From a Generator to a Probability Law
A diffusion operator records how a process changes when tested against smooth functions. The associated martingale problem turns that local description into a condition on the entire path law. When the problem has a solution and that solution is unique for every fixed starting point, the operator identifies a unique diffusion law from each such point. This conclusion is about distributions of paths; it does not say that two solutions driven by the same Brownian motion must coincide.
Fix a filtered probability space \((\Omega,\mathcal{F},(\mathcal{F}_t)_{t\ge0},\mathbb{P})\). For a scalar diffusion with drift \(b\) and diffusion coefficient \(\sigma\), define \(a(x)=\sigma(x)^2\) and \(\mathcal{L}f(x)=b(x)f'(x)+\tfrac12a(x)f''(x)\). Here \(b\) is the drift coefficient and \(\sigma\) is the diffusion coefficient. The natural test class used below is \(C_c^2(\mathbb{R})\), the twice continuously differentiable functions with compact support.
A martingale here is an integrable adapted process \(M_t\) satisfying \(\mathbb{E}[M_t\mid\mathcal{F}_s]=M_s\) for \(s\le t\). This is stronger than being a local martingale, which need only become a martingale after suitable stopping. The martingales in the definition are genuine martingales. Local martingales will arise when coordinate functions are recovered by stopping; they need not be true martingales without additional integrability.
Why Well-Posedness Gives Uniqueness in Law
Proof. Existence in the definition supplies at least one path law \(P_x\). Suppose \(P_x^{(1)}\) and \(P_x^{(2)}\) are laws of two weak solutions from \(x\), and suppose each solves the martingale problem for \(\mathcal{L}\). They are therefore two solutions of that same problem with the same initial state. Uniqueness in the definition gives \(P_x^{(1)}=P_x^{(2)}\). This is equality of probability measures on path space, hence equality of all finite-dimensional distributions and of the distributions of measurable path functionals. Applying the argument separately for each \(x\) proves the assertion for every deterministic starting state. \(\square\)
The link to an SDE comes from Itô’s formula. For example, suppose a weak solution satisfies \(dX_t=b(X_t)\,dt+\sigma(X_t)\,dB_t\), where \(B_t\) is Brownian motion on the filtered space, and the stochastic integral is an Itô integral. For each finite horizon \(T\), its integrand \(H_s=f'(X_s)\sigma(X_s)\) must be progressively measurable and satisfy \(\mathbb{E}\int_0^T H_s^2\,ds<\infty\) for the integral to be square integrable; localization supplies the corresponding local statement when this integrability is only local. Itô’s formula, with the second-derivative correction displayed, gives \[ f(X_t)=f(X_0)+\int_0^t f'(X_s)b(X_s)\,ds +\int_0^t f'(X_s)\sigma(X_s)\,dB_s +\frac12\int_0^t f''(X_s)\sigma(X_s)^2\,ds. \] Thus the finite-variation terms combine to \(\int_0^t\mathcal{L}f(X_s)\,ds\). Under the stated square-integrability condition, the stochastic integral is a martingale: it is integrable by the Itô isometry and has conditional expectation at time \(s\) equal to its value at time \(s\). Consequently the path law solves the martingale problem. The earlier material on weak SDEs and martingale problems gives the converse construction under its hypotheses; the theorem here uses the implication from SDE laws to martingale-problem laws.
Well-posedness does not assert pathwise uniqueness. Pathwise uniqueness compares solutions on the same probability space driven by the same Brownian motion and asks whether their paths agree almost surely. Uniqueness in law compares distributions and does not require a shared probability space or shared noise. Nor does the result assert strong existence, which requires constructing a solution from a prescribed Brownian motion and initial value. All laws in this tutorial are under \(\mathbb{P}\); no risk-neutral measure \(\mathbb{Q}\) or change of measure is involved.
The Brownian Martingale Problem
For standard Brownian motion the operator is \(\mathcal{L}f=\tfrac12f''\). We now establish both existence and uniqueness for the martingale problem starting from any \(x\in\mathbb{R}\).
