What Makes a Game Fair?
In Expected Value in Games and Raffles, you calculated the expected net gain for a ticket with a known price. Now we can work backward: given the possible prizes and their probabilities, what ticket price would make the expected net gain zero?
In this tutorial, a game is fair to the player when the player's expected net gain is zero. This is a mathematical definition based on the probability model. It does not mean that the player is guaranteed to break even on a particular play, that the chance of winning equals the chance of losing, or that every possible outcome is equally favorable.
The expected value formula from The Mean of a Discrete Random Variable gives \(\mu_X=\sum xP(X=x)\). As in Expected Value in Games and Raffles, the cost \(c\) is subtracted from each prize outcome. Since the same cost is paid for every outcome, the expected net gain can also be found by subtracting \(c\) once from the expected prize value.
To make the game fair, set \(\mu_X=0\). The price that solves the equation is called the break-even price: it is the ticket price at which the player's expected net gain is zero.
The no-prize outcome must be included in the distribution, with prize value \(G=0\). Its contribution to expected prize value is \(0P(G=0)=0\), but including it helps confirm that every possible outcome is accounted for and that the probabilities sum to 1. The ticket cost still affects the net gain on a no-prize play: it is \(-c\).
A Method for Finding and Using the Break-Even Price
First find the expected prize value using all possible prizes and their probabilities. That amount is the break-even price. Then compare the game's actual price with the break-even price, or subtract the actual price from the expected prize value to find the player's expected net gain directly.
Let \(G\) be the prize value on one play. List every possible prize, including zero for no prize.
Multiply each prize value by its probability and add the products: \(E(G)=\sum gP(G=g)\).
The ticket price equal to \(E(G)\) makes the player's expected net gain zero.
Calculate \(E(G)-c\). A positive result favors the player in expected value, a negative result favors the game's organizer, and zero means fair to the player.
Before interpreting the result, check that the outcomes form a complete probability distribution: the probabilities are between 0 and 1 and add to 1, as described in Checking Whether a Probability Distribution Is Valid. The calculation also assumes the listed prize values represent what the player receives and that the same price is paid on every play. If there are additional fees or costs, include them when defining net gain.
Worked Example: Find the Fair Price for a Token Game
Worked Example: Find the Fair Price for a Token Game
An invented arcade game awards a $40 prize on 2 of 20 equally likely tokens, an $8 prize on 5 tokens, and no prize on the remaining tokens. Find the break-even price. Then decide whether a $7 play is fair to the player.
Define the outcomes and probabilities. Let \(G\) be the prize value on one play. The no-prize outcome has \(20-2-5=13\) tokens. Therefore, the probabilities of prizes $40, $8, and $0 are \(2/20=0.10\), \(5/20=0.25\), and \(13/20=0.65\). They add to \(0.10+0.25+0.65=1.00\).
Calculate expected prize value. Weight each prize by its probability and add:
The break-even price is therefore $6.00 per play. At that price, the expected net gain is \(E(G)-c=\$6.00-\$6.00=\$0.00\), so the game is fair to the player according to this probability model.
Assess the $7 price. At $7, the player's expected net gain is \(E(G)-c=\$6.00-\$7.00=-\$1.00\) per play. As a check, the possible net gains at that price are $33 for a $40 prize, $1 for an $8 prize, and \(-\$7\) for no prize. Their weighted average is \(33(0.10)+1(0.25)+(-7)(0.65)=3.30+0.25-4.55=-\$1.00\).
Conclude in context. A $7 play is not fair to the player under this model: the player's expected net gain is \(-\$1.00\) per play. If the plays are independent repetitions of the same game, the average net gain over many plays would tend toward a loss of about $1 per play. This is a long-run average, not a prediction that every player loses exactly $1.
Worked Example: Use a Four-Step Solution
Worked Example: Use a Four-Step Solution
An invented prize wheel gives a $20 prize with probability 0.15, an $8 prize with probability 0.25, and no prize with probability 0.60. A player pays $4 to spin. Is the game fair to the player?
State. Let \(G\) be the prize value on one spin and \(X=G-4\) be the player's net gain. We want to determine whether \(\mu_X=0\), the definition of a fair game for the player.
Plan. Find \(E(G)\) by multiplying each prize value by its probability and adding. The probabilities are all between 0 and 1, and \(0.15+0.25+0.60=1.00\), so they describe all possible prize outcomes. The fixed $4 cost is paid on every spin, so \(\mu_X=E(G)-4\).
Do. The expected prize value is:
The expected net gain is \(\mu_X=\$5.00-\$4.00=\$1.00\) per spin. To check, the net gains are $16, $4, and \(-\$4\), giving \(16(0.15)+4(0.25)+(-4)(0.60)=2.40+1.00-2.40=\$1.00\).
