A Diagnostic Framework for Partition Sums
Quadratic variation and covariation problems often involve simple operations—scaling a Brownian motion, combining correlated coordinates, or adding a finite-variation path. The diagnostic work is to track what each operation does to the partition sums, calculate the relevant limit in the stated mode of convergence, and avoid confusing that limit with total variation.
Work on a filtered probability space \((\Omega,\mathcal{F},(\mathcal{F}_t)_{t\ge0},\mathbb{P})\) carrying standard Brownian motions \(B_t\) and, when needed, \(C_t\). Assume \(C_t\) is independent of \(B_t\). No stochastic integrals are used in this tutorial. For \(T>0\), let \(\Pi=\{0=t_0<t_1<\cdots<t_n=T\}\) be a deterministic partition, let \(|\Pi|=\max_i(t_i-t_{i-1})\), and write \(\Delta_i X=X_{t_i}-X_{t_{i-1}}\).
Earlier material on Brownian quadratic variation establishes that \(Q_\Pi(B)\to T\) in mean square for deterministic partitions whose mesh tends to zero. For independent Brownian motions, their covariation sums tend to zero in mean square. These are convergence statements about sums over increasingly fine partitions; they do not assert that an individual squared increment equals its time increment.
Scaling Changes Quadratic Variation Quadratically
Proof. For every partition, \(\Delta_iX=a\Delta_iB\), so \(Q_\Pi(X)=a^2Q_\Pi(B)\). Therefore \(\mathbb{E}[(Q_\Pi(X)-a^2T)^2]=a^4\mathbb{E}[(Q_\Pi(B)-T)^2]\), which tends to zero by Brownian quadratic-variation convergence. This computation also covers \(a=0\), when the left-hand side is identically zero. \(\square\)
Worked Example: A Scaled Brownian Motion on Four Intervals
Let \(X_t=2B_t\) on \([0,2]\), and partition the interval into four equal pieces. Find the mean and variance of \(Q_\Pi(X)\), and its limit as the mesh tends to zero.
Each time increment has length \(h=2/4=1/2\). Since \(Q_\Pi(X)=4Q_\Pi(B)\), the Brownian quadratic-variation sum has mean \(T=2\) and variance \(2\sum_{i=1}^4h^2=2\cdot4\cdot(1/2)^2=2\). Scaling gives \(\mathbb{E}[Q_\Pi(X)]=4\cdot2=8\) and \(\operatorname{Var}(Q_\Pi(X))=16\cdot2=32\).
For partitions with mesh tending to zero, the proposition gives \(Q_\Pi(X)\to 2^2\cdot2=8\) in mean square. Check: the mean of the finite-partition sum is already \(8\), and its variance is \(32\) for this particular coarse partition; convergence says the variance tends to zero as the partition is refined, not that it is zero here. The factor is \(2^2\), not \(2\).
Correlated Coordinates and Covariation
Suppose \(B\) and \(C\) are independent standard Brownian motions and \(\rho\in[-1,1]\). The process \(D_t=\rho B_t+\sqrt{1-\rho^2}\,C_t\) is a standard Brownian motion correlated with \(B\), with covariation rate \(\rho\). At \(\rho=1\) or \(\rho=-1\), the coefficient of \(C\) is zero; the formulas below include these cases.
Proof. Write \(h_i=t_i-t_{i-1}\). Brownian increments on disjoint partition intervals are independent. For a centered normal variable with variance \(h_i\), its second moment is \(h_i\) and its fourth moment is \(3h_i^2\). Thus \(\mathbb{E}[Q_\Pi(B)]=T\) and \(\operatorname{Var}(Q_\Pi(B))=2\sum_i h_i^2\). The same formulas hold for \(C\).
For \(R_\Pi=\sum_i\Delta_iB\,\Delta_iC\), independence gives \(\mathbb{E}[R_\Pi]=0\). Its summands are independent across intervals, and each has variance \(\mathbb{E}[(\Delta_iB)^2]\mathbb{E}[(\Delta_iC)^2]=h_i^2\). Therefore \(\mathbb{E}[R_\Pi^2]=\sum_i h_i^2\). Since \(\sum_i h_i^2\le|\Pi|\sum_i h_i=T|\Pi|\), these variances tend to zero.
