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Translational Modeling and Uncertainty · Tutorial 132 of 596

Model Discrepancy in Preclinical-to-Human Extrapolation

Represent cross-species model mismatch explicitly and quantify how its bias, uncertainty, and dependence on model predictions affect human predictions.

Advanced 10 min read

What You'll Learn

  • Distinguish model discrepancy from parameter uncertainty, assay error, and population variability.
  • Define a discrepancy term on a scientifically suitable scale for a human prediction.
  • Derive how discrepancy changes a predictive mean and variance.
  • Calculate human prediction intervals with zero or nonzero discrepancy bias.
  • Estimate a simple discrepancy distribution from hypothetical paired residuals and identify what that estimate leaves uncertain.
  • Recognize when independence, normality, or transportability assumptions are questionable.

Why Include a Discrepancy Term?

A cross-species model can be carefully fitted, its parameters can be uncertain, and its calculations can be correct, yet its human prediction can still be systematically wrong. The model may omit a biological process, use an imperfect scaling relationship, or represent a species difference too simply. Model discrepancy is a term for this residual mismatch between the model's prediction and the biological quantity it is intended to predict. Representing it explicitly prevents a precise model calculation from being mistaken for a complete account of predictive uncertainty.

Discrepancy is not the same as uncertainty in a model parameter. Parameter uncertainty concerns which values of the model's parameters are compatible with the evidence; discrepancy concerns the gap between the model, even at specified parameter values, and biological reality. It is also not automatically between-subject variability or assay error. Those describe different sources of variation and should not be silently combined with discrepancy.

Definition: Let \(B_h\) be a model-based prediction for a specified human quantity, on a chosen scale, before adding a discrepancy term. A discrepancy model represents that quantity as \(Y_h = B_h + D_h\), where \(D_h\) is the discrepancy for the prediction target. Its mean represents systematic bias on that scale; its variance represents uncertainty about the discrepancy. The distribution assigned to \(D_h\) is a modelling assumption informed by relevant evidence or elicitation, not a claim that biological mismatch is necessarily a random process.

The scale matters. For a positive quantity such as exposure, an additive discrepancy on the natural scale can imply implausible negative values. A log-scale representation is often convenient: if \(B_h\) is a prediction for log exposure, then a discrepancy of \(d\) corresponds to multiplying exposure by \(\exp(d)\). A positive log-scale discrepancy therefore raises the predicted exposure, and a negative one lowers it. The examples below use log exposure and report final intervals in exposure units.

A discrepancy term must also have a defined target. It might describe the mismatch for one human estimand under specified conditions, such as typical exposure at a specified dose, rather than a universal correction for every drug, dose, endpoint, or population. If evidence suggests the mismatch changes with dose or another covariate, a single constant discrepancy may be inadequate; the discrepancy may need a structured dependence on those conditions.

Propagating Discrepancy Into a Human Prediction

Suppose the model-based log-scale prediction \(B_h\) has mean \(\mu_0\) and variance \(v_0\), incorporating the uncertainty sources already included in that prediction. For a simple calculation, assume that \(B_h\) is normally distributed and that the discrepancy is normally distributed with mean \(m_D\) and variance \(\tau_D^2\). If the two are independent, their sum is normal. The resulting mean and variance follow directly from the rules for expectations and variances.

1
Define the components.
Write the log-scale prediction as \(Y_h=B_h+D_h\), with \(E(B_h)=\mu_0\), \(\operatorname{Var}(B_h)=v_0\), \(E(D_h)=m_D\), and \(\operatorname{Var}(D_h)=\tau_D^2\).
2
Calculate the mean.
Linearity of expectation gives \(E(Y_h)=E(B_h)+E(D_h)=\mu_0+m_D\). Thus the discrepancy mean shifts the prediction on the model's scale.
3
Calculate the variance.
The variance of a sum is \(\operatorname{Var}(Y_h)=v_0+\tau_D^2+2\operatorname{Cov}(B_h,D_h)\). Under the independence assumption, the covariance is zero, so the variance is \(v_0+\tau_D^2\).
4
Transform back if needed.
If \(Y_h\) is log exposure and is normal, exposure is lognormal. A central 95% predictive interval on the exposure scale is obtained by exponentiating the log-scale limits \(\mu_0+m_D \pm 1.96\sqrt{v_0+\tau_D^2}\).

