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Study Design and Optimal Sampling for NLME · Tutorial 766 of 797

Marginal Fisher Information in a Random-Intercept Model

Learn to derive and calculate marginal Fisher information after integrating out Gaussian subject-level random intercepts.

Advanced 12 min read

What You'll Learn

  • Write the marginal distribution of a Gaussian random-intercept profile.
  • Derive information for fixed effects and variance components from the marginal likelihood.
  • Explain why the expected fixed-effect and variance-component information blocks are orthogonal.
  • Calculate information for repeated observations and compare it with conditional information.
  • Identify when replication permits separate information about the random-intercept and residual variances.
  • Recognize assumptions and diagnostics that affect the interpretation of marginal information.

Why Marginal Information Is Different

In a nonlinear mixed-effects design calculation, information depends on what is treated as observed. A subject-specific random effect is latent: it is not another measured outcome. If the likelihood is formed by integrating that effect out, observations from the same subject are correlated in the marginal model. The resulting Fisher information therefore need not equal information calculated as if the random effects were known.

This tutorial derives that marginal information for a Gaussian random-intercept model. The model is deliberately simple enough to calculate by hand, while retaining the central feature of mixed-effects information: integration changes the covariance structure and hence the information available from a profile.

Model and Assumptions

Definition: For subject \(i=1,\ldots,N\), let \(y_i\) be an \(m_i\)-vector of observations and \(X_i\) a fixed, known design matrix. The Gaussian random-intercept model is $$ y_i=X_i\beta+\mathbf{1}_{m_i}b_i+\varepsilon_i, $$ where \(b_i\sim N(0,\tau^2)\), \(\varepsilon_i\sim N(0,\sigma^2 I_{m_i})\), and all random intercepts and residual vectors are mutually independent. The variance parameters are \(\tau^2\geq 0\) and \(\sigma^2>0\).

The fixed effects are collected in \(\beta\). The vector \(\mathbf{1}_{m_i}\) has \(m_i\) entries, each equal to one. The model assumes a common random-intercept variance and residual variance across subjects, independent subjects, and a correctly specified linear mean \(X_i\beta\). The design matrices are treated as fixed. These assumptions make the marginal distribution and its information available in closed form.

Integrating over \(b_i\), rather than conditioning on its unobserved value, gives

$$ y_i\sim N(X_i\beta,V_i),\qquad V_i=\tau^2\mathbf{1}_{m_i}\mathbf{1}_{m_i}^{T}+\sigma^2 I_{m_i}. $$

Thus two different observations on the same subject have covariance \(\tau^2\), while each observation has variance \(\tau^2+\sigma^2\). Profiles from different subjects are independent. Write \(V_{i,a}\) for the derivative of \(V_i\) with respect to a variance parameter \(a\). Here \(V_{i,\tau^2}=\mathbf{1}\mathbf{1}^{T}\) and \(V_{i,\sigma^2}=I\).

Marginal Fisher Information

For a parameter vector, Fisher information is the expected outer product of the log-likelihood score, equivalently the negative expected Hessian when the usual regularity conditions hold. For the marginal Gaussian likelihood, the information for the fixed effects and variance components is

$$ \mathcal{I}_{\beta\beta}=\sum_{i=1}^{N}X_i^{T}V_i^{-1}X_i,\qquad \mathcal{I}_{ab}=\frac{1}{2}\sum_{i=1}^{N} \operatorname{tr}\!\left(V_i^{-1}V_{i,a}V_i^{-1}V_{i,b}\right). $$

Here \(a\) and \(b\) range over \(\tau^2\) and \(\sigma^2\). The expected cross-information between \(\beta\) and either variance parameter is zero in this Gaussian model. These are expected-information results, evaluated at specified parameter values; they are not claims that the realized likelihood or observed information is block diagonal.