Now expand the sums directly: \(Q_\Pi(X)=a^2Q_\Pi(B)\), \(Q_\Pi(Y)=b^2\big(\rho^2Q_\Pi(B)+(1-\rho^2)Q_\Pi(C)+2\rho\sqrt{1-\rho^2}R_\Pi\big)\), and \(C_\Pi(X,Y)=ab\big(\rho Q_\Pi(B)+\sqrt{1-\rho^2}R_\Pi\big)\). The mean-square limits of \(Q_\Pi(B)\), \(Q_\Pi(C)\), and \(R_\Pi\) just proved give the three stated limits. For \(a=0\) or \(b=0\), the corresponding sums vanish identically, consistent with the formulas. \(\square\)
Worked Example: Covariation of Two Scaled Correlated Coordinates
Let \(X_t=2B_t\) and \(Y_t=-(\tfrac35B_t+\tfrac45C_t)\) on \([0,2]\), where \(B\) and \(C\) are independent. On four equal intervals, compute the means and variances of \(Q_\Pi(X)\) and \(C_\Pi(X,Y)\), and find their limiting values.
Here \(h=1/2\) and \(\sum_i h^2=4(1/2)^2=1\). For \(X\), scaling the Brownian sum gives mean \(4\cdot2=8\) and variance \(16\cdot2\sum_i h^2=32\).
On one interval, \(\Delta_iX\,\Delta_iY=-\tfrac65(\Delta_iB)^2-\tfrac85\Delta_iB\,\Delta_iC\). Its mean is \(-\tfrac65h\). The two terms have zero covariance: independence and the zero third moment give \(\mathbb{E}[(\Delta_iB)^3\Delta_iC]=0\), and \(\mathbb{E}[(\Delta_iB)^2]\mathbb{E}[\Delta_iB\,\Delta_iC]=0\). Their variances are \(\tfrac{36}{25}\cdot2h^2=\tfrac{72}{25}h^2\) and \(\tfrac{64}{25}h^2\), respectively. The variance per interval is therefore \(\tfrac{136}{25}h^2\). Summing four independent interval terms gives \(\mathbb{E}[C_\Pi(X,Y)]=-\tfrac65\cdot2=-\tfrac{12}{5}\) and \(\operatorname{Var}(C_\Pi(X,Y))=\tfrac{136}{25}\sum_i h^2=\tfrac{136}{25}\).
The theorem gives the limits \([X]_2=2^2\cdot2=8\) and \([X,Y]_2=2(-1)(\tfrac35)2=-\tfrac{12}{5}\), both in mean square. Check: the finite-partition means equal these limits, while the displayed variances are positive for four intervals. Under refinement, \(\sum_i h_i^2\le2|\Pi|\to0\), so the variances vanish.
Finite Variation: Zero Quadratic Variation, Not Zero Total Variation
Proof. The total variation \(V_T(A)\) is the supremum, over partitions of \([0,T]\), of the sum of absolute increments of \(A\); assume it is finite. For each partition, let \(m_\Pi=\max_i|\Delta_iA|\). Continuity on the compact interval implies uniform continuity, so \(m_\Pi\to0\) as \(|\Pi|\to0\). Consequently, \(Q_\Pi(A)\le m_\Pi\sum_i|\Delta_iA|\le m_\Pi V_T(A)\to0\).
The finite-sum Cauchy–Schwarz inequality gives \(|C_\Pi(A,B)|^2\le Q_\Pi(A)Q_\Pi(B)\). To verify convergence in probability, fix \(\varepsilon>0\) and \(\delta>0\). Brownian quadratic variation converges in probability to \(T\), so for sufficiently fine partitions \(\mathbb{P}(Q_\Pi(B)>T+1)<\delta\). On the event \(Q_\Pi(B)\le T+1\), the bound on \(Q_\Pi(A)\) tends to zero almost surely. Hence the probability that \(|C_\Pi(A,B)|>\varepsilon\) has limit superior at most \(\delta\). Since \(\delta\) was arbitrary, this probability tends to zero. \(\square\)
Worked Example: A Smooth Path and Its Brownian Covariation
Take \(A_t=t^2\) on \([0,1]\), and use \(n\) equal intervals. Compute its quadratic-variation sum and the variance of its covariation sum with \(B\).