This calculation makes the main consequence transparent: under independence, discrepancy variance adds to the existing predictive variance. A zero-mean discrepancy can widen an interval without shifting its centre on the log scale. A nonzero mean shifts that centre as well. If \(B_h\) and \(D_h\) are dependent, it is not correct simply to add their variances: the covariance term must be included. Independence should be supported by the way the components were constructed, not assumed merely because they have different names.

The normal distribution is a tractable assumption, not a requirement of the idea. If discrepancy is asymmetric, heavy-tailed, or related to conditions such as dose, simulation or another suitable probability calculation can propagate its specified distribution. The essential discipline is to state what the discrepancy represents, what evidence informs it, and which assumptions link it to the human prediction.

Worked Example: Adding Zero-Mean Discrepancy to Exposure Uncertainty

Hypothetical data. A translation model predicts a human exposure whose log-scale distribution has mean \(\log(20)\) and standard deviation \(0.20\). Exposure is measured in exposure units. Assume an independent, zero-mean log-scale discrepancy with standard deviation \(0.10\). Under the normal assumptions above, calculate a central 95% predictive interval.

The total log-scale standard deviation is

$$ \sqrt{0.20^2+0.10^2} =\sqrt{0.05} =0.2236. $$

The interval on the exposure scale is

$$ \left( \exp\{\log(20)-1.96(0.2236)\}, \exp\{\log(20)+1.96(0.2236)\} \right) \approx (12.90,\ 31.00) $$

The model's central prediction remains 20 exposure units because the discrepancy mean is zero, but the interval includes discrepancy uncertainty and is wider than it would be without it. Conditional on the stated model and assumptions, the calculation gives a 95% predictive interval for the human exposure; it is not a statement that there is a 95% probability that a fixed unknown value lies in this particular interval.

Worked Example: A Larger Discrepancy Produces a Wider Interval

Hypothetical scenario. Keep the model-based prediction and its log-scale standard deviation from the previous example, but suppose the discrepancy standard deviation is \(0.40\), still with zero mean and independence. The total standard deviation is

$$ \sqrt{0.20^2+0.40^2} =\sqrt{0.20} =0.4472. $$

The central 95% predictive interval is therefore

$$ \left( \exp\{\log(20)-1.96(0.4472)\}, \exp\{\log(20)+1.96(0.4472)\} \right) \approx (8.32,\ 48.05) $$

Both limits are in exposure units. The interval is much wider than the interval with discrepancy standard deviation \(0.10\), even though the central prediction is still 20. This comparison isolates the effect of increasing the assumed magnitude of discrepancy; it does not establish which discrepancy magnitude is appropriate for a particular drug.

Worked Example: Allowing for a Systematic Shift

Hypothetical scenario. Suppose the model-based log exposure has mean \(\log(30)\) and standard deviation \(0.15\). Evidence from a relevant hypothetical calibration exercise supports a discrepancy with mean \(\log(1.2)\) and standard deviation \(0.20\). Assume independence and normality on the log scale. The discrepancy mean corresponds to a 20% upward multiplicative shift, because \(\exp\{\log(1.2)\}=1.2\).

The combined log-scale mean is

$$ \log(30)+\log(1.2)=\log(36), $$

and the combined standard deviation is

$$ \sqrt{0.15^2+0.20^2} =\sqrt{0.0625} =0.25. $$

Thus the central 95% interval on the exposure scale is

$$ \left( \exp\{\log(36)-1.96(0.25)\}, \exp\{\log(36)+1.96(0.25)\} \right) \approx (22.05,\ 58.76). $$

The interval is centred at \(\log(36)\) on the log scale, so its median exposure is 36 exposure units, not 30. The added discrepancy represents both a systematic upward adjustment and uncertainty around that adjustment. The shift is justified here only because the hypothetical calibration evidence was stipulated to support it.

What Can Inform Discrepancy?

One possible source is a set of relevant historical predictions paired with suitable reference values. For each case, a log-scale residual can be calculated as the reference value minus the model prediction. The mean residual can inform a systematic shift, and the residual spread can inform discrepancy variability. These summaries are informative only to the extent that the historical cases resemble the intended human prediction in drug properties, biology, endpoint, and conditions.

For illustration, suppose four hypothetical paired cases have log-scale residuals \(0.10\), \(-0.10\), \(0.20\), and \(-0.20\). Their mean is zero. The sample variance is

$$ s^2 =\frac{(0.10-0)^2+(-0.10-0)^2+(0.20-0)^2+(-0.20-0)^2}{4-1} =\frac{0.10}{3} =0.03333, $$

so the sample standard deviation is \(s=\sqrt{0.03333}=0.1826\) log units. This is a descriptive estimate of residual spread in the hypothetical cases, not a precise or automatically transportable estimate of discrepancy for a new drug. In particular, treating an estimated spread as known omits uncertainty from estimating it; four cases provide little evidence about tail behaviour or how discrepancy varies across conditions.