A short derivation makes the role of marginalization explicit. For one subject, put \(r_i=y_i-X_i\beta\). The score for the fixed effects is \(X_i^TV_i^{-1}r_i\). The score for a variance parameter \(a\) is

$$ s_{i,a}=\frac{1}{2}\left[ r_i^{T}V_i^{-1}V_{i,a}V_i^{-1}r_i -\operatorname{tr}(V_i^{-1}V_{i,a}) \right]. $$

Since \(E(r_i)=0\) and \(E(r_ir_i^T)=V_i\), the covariance of the fixed-effect score is \(X_i^TV_i^{-1}X_i\). For the variance scores, the Gaussian quadratic-form identity gives covariance \(\frac{1}{2}\operatorname{tr}(V_i^{-1}V_{i,a}V_i^{-1}V_{i,b})\). The cross-covariance is zero because it involves a centered third moment of a multivariate normal vector, and all such third moments are zero. Independent subjects contribute additively, producing the sums above.

The expression for \(\mathcal{I}_{\beta\beta}\) also shows directly how the integrated random intercept matters: it is \(V_i^{-1}\), not the residual-only matrix \((\sigma^2 I)^{-1}\), that weights the design. Information for a variance component depends on how changing that component changes the entire marginal covariance matrix.

Worked Example: Fixed-Effect Information for Two Sampling Times

Suppose each hypothetical subject has observations at times 0 and 1, with mean \(\beta_0+\beta_1t\). Let \(\tau^2=9\) concentration-units-squared and \(\sigma^2=4\) concentration-units-squared. The design matrix and marginal covariance for one profile are

$$ X_i=\begin{pmatrix}1&0\\1&1\end{pmatrix},\qquad V_i=\begin{pmatrix}13&9\\9&13\end{pmatrix},\qquad V_i^{-1}=\frac{1}{88}\begin{pmatrix}13&-9\\-9&13\end{pmatrix}. $$

The determinant of \(V_i\) is \(13(13)-9(9)=88\), so the stated inverse is valid. Applying the marginal formula gives

$$ X_i^TV_i^{-1}X_i = \begin{pmatrix} 1/11&1/22\\ 1/22&13/88 \end{pmatrix} \approx \begin{pmatrix} 0.09091&0.04545\\ 0.04545&0.1477 \end{pmatrix}. $$

For example, the intercept entry is \((1,1)V_i^{-1}(1,1)^T=8/88=1/11\). With 10 independent subjects following this same schedule, the total fixed-effect information is 10 times this matrix. If the random intercept were incorrectly treated as known, the residual-only calculation would use \(X_i^T(4I)^{-1}X_i\); its intercept entry is \(2/4=0.5\), substantially greater than the marginal value \(0.09091\). The comparison illustrates why latent subject effects must be integrated out for population-design information.

Worked Example: Information for the Two Variance Components

Use the same hypothetical two-observation profile, so \(V_i\) has eigenvalues 22 in the common-observation direction and 4 in the contrast direction. The derivative \(V_{i,\tau^2}=\mathbf{1}\mathbf{1}^T\) has eigenvalues 2 and 0 in these directions; \(V_{i,\sigma^2}=I\) has eigenvalues 1 and 1. The trace formula therefore gives, for one subject,

$$ \mathcal{I}_{\tau^2,\tau^2} =\frac{1}{2}\left(\frac{2}{22}\right)^2 =\frac{1}{242} \approx0.004132, $$
$$ \mathcal{I}_{\tau^2,\sigma^2} =\frac{1}{2}\left(\frac{2}{22}\right)\left(\frac{1}{22}\right) =\frac{1}{484} \approx0.002066, $$
$$ \mathcal{I}_{\sigma^2,\sigma^2} =\frac{1}{2}\left[\left(\frac{1}{22}\right)^2+ \left(\frac{1}{4}\right)^2\right] =\frac{125}{3872} \approx0.03228. $$

For 12 independent profiles with this schedule, multiply each entry by 12. The information matrix for \((\tau^2,\sigma^2)\) is then approximately

$$ \begin{pmatrix} 0.04959&0.02479\\ 0.02479&0.3874 \end{pmatrix}. $$

The units of each entry are the inverse product of the units of its two variance parameters. The off-diagonal entry is positive because increasing either variance increases variation in the common-observation direction. It does not mean the estimates must have positive sampling correlation; that depends on the inverse information and on the estimation procedure.

