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Probability foundations · Tutorial 225 of 1000

Equally Likely Outcomes and Counting Probability

Use a standard deck’s 52 equally likely cards to count favorable outcomes and calculate probabilities for specific events.

Beginner 8 min read

What You'll Learn

  • Identify the individual cards that make up the sample space for one draw from a standard deck.
  • Use favorable outcomes divided by total outcomes when all outcomes are equally likely.
  • Count cards by suit, rank, color, and face-card category.
  • Avoid counting a card twice when an event includes overlapping categories.
  • Express a card-drawing probability as a fraction, decimal, or percentage.

From Equally Likely Outcomes to Probability

In Sample Spaces and Outcomes, we learned to describe a chance process by listing its possible outcomes. In Events as Subsets of the Sample Space, we learned that an event consists of outcomes that meet a stated condition. Now we can calculate probabilities for a particularly useful kind of chance model: one in which every individual outcome is equally likely.

Consider drawing one card from a well-shuffled standard deck. The deck has 52 cards: 13 ranks in each of four suits. Unless stated otherwise, it has no jokers. If the deck is well shuffled and one card is drawn, each of those 52 individual cards has the same probability of being selected. A probability can therefore be found by counting how many individual cards satisfy the event and comparing that count with 52.

Formula: When the outcomes in a finite sample space are equally likely, the probability of an event is the number of favorable outcomes divided by the total number of outcomes in the sample space.
$$ P(\text{event})=\frac{\text{number of favorable outcomes}}{\text{total number of equally likely outcomes}} $$

A favorable outcome is an outcome in the event being considered. “Favorable” does not mean that the outcome is good or desirable; it means only that it meets the event’s definition. For a one-card draw, the individual cards are the outcomes. If the event is “draw a heart,” each heart is one favorable outcome.

The denominator comes from the entire sample space for the chance process—not just the cards that might seem relevant to the event. For one draw from a standard deck, there are 52 possible individual-card outcomes, so the denominator is 52. The numerator counts how many of those 52 cards belong to the event.

Important: Use favorable outcomes divided by total outcomes only when all outcomes in the sample space are equally likely. For one card drawn at random from a well-shuffled standard deck, the 52 individual cards are equally likely. Categories such as “red” and “black” are not the individual outcomes; each category contains many individual cards.

Count the Individual Cards

It helps to know how the 52 cards are organized. There are four suits—hearts, diamonds, clubs, and spades—with 13 cards in each suit. Hearts and diamonds are red; clubs and spades are black. The ranks are ace, 2 through 10, jack, queen, and king. In this tutorial, a face card means a jack, queen, or king. An ace is not a face card under this definition.

Card categoryNumber of cards
Each suit13
Red cards (hearts and diamonds)26
Black cards (clubs and spades)26
Each rank (for example, all queens)4
Face cards (jacks, queens, and kings)12

These counts are shortcuts for organizing the outcomes, but they do not change what is being counted: individual cards. For example, “a queen” is an event containing four cards, one queen in each suit. The event’s probability is \(4/52\), not \(1/13\) because “queen” is one rank label among 13. Both calculations happen to agree after simplifying: \(4/52=1/13\). The favorable-over-total count makes clear why the probability is correct.

A probability may be left as a fraction or written as a decimal or percentage, as appropriate. Simplifying a fraction does not change its value. A decimal or percentage is often rounded, so indicate that rounding when the number is not exact.

Worked Example: Drawing a Heart

A card is drawn at random from a well-shuffled standard deck. What is the probability that it is a heart?

The sample space consists of all 52 individual cards, so there are 52 equally likely outcomes. The event is “the card is a heart.” There are 13 hearts, one for each rank, so there are 13 favorable outcomes.

$$ P(\text{heart})=\frac{13}{52}=\frac{1}{4}=0.25=25\% $$

The probability of drawing a heart is \(1/4\), or 25%. In the long-run relative-frequency sense described in Interpreting Probability as Long-Run Relative Frequency, if this same one-card draw from a freshly shuffled standard deck were repeated many times under comparable conditions, about 25% of the draws would be hearts. This interpretation does not mean that every set of four draws must contain exactly one heart.

Use the Event to Decide What Counts

The wording of an event determines which cards count as favorable. “A king” means any of the four kings. “A black king” means only the king of clubs and the king of spades. A card that does not meet the event’s condition is not favorable, even if it shares one feature with cards that do.

It can be useful to write down the event in ordinary language before counting. Then identify the relevant cards by suit, rank, color, or a combination of those characteristics. This prevents a common counting error: using a correct-looking count for the wrong event.

Worked Example: Drawing a Black Face Card

A card is drawn at random from a well-shuffled standard deck. Find the probability of drawing a black face card. Use “face card” to mean jack, queen, or king.

