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Trigonometric Function Toolkit · Tutorial 116 of 1495

Arc Length and Sector Area

Use radian measure to calculate arc lengths and sector areas, while keeping angle measure distinct from physical length.

Beginner 9 min read

What You'll Learn

  • Define a radian as the ratio of arc length to radius.
  • Derive the arc-length formula from the definition of radian measure.
  • Derive the sector-area formula from the fraction of a full circle.
  • Calculate arc lengths and sector areas with exact units.
  • Convert a degree measure before using the radian formulas.
  • Check results using circle proportions and dimensional units.

Why Radian Measure Connects Angles to Circle Measurements

A central angle describes how far two radii turn apart, while an arc is a physical part of a circle’s circumference. A sector is the region enclosed by those two radii and the arc between them. Radian measure is especially useful because it directly relates the angle to the circle’s physical dimensions.

The key distinction is that an angle is a measure of rotation, whereas an arc length is a distance. The formulas in this tutorial connect them, but they do not make them the same kind of quantity. The radius supplies the length scale: at a fixed angle, a larger circle has a proportionally longer arc and a proportionally larger sector.

Radian Measure and Arc Length

For a circle with radius \(r>0\), an arc subtended by a central angle has arc length \(s\). When the angle is measured in radians, its measure is the ratio of that arc length to the radius. For a particular arc, the angle and arc length must refer to the same portion of the circle.

Definition: If an arc of length \(s\) lies on a circle of radius \(r\), the radian measure \(\theta\) of its central angle is \(\theta=s/r\). Equivalently, for a central angle measured in radians, the arc length is \(s=r\theta\).

The equation \(\theta=s/r\) also explains why the angle itself is not a physical length. Both \(s\) and \(r\) have units of length, so their ratio has no physical length unit. The unit “radian” is often written to make clear that an angle is being measured, but in calculations it is a dimensionless ratio.

The formula \(s=r\theta\) requires \(\theta\) to be in radians. If an angle is given in degrees, first convert it to radians. For example, an angle of \(90^\circ\) is \(\pi/2\) radians, so a quarter-circle arc has length \(r\pi/2\), not \(90r\).

Deriving the Arc-Length Formula

The definition of radian measure already contains the relationship between arc length, radius, and angle. Rearranging it gives the arc-length formula. A full circle provides a useful check: its circumference is \(2\pi r\), and its angle is \(2\pi\) radians. Substituting that angle into the formula gives exactly the full circumference.

$$ \theta=\frac{s}{r} \quad\Longrightarrow\quad s=r\theta. $$

The derivation is short, but the condition on units is essential. The numerical value of \(\theta\) must be its radian measure. Using the degree value in the same formula would not preserve the defining ratio \(s/r\).

Worked Examples with Arc Length

Worked Example: Find an Arc Length from a Radian Angle

A circle has radius \(7\text{ cm}\), and a central angle of \(2\pi/3\) radians subtends an arc. Find the arc length.

Use \(s=r\theta\). The radius is \(r=7\text{ cm}\), and the angle is already in radians, so

$$ s=(7\text{ cm})\left(\frac{2\pi}{3}\right) =\frac{14\pi}{3}\text{ cm}. $$

To check, \(2\pi/3\) is one third of a full turn, since \((2\pi/3)/(2\pi)=1/3\). The full circumference is \(2\pi(7\text{ cm})=14\pi\text{ cm}\), and one third of that is \(14\pi/3\text{ cm}\), as calculated.

Worked Example: Find an Arc Length from a Decimal Radian Measure

A circle has radius \(5\text{ m}\), and a central angle measures \(1.2\) radians. Find the arc length.

Substitute the radius and radian measure:

$$ s=r\theta =(5\text{ m})(1.2) =6\text{ m}. $$

For a check, the circumference is \(2\pi(5\text{ m})=10\pi\text{ m}\). The fraction of a full circle corresponding to \(1.2\) radians is \(1.2/(2\pi)\). The associated arc length is therefore \((1.2/(2\pi))(10\pi\text{ m})=6\text{ m}\), matching the formula.

Sector Area

A sector is the part of a disk cut out by two radii and the arc between them. For a central angle between \(0\) and \(2\pi\) radians, its area is the same fraction of the full disk’s area as its angle is of a full turn. Thus, if the angle is \(\theta\), the fraction is \(\theta/(2\pi)\). The area of the full disk is \(\pi r^2\).

Formula: For a sector of radius \(r>0\) and central angle \(\theta\) measured in radians, with \(0\leq\theta\leq2\pi\), its area \(A\) is \(A=\frac{1}{2}r^2\theta\).

Deriving the Sector-Area Formula

The sector formula follows by taking the appropriate fraction of the disk’s area. The angle \(\theta\) is a fraction \(\theta/(2\pi)\) of a full \(2\pi\)-radian turn. Multiplying that fraction by \(\pi r^2\) gives the sector area.

$$ A=\frac{\theta}{2\pi}\,\pi r^2 =\frac{1}{2}r^2\theta. $$

This argument applies to a sector whose angle is between \(0\) and \(2\pi\), including a reflex sector. When \(\theta=0\), the area is zero; when \(\theta=2\pi\), it is the area of the full disk. As with arc length, \(\theta\) must be in radians. If the angle is in degrees, use its radian measure in the formula.