Worked Example: Why Replication Separates the Variances

Consider one hypothetical observation per subject. Its marginal variance is \(v=\tau^2+\sigma^2\). Both variance parameters have derivative 1 with respect to \(v\), so one subject contributes

$$ \mathcal{I}_{(\tau^2,\sigma^2)} =\frac{1}{2v^2} \begin{pmatrix}1&1\\1&1\end{pmatrix}. $$

The determinant is zero: from a single observation per subject, the marginal variance identifies only the sum \(\tau^2+\sigma^2\), not the two components separately. With two observations in a profile, the common direction has variance \(2\tau^2+\sigma^2\), while the contrast direction has variance \(\sigma^2\). The contrast therefore carries information about residual variation without a contribution from the random intercept. As the previous calculation shows, the two-component information matrix is no longer rank one.

Using the Result Carefully

Marginal information is useful when asking how a proposed profile informs population parameters under a specified random-effects model. It incorporates both the within-subject correlation and the loss of independent information that comes from a shared latent intercept. For unequal profile sizes or sampling schedules, calculate each subject's matrix with its own \(X_i\) and \(V_i\), then add the contributions. The calculation is local: it depends on the variance values used to construct \(V_i\).

Several checks can reveal a faulty calculation or an unsuitable model. Each \(V_i\) must be positive definite for the inverse and regular Gaussian information formula to apply; \(\sigma^2>0\) ensures this here, including when \(\tau^2=0\). The resulting information matrix should be symmetric and positive semidefinite. If variance-component information is singular or nearly singular, some combination of components may be weakly distinguished by the proposed replication pattern. A singular matrix is not fixed simply by collecting more subjects on a schedule that preserves the same lack of separation.

The standard regular information interpretation is simplest at interior parameter values \(\tau^2>0\) and \(\sigma^2>0\). At the boundary \(\tau^2=0\), variance-component inference can have nonstandard behavior, so ordinary interior asymptotic approximations require caution. The Gaussian result also relies on the assumed residual covariance and distribution. If residuals are correlated, heteroscedastic, or non-Gaussian, the marginal covariance and possibly the information expression must be changed.

A common mistake is to calculate \(X_i^T(\sigma^2I)^{-1}X_i\) and call it marginal fixed-effect information. That calculation conditions on the random intercept as though it were known; it omits the extra shared variation and correlation induced by the latent effect. The correction is to integrate over the random intercept, form \(V_i=\tau^2\mathbf{1}\mathbf{1}^T+\sigma^2I\), and use \(X_i^TV_i^{-1}X_i\). Another alternative is observed information from a fitted marginal likelihood, which reflects the particular data set; it is not interchangeable with the expected information used here for design calculations.

The central distinction is therefore between information conditional on subject effects and information in the marginal distribution of observed profiles. For population design, the latter matches the likelihood in which those effects are unobserved. Its matrix structure reveals not only how precisely fixed effects may be estimated, but also whether the planned replication can distinguish sources of variability.

Check Your Understanding

Answer each question, then compare with the brief solutions.

  1. For two observations per subject, state the marginal covariance matrix under the random-intercept model.
  2. Why is the expected cross-information between \(\beta\) and a variance component zero in this Gaussian model?
  3. With one observation per subject, which combination of \(\tau^2\) and \(\sigma^2\) is identified by the marginal variance?
  4. What should replace the residual-only covariance matrix when calculating marginal fixed-effect information?

Solutions. (1) \(V_i=\begin{pmatrix}\tau^2+\sigma^2&\tau^2\\\tau^2&\tau^2+\sigma^2\end{pmatrix}\). (2) The score covariance involves a centered third moment of a multivariate normal residual vector, which is zero. (3) Only the sum \(\tau^2+\sigma^2\) is identified from that marginal variance. (4) Use \(V_i=\tau^2\mathbf{1}\mathbf{1}^T+\sigma^2I\), so the information is \(X_i^TV_i^{-1}X_i\).