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Exam FM · Net Present Value · Tutorial 451 of 998

NPV at a Nonzero Valuation Date

Learn how to value a complete dated cash-flow stream at a nonzero date using consistent accumulation and discounting.

Intermediate 10 min read

What You'll Learn

  • Define NPV at a chosen date for signed cash flows occurring both before and after that date.
  • Apply the effective annual rate consistently to whole-year and fractional-year intervals.
  • Convert each cash flow to the valuation date using accumulation or discounting as appropriate.
  • Check the direction of each time adjustment and distinguish a stream’s value from excluded sunk costs.
  • Work through multi-date NPV calculations and identify common sign and timing errors.

Why the Valuation Date Matters

A net present value is tied to a date. When all cash flows are valued at time zero, later amounts are discounted to time zero. But a project or contract may instead need to be valued at a reporting date, a decision date, or another specified point on its timeline. At a nonzero valuation date, cash flows before that date must be accumulated forward, while cash flows after it must be discounted back.

The date of valuation does not change the cash flows themselves. It changes how far each cash flow must be moved in time. The key is to compare every cash-flow date with the chosen valuation date before deciding whether to accumulate or discount. This technique is aligned with the SOA Exam FM (Financial Mathematics) syllabus.

Definition: Suppose signed cash flows \(C_k\) occur at times \(t_k\), measured in years, and the valuation date is \(T\). Under a constant effective annual interest rate \(i\), the net present value at date \(T\) is $$ \operatorname{NPV}_T=\sum_k C_k(1+i)^{T-t_k}. $$ A positive \(C_k\) is an inflow and a negative \(C_k\) is an outflow. A cash flow before \(T\) has \(T-t_k>0\) and is accumulated to \(T\); a cash flow after \(T\) has \(T-t_k<0\) and is discounted to \(T\). A cash flow at \(T\) has factor \(1\).

How to Move Each Cash Flow to the Valuation Date

Assume a constant effective annual rate \(i\), with \(i>-1\), over the entire period being valued. Time is measured in years, and the annual compound-interest model is applied over fractional years when needed. For a cash flow \(C\) at time \(t\), its value at time \(T\) is \(C(1+i)^{T-t}\). If \(T>t\), the amount is carried forward; if \(T<t\), the negative exponent means discounting.

This formula relies on a single rate applying over every interval between the cash-flow date and the valuation date. If the rate changes by period, or different rates apply to different intervals, each interval must be valued using its applicable accumulation factors rather than one constant \(i\). If a problem gives a nominal rate convertible more than once per year, first use the appropriate period rate and period count; do not treat the nominal rate as an effective annual rate.

1
Mark the valuation date.
Write \(T\) on the timeline and record each cash flow’s date and sign.
2
Compare each date with \(T\).
For \(t_k<T\), accumulate from \(t_k\) to \(T\). For \(t_k>T\), discount from \(t_k\) to \(T\). For \(t_k=T\), leave the amount unchanged.
3
Apply the signed cash flow.
Multiply each amount, including a negative outflow, by its time factor. Do not change the sign merely because the amount is moved forward or backward.
4
Sum the values at \(T\).
All adjusted amounts now refer to the same date, so their signed sum is the NPV at that date.

Why the Formula Works

Under compound interest at an effective annual rate \(i\), one unit at time \(t\) accumulates to \((1+i)^{T-t}\) units after \(T-t\) years when \(T>t\). Multiplying by a cash flow \(C\) gives its accumulated value \(C(1+i)^{T-t}\). When \(T<t\), the amount at \(t\) must instead be divided by the accumulation factor for the interval from \(T\) to \(t\):

$$ \frac{C}{(1+i)^{t-T}}=C(1+i)^{-(t-T)}=C(1+i)^{T-t}. $$

Thus the same expression handles both directions. Applying it to every dated amount puts all values at \(T\); the signed sum is the value of the cash-flow stream at that date. The exponent \(T-t_k\) is therefore a useful check: it is positive for an earlier cash flow and negative for a later one.

Worked Example: Valuing Flows at Time 2

A stream has cash flows of \(-\$500\) at time 0, \(+\$100\) at time 1, \(+\$50\) at time 2, and \(+\$432\) at time 3. Find the NPV at time 2 using an effective annual rate of 4%. Give the final amount to the nearest cent.

Method. Move every cash flow to time 2. The time-0 and time-1 amounts are earlier than the valuation date, the time-2 amount stays as it is, and the time-3 amount is discounted one year.

$$ \begin{aligned} \operatorname{NPV}_2 &=-500(1.04)^2+100(1.04)+50+\frac{432}{1.04}\\ &=-500(1.0816)+104+50+415.384615\ldots\\ &=-540.80+104+50+415.384615\ldots\\ &=28.584615\ldots \end{aligned} $$

The NPV at time 2 is \$28.58, rounded to the nearest cent. As a check, the four adjusted amounts are all valued at time 2 and their signed sum is positive.

Common mistake avoided: Discounting every amount to time 2 would incorrectly treat earlier flows as if they were later flows. For example, the wrong-direction calculation is $$ -\frac{500}{(1.04)^2}+\frac{100}{1.04}+50+432(1.04)=133.1557\ldots, $$ which gives about \(\$133.16\), not the correct value. The direction depends on the date, not on whether a cash flow is positive or negative.

Fractional-Year Dates

Cash flows do not have to occur at whole-year intervals. When time is measured in years and the model uses an effective annual rate, a fractional-year interval \(h\) has accumulation factor \((1+i)^h\). For example, under an effective annual rate of 21%, the half-year accumulation factor is \((1.21)^{0.5}=1.1\). This follows because \(1.1^2=1.21\). The exponent must match the time interval in years.

