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Formulation Effects and In Vitro-In Vivo Correlation · Tutorial 343 of 399

Deconvolution Using an Intravenous Disposition Reference

Use an intravenous disposition function to recover a drug-input profile from plasma concentrations, and assess when the result is reliable.

Advanced 12 min read

What You'll Learn

  • Define the disposition function as a dose-normalized intravenous concentration response.
  • Derive a discrete convolution equation and recover interval-specific input rates.
  • Identify the linearity, time-invariance, and reference-matching assumptions required.
  • Quantify how concentration error can be amplified during deconvolution.
  • Select and check an intravenous reference for compatibility with the study.
  • Recognize when negative or erratic recovered rates signal numerical or model problems.

Why Use an Intravenous Disposition Reference?

After an extravascular dose, the plasma concentration reflects both when drug enters the systemic circulation and how the body distributes and eliminates it. The earlier material on connecting dissolution to absorption through convolution describes this relationship: concentration is the accumulated response to drug entering over time. Deconvolution works in the reverse direction. Given a concentration profile and a suitable disposition response, it estimates the rate at which drug appeared systemically.

An intravenous bolus can provide that response because its dose enters the systemic circulation at a known time. The resulting concentration-time profile, divided by the administered dose, is a dose-normalized disposition function. In this tutorial, the estimated input is the rate of systemic drug appearance. For an oral product, that rate reflects the effects of absorption and bioavailability; it is not automatically the rate of drug release from the dosage form or the rate at which drug crosses the gut wall.

Definition: Let \(h(t)\) be the plasma concentration at time \(t\) per unit amount of drug given instantaneously by intravenous bolus. Under linear, time-invariant pharmacokinetics, a systemic input rate \(R(t)\) produces concentration \(C(t)=\int_0^t R(\tau)h(t-\tau)\,d\tau\). Here \(R(t)\) has units of amount per time, \(h(t)\) has units of concentration per amount, and \(C(t)\) has units of concentration.

For an intravenous bolus of dose \(D_{\mathrm{IV}}\), the reference estimate is \(h(t)=C_{\mathrm{IV}}(t)/D_{\mathrm{IV}}\), after appropriate accounting for baseline concentration and any relevant sample or dose corrections. If the disposition is represented by a one-compartment model with volume \(V\) and elimination rate constant \(k\), then \(h(t)=e^{-kt}/V\). An empirical measured reference can also be used; it need not be forced into a one-compartment form.

Assumptions and Reference Selection

Deconvolution does not create information about the disposition process. Its result is meaningful only if the reference describes the disposition that would apply to the drug entering after the test dose. The central assumptions are:

  • Linearity: the concentration response to multiple input amounts is the sum of their individual responses. Clearance, distribution, and other relevant disposition properties must not change materially with concentration or dose.
  • Time invariance: the response to an input at a given time is the same as the response to the same input at another time, apart from the shift in time. There must not be a material change in disposition during the observation period.
  • Reference compatibility: the IV and extravascular observations represent the same active drug and sufficiently comparable physiological and analytical conditions. A change in clearance or distribution between occasions can be mistaken for a change in input.
  • Suitable reference data: the IV profile must adequately characterize the response over the times needed for deconvolution. Dose normalization is valid only when the IV disposition is dose proportional.
  • Adequate sampling and measurement: samples must resolve meaningful changes in the concentration profile, and assay error, baseline effects, and timing errors must not dominate the signal.

A useful reference is usually obtained from the same drug, with a known IV dose and sampling that captures both early distribution and later disposition. A reference from a different occasion or population may still be usable, but the analyst should justify comparability rather than assume it. If the IV dose is infused over time rather than given as a bolus, its observed concentration profile already reflects a non-instantaneous input; it cannot simply be divided by dose and treated as a bolus response without accounting for the infusion.

Key condition: The deconvolved profile is an estimate of systemic input only to the extent that the selected \(h(t)\) is the appropriate disposition response for that input. If the reference is mismatched, a smooth numerical answer may still be biased.

From Convolution to a Discrete Input Profile

Concentration samples are discrete, so a practical calculation represents the input as constant within each sampling interval. Suppose samples are taken at \(t_j=j\Delta\), and let \(R_k\) be the input rate during \(((k-1)\Delta,k\Delta]\). The contribution at time \(t_j\) from that interval depends on the response integrated over the corresponding range of elapsed times. Define

$$ w_m=\int_{m\Delta}^{(m+1)\Delta} h(u)\,du,\qquad m=0,1,2,\ldots $$

Then the discrete convolution is \(C_j=\sum_{k=1}^{j}R_k w_{j-k}\). The first observation contains only the first interval's input. At each subsequent observation, the current interval contributes through \(w_0\), while earlier intervals contribute through the appropriate later weights.

$$ C_j=\sum_{k=1}^{j}R_k w_{j-k} \qquad\Longrightarrow\qquad R_j=\frac{C_j-\sum_{k=1}^{j-1}R_k w_{j-k}}{w_0}. $$

This recurrence is the simplest discrete deconvolution. Its logic follows directly from isolating the term \(R_jw_0\) in the convolution sum. It also reveals an important limitation: each new rate is obtained by subtracting the predicted contributions of earlier rates, then dividing by \(w_0\). If \(w_0\) is small, errors in concentrations, previous rates, or weights can be magnified.

