Tutorials › Calculus I › Geometric Measurement With Differentials

Linearization and Differentials · Tutorial 633 of 1495

Geometric Measurement With Differentials

Learn how a radius uncertainty affects circumference and area, and why their absolute error estimates have different scales.

Intermediate 9 min read

What You'll Learn

  • Find circumference and area differentials from their radius formulas.
  • Use a radius uncertainty to estimate uncertainty in each measurement.
  • Explain why circumference’s absolute error is independent of the radius.
  • Explain why area’s absolute error estimate grows with the radius.
  • Compare differential estimates with exact changes in area.
  • Distinguish absolute output uncertainty from relative uncertainty.

One Radius, Two Different Measurement Effects

A small uncertainty in a circle’s radius affects both its circumference and its area. But the resulting absolute uncertainties do not have the same scale: the circumference estimate depends on the radius uncertainty alone, while the area estimate also depends on the circle’s radius.

Differentials make this comparison direct. They describe the first-order change in an output produced by a small change in an input. For circumference, that first-order estimate is exact. For area, it is a local estimate: the exact change also contains a second-order term.

Circle Measurements and Their Differentials

Let \(r>0\) be a circle’s radius. Its circumference \(C\) and area \(A\), as functions of the radius, are

$$ C(r)=2\pi r, \qquad A(r)=\pi r^2. $$

Suppose the measured radius is \(r_0\), and its actual value differs by \(\Delta r\). Thus the actual radius is \(r_0+\Delta r\). The differential uses a small input change \(dr\); when estimating the effect of the radius uncertainty, we set \(dr=\Delta r\).

Definition: If \(y=f(r)\) is differentiable, its differential at \(r_0\) is \(dy=f'(r_0)\,dr\). It is the first-order estimate of the output change caused by an input change \(dr\). A differential estimate need not equal the exact output change.

Differentiate each circle formula with respect to \(r\). The resulting differentials are

$$ dC=2\pi\,dr, \qquad dA=2\pi r\,dr. $$

For an uncertainty estimate based at the measured radius \(r_0\), use that base point in the area differential:

$$ dC=2\pi\,dr, \qquad dA=2\pi r_0\,dr. $$

The units provide a useful check. If \(r\) and \(dr\) are measured in centimetres, then \(dC\) is in centimetres, while \(dA\) is in square centimetres. The circumference estimate depends on the size of \(dr\), but not on \(r_0\). The area estimate depends on both.

Why the Two Estimates Differ

The distinction follows directly by comparing the differentials with the exact changes. If the radius changes from \(r_0\) to \(r_0+\Delta r\), the exact circumference change is

$$ \begin{aligned} \Delta C &=C(r_0+\Delta r)-C(r_0)\\ &=2\pi(r_0+\Delta r)-2\pi r_0\\ &=2\pi\Delta r. \end{aligned} $$

With \(dr=\Delta r\), this is exactly \(dC\), not merely an approximation. This happens because \(C(r)\) is a linear function of \(r\).

For area, expand the square to find the exact change:

$$ \begin{aligned} \Delta A &=A(r_0+\Delta r)-A(r_0)\\ &=\pi(r_0+\Delta r)^2-\pi r_0^2\\ &=\pi\bigl(r_0^2+2r_0\Delta r+(\Delta r)^2\bigr)-\pi r_0^2\\ &=2\pi r_0\Delta r+\pi(\Delta r)^2. \end{aligned} $$

The differential \(dA=2\pi r_0\Delta r\) is the first term. The remaining term, \(\pi(\Delta r)^2\), is second order in the radius change. It is positive for every nonzero \(\Delta r\), whether the radius increases or decreases. This explains why the differential gives a useful estimate for small changes but is not generally the exact area change.

Theorem: For a radius change \(\Delta r\), the circumference change is exactly \(\Delta C=2\pi\Delta r\). The area change is exactly \(\Delta A=2\pi r_0\Delta r+\pi(\Delta r)^2\), so its differential estimate omits the second-order term.

Worked Examples

Worked Example: Estimating Circumference and Area Uncertainty

A circle’s measured radius is \(10.0\text{ cm}\), with an absolute uncertainty of \(0.1\text{ cm}\). Estimate the resulting uncertainty in its circumference and area using differentials.

