Why Rewrite an Integrand?
Some integrands do not look like they match a basic antiderivative rule, even when they are built from familiar powers and sums. A quotient may hide a polynomial, a radical may hide a fractional power, or a sum in the numerator may be easier to handle term by term.
The useful move is algebraic: rewrite the integrand into an equivalent form that matches a rule you already know. The word equivalent matters. The rewritten expression must agree with the original wherever the original is defined, and any restrictions on the original domain must remain in force.
The Basic Rules to Reveal
For a real exponent \(p\), the real-valued power \(x^p\) is defined for all \(x>0\). On that domain, the power antiderivative rule is
For integer exponents, the same rule also applies when \(x<0\), provided the powers involved are defined; in particular, negative integer powers require \(x\ne 0\). The rule does not cover exponent \(-1\). Keep this exception in mind rather than forcing that term into the power rule.
We will also use the constant rule and the sum rule. If \(a\) is constant and each displayed power satisfies the conditions of the power rule on an interval, then
The sum rule applies to a finite sum term by term. In practice, algebraic rewriting is the step that turns an unfamiliar-looking expression into a sum of powers or constants.
Which Exponent Rewrites Are Valid?
For arbitrary real exponents \(a\) and \(b\), the quotient law is valid for \(x>0\):
The condition \(x>0\) is important. It ensures that both real powers are defined as real numbers. If the exponents are integers, the identity also holds for \(x\ne 0\), as long as the quotient is defined. Do not extend the real-exponent version to negative \(x\) merely because \(x\) is nonzero.
For instance, a radical can be rewritten as a fractional power on its real domain: \(\sqrt{x}=x^{1/2}\) for \(x\ge 0\). If the radical appears in a denominator, the denominator must also be nonzero, so the full expression may require \(x>0\).
Why the Rewriting Method Works
The justification has two parts. First, the algebraic identity says the rewritten expression equals the original integrand on the original domain. Second, differentiation verifies that the proposed antiderivative has that rewritten expression as its derivative.
Let \(D\) be the set where the original integrand is defined. Choose an interval \(I\) contained in \(D\), so differentiation and antiderivatives are considered on a single interval.
Suppose algebra gives \(f(x)=g(x)\) for every \(x\in I\). The equality is required on the interval where the original expression is defined.
Use the sum rule and the applicable basic antiderivative rules to find \(G\) with \(G'(x)=g(x)\) on \(I\).
Because \(g(x)=f(x)\) on \(I\), we have \(G'(x)=g(x)=f(x)\) there. Thus \(G\) is an antiderivative of the original integrand on \(I\).
This is a complete justification: the algebra establishes equality of the integrands, and the derivative establishes the antiderivative. If the original domain has separate intervals, the argument applies on each one. The constants of integration can be different on different intervals because there is no requirement that an antiderivative match across a point outside the domain.
The power rule itself follows from the derivative power rule. For \(p\ne-1\), differentiating the proposed expression gives
On \(x>0\), this computation applies to real \(p\); for integer powers it also applies wherever the powers are defined. The sum rule is justified in the same way: the derivative of a sum is the sum of its derivatives.
Worked Example: Cancel a Factor Without Losing the Exclusion
Find an antiderivative of \(\displaystyle \frac{x^2-1}{x-1}\), and state where it applies.
The original denominator is zero at \(x=1\), so the original domain is \(x\ne1\). Factor the numerator:
The cancellation is valid only when \(x-1\ne0\). Now integrate the revealed terms on either interval of the original domain:
Check by differentiating:
Thus the result is an antiderivative on \((-\infty,1)\) and on \((1,\infty)\). The constants may be chosen independently on those two intervals. The simplified formula does not make the original quotient defined at \(x=1\).
Quotients of Sums
When every term in a numerator is divided by the same power, divide each term separately and then simplify its exponent. The result may be a sum of powers that can be integrated term by term. Track whether the denominator excludes zero before simplifying.
