Why Exact Contact With a Margin Matters
An equivalence conclusion depends on more than whether an estimate is between two margins. The uncertainty around that estimate must also be sufficiently small: the confidence interval must lie strictly inside the equivalence region. That strictness matters at the boundary. If a confidence limit is exactly equal to a margin, the corresponding one-sided test is exactly at its critical value, so the test does not pass under the strict rejection rule used here.
This is a boundary case, not a practically likely event in continuously distributed data. But it is important for interpreting software output, checking calculations, and writing a reproducible decision rule. A displayed endpoint may appear equal to a margin because of rounding even when the underlying values differ. Conversely, calculations that round an intermediate value can turn an intended equality into a small inequality.
For a difference-scale analysis, the margins and parameter are expressed in the units of the difference. For a ratio analysis, TOST is commonly performed on the log-ratio scale, where ratio limits become additive limits. The same boundary logic applies on either scale: a test statistic exactly at its critical value does not satisfy a strict rejection inequality.
Strict Tests and Their Confidence-Interval Equivalent
Suppose the estimate is \(\hat{\theta}\), its standard error is \(SE\), and inference uses a critical value \(c\) for a one-sided test at level \(\alpha\). For a large-sample normal procedure, \(c=z_{1-\alpha}\); for a \(t\)-procedure, \(c=t_{1-\alpha,df}\). The model must justify the chosen reference distribution: for example, a normal approximation for the estimate with a valid standard error, or a \(t\)-statistic with the stated degrees of freedom under the fitted model's assumptions.
The lower-margin test rejects when the estimate is sufficiently above \(L\). The upper-margin test rejects when the estimate is sufficiently below \(U\). Written in terms of the component statistics, the decision rules are:
Both inequalities must hold. Equality in either one is not rejection under these strict rules. Equivalently, the one-sided p-value for that component is equal to \(\alpha\) when its statistic is exactly \(c\); it has not fallen below the significance threshold.
The two rules can be rearranged directly, without relying on a verbal interpretation. Since \(SE>0\), the lower test rejects exactly when \(\hat{\theta}-cSE>L\). The upper test rejects exactly when \(\hat{\theta}+cSE<U\). Thus both reject exactly when the interval formed with those endpoints is strictly inside the margins.
For \(\alpha=0.05\), the matching interval is a 90% two-sided confidence interval, since \(1-2\alpha=0.90\). This relationship only holds when the interval and tests use the same estimate, standard error, reference distribution, degrees of freedom where applicable, and margins. Comparing a 90% interval from one model with TOST statistics from another does not establish this duality.
Worked Boundary Cases
Worked Example: Both Limits Exactly Meet Symmetric Margins
Hypothetical data. A difference estimate is \(\hat{\theta}=0\) units, with margins \(L=-5\) units and \(U=5\) units. Assume a valid normal-reference analysis with \(SE=5/c\), where \(c=z_{0.95}=1.644853626951\). Keeping the standard error in this exact form avoids introducing a rounding discrepancy.
The interval limits are:
Both limits equal their respective margins. The lower statistic is \(T_L=(0-(-5))/(5/c)=c\), and the upper statistic is \(T_U=(5-0)/(5/c)=c\). Neither statistic is strictly greater than \(c\), so neither component test passes the strict rejection rule. Equivalence is not established. The result is a boundary, inconclusive result: the interval is not strictly inside the margins, but it is not wholly beyond either margin.
Worked Example: One Limit Equals a Margin and the Other Is Inside
Hypothetical data. Let \(L=-5\) units, \(U=5\) units, and \(\hat{\theta}=-1\) unit. Use the same normal-reference critical value \(c=1.644853626951\), and take \(SE=4/c\). The 90% interval is:
The lower limit equals \(L\), while the upper limit, 3 units, is below \(U=5\) units. For the lower test,
Therefore \(T_L\) is not strictly greater than \(c\), and the lower-margin null is not rejected under the stated rule. For the upper test,
The upper-margin test passes, but both tests must pass. The outcome is not equivalent. The location of the interval shows why a single endpoint can determine the overall decision: the other test cannot compensate for failure at the boundary.
Worked Example: Exact Contact With a Ratio Margin on the Log Scale
Hypothetical data. Suppose the estimated ratio is 0.9600, the ratio margins are 0.8000 and 1.250, and the analysis uses a normal reference distribution. On the log scale, the estimate is \(\ln(0.9600)\), the lower limit is \(\ln(0.8000)\), and the upper limit is \(\ln(1.250)\). Set \(c=1.644853626951\) and \(SE=\ln(1.2)/c\), retaining that expression at full precision.