Worked Example: Irregular Dates on Both Sides of the Valuation Date

A hypothetical project has cash flows of \(-\$1{,}000\) at time 0, \(+\$500\) at time 0.5, \(-\$330\) at time 1.5, and \(+\$1{,}210\) at time 2. Find its NPV at time 1 if the effective annual rate is 21%. Give the final amount to the nearest cent.

Method. Use the half-year factor \(1.1\), since \((1.21)^{0.5}=1.1\). Accumulate the flows at times 0 and 0.5 to time 1; discount the flow at time 1.5 by half a year and the flow at time 2 by one year.

$$ \begin{aligned} \operatorname{NPV}_1 &=-1000(1.21)+500(1.1)-\frac{330}{1.1}+\frac{1210}{1.21}\\ &=-1210+550-300+1000\\ &=40. \end{aligned} $$

The NPV at time 1 is \$40.00. The calculation checks directly: \(-\$1{,}210+\$550-\$300+\$1{,}000=\$40\). In particular, the \(-\$330\) flow remains negative after discounting; its value at time 1 is \(-\$300\).

Common mistake avoided: Treating a half-year as a full year would use \(1.21\) instead of \(1.1\) for that interval. The conversion is based on the length of the interval: half a year uses exponent \(0.5\), while one year uses exponent \(1\).

Reading the Sign and Meaning of the Result

A positive NPV at \(T\) means the signed cash-flow stream has positive value at \(T\) under the stated interest-rate model; a negative NPV means it has negative value at \(T\). The sign does not by itself say whether a project should be accepted. That conclusion depends on the decision being made and on which cash flows belong in the valuation.

In particular, a problem that asks for the value of a complete stream at \(T\) includes the stated earlier cash flows, accumulated to \(T\), as well as later cash flows discounted to \(T\). In a decision made at \(T\), however, an earlier outlay may be a sunk cost that the decision-maker is instructed to exclude. Follow the cash-flow definition in the question: do not silently remove a stated flow from a full-stream valuation, and do not include a sunk amount when the decision question explicitly excludes it.

Worked Example: A Negative Value at a Later Date

A hypothetical equipment upgrade has cash flows of \(-\$800\) at time 0, \(+\$300\) at time 2, \(-\$100\) at time 3, and \(+\$700\) at time 5. Find the NPV at time 3 using an effective annual rate of 8%. Include every stated cash flow and round to the nearest cent.

Method. Time 0 and time 2 precede the valuation date, so accumulate them to time 3. The time-3 amount remains unchanged, and the time-5 inflow is discounted two years.

$$ \begin{aligned} \operatorname{NPV}_3 &=-800(1.08)^3+300(1.08)-100+\frac{700}{(1.08)^2}\\ &=-800(1.259712)+324-100+\frac{700}{1.1664}\\ &=-1007.7696+324-100+600.137174\ldots\\ &=-183.632425\ldots \end{aligned} $$

The NPV at time 3 is -\$183.63, rounded to the nearest cent. The negative result is consistent with the adjusted amounts: the earlier outflow and the time-3 outflow together exceed the accumulated and discounted inflows.

Common mistake avoided: The time-2 inflow is before the valuation date, even though it is a positive amount. It must be accumulated by one year to \(\$324\), not discounted. The time-5 inflow is after the valuation date and must be discounted by two years.

Common Timing Checks

Before finalizing an NPV at a nonzero date, check the timeline and the model rather than relying on a memorized pattern. These checks catch many errors:

  • Compare dates first. A flow before \(T\) is accumulated; a flow after \(T\) is discounted.
  • Use signed amounts. A negative outflow stays negative after either accumulation or discounting.
  • Use the correct interval. The exponent is the number of years between the cash-flow date and \(T\), not the cash-flow date itself.
  • Respect the rate convention. Apply an effective annual rate over years as stated; convert a nominal rate or a different compounding convention before using this formula.
  • Check the stated scope. Include all flows when valuing the complete stream, but respect explicit instructions about excluded sunk costs.
Key takeaway: For a constant effective annual rate, move each signed cash flow at time \(t_k\) to valuation date \(T\) using \(C_k(1+i)^{T-t_k}\). The exponent’s sign determines whether the amount is accumulated or discounted.

Check Your Understanding

For each problem, identify which cash flows are before and after the valuation date before calculating.

  1. A stream has \(-\$200\) at time 0, \(+\$80\) at time 1, and \(+\$140\) at time 3. Find its NPV at time 2 using an effective annual rate of 6%. Round to the nearest cent. (Answer: \(-\$7.84\))
  2. A stream has \(-\$500\) at time 0, \(+\$50\) at time 1, and \(+\$400\) at time 2. Find its NPV at time 1 using an effective annual rate of 10%. Round to the nearest cent. (Answer: \(-\$136.36\))
  3. A stream has \(-\$400\) at time 0, \(+\$100\) at time 0.5, \(-\$220\) at time 1.5, and \(+\$605\) at time 2. Find its NPV at time 1 using an effective annual rate of 21%. Round to the nearest cent. (Answer: \(-\$74.00\))
  4. A stream has \(-\$1{,}000\) at time 0, \(+\$250\) at time 1, \(-\$100\) at time 2, and \(+\$1{,}100\) at time 4. Find its NPV at time 2 using an effective annual rate of 4%. Round to the nearest cent. (Answer: \(\$95.41\))
  5. A stream has \(-\$1{,}000\) at time 0, \(+\$300\) at time 0.5, \(-\$50\) at time 1, and \(+\$600\) at time 1.5. Find its NPV at time 1 using an effective annual rate of 44%. Round to the nearest cent. (Answer: \(-\$630.00\))
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