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Crossover Designs · Tutorial 116 of 399

Worked Four-Period Full-Replicate Layout

Learn to build a TRTR/RTRT schedule table, verify within-participant replication, and determine whether treatment allocation is balanced across periods.

Intermediate 12 min read

What You'll Learn

  • Define the TRTR and RTRT sequences across four study periods.
  • Check whether each participant is scheduled to receive each formulation twice.
  • Build period-specific treatment counts from sequence enrollment numbers.
  • Distinguish equal total exposure to T and R from treatment-by-period balance.
  • Diagnose how unequal sequence allocation affects the layout.
  • Compare the four-period full replicate with shorter replicate layouts.

What the Four-Period Full-Replicate Layout Shows

A four-period full-replicate layout gives each participant two planned administrations of the test formulation and two of the reference formulation. The sequence labels show the treatment assigned in each successive period: T denotes test and R denotes reference. In the TRTR/RTRT layout, participants are assigned to one of two sequences, each of which contains both formulations twice.

The key checks are distinct. First, inspect each sequence to confirm that it repeats both formulations within a participant. Second, count the number assigned to each formulation in each period to assess treatment-by-period balance. Equal total numbers of T and R administrations do not, by themselves, guarantee that the treatments are balanced within every period.

Definition: A four-period full-replicate layout using the TRTR/RTRT sequences assigns each participant to either T-R-T-R or R-T-R-T across periods 1 through 4. Each participant is scheduled to receive T twice and R twice. Treatment-by-period balance means that within each period, the number assigned to T equals the number assigned to R.

This is a schedule-level audit: it describes planned assignments, not whether participants completed every period or received every assigned dose. Its basic assumptions are that T and R consistently identify the same formulations throughout the table, each participant follows one complete four-period sequence as assigned, and the displayed sequence counts describe the participants being audited. If actual administrations are incomplete, the planned layout and the observed dosing records should not be conflated.

Build the Sequence Table

Start with periods as columns and the sequence assignments as rows. The sequence pattern makes the within-participant replication visible before any participants are counted.

SequencePeriod 1Period 2Period 3Period 4T per participantR per participant
TRTRTRTR22
RTRTRTRT22

This table establishes the replication property for either assigned sequence: every row contains two T entries and two R entries. It does not yet establish period balance in a particular study. That depends on how many participants are assigned to each row.

Worked Example: Checking the Sequence for One Participant

Suppose a hypothetical participant is assigned to TRTR. Verify the number of planned administrations of each formulation and state what this check establishes.

Reading across the four periods gives T, R, T, R. The T count is \(1+1=2\), from periods 1 and 3; the R count is \(1+1=2\), from periods 2 and 4. Thus this participant is scheduled to receive each formulation twice. The check verifies replication within this assigned sequence; it does not establish that the participant completed the schedule or that the study has equal treatment counts in every period.

Count Treatments Within Each Period

Let \(n_A\) be the number of participants assigned to TRTR and \(n_B\) the number assigned to RTRT. Each participant contributes one planned treatment assignment to each period. Consequently, the count in each treatment-by-period cell follows directly from the sequence row.

$$ \begin{array}{c|cc} \text{Period} & T & R\\ \hline 1 & n_A & n_B\\ 2 & n_B & n_A\\ 3 & n_A & n_B\\ 4 & n_B & n_A \end{array} $$

For example, in period 1 every TRTR participant receives T and every RTRT participant receives R. In period 2 those assignments reverse; the same pattern repeats in periods 3 and 4. This yields a simple condition for exact treatment-by-period balance: the two sequence counts must be equal.

$$ \text{Exact balance in every period} \quad\Longleftrightarrow\quad n_A=n_B. $$

A related check concerns the total number of planned administrations across all periods. Each participant contributes two T and two R administrations, so the total T and R counts are equal for any sequence allocation, even when the counts differ between sequences. This equality across the whole study is not the same as equality of T and R within each period.

$$ \text{Total T administrations}=2(n_A+n_B) \qquad\text{and}\qquad \text{total R administrations}=2(n_A+n_B). $$

Worked Example: Balanced Sequence Allocation

In a hypothetical study, 20 participants are assigned to TRTR and 20 to RTRT. Construct the treatment-by-period counts and verify both replication and period balance.

Here \(n_A=20\) and \(n_B=20\). Substituting these counts into the period table gives 20 participants assigned to T and 20 to R in each period:

PeriodT countR countBalanced?
12020Yes
22020Yes
32020Yes
42020Yes

Each participant's sequence contains two T and two R assignments, so there are \(40\times2=80\) planned T administrations and \(40\times2=80\) planned R administrations overall. There are also 40 planned administrations in each period, split equally between formulations. The layout therefore has both within-participant replication and exact treatment-by-period balance.

