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Exam FM · Loan Amortization Schedules · Tutorial 236 of 998

Why Principal Portions Grow Geometrically

Learn why each principal portion is the previous one multiplied by one plus the periodic interest rate, and how to use that pattern to find a later component.

Intermediate 10 min read

What You'll Learn

  • State the assumptions that make principal repayments follow a geometric progression
  • Derive the ratio between consecutive principal portions from the balance recurrence
  • Calculate a later principal component from the first component or the loan payment
  • Match the rate period to the payment period, including for nominal rates convertible quarterly
  • Check a component calculation against the loan’s payment and balance structure
  • Recognize indexing and rate-period mistakes that produce incorrect components

Why Principal Portions Follow a Pattern

In a fixed-rate loan with equal payments, the total payment stays level, but its principal component does not. The principal repaid in each successive payment follows a precise pattern: each component is the previous one multiplied by \(1+i\), where \(i\) is the effective interest rate for one payment period. This relationship can turn a later component calculation into a short calculation from an early one.

The period attached to \(i\) matters. If payments are quarterly, for example, use the effective rate per quarter, not an annual rate applied directly to a quarterly balance. The result also relies on level payments and an unchanged rate; it need not hold when either of those conditions changes.

Definition: For a loan with level payments made at the end of each period, let \(C\) be the payment amount, \(i\) the effective interest rate per payment period, and \(P_k\) the principal portion of payment \(k\). The principal portions form a geometric progression if there is a constant ratio between consecutive terms. Under a fixed periodic rate and level payments, that ratio is \(1+i\): $$ P_{k+1}=(1+i)P_k. $$

Deriving the Geometric Progression

Assume a loan is repaid by equal payments at the end of each period. The interest rate \(i\) is constant and effective for each such period. There are no fees, extra payments, or payment rounding, and the scheduled payments amortize the loan. Let \(B_k\) be the balance immediately after payment \(k\), with \(B_0\) the original loan amount. A period’s interest is \(i\) times the balance at the start of that period.

The payment in period \(k\) first covers interest on \(B_{k-1}\); what remains pays down principal. Thus the principal portion \(P_k\) and the balance recurrence satisfy:

$$ P_k=C-iB_{k-1}, \qquad B_k=B_{k-1}-P_k. $$

In the next period, the principal portion is the level payment minus interest on the new opening balance. Substituting the balance recurrence shows why the ratio is \(1+i\):

1
Write the next principal portion.
By the same payment split, \(P_{k+1}=C-iB_k\).
2
Substitute the balance after payment \(k\).
Since \(B_k=B_{k-1}-P_k\), this gives \(P_{k+1}=C-i(B_{k-1}-P_k)\).
3
Use the current payment split.
Expand to obtain \(P_{k+1}=C-iB_{k-1}+iP_k\). Because \(C-iB_{k-1}=P_k\), it follows that \(P_{k+1}=(1+i)P_k\).

Repeated application gives the principal portion in any later payment:

$$ P_k=P_1(1+i)^{k-1}. $$

The exponent is \(k-1\), not \(k\), because payment 1 is the starting component and has not yet been multiplied by the ratio. This expression requires the same rate period in every step. If \(i=0\), the ratio is 1 and the principal portions are equal; the progression still holds.

Finding a Component From the Payment and Term

When the loan amount is the present value of \(n\) level payments, it can be written \(L=C a_{\overline{n}|}\), where \(a_{\overline{n}|}\) uses the same periodic rate \(i\). This lets us express the first principal portion using the payment and term. The first payment’s interest is \(iL\), so:

$$ P_1=C-iL =C\left(1-i a_{\overline{n}|}\right) =Cv^n, \qquad v=\frac{1}{1+i}. $$

The last equality follows from \(a_{\overline{n}|}=(1-v^n)/i\) when \(i>0\). Combining this expression with the geometric progression gives a direct formula for the \(k\)th principal portion:

$$ P_k=Cv^n(1+i)^{k-1} =Cv^{\,n-k+1}, \qquad 1\leq k\leq n. $$

This is a shortcut for a fully amortizing loan with level end-of-period payments and a fixed rate per payment period. If the rate changes, the payment varies, or there are irregular extra payments, use the actual period-by-period payment and balance information instead; the constant-ratio conclusion may not apply.

Worked Example: Checking the First Two Principal Portions

A hypothetical two-year loan has annual effective interest at 10% and two equal payments of $1,000 at the end of each year. Find the loan amount and the principal portions of both payments. Show that the second principal portion is 1.10 times the first. Use unrounded values in the calculations and report dollar amounts to the nearest cent.

Method. Find the original loan amount as the present value of the two payments, then split each payment into interest and principal. This checks the geometric relationship directly from the balance recurrence.

The rate period is one year, so \(i=0.10\). The discount factor is \(v=1/1.10=0.9090909091\). The loan amount is:

$$ L=1{,}000(v+v^2) =1{,}000(0.9090909091+0.8264462810) =\$1{,}735.5371901. $$

The first year’s interest is \(0.10L=\$173.5537190\). Therefore, the principal portion of payment 1 is:

$$ P_1=\$1{,}000-\$173.5537190 =\$826.4462810. $$

The balance after that payment is \(B_1=L-P_1=\$909.0909091\). The second year’s interest is \(0.10B_1=\$90.9090909\), giving:

$$ P_2=\$1{,}000-\$90.9090909 =\$909.0909091. $$

The ratio is \(P_2/P_1=\$909.0909091/\$826.4462810=1.10\), as required. Rounded to cents, the principal portions are $826.45 and $909.09. As a check, their unrounded sum is $1,735.5371901, the original principal. Common mistake avoided: using the 10% rate as the ratio itself. The ratio is \(1+i=1.10\), not \(i=0.10\).