At \(t_i=i/n\), the increment is \(\Delta_iA=(i^2-(i-1)^2)/n^2=(2i-1)/n^2\). Since \(\sum_{i=1}^n(2i-1)^2=n(4n^2-1)/3\), \(Q_\Pi(A)=n^{-4}\,n(4n^2-1)/3=(4n^2-1)/(3n^3)\to0\).
The covariation sum is \(\sum_i\Delta_iA\,\Delta_iB\). Its mean is zero, and independent Brownian increments give variance \(\sum_i(\Delta_iA)^2(1/n)=Q_\Pi(A)/n=(4n^2-1)/(3n^4)\to0\). It therefore converges to zero in mean square. Check: for \(n=2\), \(Q_\Pi(A)=1/16+9/16=10/16=5/8\); the formula gives \((16-1)/(3\cdot8)=15/24=5/8\). The total variation of this increasing path is \(A_1-A_0=1\), not zero, even though its quadratic variation tends to zero.
Convergence Modes and Common Errors
Mean-square convergence implies convergence in probability by Chebyshev's inequality: if \(\mathbb{E}[(Z_n-z)^2]\to0\), then for every \(\varepsilon>0\), \(\mathbb{P}(|Z_n-z|>\varepsilon)\le \mathbb{E}[(Z_n-z)^2]/\varepsilon^2\to0\). Almost-sure convergence is a separate assertion. Convergence in probability alone does not imply almost-sure convergence along the same sequence; almost-sure claims require a suitable argument, such as a summable probability bound and Borel–Cantelli. Keep the mode supplied by the calculation rather than upgrading it without justification.
Common mistake—scaling only once. A wrong calculation might say \(Q_\Pi(2B)=2Q_\Pi(B)\), and hence claim a limit \(2T\). But each increment is \(2\Delta_iB\), so its square is \(4(\Delta_iB)^2\); summing gives \(Q_\Pi(2B)=4Q_\Pi(B)\), with limit \(4T\). For example, at \(T=2\) the correct limit is \(4\cdot2=8\), not \(2\cdot2=4\).
Another error is to treat quadratic variation as total variation. For \(A_t=t^2\), the total variation on \([0,1]\) is \(1\), whereas the quadratic-variation sums tend to zero. Conversely, Brownian motion has quadratic variation \(T\) and almost surely infinite total variation. These quantities answer different questions: quadratic variation tracks sums of squared increments; total variation tracks sums of absolute increments.
| Path or pair | Partition-sum limit | Diagnostic |
|---|---|---|
| \(aB\) | \([aB]_T=a^2T\) | Scale increments, then square. |
| \(aB,\ b(\rho B+\sqrt{1-\rho^2}C)\) | \([X,Y]_T=ab\rho T\) | Track both coefficients and the correlation. |
| Continuous finite-variation \(A\) | \([A]_T=0\), \([A,B]_T=0\) | Zero quadratic variation does not mean zero total variation. |
Check Your Understanding
For each question, state the limit and the convergence mode when it is specified or follows from the results above.
- For \(X_t=-3B_t\) on \([0,T]\), what is the quadratic-variation limit?
- If \(X=B\) and \(Y=2(\tfrac12B+\tfrac{\sqrt3}{2}C)\), with independent \(B,C\), what is \([X,Y]_T\)?
- Why does \(Q_\Pi(A)\to0\) for a continuous finite-variation path not imply that its total variation is zero?
- Which inequality bounds \(|C_\Pi(A,B)|^2\) by quadratic-variation sums?
- What additional justification is needed to infer almost-sure convergence from convergence in probability along a sequence?