Tutorials › Calculus I › Concavity from a Graph of f’

Concavity and Inflection · Tutorial 802 of 1495

Concavity from a Graph of f'

Use the direction of change in the graph of \(f'\), rather than its height, to identify where \(f\) is concave up or down.

Intermediate 10 min read

What You'll Learn

  • Infer concavity from intervals where the graph of \(f'\) rises or falls.
  • Interpret flat sections of \(f'\) as intervals where \(f\) is linear.
  • Distinguish a turning point of \(f'\) from the sign of \(f'\).
  • Handle transitions between rising, falling, and flat sections.
  • Check concavity conclusions by tracking changes in \(f'\).

Reading Concavity from the Direction of \(f'\)

A graph of \(f'\) carries information about the shape of \(f\). The key is to follow whether the graph of \(f'\) rises, falls, or stays level as \(x\) increases. Rising \(f'\) means the slopes of \(f\) are getting larger, so \(f\) is concave up. Falling \(f'\) means those slopes are getting smaller, so \(f\) is concave down.

This is different from asking whether \(f'\) is above or below the horizontal axis. The height of \(f'\) tells us the sign of the slope of \(f\). Its direction of change tells us about concavity. Keeping those two readings separate is essential when interpreting a graph.

Key rule: On an interval where \(f\) is differentiable, if \(f'\) is increasing, then \(f\) is concave up. If \(f'\) is decreasing, then \(f\) is concave down. A constant section of \(f'\) corresponds to a linear section of \(f\), which is both concave up and concave down under the non-strict definitions.

What “Rising” and “Falling” Mean

As we move from left to right on the graph, \(f'\) is increasing when its values do not decrease, and it is decreasing when its values do not increase. A graph that rises strictly has increasing values; one that falls strictly has decreasing values. A horizontal section is constant, so it meets both non-strict descriptions.

The concavity rule follows the monotonicity criterion from the earlier material on concavity and monotonicity of the first derivative. In the usual concavity convention, non-strict monotonicity matters: linear pieces count as both concave up and concave down. If a question asks for strict concavity, a linear interval is neither strictly concave up nor strictly concave down.

A graph of \(f'\) may have a corner where its direction changes. That does not prevent us from reading whether \(f'\) rises or falls on either side. We do not need \(f'\) itself to have a derivative at every point in order to use its monotonicity to infer concavity.

Why the Rule Works

Here is a justification using chord slopes. Suppose \(f'\) is nondecreasing on an interval and choose any \(a<b<c\) in that interval. Assume \(f\) is continuous on the relevant closed intervals and differentiable on their interiors. By the Mean Value Theorem, there are points \(u\in(a,b)\) and \(v\in(b,c)\) such that

$$ \frac{f(b)-f(a)}{b-a}=f'(u) \qquad\text{and}\qquad \frac{f(c)-f(b)}{c-b}=f'(v). $$

Since \(u<v\) and \(f'\) is nondecreasing, \(f'(u)\leq f'(v)\). Therefore, the slope of the chord from \(a\) to \(b\) is no greater than the slope of the chord from \(b\) to \(c\). This is the chord-slope condition for \(f\) to be concave up. If \(f'\) is nonincreasing, the inequalities reverse, giving concavity down.

If \(f'\) is constant on an interval, say \(f'(x)=m\), the Mean Value Theorem gives \(f(b)-f(a)=m(b-a)\) for any two points \(a<b\) there. Thus \(f(x)-mx\) is constant on that interval, so \(f\) is a straight line there. Its chord slopes are equal, which is why the interval meets both non-strict concavity descriptions.

Worked Example: Three Straight Sections of \(f'\)

Worked Example: Three Straight Sections of \(f'\)

Suppose the graph of \(f'\) consists of straight segments joining the points \((-3,4)\), \((-1,0)\), \((2,0)\), and \((5,6)\). Identify the concavity of \(f\) on the corresponding intervals.

First calculate the change in \(f'\) on each segment:

$$ \frac{0-4}{-1-(-3)}=\frac{-4}{2}=-2, \qquad \frac{0-0}{2-(-1)}=0, \qquad \frac{6-0}{5-2}=\frac{6}{3}=2. $$

The first segment falls, the second is horizontal, and the third rises. Therefore \(f'\) is decreasing on \((-3,-1)\), constant on \((-1,2)\), and increasing on \((2,5)\). It follows that \(f\) is concave down on \((-3,-1)\), both concave up and concave down on the linear section \((-1,2)\), and concave up on \((2,5)\).

Check: The corresponding changes in \(f'\) are \(4\) to \(0\), \(0\) to \(0\), and \(0\) to \(6\). These values confirm the falling, flat, and rising descriptions. On the flat segment, \(f'=0\), so \(f\) is constant there, a special case of a linear function.

Turning Points of \(f'\)

A local maximum or minimum in the graph of \(f'\) often marks a transition between concavity directions. If \(f'\) rises on one side of a turning point and falls on the other, \(f\) changes from concave up to concave down. If \(f'\) falls and then rises, the direction of concavity changes the other way. These observations identify where concavity changes; they do not say that every turning point must be an isolated point or that every flat stretch counts as a change.

Worked Example: A Smooth Maximum in \(f'\)

On \([-1,3]\), suppose the graph is described by \(f'(x)=4-(x-1)^2\). Determine where \(f\) is concave up or down from the shape of this graph.