Proof. For existence, take a filtered probability space carrying standard Brownian motion \(B_t\) and set \(X_t=x+B_t\). For \(f\in C_c^2(\mathbb{R})\), Itô’s formula uses \(f'(X_s)\) as the stochastic-integral integrand, and gives \(f(X_t)=f(x)+\int_0^t f'(X_s)\,dB_s+\tfrac12\int_0^t f''(X_s)\,ds\). Both \(f'\) and \(f''\) are bounded. Thus \(f'(X_s)\) is progressively measurable and \(\mathbb{E}\int_0^T f'(X_s)^2\,ds\le T\|f'\|_\infty^2<\infty\). The integral is a true martingale by the Itô isometry and the martingale property of the Itô integral, so the required martingale problem holds.
For uniqueness, let \(X\) be any continuous coordinate process solving this problem from \(x\). Fix \(R>|x|\), and let \(\tau_R=\inf\{t\ge0:|X_t|\ge R\}\), with the infimum of the empty set taken as infinity. Choose compactly supported \(C^2\) functions that agree with \(y\) and \(y^2\), respectively, on \([-R,R]\). Up to \(\tau_R\), their derivatives give \(\mathcal{L}y=0\) and \(\mathcal{L}(y^2)=1\). Stopping their martingale identities shows that \(X_{t\wedge\tau_R}-x\) and \(X_{t\wedge\tau_R}^2-x^2-(t\wedge\tau_R)\) are martingales. Since paths are continuous, \(\tau_R\) tends to infinity as \(R\) tends to infinity on every path over any fixed bounded time interval. Hence \(M_t=X_t-x\) is a continuous local martingale and \(M_t^2-t\) is a local martingale.
For a continuous local martingale \(M\), the defining quadratic-variation property is that \(M_t^2-[M]_t\) is a local martingale. Subtracting this process from \(M_t^2-t\) shows that \([M]_t-t\) is a continuous finite-variation local martingale starting at zero, and such a process is identically zero. Therefore \([M]_t=t\). Lévy’s characterization states that a continuous local martingale starting at zero with quadratic variation \(t\) is Brownian motion relative to its filtration. Applying it to \(M\) shows that \(X_t-x\) is Brownian motion. Brownian motion has independent \(N(0,t-s)\) increments after time \(s\), so all finite-dimensional distributions of \(X\) are fixed. On continuous path space, the Borel sigma-field is generated by evaluations at rational times; those distributions determine the path law. Thus every solution has the law of \(x+B\), proving uniqueness. \(\square\)
The use of Lévy’s characterization is a standard result: the proof is not repeated here. The localization above is important because \(y\) and \(y^2\) are not compactly supported test functions. It also explains why the coordinate martingales obtained in the argument are initially local martingales, rather than being asserted to be true martingales without a moment bound.
Worked Consequences
Worked Example: The Brownian Law from a Starting Point
Find the law of the process at time \(t=3\) when the Brownian martingale problem starts at \(x=2\).
The unique law is that of \(X_t=2+B_t\). Since \(B_3\sim N(0,3)\), translation gives \(X_3\sim N(2,3)\). Its mean is \(2+0=2\), its variance is \(3\), and its characteristic function at \(u\in\mathbb{R}\) is \(e^{2iu}e^{-3u^2/2}\).
Check: subtracting the starting value gives \(X_3-2=B_3\), whose mean is \(0\) and variance is \(3\), as required by the Brownian law. The martingale problem’s uniqueness says this is not merely one possible endpoint law: it is the endpoint law under every solution from \(2\).
Worked Example: Constant Drift and Volatility
Consider the operator \(\mathcal{L}f(y)=\tfrac12f'(y)+2f''(y)\), corresponding to drift \(b=\tfrac12\) and diffusion coefficient \(\sigma=2\). Find the law at time \(2\) from \(x=-1\).
