefit for death during the two remaining years of deferral.
Practical Checks and Common Traps
Deferred insurance reserves are especially sensitive to whether a cash flow is still possible under the contract. Before calculating, identify the valuation date, the end of the deferral period, the benefit-payment timing, and the final premium date. Then condition probabilities on survival to the valuation duration.
Compare duration \(k\) with deferral period \(n\). If \(k<n\), future deaths before the end of the remaining wait are not covered.
Sum over covered death years if still deferred; use \(A_{x+k}\) once active coverage has begun.
Apply the contract’s schedule and valuation timing. A premium already paid is not a future premium, and a premium after the final scheduled date is not due.
Use probabilities conditional on being alive at the valuation date, and check that each discount period matches its payment date.
A frequent exam trap is to treat a deferred whole-life policy as ordinary whole-life insurance throughout its term. During deferral, that overstates benefits by including deaths that produce no payment. The opposite mistake is to omit premiums that remain payable during the waiting period. Another trap is a one-year timing shift: a benefit paid at the end of a death year is discounted for that year, while a premium due at its beginning is not discounted from that date.
The prospective reserve is meaningful only with the policy terms and timing stated. A negative value is not automatically an arithmetic error; it can occur when future premiums have greater expected present value than future benefits under the chosen premium basis. For a net premium calculated by equivalence, the issue reserve is zero under the same assumptions and timing used to calculate that premium.
Check Your Understanding
For each problem, use the stated discrete timing and report the requested reserve or value.
- A hypothetical policy has a two-year deferral, no interest, and constant annual mortality \(q=0.20\). Death is eventually certain. What is the issue-date value of a unit deferred whole-life benefit? (Answer: 0.6400)
- Mortality is constant with \(q=0.10\), and \(i=25\%\). A one-year deferred whole-life policy has level premiums payable for life while alive. Find its net annual premium. Use \(A_x=2/7\) and \(\ddot{a}_x=25/7\) for this model. (Answer: 0.0576)
- A policy is already in active whole-life coverage. Immediately after a premium date, future annual death probabilities are \(0.20\), \(0.50\), and then \(1\). Interest is zero, and the level premium is \(0.10\), payable while alive. Find the reserve. (Answer: 0.8800)
- A three-year deferred whole-life policy is valued immediately after the premium at duration 1. Interest is zero. Future annual death probabilities, starting with the year after valuation, are \(0.10\), \(0.20\), \(0.50\), and then \(1\). The annual premium is \(0.05\), payable for life while alive. Find the reserve. (Answer: 0.6210)