The graph of \(f'\) is a downward-opening parabola with its maximum at \(x=1\). To check the direction on either side, evaluate \(f'\) at several points:

$$ f'(-1)=4-(-2)^2=0,\qquad f'(0)=4-(-1)^2=3,\qquad f'(1)=4-0^2=4, $$ $$ f'(2)=4-1^2=3,\qquad f'(3)=4-2^2=0. $$

From \(-1\) to \(1\), the values rise from \(0\) to \(4\), so \(f'\) is increasing there and \(f\) is concave up on \((-1,1)\). From \(1\) to \(3\), the values fall from \(4\) to \(0\), so \(f'\) is decreasing there and \(f\) is concave down on \((1,3)\). The graph of \(f'\) turns at \(x=1\), where the concavity direction switches.

Check: Differentiating the stated expression for \(f'\) gives \(\frac{d}{dx}f'(x)=-2(x-1)\). This is positive for \(x<1\), zero at \(x=1\), and negative for \(x>1\), confirming the graph’s rise, maximum, and fall.

Flat Sections and Their Neighbours

A horizontal section of the graph of \(f'\) must not be mistaken for a gap in the concavity information. It says that \(f\) has constant slope on that interval, hence is linear there. But how the flat section joins the sections around it also matters. For instance, a rising section followed by a flat one leaves \(f'\) nondecreasing across the join, so \(f\) remains concave up across that combined interval.

Worked Example: A Plateau, a Fall, and a Rise

Suppose the graph of \(f'\) is made of straight segments joining \((-4,-1)\), \((-2,3)\), \((1,3)\), \((3,-1)\), \((4,-1)\), and \((6,3)\). Find where \(f\) is concave up or down, paying attention to the flat sections.

Calculate the slope of each segment of the graph of \(f'\):

$$ \frac{3-(-1)}{-2-(-4)}=\frac{4}{2}=2,\qquad \frac{3-3}{1-(-2)}=0, $$ $$ \frac{-1-3}{3-1}=\frac{-4}{2}=-2,\qquad \frac{-1-(-1)}{4-3}=0,\qquad \frac{3-(-1)}{6-4}=\frac{4}{2}=2. $$

Thus \(f'\) rises on \((-4,-2)\), stays level on \((-2,1)\), falls on \((1,3)\), stays level on \((3,4)\), and rises on \((4,6)\). The first rising section followed by the plateau is nondecreasing throughout \((-4,1)\), so \(f\) is concave up there. The plateau from \(-2\) to \(1\) is also a linear section of \(f\), and thus both concave up and concave down on that section considered alone.

From \(x=1\) through \(x=4\), \(f'\) is nonincreasing: it falls, then remains level. Therefore \(f\) is concave down on \((1,4)\). From \(x=4\) to \(x=6\), \(f'\) rises, so \(f\) is concave up on \((4,6)\).

Check: The segment changes in \(f'\) are \(+4, 0, -4, 0,\) and \(+4\), matching the sequence rise, flat, fall, flat, rise. In particular, a flat segment is not automatically “up” or “down”: it is linear and qualifies as both by itself. Its neighbouring sections determine whether a larger interval has a consistent nondecreasing or nonincreasing \(f'\).

A Common Mistake: Reading Height Instead of Direction

It is tempting to use whether the graph of \(f'\) lies above or below the \(x\)-axis to decide concavity. That reads the wrong feature. Consider \(f'(x)=3-x\) on \((0,1)\). Its graph is above the axis throughout, but it falls as \(x\) increases.

$$ f'(0)=3,\qquad f'\!\left(\frac12\right)=\frac52,\qquad f'(1)=2. $$

A mistaken conclusion would be: “\(f'\) is positive, so \(f\) is concave up.” Positivity means that \(f\) is increasing, not that it is concave up. The displayed values show that \(f'\) is decreasing, so \(f\) is concave down. The correction is to track the vertical change in the graph of \(f'\) as \(x\) moves from left to right, rather than just its position relative to the axis.

Reading a Graph Systematically

When given a graph of \(f'\), divide its domain into intervals on which it consistently rises, falls, or stays level. Then translate each direction into a concavity statement for \(f\). At a turning point, inspect the intervals on both sides instead of assigning concavity from the point alone. At a flat section, state that \(f\) is linear there; if the section joins a rising or falling segment, check whether the monotonicity of \(f'\) continues across the join.

Use only the intervals represented by the graph. If the graph has a break or the domain has a gap, conclusions from one side do not automatically extend across it. Finally, keep two readings distinct: the sign of \(f'\) describes whether \(f\) increases or decreases, while the trend of \(f'\) describes the concavity of \(f\).

Check Your Understanding

For each question, focus on how the graph of \(f'\) changes from left to right.

  1. If \(f'\) rises throughout an interval, what is the concavity of \(f\) there?
  2. If \(f'\) is constant on an interval, what does that imply about \(f\), and how is that interval classified under non-strict concavity?
  3. The graph of \(f'\) falls to a local minimum and then rises. What concavity directions occur on either side of the minimum?
  4. Can a graph of \(f'\) above the \(x\)-axis still correspond to a concave-down function? Explain briefly.
  5. If \(f'\) rises and then becomes level, is it nondecreasing across the transition? What does that imply for \(f\)?

Test yourself: Calculus I final exam practice

Ready to check what you know? Work a full-length practice final, then open the complete worked solutions.

Want all 1,114 practice problems?

This tutorial covers one topic. Calc Pass covers the full Calculus AB & BC curriculum (the core of Calculus I and II): full review, every practice question, and step-by-step solutions to each one.

QR code to download the Calc Pass app

Get the Calc Pass App

Scan to download and practice on the go, with instant scoring.

Calc Pass Volume 1: 1,114 Practice Questions book cover

Vol. 1: 1,114 Questions

The complete practice question bank, organized by AB & BC topic.

View on Amazon
Calc Pass Volume 2: Solutions Manual book cover

Vol. 2: Solutions Manual

Fully worked solutions to every question in Volume 1.

View on Amazon