For a one-compartment disposition function \(h(t)=e^{-kt}/V\), the weights can be integrated exactly:

$$ w_m=\frac{1}{Vk}\left(e^{-km\Delta}-e^{-k(m+1)\Delta}\right). $$

Worked Example: Recovering Two Input Rates

Suppose a hypothetical drug has one-compartment disposition with \(V=1.00\) L and \(k=1.00\ \mathrm{h}^{-1}\). Concentrations are observed at 1-hour intervals, and the input is assumed constant within each interval. The hypothetical input rates are \(R_1=10.0\) mg/h and \(R_2=5.00\) mg/h. Calculate the corresponding concentrations and recover the second rate from them.

For \(\Delta=1\) h, the first two weights are \(w_0=1-e^{-1}=0.6321206\ \mathrm{h/L}\) and \(w_1=e^{-1}-e^{-2}=0.2325442\ \mathrm{h/L}\). The units follow from integrating \(h(t)\), which is in \(\mathrm{L}^{-1}\), over time.

At 1 hour, only the first interval contributes: \(C_1=R_1w_0=(10.0\ \mathrm{mg/h})(0.6321206\ \mathrm{h/L})=6.321206\ \mathrm{mg/L}\).

At 2 hours, the first interval contributes through \(w_1\), and the second through \(w_0\): \(C_2=R_1w_1+R_2w_0=(10.0)(0.2325442)+(5.00)(0.6321206)=2.325442+3.160603=5.486045\ \mathrm{mg/L}\).

Recover the second rate by subtracting the first interval's contribution: \(R_2=(C_2-w_1R_1)/w_0=(5.486045-2.325442)/0.6321206=5.000\ \mathrm{mg/h}\). This agrees with the hypothetical rate used to construct the concentrations. The calculation assumes the stated disposition model and interval-constant input; it does not establish that those assumptions hold for observed data.

Numerical Sensitivity and Diagnostics

The recurrence is algebraically straightforward but may be numerically fragile. Concentration measurement error at one time affects the rate recovered at that time and can also affect later rates, because later calculations subtract contributions from all previously estimated intervals. A small \(w_0\) magnifies these errors. Coarse sampling can also conceal rapid input changes, while very late samples may contain little signal relative to assay noise.

Negative recovered rates are a warning, not evidence that drug entered the body in a physically negative amount. They can arise when noisy or rounded concentrations are inconsistent with the assumed response, when the IV reference is mismatched, or when the interval-based approximation is inadequate. A negative rate should prompt examination of the data, units, sampling times, reference function, and assumptions. Silently replacing it with zero changes the estimated profile and should not be presented as a neutral correction.

Worked Example: A Concentration Perturbation and a Negative Rate

Use the weights and first-interval rate from the previous hypothetical calculation: \(w_0=0.6321206\ \mathrm{h/L}\), \(w_1=0.2325442\ \mathrm{h/L}\), and \(R_1=10.0\) mg/h. The second concentration predicted by rates of 10.0 and 5.00 mg/h is 5.486045 mg/L.

First consider a 0.100 mg/L reduction in the second concentration, to \(C_2=5.386045\) mg/L. The recovered rate is \(R_2=(5.386045-2.325442)/0.6321206=4.8418\ \mathrm{mg/h}\). The concentration change of \(-0.100\) mg/L changes the estimated rate by \(-0.100/0.6321206=-0.1582\) mg/h. This is an amplification by the reciprocal of \(w_0\), with units consistent with a rate change.

Now consider a much larger change: if the second concentration is 2.300 mg/L instead of 5.486 mg/L, the difference is 3.186 mg/L. Then \(R_2=(2.300-2.325442)/0.6321206=-0.04025\ \mathrm{mg/h}\). The negative estimate indicates inconsistency between this concentration and the assumed first-interval contribution and disposition response. It does not justify interpreting the input as negative; it signals a need to investigate measurement error, reference compatibility, and model adequacy.

Useful diagnostics include plotting observed concentrations alongside concentrations reconstructed by reconvolving the estimated input with \(h(t)\), inspecting the recovered rates for abrupt oscillation or implausible values, and checking sensitivity to sampling interval and reference estimation. Agreement after reconvolution is necessary for numerical consistency, but not sufficient evidence of a correct input profile: different input profiles can be difficult to distinguish when data are sparse or noisy.