The distance from the log estimate to the lower log margin is:
Consequently, the lower log confidence limit is exactly \(\ln(0.8000)\); after back-transformation it is exactly 0.8000. The upper endpoint on the ratio scale is:
Since \(1.152<1.250\), the upper endpoint is inside its margin. But the lower statistic is \(T_L=\ln(1.2)/SE=c\), exactly critical, so the lower test does not pass the strict rule. Equivalence is not established. Back-transformation preserves the ordering, so it cannot turn exact contact on the log scale into strict containment on the ratio scale.
Why the Derivation Determines the Boundary Rule
The confidence-interval rule follows from the test rules, rather than being an additional convention. For the lower test, the rejection region is \(T_L>c\). Multiplying by the positive \(SE\) and rearranging gives \(\hat{\theta}-cSE>L\), which says that the interval's lower limit must exceed the lower margin. If the lower limit equals \(L\), the rearrangement gives \(T_L=c\), not \(T_L>c\). The same algebra for the upper test requires \(\hat{\theta}+cSE<U\). Equality at \(U\) likewise produces a statistic equal to \(c\), not greater than \(c\).
A closed confidence interval that merely shares an endpoint with the closed interval \([L,U]\) can be described informally as “within or on the margins.” That wording is not the strict containment condition corresponding to both tests passing. For TOST, the acceptance region for the parameter is open, \(L<\theta<U\), and the confidence interval must be contained in that open region. Exact contact leaves a boundary point in the confidence interval, so strict containment fails.
Precision, Diagnostics, and Common Mistakes
Exact equality should be assessed using the unrounded values used in the test. Printed estimates, standard errors, confidence limits, and p-values are often rounded for display. A limit printed as 0.800 may be 0.7996 or 0.8004 internally; those values lie on opposite sides of a 0.800 margin. The display alone cannot resolve the decision.
For a deliberate boundary check, retain the defining quantities at full available precision and calculate the limit and test statistic from the same inputs. If a hypothetical example defines \(SE=5/c\), using \(SE=3.039\) in subsequent arithmetic does not preserve exact equality. The rounded standard error can make the computed statistic slightly larger or smaller than \(c\). Likewise, do not round a p-value to 0.050 and infer that its unrounded value equals \(\alpha=0.05\).
- Check the matching procedure. Verify that the confidence interval and both tests use the same estimate, \(SE\), critical distribution, and degrees of freedom.
- Inspect unrounded limits. Compare the stored limits with the prespecified margins before applying display formatting.
- Check the direction. The lower limit must be greater than \(L\); the upper limit must be less than \(U\). Reversing either inequality changes the conclusion.
- Check the comparison operator. Document whether the decision rule uses strict inequalities. In exact continuous models, equality has probability zero, so alternative conventions at the single point can yield the same nominal level; nevertheless, implementations and reports need a consistent rule for computed boundary cases.
A common mistake is to say, “The confidence interval reaches the margin but does not cross it, so equivalence is established.” That reasoning treats touching as strict containment. The correction is to test each endpoint using the defined inequalities: \(CI_L>L\) and \(CI_U<U\). If either comparison is equality, the corresponding component test is at the critical value and equivalence is not concluded under the strict rule.
The interval is the most direct presentation for seeing endpoint contact, while the two test statistics show which one-sided condition fails. Neither replaces the need to state the decision rule. A rounded table is convenient for communication; a full-precision computation is necessary for resolving a boundary comparison. If finite numerical precision makes equality indistinguishable from a tiny difference, retain greater precision or use a numerically stable comparison rather than silently treating the displayed values as exact.
Check Your Understanding
Answer each question using the strict TOST rule described above. Solutions follow the questions.
- For margins \([-2,2]\), a 90% confidence interval is \([-1.7,2.0]\). Is equivalence established? Which component test determines the answer?
- A lower-margin statistic is \(T_L=1.645\), and the critical value is \(c=1.645\). Does the lower test pass under the strict rule? What is its p-value relative to \(\alpha\), assuming the statistic is exactly critical?
- Why must the interval and TOST calculations use the same standard error and reference distribution for the endpoint rule to apply?
- A ratio-scale confidence interval has lower endpoint 0.80 and lower margin 0.80. What does the equality imply after taking logs?
- A report prints a confidence limit as 1.25 and an upper margin as 1.25. What information is needed before deciding whether the internal values are equal?
Solutions. (1) No. The upper endpoint equals \(U=2\), so the upper test is exactly at its critical boundary and does not pass under the strict rule. (2) No. Equality is not \(T_L>c\); the exact one-sided p-value is \(\alpha\), not below it. (3) The interval-test equivalence was derived using the same estimate, standard error, and critical value; changing the reference distribution or standard error changes the endpoints or rejection threshold, so the algebraic correspondence no longer describes the reported pair. (4) The log lower endpoint equals the log lower margin, since the logarithm is strictly increasing and \(\ln(0.80)=\ln(0.80)\). The lower test is at its critical boundary, so equivalence is not established. (5) The unrounded computed limit and margin, along with the numerical precision used to calculate and compare them. Displayed equality alone does not establish internal equality.