Why Double-Angle Identities Follow from Angle Addition
An angle addition formula describes the sine or cosine of a sum of two angles. A double-angle expression is the special case in which those two angles are equal: \(x+x=2x\). This simple substitution produces useful identities for \(\sin(2x)\), \(\cos(2x)\), and, when the relevant denominators are nonzero, \(\tan(2x)\).
The sine and cosine identities are valid for every real \(x\). The tangent identity needs more care: tangent is a quotient, so it is defined only when its cosine denominator is nonzero. Keeping track of those restrictions is part of deriving the identity correctly.
Deriving the Sine Double-Angle Identity
Set \(a=x\) and \(b=x\) in the sine addition formula. Each sine and cosine on the right is then evaluated at \(x\):
The last equality uses the commutativity of multiplication: \(\cos x\sin x=\sin x\cos x\). There are no divisions in this derivation, so the result holds for every real \(x\).
Deriving the Cosine Double-Angle Identities
Now set \(a=b=x\) in the cosine addition formula. This gives the first form directly:
Two other forms follow from the Pythagorean identity \(\sin^2 x+\cos^2 x=1\). To obtain a form involving only \(\cos x\), replace \(\sin^2 x\) with \(1-\cos^2 x\):
Alternatively, replace \(\cos^2 x\) with \(1-\sin^2 x\):
These are not three separate rules about different angles. They are equal expressions for the same quantity. The first comes directly from angle addition; the other two are algebraic consequences of the Pythagorean identity.
Deriving the Tangent Double-Angle Identity
Tangent is defined by \(\tan u=\frac{\sin u}{\cos u}\) when \(\cos u\ne 0\). Therefore \(\tan(2x)\) is defined only if \(\cos(2x)\ne 0\). To express it in terms of \(\tan x\), we also need \(\tan x\) to be defined, which requires \(\cos x\ne 0\).
Under those conditions, use the sine and cosine double-angle identities and divide:
The division by \(\cos^2 x\) is valid because \(\cos x\ne 0\). The final denominator must also be nonzero: \(1-\tan^2 x\ne 0\). With \(\cos x\ne 0\), the cosine identity gives \(\cos(2x)=\cos^2 x(1-\tan^2 x)\), so this last condition is exactly what ensures \(\cos(2x)\ne 0\).
A Complete Derivation in Steps
The derivations can be organized as a short sequence. The domain check belongs specifically to the tangent step because that step involves division.
Use \(a=b=x\) in the sine and cosine addition formulas, so \(a+b=2x\).
The two terms \(\sin x\cos x\) and \(\cos x\sin x\) are equal, giving \(\sin(2x)=2\sin x\cos x\).
The cosine addition formula gives \(\cos(2x)=\cos^2 x-\sin^2 x\); the Pythagorean identity yields the other two forms.
Write \(\tan(2x)=\sin(2x)/\cos(2x)\), then divide by \(\cos^2 x\). This requires \(\cos x\ne 0\) and \(1-\tan^2 x\ne 0\).
Worked Examples
Worked Example: Evaluate the Double Angle at \(x=\frac{\pi}{6}\)
Use \(\sin(\pi/6)=1/2\) and \(\cos(\pi/6)=\sqrt{3}/2\). First apply the sine identity:
For cosine, use the difference of squares:
Since \(\tan(\pi/6)=\sqrt3/3\), the tangent formula gives
Check: \(2(\pi/6)=\pi/3\), where the exact values are \(\sin(\pi/3)=\sqrt3/2\), \(\cos(\pi/3)=1/2\), and \(\tan(\pi/3)=\sqrt3\). They agree with all three results.
Worked Example: Use Given Sine and Cosine Values
Suppose \(\sin x=5/13\) and \(\cos x=12/13\). These values are consistent with the Pythagorean identity because \( (5/13)^2+(12/13)^2=25/169+144/169=1 \). Calculate the three double-angle values.
For tangent, first calculate \(\tan x=(5/13)/(12/13)=5/12\). Then
Check the tangent result using the sine and cosine values just found: \(\sin(2x)/\cos(2x)=(120/169)/(119/169)=120/119\). The quotient agrees.
Worked Example: Recognize When the Tangent Formula Cannot Be Used
Take \(x=\pi/4\). Here \(\sin x=\cos x=\sqrt2/2\), so the sine and cosine identities are still available:
But \(\tan(2x)=\tan(\pi/2)\) is undefined because its cosine denominator is zero. The tangent double-angle expression also signals the problem: \(\tan(\pi/4)=1\), so \(1-\tan^2(\pi/4)=1-1=0\). The formula would require division by zero and must not be used here.
Check: \(2x=\pi/2\), and \(\cos(\pi/2)=0\), confirming directly that \(\tan(2x)\) is undefined. The sine and cosine identities remain valid because neither requires division.
A Common Mistake: Ignoring the Denominator
A frequent error is to use the tangent identity whenever \(\tan x\) exists, without checking the denominator \(1-\tan^2 x\). For example, at \(x=\pi/4\), \(\tan x=1\) exists, but the proposed calculation
is not a real number. It does not mean that \(\tan(\pi/2)\) has some value obtained by this calculation. Rather, both the right-hand expression and \(\tan(\pi/2)\) are undefined. The correction is to check the denominator before applying the formula and to use the sine and cosine identities when those quantities are what is needed.
Why These Identities Matter
The identities connect trigonometric values at \(x\) to values at \(2x\). They let a calculation involving a doubled angle be rewritten using the sine, cosine, or tangent of the original angle. The derivation also illustrates a general mathematical habit: algebraic rearrangement is safe only after checking that every division is permitted.
For sine and cosine, setting equal angles in the addition formulas introduces no restrictions. For tangent, the quotient definition creates domain conditions that cannot be dropped. Remembering this distinction makes the identities both useful and precise.
Check Your Understanding
Try each question using the identities and conditions developed above.
- Starting from the sine addition formula, show why \(\sin(2x)=2\sin x\cos x\).
- Use the Pythagorean identity to obtain \(1-2\sin^2 x\) as a form of \(\cos(2x)\).
- For which values of \(x\) is the expression \(\frac{2\tan x}{1-\tan^2 x}\) defined?
- Given \(\sin x=3/5\) and \(\cos x=4/5\), calculate \(\sin(2x)\) and \(\cos(2x)\).
- Explain why the tangent identity cannot be evaluated at \(x=\pi/4\), even though \(\tan(\pi/4)\) exists.