From One Distribution to an Infinite Sequence
To construct an independent, identically distributed sequence, it is not enough to prescribe the distribution of each coordinate separately: those one-coordinate distributions do not determine how the coordinates depend on one another. The product measure supplies the required joint laws. Its coordinate maps then form an IID sequence, with every finite collection of coordinates having the corresponding finite product distribution.
Let \((S,\mathcal{B})\) be a standard Borel space, meaning a measurable space measurably isomorphic to a Borel subset of a complete separable metric space. Let \(\nu\) be a probability measure on \((S,\mathcal{B})\). The countable product \(S^{\mathbb{N}}\) is equipped with the product sigma-algebra \(\mathcal{B}^{\otimes\mathbb{N}}=\sigma(\pi_n^{-1}(A): n\in\mathbb{N},\,A\in\mathcal{B})\), where \(\pi_n(\omega)=\omega_n\) is the \(n\)th coordinate map. The probability space constructed below is finite, hence sigma-finite; it need not be complete.
The events in this definition are cylinder events: they restrict only finitely many coordinates. The construction uses the Kolmogorov Extension Theorem, established earlier in the course. In the form needed here, it says that a consistent family of finite-dimensional probability distributions on standard Borel coordinate spaces determines a unique probability measure on the product sigma-algebra. We check consistency before applying it.
Constructing the Product Probability Space
For each \(k\ge1\), give the first \(k\) coordinates the finite product probability measure \(\nu^{\otimes k}\) on \((S^k,\mathcal{B}^{\otimes k})\). Its value on a measurable rectangle is
These distributions are consistent under projection. Indeed, for \(m<k\), the projection of \(\nu^{\otimes k}\) onto the first \(m\) coordinates assigns the rectangle \(A_1\times\cdots\times A_m\) the value \(\prod_{j=1}^m\nu(A_j)\): the omitted coordinates contribute \(\nu(S)=1\). This is exactly \(\nu^{\otimes m}(A_1\times\cdots\times A_m)\). Since probability measures agreeing on measurable rectangles agree on the product sigma-algebra, the projected measure is \(\nu^{\otimes m}\).
Proof. The preceding consistency check verifies the hypothesis of the Kolmogorov Extension Theorem for the finite-dimensional distributions \(\nu^{\otimes k}\). The coordinate spaces are standard Borel, so that theorem gives a unique probability measure \(\mathbb{P}\) on \((S^{\mathbb{N}},\mathcal{B}^{\otimes\mathbb{N}})\) with the specified finite-dimensional distributions. The existence and uniqueness assertion is precisely the application of that standard theorem; its proof is not repeated here.
For each \(n\), \(X_n=\pi_n\) is measurable: for \(A\in\mathcal{B}\), \(X_n^{-1}(A)=\pi_n^{-1}(A)\) belongs to the product sigma-algebra by its definition. The one-coordinate distribution is \(\mathbb{P}(X_n\in A)=\nu(A)\), since the one-coordinate marginal is \(\nu^{\otimes1}=\nu\).
Now take distinct indices \(i_1,\dots,i_k\). The joint map \(\omega\mapsto(X_{i_1}(\omega),\dots,X_{i_k}(\omega))\) is measurable. Its distribution on a rectangle \(A_1\times\cdots\times A_k\) is \(\prod_{j=1}^k\nu(A_j)\): this follows from the specified finite-dimensional distribution on the coordinates up to \(\max_j i_j\), by projecting away the unused coordinates. Rectangles determine the probability measure on \(\mathcal{B}^{\otimes k}\), so this joint distribution is \(\nu^{\otimes k}\). In particular, the probability of the cylinder event is \(\prod_{j=1}^k\nu(A_j)\), proving independence for every finite selection of distinct coordinates. Together with the common marginal \(\nu\), this proves that the sequence is IID. \(\square\)
Worked Constructions and Probability Checks
Worked Example: A Bernoulli Sequence
Take \(S=\{0,1\}\) with \(\mathcal{B}\) its power set, and let \(\nu(\{1\})=2/5\), \(\nu(\{0\})=3/5\). On \(\Omega=\{0,1\}^{\mathbb{N}}\), the product probability gives an IID Bernoulli sequence \(X_n(\omega)=\omega_n\). Find the probability of \(X_1=1,\ X_2=0,\ X_3=1,\ X_4=1,\ X_5=0\).