Worked Example: Finding a Later Portion From a Loan’s Term

A hypothetical loan is repaid by three equal annual payments of $1,000. The annual effective interest rate is 5%, and the payments are made at each year-end. Find the principal portion of the third payment and verify the geometric progression. Report dollar amounts to the nearest cent.

Method. Use the present-value formula to specify the loan amount and then use \(P_k=Cv^{n-k+1}\). This avoids building the entire schedule just to find one component.

Here \(i=0.05\), \(v=1/1.05=0.9523809524\), and \(n=3\). The original loan amount is:

$$ L=1{,}000(v+v^2+v^3) =1{,}000(0.9523809524+0.9070294785+0.8638375985) =\$2{,}723.2480294. $$

The first principal portion is \(P_1=Cv^3\), and the geometric progression multiplies it by \(1.05\) for each subsequent payment:

$$ P_1=1{,}000(0.8638375985)=\$863.8375985, $$ $$ P_2=P_1(1.05)=\$907.0294785, $$ $$ P_3=P_2(1.05)=\$952.3809524. $$

Equivalently, the direct formula gives \(P_3=Cv^{3-3+1}=1{,}000v=\$952.3809524\). The third principal portion is therefore $952.38. The ratios \(P_2/P_1\) and \(P_3/P_2\) are both 1.05. As a further check, the unrounded principal portions sum to $2,723.2480294, the loan amount. Common mistake avoided: using \(Cv^3\) for the third component. That is the first component; the exponent for payment \(k\) is \(n-k+1\).

Worked Example: Matching a Nominal Rate to Quarterly Payments

A hypothetical loan has four equal quarterly payments of $2,500. Interest is at a nominal annual rate of 8% convertible quarterly. Find the principal portion of the third payment, and check its position in the progression. Report dollar amounts to the nearest cent.

Method. Convert the nominal rate to the effective rate for one payment period, then apply the direct component formula. The main trap is using 8% per quarter rather than the quarterly rate.

There are four periods per year, so the effective quarterly rate is \(i=0.08/4=0.02\). Thus \(v=1/1.02=0.9803921569\), and the term is \(n=4\). The loan amount consistent with the stated payments is:

$$ L=2{,}500a_{\overline{4}|} =2{,}500(v+v^2+v^3+v^4) =2{,}500(0.9803921569+0.9611687812+0.9423223345+0.9238454265) =\$9{,}519.3217478. $$

For the third payment, the exponent is \(n-k+1=4-3+1=2\). Hence:

$$ P_3=2{,}500v^2 =\frac{\$2{,}500}{(1.02)^2} =\$2{,}402.9219531. $$

To check the progression, the first portion is \(P_1=2{,}500v^4=\$2{,}309.6135663\). Multiplying twice by 1.02 gives:

$$ P_1(1.02)^2 =\$2{,}309.6135663(1.0404) =\$2{,}402.9219531=P_3. $$

The requested component is $2,402.92. Common mistake avoided: treating the nominal annual rate as the rate per quarterly period. The appropriate rate for this schedule is 2% per quarter.

Using the Pattern Carefully

The progression is useful when a question gives one principal component and asks for another, or when the payment amount and term are known but the schedule is not provided. Before calculating, identify the period rate, the payment number, and which component is being requested. A reliable setup is:

  • Set the rate period equal to the payment period.
  • Use \(P_k=P_1(1+i)^{k-1}\) when the first component is known.
  • Use \(P_k=Cv^{n-k+1}\) when the level payment and total number of payments are known for a fully amortizing loan.
  • Keep unrounded values through the calculation, rounding only the final reported dollar amount.

The exponent’s direction is a useful check. Later principal portions are larger when \(i>0\), so \(P_k\) must rise as \(k\) rises. In the direct formula, \(n-k+1\) gets smaller for later payments; since \(0<v<1\), a smaller exponent gives a larger value. If a calculation instead makes later principal portions smaller for a positive rate, check the indexing or rate conversion.

The conclusion concerns principal portions, not the full payment: the payment remains \(C\) in the model. It also does not say that the principal portions rise by a fixed dollar amount. Their dollar increases change from period to period because the increase is proportional to the current portion. This distinction is useful when checking a schedule or deciding whether a calculation is consistent with a fixed-rate, level-payment loan.

Check Your Understanding

For each problem, identify the rate per payment period before using the principal progression. Answers are rounded to the nearest cent unless an exact expression is given.

  1. A loan has three equal year-end payments of $800 and an annual effective rate of 4%. Find the principal portion of payment 2. (Answer: $739.64)
  2. In a fixed-rate loan at 6% effective annually, the principal portion of payment 1 is $450. Find the principal portion of payment 4. (Answer: $535.96)
  3. A loan is repaid by eight equal quarterly payments. Its nominal annual interest rate is 9% convertible quarterly, and each payment is $1,200. Find the principal portion of payment 6. (Answer: $1,122.52)
  4. A fully amortizing loan has five equal annual payments and an annual effective rate of 5%. If each payment is $2,300, find the principal portion of payment 4 using the direct formula. (Answer: $2,086.17)
  5. For a fixed-rate loan, the principal portion of payment 2 is $720, and the effective rate per payment period is 5%. Find the principal portion of payment 5. (Answer: $833.49)
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