Worked Example: Choosing and Applying a Dose-Normalized Reference

Suppose a hypothetical 100 mg IV bolus produces an initial concentration of 5.00 mg/L and has a one-compartment elimination rate constant \(k=0.200\ \mathrm{h}^{-1}\). The implied volume is \(V=100\ \mathrm{mg}/(5.00\ \mathrm{mg/L})=20.0\) L. Thus the dose-normalized disposition function is \(h(t)=e^{-0.200t}/20.0\ \mathrm{L}^{-1}\).

For 1-hour intervals, \(w_0=[1/(20.0\times0.200)](1-e^{-0.200})=0.0453173\ \mathrm{h/L}\), and \(w_1=[1/(20.0\times0.200)](e^{-0.200}-e^{-0.400})=0.0371027\ \mathrm{h/L}\).

If the hypothetical input rates are \(R_1=10.0\) mg/h and \(R_2=5.00\) mg/h, then \(C_1=(10.0)(0.0453173)=0.453173\) mg/L. At 2 hours, \(C_2=(10.0)(0.0371027)+(5.00)(0.0453173)=0.371027+0.226587=0.597614\) mg/L.

This example illustrates why the IV dose must be used to normalize the reference: the function is concentration per unit amount, not the raw concentration after a 100 mg dose. It also illustrates reference selection. The calculation is defensible only if the IV disposition represents the disposition of drug entering after the extravascular dose. If clearance, distribution, or physiological conditions differ materially, the recovered rates may reflect that difference as well as the true input.

Alternatives, Limitations, and Common Mistakes

The recurrence above is a direct, interval-based numerical method. It is transparent and easy to audit, but can be sensitive to measurement error. A parametric compartment model instead specifies a smooth input function and estimates its parameters by fitting predicted concentrations. This can stabilize estimation when the chosen model is appropriate, but it restricts the input to the assumed functional form. Smoothing or regularized deconvolution can reduce erratic estimates by penalizing rapid changes, but the penalty introduces a modeling choice and may smooth away real features. These approaches answer related but not identical questions; none removes the need for a suitable disposition reference.

Deconvolution is also limited by the available sampling window. Input occurring before the first sample, or input after the last informative sample, may be poorly estimated. A long disposition tail can carry contributions from earlier input into later concentrations, so truncating the reference too early can distort the recovered profile. For oral dosing, the estimated systemic input combines absorption with the fraction reaching systemic circulation; deconvolution alone does not separate those processes.

  • Mistake: treating the measured IV concentration curve as \(h(t)\) without dividing by the IV dose. Correction: normalize the IV response to concentration per unit amount, and confirm dose proportionality.
  • Mistake: interpreting every jagged or negative estimate as a real feature of absorption. Correction: check noise amplification, interval width, reference compatibility, and model assumptions before assigning physiological meaning.
  • Mistake: assuming that a concentration curve that can be reconstructed proves the recovered input is unique or correct. Correction: reconstruction checks consistency with the chosen response; sparse or noisy data can still leave substantial uncertainty about the input profile.
Key takeaway: An IV disposition reference enables concentration data to be inverted into an estimated systemic input profile under linear, time-invariant, reference-compatible pharmacokinetics. The result is an estimate whose resolution and stability depend on the reference, sampling design, and measurement quality.

Check Your Understanding

Answer each question, then compare your reasoning with the solutions below.

  1. What does the dose-normalized IV function \(h(t)\) represent, and what are its units?
  2. Suppose \(w_0=0.400\ \mathrm{h/L}\), \(w_1=0.200\ \mathrm{h/L}\), \(C_1=2.00\) mg/L, and \(C_2=1.60\) mg/L. Recover \(R_1\) and \(R_2\).
  3. Why can a small error in \(C_j\) produce a larger error in the estimated \(R_j\)?
  4. Name two checks to make if deconvolution gives negative or rapidly oscillating rates.

Solutions. (1) \(h(t)\) is the concentration response per unit amount administered instantaneously by IV bolus; its units are concentration per amount, such as \(\mathrm{L}^{-1}\). (2) \(R_1=C_1/w_0=2.00/0.400=5.00\) mg/h. Then \(R_2=(C_2-w_1R_1)/w_0=(1.60-(0.200)(5.00))/0.400=1.50\) mg/h. (3) The recurrence divides the residual concentration by \(w_0\), so concentration error is scaled by \(1/w_0\); a small \(w_0\) amplifies it. (4) Check the concentration and time units, sampling and assay quality, the IV reference and its dose normalization, and whether linearity and time invariance are credible.