Here \(r_0=10.0\text{ cm}\) and the uncertainty magnitude is \(\delta=0.1\text{ cm}\). For the upper estimates, set \(dr=\delta\). The circumference estimate is

$$ dC=2\pi(0.1\text{ cm})=0.2\pi\text{ cm}\approx 0.6283\text{ cm}. $$

The area estimate is

$$ dA=2\pi(10.0\text{ cm})(0.1\text{ cm}) =2\pi\text{ cm}^2 \approx 6.283\text{ cm}^2. $$

These are differential estimates. To check them, consider the exact changes for a radius increase of \(0.1\text{ cm}\). The circumference change is \(2\pi(0.1\text{ cm})=0.2\pi\text{ cm}\), exactly the differential. The exact area change is

$$ \begin{aligned} \Delta A &=2\pi(10.0\text{ cm})(0.1\text{ cm}) +\pi(0.1\text{ cm})^2\\ &=2.01\pi\text{ cm}^2 \approx 6.315\text{ cm}^2. \end{aligned} $$

For a decrease of \(0.1\text{ cm}\), the exact area change is \(-1.99\pi\text{ cm}^2\), whereas the differential predicts \(-2\pi\text{ cm}^2\). Thus the area estimate is close, but the exact upward and downward changes are not perfectly symmetric. The exact circumference change still equals its differential in either direction.

Worked Example: A Larger Radius with the Same Radius Uncertainty

Compare two circles with measured radii \(3\text{ m}\) and \(15\text{ m}\). Each radius has uncertainty \(0.05\text{ m}\). Find the differential estimates of absolute circumference and area uncertainty.

For both circles, \(dr=0.05\text{ m}\). Therefore the circumference estimates are identical:

$$ dC=2\pi(0.05\text{ m})=0.1\pi\text{ m} \approx 0.3142\text{ m}. $$

For the circle of radius \(3\text{ m}\), the area estimate is

$$ dA=2\pi(3\text{ m})(0.05\text{ m}) =0.3\pi\text{ m}^2 \approx 0.9425\text{ m}^2. $$

For the circle of radius \(15\text{ m}\), it is

$$ dA=2\pi(15\text{ m})(0.05\text{ m}) =1.5\pi\text{ m}^2 \approx 4.712\text{ m}^2. $$

The radius uncertainty is the same in both cases, so the estimated absolute circumference uncertainty is the same. The larger circle’s area estimate is five times the smaller circle’s: \(1.5\pi/(0.3\pi)=5\). For a check, the exact circumference change in either case is \(0.1\pi\text{ m}\). The exact area change for a radius increase is the differential plus \(\pi(0.05\text{ m})^2=0.0025\pi\text{ m}^2\), as the area-change formula requires.

Worked Example: Exact Uncertainty Bounds for Area

A circle has measured radius \(4\text{ cm}\), with radius uncertainty at most \(0.02\text{ cm}\). Find the differential estimates, then compare them with the exact area bounds.

The circumference uncertainty is exactly

$$ 2\pi(0.02\text{ cm})=0.04\pi\text{ cm} \approx 0.1257\text{ cm}. $$

The differential estimate for the magnitude of the area change is

$$ 2\pi(4\text{ cm})(0.02\text{ cm}) =0.16\pi\text{ cm}^2 \approx 0.5027\text{ cm}^2. $$

Since \(0.02<4\), the possible radii remain positive. The smallest and largest possible radii are \(3.98\text{ cm}\) and \(4.02\text{ cm}\). The exact area changes at these endpoints are

$$ \begin{aligned} A(4.02)-A(4) &=\pi(4.02^2-4^2)\text{ cm}^2\\ &=\pi(16.1604-16)\text{ cm}^2\\ &=0.1604\pi\text{ cm}^2, \end{aligned} $$

and

$$ \begin{aligned} A(3.98)-A(4) &=\pi(3.98^2-4^2)\text{ cm}^2\\ &=\pi(15.8404-16)\text{ cm}^2\\ &=-0.1596\pi\text{ cm}^2. \end{aligned} $$

The positive change exceeds the differential estimate \(0.16\pi\text{ cm}^2\) by \(0.0004\pi\text{ cm}^2\); the magnitude of the negative change is smaller by the same amount. These differences equal \(\pi(0.02)^2\text{ cm}^2\), confirming the exact remainder formula.