The associated SDE is \(dX_t=\tfrac12\,dt+2\,dB_t\), with \(X_0=-1\). Its stochastic-integral integrand is the constant \(H_s=2\), which is progressively measurable and satisfies \(\mathbb{E}\int_0^T H_s^2\,ds=4T<\infty\). Thus its law solves the martingale problem by Itô’s formula. The process has the explicit form \(X_t=-1+\tfrac12t+2B_t\). At time \(2\), its mean is \(-1+\tfrac12\cdot2=-1+1=0\), and its variance is \(2^2\cdot2=8\). Therefore \(X_2\sim N(0,8)\).
More generally, for constant \(b\) and \(\sigma\ne0\), the centered process \(X_t-x-bt\), divided by \(\sigma\), is a continuous local martingale with quadratic variation \(t\); Lévy’s characterization identifies it as Brownian motion. This gives uniqueness in law for the constant-coefficient martingale problem. Check: in the stated example the formula predicts \(\mathbb{E}[X_2]=0\) and \(\operatorname{Var}(X_2)=8\); these agree with the mean and variance of \(N(0,8)\).
Worked Example: A Joint Event for Brownian Motion
For Brownian motion started at \(0\), compute \(\mathbb{P}(B_1>0,\ B_2-B_1>0)\).
The increment \(B_1-B_0=B_1\) has law \(N(0,1)\), and \(B_2-B_1\) also has law \(N(0,1)\). They are independent because Brownian increments on disjoint time intervals are independent. Each normal variable has a continuous symmetric distribution, so its probability of being strictly positive is \(\tfrac12\), and its probability of being zero is \(0\). Hence \(\mathbb{P}(B_1>0,\ B_2-B_1>0)=\tfrac12\cdot\tfrac12=\tfrac14\).
Check: the two events concern increments on \([0,1]\) and \([1,2]\), so independence applies; the strict inequalities do not change the probabilities relative to non-strict inequalities because neither increment has an atom at zero.
Common Pitfall: Uniqueness Is State-by-State
Uniqueness from one starting point does not by itself identify laws from other starting points. The hypothesis “well posed from every state” is a family of separate assertions: existence and uniqueness are required for each \(x\). The Brownian proof verifies this for an arbitrary \(x\), rather than only for \(x=0\).
A related error is to conclude pathwise uniqueness from uniqueness of the martingale problem. The martingale problem identifies the distribution on path space. It does not compare two processes coupled to the same Brownian motion. For example, the theorem’s conclusion is that all Brownian solutions started at \(x\) have the law of \(x+B\); it is not a claim about arbitrary couplings of two solutions. Conversely, if weak SDE solutions from a fixed state all induce the same martingale-problem law, uniqueness in law follows even when no common driving Brownian motion has been specified.
| Question | What the martingale problem provides |
|---|---|
| Does a solution law exist? | Yes, when existence is part of well-posedness. |
| Are two solution path laws equal? | Yes, for the same operator and the same fixed initial state. |
| Must two solutions driven by the same noise agree path by path? | Not from uniqueness in law alone. |
| Does the result use a change from \(\mathbb{P}\) to \(\mathbb{Q}\)? | No; all laws considered here are under \(\mathbb{P}\). |
Check Your Understanding
Use the definitions and the Brownian uniqueness argument to answer the following.
- What two requirements are included in the phrase “well posed from \(x\)”?
- Why does Itô’s formula show that the law of \(x+B_t\) solves the martingale problem for \(\tfrac12 f''\)? State the integrability condition on the stochastic-integral integrand.
- In the Brownian uniqueness proof, why are compactly supported test functions chosen to agree with \(y\) and \(y^2\) only up to the exit time \(\tau_R\)?
- For drift \(b=1\), diffusion coefficient \(\sigma=1\), initial state \(x=2\), and time \(t=3\), what are the mean and variance of the endpoint law?
- In one sentence, distinguish uniqueness in law from pathwise uniqueness.