Correlated Noise and the Covariance Matrix
In a multidimensional Itô calculation, the second-order terms depend not only on each Brownian coordinate’s quadratic variation but also on the covariations between coordinates. When two Brownian motions are correlated, their product contributes a drift term. The covariance matrix records all these second-order contributions in one place.
Work on a filtered probability space \((\Omega,\mathcal{F},(\mathcal{F}_t)_{t\ge0},\mathbb{P})\). Let \((B^1_t,B^2_t)\) be a two-dimensional Brownian motion with respect to this filtration, with constant correlation \(\rho\in[-1,1]\). This means that the vector has continuous paths, starts at \((0,0)\), and its increments after time \(s\) are independent of \(\mathcal{F}_s\); each increment over \([s,t]\) is a centered Gaussian vector with covariance matrix \((t-s)C\), where
In particular, each coordinate is a Brownian motion relative to the stated filtration. Merely requiring that two Brownian paths be adapted would not suffice: their future increments must be independent of the filtration’s past.
The covariation follows from the covariance of the Brownian increments; equivalently, it is the limit in probability of sums of products of corresponding increments. The same identity remains valid at the degenerate endpoint correlations \(\rho=1\) and \(\rho=-1\). For example, when \(\rho=1\), the difference \(B^1-B^2\) has zero quadratic variation and is identically zero; when \(\rho=-1\), the sum is identically zero.
All stochastic integrals below are Itô integrals. On each finite interval \([0,T]\), an integrand \(H_s\) is required to be progressively measurable and to satisfy \(\mathbb{E}\int_0^T H_s^2\,ds<\infty\), that is, \(H\in\mathcal{L}^2\). Such an integral is a square-integrable martingale: it is integrable by the Itô isometry, and its conditional expectation at a later time, given \(\mathcal{F}_s\), equals its value at time \(s\). If only local square integrability is available, the corresponding integral is in general only a local martingale; it need not be a true martingale.
Multidimensional Itô Formula and the Generator
This is the standard multidimensional Itô formula; its proof from partition sums comes later in the course. The covariance matrix enters through \(a=\sigma C\sigma^\mathsf{T}\), the instantaneous covariance matrix of the diffusion coordinates. In particular, the coefficient of \(f_{x_ix_j}\) cannot be computed by treating correlated Brownian coordinates as independent.
For a time-homogeneous diffusion, the second-order differential operator
is called its generator. It is the drift coefficient in Itô’s formula applied to \(f(X_t)\). This definition concerns the drift term and does not by itself assert that \(f(X_t)\) is a martingale; that also depends on the stochastic integral and the integrability of its integrand.
Products Reveal the Cross-Variation Term
Proof. Apply the multidimensional Itô formula to \(f(x,y)=xy\). Its first derivatives are \(f_x=y\) and \(f_y=x\); its second derivatives are \(f_{xx}=f_{yy}=0\) and \(f_{xy}=f_{yx}=1\). The instantaneous covariance between \(X\) and \(Y\) is \(\alpha_1\beta_1+\alpha_2\beta_2+\rho\alpha_1\beta_2+\rho\alpha_2\beta_1\), by multiplying their Brownian coefficients using \(dB^1dB^2=\rho\,dt\). The second-order term is this covariance times \(f_{xy}=1\), yielding the displayed correction. The first-order terms are \(X\,dY+Y\,dX\). \(\square\)
Worked Example: The Product of Correlated Brownian Motions
Take \(\rho=\tfrac12\), \(X_t=B^1_t\), and \(Y_t=B^2_t\). Compute the product differential and its expectation at time \(T\).
Here \(b_X=b_Y=0\), \((\alpha_1,\alpha_2)=(1,0)\), and \((\beta_1,\beta_2)=(0,1)\). The cross-variation coefficient is \(1\cdot1\cdot\rho=\tfrac12\), so
For finite \(T\), the integrands \(B^1\) and \(B^2\) are in \(\mathcal{L}^2\), since \(\mathbb{E}\int_0^T(B^i_s)^2\,ds=\int_0^T s\,ds=T^2/2\). Each Itô integral is therefore a square-integrable martingale with conditional mean-zero increments. Taking expectations in the integrated identity gives \(\mathbb{E}[B^1_TB^2_T]=T/2\).
Check: the centered Gaussian vector \((B^1_T,B^2_T)\) has covariance \(\rho T=T/2\), so its product expectation is also \(T/2\). This independently confirms the correction term.
A Generator Calculation for a Nonlinear Function
Worked Example: A Quadratic Function of Two Correlated Diffusions
Let \(\rho=-\tfrac12\), \(U_t=1+t+B^1_t\), and \(V_t=-1+2t+B^2_t\). For \(f(u,v)=u^2+uv+2v^2\), calculate \(\mathcal{L}f\) and \(\mathbb{E}[f(U_t,V_t)]\).