The arc-length formula also gives an equivalent way to calculate sector area. Since \(s=r\theta\), we have \(\theta=s/r\). Substituting this into \(A=\frac{1}{2}r^2\theta\) gives \(A=\frac{1}{2}rs\). This version is useful when the arc length is known.

$$ A=\frac{1}{2}r^2\theta =\frac{1}{2}r(r\theta) =\frac{1}{2}rs. $$

Worked Examples with Sector Area

Worked Example: Find the Area of a Sector

A circle has radius \(7\text{ cm}\), and a sector has central angle \(2\pi/3\) radians. Find the sector’s area.

Use \(A=\frac{1}{2}r^2\theta\). First square the radius: \((7\text{ cm})^2=49\text{ cm}^2\). Then substitute:

$$ A=\frac{1}{2}(49\text{ cm}^2)\left(\frac{2\pi}{3}\right) =\frac{49\pi}{3}\text{ cm}^2. $$

Check by using the angle’s fraction of a full turn. The fraction is \((2\pi/3)/(2\pi)=1/3\). The full disk area is \(\pi(7\text{ cm})^2=49\pi\text{ cm}^2\), and one third of that is \(49\pi/3\text{ cm}^2\), as required.

Worked Example: Use a Degree Measure for Arc Length and Sector Area

A circle has radius \(8\text{ in}\), and a sector has central angle \(135^\circ\). Find both the arc length and the sector area.

The formulas require radians. Convert the angle first:

$$ 135^\circ\left(\frac{\pi\text{ radians}}{180^\circ}\right) =\frac{3\pi}{4}\text{ radians}. $$

Now find the arc length:

$$ s=r\theta =(8\text{ in})\left(\frac{3\pi}{4}\right) =6\pi\text{ in}. $$

Find the sector area using the same radian measure:

$$ A=\frac{1}{2}r^2\theta =\frac{1}{2}(64\text{ in}^2)\left(\frac{3\pi}{4}\right) =24\pi\text{ in}^2. $$

Check the arc length using a fraction of the full circumference. Since \(135^\circ/360^\circ=3/8\), the arc is \(3/8\) of \(2\pi(8\text{ in})=16\pi\text{ in}\), giving \(6\pi\text{ in}\). For the area, the same fraction of the disk’s area, \(64\pi\text{ in}^2\), is \(24\pi\text{ in}^2\). Both results agree.

Keep Units and Quantities Distinct

The formulas provide a useful units check. If \(r\) is measured in centimetres, then \(s\) must be in centimetres, while \(A\) must be in square centimetres. In \(s=r\theta\), the angle contributes no physical length unit. In \(A=\frac{1}{2}r^2\theta\), the squared radius supplies the area unit.

Quantity Formula Units when \(r\) is in metres
Arc length \(s\) \(s=r\theta\) Metres
Sector area \(A\) \(A=\frac{1}{2}r^2\theta\) Square metres

These checks can reveal errors even when the arithmetic looks plausible. For instance, an answer for an arc length written in square metres cannot be correct: square metres measure area, not distance.

Common Pitfall: Substituting Degrees Directly

A frequent error is to use a degree measure as though it were a radian measure. For example, suppose \(r=4\text{ cm}\) and \(\theta=90^\circ\). The incorrect calculation \(s=4(90)=360\text{ cm}\) treats \(90\) as a radian measure. It would imply an arc much longer than the circle’s circumference, which is \(8\pi\text{ cm}\).

The correction is to convert \(90^\circ\) to \(\pi/2\) radians before using the formula:

$$ s=(4\text{ cm})\left(\frac{\pi}{2}\right) =2\pi\text{ cm}. $$

A quarter of the circumference \(8\pi\text{ cm}\) is \(2\pi\text{ cm}\), so the corrected answer passes the circle-proportion check. The sector area is likewise \(\frac{1}{2}(4\text{ cm})^2(\pi/2)=4\pi\text{ cm}^2\), one quarter of the disk area \(16\pi\text{ cm}^2\).

Why These Formulas Matter

Arc length and sector area translate an angular description into measurable quantities. They are useful whenever a circular object turns through a specified angle: the angle can determine how far a point on the edge travels and how much area a rotating radius sweeps out. In every such application, the radius sets the physical scale, and the angle must be expressed in radians for these compact formulas to apply.

Before calculating, identify the requested quantity, record the radius with its units, and check how the angle is measured. Then use \(s=r\theta\) for distance along the arc or \(A=\frac{1}{2}r^2\theta\) for sector area. Finally, check that the answer has the right units and is consistent with the corresponding fraction of a full circle.

Check Your Understanding

Answer each question, paying attention to the angle measure and the units.

  1. A circle has radius \(6\text{ cm}\) and central angle \(\pi/3\) radians. What is the arc length?
  2. A circle has radius \(3\text{ m}\) and central angle \(\pi/2\) radians. What is the sector area?
  3. Why must a degree measure be converted before using \(s=r\theta\)?
  4. A sector has radius \(5\text{ cm}\) and arc length \(4\text{ cm}\). Use \(A=\frac{1}{2}rs\) to find its area.
  5. What units should an arc length and a sector area have if the radius is measured in inches?

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