The five specified coordinate sets are respectively \(\{1\},\{0\},\{1\},\{1\},\{0\}\). Their probabilities under \(\nu\) are \(2/5,3/5,2/5,2/5,3/5\). The cylinder formula therefore gives
Check: multiplying the three success factors gives \(2^3/5^3=8/125\), and the two failure factors give \(3^2/5^2=9/25\). Their product is \(8\cdot9/(125\cdot25)=72/3125\), as above.
Worked Example: Uniform Random Variables on the Unit Interval
Let \(S=[0,1]\), let \(\mathcal{B}\) be its Borel sigma-algebra, and let \(\nu\) be the restriction of Lebesgue measure to \([0,1]\). The construction gives IID \([0,1]\)-valued coordinates. Compute the probability of \(X_1\in[0,1/4]\), \(X_2\in(1/2,1]\), and \(X_4\in[0,1/3]\), with no restriction on \(X_3\) or any other coordinate.
The three sets are Borel. Their Lebesgue measures are \(1/4\), \(1-1/2=1/2\), and \(1/3\), respectively. The unrestricted coordinates contribute probability \(1\), so the cylinder probability is
Check: the finite-dimensional law of \((X_1,X_2,X_4)\) is \(\nu^{\otimes3}\). The rectangle has product measure \((1/4)(1/2)(1/3)=1/24\), the same value. The endpoint conventions are included in the specified sets; changing any one endpoint would not change these probabilities because a singleton has Lebesgue measure zero.
Worked Example: Identical Marginals Do Not Guarantee Independence
On \(\Omega=\{0,1\}^{\mathbb{N}}\), define \(\mathbb{P}\) to put mass \(1/2\) on the all-zero sequence and mass \(1/2\) on the all-one sequence. This is a probability measure on the product sigma-algebra. Each coordinate has Bernoulli distribution with parameter \(1/2\): for every \(n\), \(\mathbb{P}(X_n=1)=1/2\) and \(\mathbb{P}(X_n=0)=1/2\). Test whether \(X_1\) and \(X_2\) are independent.
The event \(\{X_1=1,X_2=0\}\) contains neither sequence in the support, so its probability is \(0\). If the two coordinates were independent, that probability would be \(\mathbb{P}(X_1=1)\mathbb{P}(X_2=0)=(1/2)(1/2)=1/4\). Since \(0\ne1/4\), they are not independent, despite having identical marginal distributions.
Check: the event \(\{X_1=X_2\}\) has probability \(1\) under this measure, while for two independent Bernoulli variables with parameter \(1/2\) its probability would be \((1/2)(1/2)+(1/2)(1/2)=1/2\). Thus the dependence is visible in a second cylinder event as well.
What the Product Construction Gives—and What It Does Not
The construction gives more than a formula for a single pattern. For any finite set of distinct indices and any Borel restrictions on those coordinates, the joint probability is determined by the product of their individual probabilities. This verifies the IID property directly at the level of cylinder events, which generate the product sigma-algebra. It also makes the common law flexible: the coordinate space may be finite or countably infinite, a Borel subset of Euclidean space, or any other standard Borel space.
A common error is to infer independence from identical distributions. The preceding example shows why that inference is invalid: the marginal probabilities alone do not specify joint probabilities. In the product construction, independence is guaranteed by the finite-dimensional product laws, not merely by the fact that every coordinate has law \(\nu\).
Another useful distinction is between a cylinder probability and the probability of an event involving infinitely many coordinates. The defining calculation above applies to finitely many restrictions. Events depending on infinitely many coordinates may also be measurable in the product sigma-algebra, but their probabilities generally require an additional argument; they are not computed by multiplying infinitely many marginal probabilities without justification.
Check Your Understanding
Use the product-space construction and the cylinder formula to answer the following.
- For Bernoulli parameter \(p\in[0,1]\), write the probability of a specified finite pattern containing \(r\) ones and \(k-r\) zeros as a product of one-coordinate probabilities.
- Explain why the finite-dimensional distributions \(\nu^{\otimes k}\) are consistent when one coordinate is projected away.
- For IID uniform coordinates on \([0,1]\), compute the probability that \(X_1\in[0,1/2]\) and \(X_3\in(1/4,1]\).
- Give a reason that the coordinate maps on \(S^{\mathbb{N}}\) are measurable with respect to the product sigma-algebra.
- In the two-point mixture of the all-zero and all-one sequences, calculate \(\mathbb{P}(X_1=1,X_2=1)\) and compare it with the value that independence would require.