The drift vector is \((1,2)\), and the diffusion coefficients of \((U,V)\) against \((B^1,B^2)\) are the identity matrix. Thus \(a=C\), with diagonal entries \(1\) and off-diagonal entries \(-\tfrac12\). The derivatives are \(f_u=2u+v\), \(f_v=u+4v\), \(f_{uu}=2\), \(f_{uv}=f_{vu}=1\), and \(f_{vv}=4\). Consequently,
Itô’s formula therefore gives drift \(4U_t+9V_t+\tfrac52\) and stochastic terms \((2U_t+V_t)dB^1_t+(U_t+4V_t)dB^2_t\). Those integrands are in \(\mathcal{L}^2\) on every finite interval because \(U,V\) are Brownian motions plus deterministic functions and have finite second moments there.
For an independent expectation check, the means are \(m_U=1+t\) and \(m_V=-1+2t\); the variances of \(U_t,V_t\) are both \(t\), and their covariance is \(-t/2\). Hence
To check against the generator, its value at the means is \(4(1+t)+9(-1+2t)+\tfrac52=-\tfrac52+22t\). Its integral from \(0\) to \(t\) is \(-\tfrac52t+11t^2\); adding the initial value \(f(1,-1)=2\) reproduces the expectation above.
Correlated Geometric Diffusions
Worked Example: The Expected Product of Two Exponential Diffusions
Let \(S_0=2\), \(Y_0=3\), and consider \(dS_t=\tfrac14 S_t\,dt+S_t\,dB^1_t\), \(dY_t=-\tfrac14Y_t\,dt+2Y_t\,dB^2_t\), with \(\rho=\tfrac12\). Find \(\mathbb{E}[S_tY_t]\).
First verify the solutions. Applying one-dimensional Itô’s formula to \(2e^{B^1_t-t/4}\), whose time derivative is \(-S_t/4\), first space derivative is \(S_t\), and second space derivative is \(S_t\), gives drift \((-1/4+1/2)S_t=S_t/4\) and diffusion \(S_t\,dB^1_t\). For \(3e^{2B^2_t-9t/4}\), the time derivative is \(-9Y_t/4\), the first space derivative is \(2Y_t\), and the second is \(4Y_t\); the correction is \(2Y_t\,dt\), leaving drift \(-Y_t/4\) and diffusion \(2Y_t\,dB^2_t\). Thus
The product formula gives drift \((\tfrac14-\tfrac14+\rho\cdot1\cdot2)S_tY_t=S_tY_t\). Its stochastic terms are \(S_tY_t\,dB^1_t+2S_tY_t\,dB^2_t\). Their integrands are in \(\mathcal{L}^2\) on finite intervals: for example, \(S_tY_t=6e^{B^1_t+2B^2_t-5t/2}\), and the Gaussian exponential moment gives \(\mathbb{E}[(S_tY_t)^2]=36e^{9t}\), which is integrable on \([0,T]\). The stochastic integrals are therefore true martingales, and taking expectations in the integrated product equation yields \(\mathbb{E}[S_tY_t]=6e^t\).
Check: \(B^1_t+2B^2_t\) is centered Gaussian with variance \(t+4t+4(\tfrac12)t=7t\). The explicit product has expectation \(6e^{-5t/2}e^{(7t)/2}=6e^t\), agreeing with the differential calculation.
Common Pitfall: Dropping the Covariation
A frequent error is to multiply differentials as if distinct Brownian motions always had zero product. In the first worked example, omitting \(dB^1_t\,dB^2_t=\tfrac12dt\) would give \(d(B^1_tB^2_t)=B^1_t\,dB^2_t+B^2_t\,dB^1_t\). Taking expectations would then incorrectly predict \(\mathbb{E}[B^1_TB^2_T]=0\). The correct calculation includes \(+\tfrac12dt\) and gives \(T/2\), in agreement with the covariance of the Gaussian pair.
The same discipline applies to the generator. Write the full covariance matrix \(a=\sigma C\sigma^\mathsf{T}\) before taking second derivatives. In two dimensions the second-order part is \(\tfrac12(a_{11}f_{xx}+2a_{12}f_{xy}+a_{22}f_{yy})\); the factor \(2\) in the mixed term combines with \(\tfrac12\), leaving \(a_{12}f_{xy}\). This is why a correlated pair contributes a mixed derivative even when both individual variances are unchanged.
Check Your Understanding
Use the covariance matrix and the hypotheses for Itô integrals in each answer.
- If \(\rho=-\tfrac13\), what is \(d(B^1_tB^2_t)\), and what is \(\mathbb{E}[B^1_TB^2_T]\)?
- For \(dX_t=b_1dt+\sigma_1dB^1_t\) and \(dY_t=b_2dt+\sigma_2dB^2_t\), identify the instantaneous covariance term in \(d(X_tY_t)\).
- For \(f(u,v)=u^2+v^2\) and unit diffusion coefficients driven by a correlated Brownian pair, does the generator have a mixed derivative term? Explain using \(f_{uv}\).
- For the quadratic function in the second worked example, evaluate \(\mathcal{L}f\) at \((u,v)=(0,1)\).
- Why does local square integrability alone not justify taking expectations as though a stochastic integral were a true martingale?