Why Equal Sequence Counts Give Period Balance

The balance condition can be justified by considering the two possible entries in each period. In periods 1 and 3, TRTR participants receive T and RTRT participants receive R, so the difference between the T and R counts is \(n_A-n_B\). In periods 2 and 4, the assignments switch, so the difference is \(n_B-n_A\). All four differences are zero precisely when \(n_A=n_B\).

$$ \begin{aligned} T-R\text{ count difference in periods 1 and 3} &= n_A-n_B,\\ T-R\text{ count difference in periods 2 and 4} &= n_B-n_A. \end{aligned} $$

If \(n_A=n_B\), both expressions equal zero, proving balance in every period. Conversely, if period 1 is balanced, then \(n_A-n_B=0\), which requires \(n_A=n_B\). Thus the condition is both sufficient and necessary for exact balance under this two-sequence layout.

Worked Example: Equal Totals but Unequal Period Counts

A hypothetical allocation assigns 12 participants to TRTR and 8 to RTRT. Determine the treatment counts in every period, and explain whether the study is treatment-by-period balanced.

Use \(n_A=12\) and \(n_B=8\). In periods 1 and 3, the TRTR group receives T and the RTRT group receives R, giving 12 T and 8 R. In periods 2 and 4, the assignments reverse, giving 8 T and 12 R.

PeriodT countR countDifference in counts
11284 more T
28124 more R
31284 more T
48124 more R

There are \(12+8=20\) participants, so the totals across all periods are \(20\times2=40\) T administrations and \(20\times2=40\) R administrations. Nevertheless, no period has equal treatment counts: the sequence groups are unequal in size. The layout has equal total exposure to T and R but is not treatment-by-period balanced.

Diagnostics, Alternatives, and Limits

A practical audit should display the assigned sequence counts and the treatment counts by period, rather than relying on a statement that the study is “balanced.” A useful diagnostic table has one row per period and separate T and R counts, as in the examples. If a period total does not equal the number assigned to the study, check for a transcription error, a missing sequence assignment, or a table that mixes planned assignments with observed administrations.

Also verify that each listed sequence has two entries of each formulation. A sequence containing three T assignments and one R assignment is not the stated full-replicate layout, even if the overall study happens to have equal numbers of T and R administrations. The count should be checked at both levels: within each participant's assigned sequence and across participants within each period.

The four-period full replicate differs from shorter alternatives in what it repeats. A two-period crossover assigns each participant one T and one R, so it does not provide repeated administrations of each formulation within the participant. A three-period partial-replicate layout repeats one formulation but not both for every participant. Those alternatives can be appropriate for different design goals, but neither has the same per-participant replication pattern as TRTR/RTRT. The earlier material on period balance in replicate designs provides broader context for why period-specific counts matter.

The schedule alone does not demonstrate that participants completed all periods, that missing observations are absent, or that any other design concern has been resolved. In particular, equal treatment-by-period counts are a property of assigned counts, not proof that observed data are complete or that the design is free of all possible bias. The audit answers a narrower question: whether this sequence layout repeats both formulations as intended and balances their planned counts by period.

Common mistake: “There are 40 T administrations and 40 R administrations overall, so every period is balanced.” The conclusion does not follow: totals can be equal while individual periods have unequal treatment counts. Calculate the T and R counts separately for each period; in this layout, exact balance requires equal numbers assigned to TRTR and RTRT.

Check Your Understanding

Answer each question, then compare your reasoning with the solutions below.

  1. How many planned administrations of T and R does a participant assigned to RTRT receive?
  2. A study assigns 15 participants to TRTR and 15 to RTRT. What are the T and R counts in period 2?
  3. A study has 18 participants in total, with 11 assigned to TRTR and 7 to RTRT. Are total T and R administrations equal? Is each period balanced?
  4. What condition on the two sequence counts guarantees exact treatment-by-period balance in all four periods?

Solutions. (1) RTRT contains two T entries and two R entries, so the participant is scheduled for two administrations of each. (2) In period 2, TRTR participants receive R and RTRT participants receive T; the counts are 15 R and 15 T. (3) Each participant contributes two administrations of each formulation, giving \(18\times2=36\) T and 36 R administrations overall. The periods are not balanced because the sequence counts are 11 and 7; periods 1 and 3 have 11 T and 7 R, while periods 2 and 4 have 7 T and 11 R. (4) The sequence counts must be equal, \(n_A=n_B\).