There are 52 equally likely individual cards in the sample space. The black suits are clubs and spades. Each black suit contains three face cards: jack, queen, and king. Thus there are \(2 \times 3=6\) favorable cards: the jack, queen, and king of clubs, and the jack, queen, and king of spades.

$$ P(\text{black face card})=\frac{6}{52}=\frac{3}{26}\approx 0.1154\approx 11.54\% $$

The probability is \(3/26\), or approximately 0.1154 (11.54%), rounded to four decimal places as a decimal. We count six favorable cards, not 12: there are 12 face cards in the whole deck, but only the six in the two black suits satisfy the event.

When Event Categories Overlap

Some events can be described using the word “or,” as in “a red card or a queen.” A card can meet both parts of that description. The queen of hearts and queen of diamonds are both red cards and queens. If we count all 26 red cards and then add all four queens, those two cards have been counted twice.

When two event categories overlap, count each individual outcome only once in the event. One practical method is to count the outcomes that meet the first condition, then add only the outcomes that meet the second condition but were not already included. Another is to count the individual cards in the combined event directly. Both methods avoid double-counting.

Worked Example: Drawing a Red Card or a Queen

A card is drawn at random from a well-shuffled standard deck. Find the probability that the card is red or is a queen. Here, “or” includes a card that satisfies both conditions.

There are 26 red cards and four queens. Two queens—the queen of hearts and the queen of diamonds—are already among the 26 red cards. To count the combined event without counting those two cards twice, add the two black queens to the red cards. This gives \(26+2=28\) favorable cards.

$$ P(\text{red or queen})=\frac{26+4-2}{52}=\frac{28}{52}=\frac{7}{13}\approx 0.5385 $$

The probability is \(7/13\), or approximately 0.5385 (53.85%), rounded to four decimal places as a decimal. Subtracting the two overlapping cards is essential: \(26+4=30\) counts each red queen twice, even though each card is only one outcome in the sample space.

A Reliable Counting Routine

For a card-drawing question with equally likely outcomes, use a short routine to keep the event, sample space, and calculation connected. This is a counting method, not a new chance process: the sample space is still the set of individual cards that could be drawn.

1
Define the event.
State exactly what the drawn card must be. Pay attention to words such as “and,” “or,” “not,” and “exactly.”
2
Count the total outcomes.
For one draw from a standard deck, count all 52 individual cards in the sample space.
3
Count the favorable outcomes.
Use suits and ranks to identify the cards that meet the event. If categories overlap, count each card once.
4
Calculate and interpret.
Divide the favorable count by the total count, simplify if useful, and state what the probability means for the event.

This routine also offers a quick check: the favorable count cannot be greater than the total count. The resulting probability should be between 0 and 1, as described in Probability Is a Number Between 0 and 1. If a count or probability falls outside those limits, revisit the event definition and the counting.

Common Mistakes and AP Exam Tips

  • Using the number of categories as the denominator. There are four suits, but a one-card draw has 52 individual outcomes. Use 52 as the denominator for a single draw from a standard deck.
  • Counting the wrong event. There are 12 face cards in all, but only six black face cards. Match the favorable count to every condition in the event.
  • Double-counting overlap. In “red or queen,” the two red queens meet both conditions. Count each card once; do not treat overlapping descriptions as separate card outcomes.
  • Confusing an exact fraction with a rounded decimal. The probability \(7/13\) is exact, while 0.5385 is a rounded decimal approximation. Keep the exact fraction when it communicates the answer clearly.
  • Assuming the counting formula always applies. Favorable outcomes divided by total outcomes works in this form because the 52 individual cards are equally likely under the stated well-shuffled-deck model. If outcomes are not equally likely, a simple count ratio may not give the probability.
  • Giving a number without naming the event. A complete answer identifies what the probability is about—for example, “The probability of drawing a black face card is \(3/26\).”

On an AP response, show the count as well as the ratio. Writing “six black face cards out of 52 cards” makes the sample space and the favorable outcomes visible, so a reader can check how the probability was obtained. Then give the probability in context and label any rounded decimal as approximate.

Key takeaway: For one card drawn at random from a well-shuffled standard deck, the 52 individual cards are equally likely outcomes. Count the cards that satisfy the event, divide that favorable count by 52, and count any overlapping card only once.

Check Your Understanding

For each question, assume one card is drawn at random from a well-shuffled standard deck with no jokers. Show the favorable count and total count.

  1. What is the probability of drawing a diamond? Give an exact fraction and a percentage.
  2. What is the probability of drawing an ace? Give an exact fraction and a decimal rounded to four places.
  3. What is the probability of drawing a red king? How many favorable cards are there?
  4. What is the probability of drawing a heart or an ace? Identify the card that satisfies both conditions and make sure it is counted only once.
  5. Explain why the denominator is 52 for a one-card draw, rather than 4 suits or 13 ranks.