Conclude. The game is not fair to the player at a $4 price because the expected net gain is positive, \(\$1.00\) per spin. The break-even price is $5.00, the expected prize value. At that price the expected net gain would be zero; at the stated price, the player has a positive expected value.
Worked Example: A Break-Even Price Need Not Be a Possible Prize
Worked Example: A Break-Even Price Need Not Be a Possible Prize
An invented school event offers a game with 100 equally likely numbered cards. One card awards $60, nine cards award $4 each, and the other 90 cards award nothing. Find the fair price and assess a 75-cent ticket.
Find the probabilities. The probabilities of prizes $60, $4, and $0 are \(1/100=0.01\), \(9/100=0.09\), and \(90/100=0.90\). These add to \(1.00\).
Find the break-even price. The expected prize value is:
Thus, 96 cents is the break-even price. It is not one of the possible prizes; that is not a problem. The break-even price is an average of the possible prize values weighted by their probabilities, so it does not have to match any single outcome.
Assess the 75-cent price. The player's expected net gain is \(\$0.96-\$0.75=\$0.21\) per play. Directly, the net gains are $59.25, $3.25, and \(-\$0.75\). The weighted calculation confirms the result: \(59.25(0.01)+3.25(0.09)+(-0.75)(0.90)=0.5925+0.2925-0.6750=\$0.2100\).
At a 75-cent price, the game is not fair to the player under the model because the expected net gain is positive. The positive expected value does not guarantee that a particular player will receive a prize: the no-prize outcome still has probability 0.90.
What “Fair” Does and Does Not Mean
A fair game has expected net gain zero, not necessarily equal probabilities of winning and losing. For example, a player might have a small chance of a large prize and a large chance of losing the ticket cost. The expected prize value balances those outcomes at the break-even price even though the outcomes are not equally likely and do not pay equal amounts.
Fairness here refers only to expected value from the player's perspective. It does not describe whether the rules are understandable, whether the game is enjoyable, or whether the organizer has other expenses. If the organizer receives the ticket price and pays only the listed prize, the organizer's net gain is the opposite of the player's net gain. Other operating costs or benefits are not included unless they are explicitly added to the model.
A price below break-even gives the player positive expected net gain, while a price above break-even gives the player negative expected net gain. Neither comparison tells you the outcome of one play. As discussed in Interpreting Expected Value as a Long-Run Average, expected value describes a probability-weighted center and a long-run average, not a guaranteed result.
Common Mistakes and AP Exam Tips
- Calling the most likely outcome the fair price. The break-even price comes from \(E(G)=\sum gP(G=g)\), not from choosing the prize with the greatest probability or the most common prize.
- Subtracting the ticket cost more than once. Either calculate expected net gain directly from \(G-c\) for each outcome, or find \(E(G)-c\). Do not subtract the cost from each outcome and then subtract it again from the weighted result.
- Leaving out the no-prize outcome. Its prize value is zero, but it is still a possible outcome and its probability belongs in the complete distribution. In a direct net-gain calculation, its net gain is \(-c\), not zero.
- Assuming “fair” means the player wins half the time. Fairness in this context means expected net gain equals zero. A game can meet that definition even if most plays lose, provided the prize amounts and probabilities balance at the break-even price.
- Interpreting expected net gain as a guaranteed result. A full-credit explanation identifies the long-run average and keeps it separate from one play. For instance: “The expected net gain is $1.00 per spin, so if the spins are independent repetitions of the same game, the average net gain over many spins tends toward $1.00 per spin; one spin may still produce a loss.”
- Giving a price without comparing it to the actual price. State the break-even price, calculate or describe \(E(G)-c\) at the stated price, and decide whether the game is fair to the player. Include dollars per play in the interpretation.
A useful final check is to calculate the expected net gain in two ways when the price is known: use expected prize value minus price, and use the probability-weighted average of the net gains. Matching results help catch arithmetic or setup errors.
Key Takeaway
The break-even price links a game's prize distribution to fairness for the player. It is the expected prize value; comparing the actual price with that value tells whether the player's expected net gain is positive, zero, or negative.
Check Your Understanding
An invented game has a 0.20 chance of awarding $12, a 0.30 chance of awarding $4, and a 0.50 chance of awarding no prize.
- Check that the three probabilities form a valid distribution.
- Calculate the expected prize value and state the break-even price.
- If the game costs $3 to play, calculate the player's expected net gain and decide whether the game is fair to the player.
- Show how to check your expected net gain by weighting the possible net gains by their probabilities.
- Explain why a fair price does not mean a player is guaranteed to break even on one play.