Absolute and Relative Uncertainty

Absolute uncertainty is expressed in the output’s units. The differential estimates show that for a radius uncertainty of magnitude \(\delta\), the circumference uncertainty is \(2\pi\delta\), while the area uncertainty is approximately \(2\pi r_0\delta\). Thus a fixed absolute uncertainty in radius gives a fixed absolute circumference uncertainty, but a larger estimated absolute area uncertainty for a larger circle.

Relative uncertainty compares an output change with the output itself. Dividing the differentials by the corresponding measurements gives, for small changes,

$$ \frac{dC}{C}=\frac{dr}{r}, \qquad \frac{dA}{A}=2\frac{dr}{r}. $$

So the estimated relative circumference change matches the relative radius change, while the estimated relative area change is twice the relative radius change. These are relative first-order estimates; the area’s exact change still includes the second-order term. Absolute and relative uncertainty answer different questions, so they should not be interchanged.

A Common Mistake: Squaring the Radius Uncertainty

A frequent error is to treat the area formula as though its differential were obtained by simply replacing \(r\) with \(dr\). For a circle with \(r_0=5\text{ cm}\) and \(dr=0.1\text{ cm}\), that incorrect calculation gives

$$ \text{Incorrect:}\qquad dA=\pi(0.1\text{ cm})^2=0.01\pi\text{ cm}^2. $$

This is not the differential. Differentiate \(A(r)=\pi r^2\) first: \(A'(r)=2\pi r\). Then evaluate at the measured radius and multiply by the input change:

$$ \text{Correct:}\qquad dA=2\pi(5\text{ cm})(0.1\text{ cm}) =\pi\text{ cm}^2. $$

The exact increase for this radius change is \(\pi(5.1^2-5^2)\text{ cm}^2=1.01\pi\text{ cm}^2\), which is close to the differential estimate \(\pi\text{ cm}^2\). The incorrect value \(0.01\pi\text{ cm}^2\) misses the first-order effect. The correction is to differentiate the measurement formula, then evaluate its derivative at the base radius.

Using the Estimates Responsibly

Differentials are especially useful when the radius uncertainty is small compared with the radius itself. In that setting, \((\Delta r)^2\) is small relative to the first-order term \(2r_0\Delta r\), so the area differential is a good estimate. When an exact bound is needed, use the endpoint radii \(r_0-\delta\) and \(r_0+\delta\) in the area formula, provided \(\delta<r_0\). The resulting area uncertainty is generally asymmetric around the measured area.

For circumference, no such approximation is needed: its exact change is already given by the differential. For area, the differential captures the leading effect and makes the dependence on the measured radius visible. These different scales matter whenever a geometric measurement is reported from an uncertain radius.

Check Your Understanding

Use the differential formulas and the exact change formulas where appropriate.

  1. For a measured radius of \(8\text{ cm}\) with uncertainty \(0.03\text{ cm}\), what are the differential estimates for circumference and area uncertainty?
  2. Why is the circumference change exactly equal to its differential for any radius change?
  3. For area, what term is omitted by the differential estimate of the exact change?
  4. If two circles have the same radius uncertainty but different measured radii, which absolute uncertainty estimate changes with the radius?
  5. How do the first-order relative changes in area and circumference compare with the relative change in radius?

Test yourself: Calculus I final exam practice

Ready to check what you know? Work a full-length practice final, then open the complete worked solutions.

Want all 1,114 practice problems?

This tutorial covers one topic. Calc Pass covers the full Calculus AB & BC curriculum (the core of Calculus I and II): full review, every practice question, and step-by-step solutions to each one.

QR code to download the Calc Pass app

Get the Calc Pass App

Scan to download and practice on the go, with instant scoring.

Calc Pass Volume 1: 1,114 Practice Questions book cover

Vol. 1: 1,114 Questions

The complete practice question bank, organized by AB & BC topic.

View on Amazon
Calc Pass Volume 2: Solutions Manual book cover

Vol. 2: Solutions Manual

Fully worked solutions to every question in Volume 1.

View on Amazon