Worked Example: Divide Each Term by a Common Power
Find an antiderivative of \(\displaystyle \frac{6x^5-4x^3+2x^2}{x^2}\), keeping its domain in view.
The original denominator requires \(x\ne0\). Divide each term in the numerator by \(x^2\), retaining that restriction:
Integrate term by term:
Differentiate to check the result, then compare with the original quotient:
The antiderivative is valid on each interval \((-\infty,0)\) and \((0,\infty)\). Although the simplified derivative expression has a value at zero, the original quotient does not, so zero remains excluded.
Negative and Fractional Powers
Rewriting can also expose negative or fractional powers. A negative integer power such as \(x^{-2}\) means \(1/x^2\), so it is defined only when \(x\ne0\). A fractional real power such as \(x^{-1/2}\) requires \(x>0\) when it occurs as a real-valued function. Once the domain is stated, use the power rule only when its exponent is not \(-1\).
Worked Example: Rewrite a Quotient as Positive and Negative Powers
Find an antiderivative of \(\displaystyle \frac{2x^6+3x^2}{x^4}\).
The denominator requires \(x\ne0\). Apply the integer exponent quotient law term by term:
Both exponents differ from \(-1\), so integrate each term:
Check by differentiation and rewrite the result in quotient form:
The check confirms the result on each interval in the original domain, not at zero.
Worked Example: Turn a Radical Quotient into Powers
Find an antiderivative of \(\displaystyle \frac{x^2+1}{\sqrt{x}}\).
The denominator is a square root and cannot be zero. For a real-valued integrand, the domain is therefore \(x>0\). Rewrite the radical and divide each term by \(x^{1/2}\):
Apply the power rule to both terms:
Differentiate the proposed antiderivative:
The original expression and the derivative agree throughout the original domain \(x>0\), so the antiderivative is verified there.
Common Pitfalls
A frequent error is to cancel or simplify and then silently enlarge the domain. In the first worked example, \((x^2-1)/(x-1)\) agrees with \(x+1\) only for \(x\ne1\). The cancellation gives a simpler formula, but it does not change where the original quotient exists.
A second error is to apply the quotient law for arbitrary real exponents whenever \(x\ne0\). For example, the claim
is not a valid real-valued identity on that stated domain: at \(x=-1\), \(x^{1/2}\) is not a real number. For arbitrary real exponents, use the quotient law on \(x>0\). If the exponents are integers, the quotient law can be used for \(x\ne0\), provided the expressions are defined.
Finally, do not combine terms merely because they share a denominator, and do not apply the power antiderivative rule when its exponent is \(-1\). First rewrite accurately, identify the domain, and then select a rule whose conditions are satisfied.
A Reliable Checklist
Before integrating an expression that looks more complicated than a basic power, use this sequence:
- Find the original domain, including values excluded by denominators and radicals.
- Rewrite quotients term by term only where the exponent laws are valid.
- Keep exclusions from the original expression after cancellation or simplification.
- Check that each resulting term matches a basic antiderivative rule and satisfies its conditions.
- Differentiate the proposed antiderivative and compare it with the original integrand on its domain.
This method matters because algebraic form can conceal the structure of an integrand. A correct rewrite often turns an unfamiliar quotient into a short sum of powers, making the antiderivative straightforward. The domain check ensures that this simplification remains mathematically equivalent to the expression you were asked to integrate.
Check Your Understanding
For each question, pay attention both to the rewritten powers and to the domain on which the statement is valid.
- Rewrite \(\displaystyle \frac{4x^5-2x^3}{x^2}\) as a sum of powers. What value of \(x\) is excluded by the original expression?
- Find an antiderivative of \(\displaystyle 5x^4+3x^{-2}\) on an interval where it is defined, and verify it by differentiation.
- On what domain is \(\displaystyle \frac{x^{3/2}}{x^{1/2}}=x\) a valid real-valued identity?
- Why does simplifying \(\displaystyle \frac{x^2-4}{x-2}\) not make the original expression defined at \(x=2\)?
- Which exponent is excluded from the basic power antiderivative rule stated here?