Judgment or elicitation may be needed when direct calibration evidence is scarce. A useful elicitation specifies a scale and a prediction target: for example, plausible multiplicative departures from a model's human exposure prediction under stated conditions. The resulting distribution should be documented and explored over scientifically defensible alternatives. Assigning a large variance without explaining its basis may make an interval wide, but does not make the discrepancy model well supported.

Checks, Alternatives, and Limitations

Before using a discrepancy distribution, check that the components have clear and non-overlapping meanings. If the model-based predictive variance already includes the same residual mismatch represented by \(D_h\), adding \(\tau_D^2\) again double-counts uncertainty. Conversely, if a model's residual spread is treated only as assay noise when it includes systematic cross-species mismatch, omitting discrepancy can understate predictive uncertainty. The intended uncertainty components should be stated before they are combined.

Also check whether a single discrepancy distribution is plausible for the prediction target. Residuals that change with dose, species, endpoint, or compound class suggest a constant correction may not represent the mismatch well. A normal log-scale discrepancy should be reconsidered if relevant calibration residuals show pronounced asymmetry, extreme values, or distinct patterns. Sparse evidence cannot reliably rule out these problems, so lack of an obvious diagnostic signal is not proof that the assumed distribution is correct.

Discrepancy modelling complements, but does not replace, other ways to represent uncertainty. Parameter uncertainty describes uncertainty within a specified model; population variability describes differences among individuals; assay error describes measurement uncertainty. Structural uncertainty and Bayesian model averaging address uncertainty across candidate model structures. A discrepancy term can capture mismatch that remains even after considering candidate structures, but it does not identify the biological cause of that mismatch. Nor should it become an unexamined catch-all that obscures a fixable model defect.

A key limitation is transportability: residuals from earlier compounds or species may not describe the discrepancy for a new human prediction. Another is confounding: with sparse data, systematic bias, parameter values, and discrepancy can be difficult to distinguish. A broad discrepancy distribution may reflect several unresolved sources at once, while a narrow one may reflect limited evidence rather than genuine precision. Prediction intervals are therefore conditional on both the specified model and the evidence or judgment used to construct the discrepancy distribution.

Common pitfall: “The model parameters are uncertain, so their predictive interval already covers model mismatch.” This does not follow. Parameter uncertainty propagates uncertainty within the chosen model; it does not automatically cover a systematic gap between that model and human biology. Define whether discrepancy is already represented in the predictive variance, then add it only if it is a distinct component. Under independence, add its variance; under dependence, include the covariance term.
Key takeaway: On a chosen scale, represent the human prediction as a model-based prediction plus an explicitly defined discrepancy. Its mean can shift the prediction, and its uncertainty can widen the predictive interval. Those effects are meaningful only in light of the discrepancy assumptions, evidence, and target conditions.

Check Your Understanding

Answer each question, then compare your reasoning with the solutions.

  1. A log-scale model prediction has variance \(0.09\). An independent discrepancy has variance \(0.04\) and mean zero. What is the variance of their sum, and what does the zero mean imply for the combined log-scale mean?
  2. Why is a discrepancy standard deviation of \(0.40\) not interchangeable with a standard deviation of \(0.40\) in a population-variability model?
  3. A discrepancy has mean \(\log(0.8)\). What multiplicative shift does this imply on the original scale?
  4. Suppose model prediction and discrepancy have covariance \(-0.01\), with variances \(0.09\) and \(0.04\). Calculate the variance of their sum.
  5. Four historical residuals have sample standard deviation \(0.1826\) log units. Give one reason why directly treating this as the known discrepancy standard deviation for a new compound could be misleading.

Solutions. (1) Under independence, the sum has variance \(0.09+0.04=0.13\); the zero discrepancy mean leaves the model's log-scale mean unchanged. (2) Discrepancy represents mismatch between the model and the biological target, whereas population variability represents differences among individuals; their interpretations and appropriate prediction targets differ. (3) The multiplicative shift is \(\exp\{\log(0.8)\}=0.8\), or a 20% downward shift. (4) The variance is \(0.09+0.04+2(-0.01)=0.11\). (5) The estimate comes from only four cases, so it is uncertain and may not transport to the new compound or its prediction conditions.