Why the Likelihood Starts With the Outcome Definition
A dose-escalation trial may record many clinical details, but a binary DLT likelihood uses a particular summary: for each patient, whether a dose-limiting toxicity occurred within a defined observation window. The likelihood then describes how plausible the observed pattern of DLT and non-DLT outcomes is under specified dose-specific toxicity probabilities. Its construction depends first on defining the outcome and deciding which patients have enough follow-up to classify it.
Let \(Y_{ij}\) denote the binary outcome for patient \(i\) treated at dose level \(j\). Set \(Y_{ij}=1\) if that patient experiences a DLT during the prespecified assessment window, and \(Y_{ij}=0\) if the patient completes that window without a DLT. Write \(p_j\) for the probability of a DLT within that window at dose level \(j\). In this tutorial, each \(p_j\) is a probability associated with a dose, not a model linking different doses.
This definition makes the assessment window part of the endpoint. For example, “DLT by day 28” and “DLT by day 42” are not interchangeable binary outcomes: a patient might have no DLT by day 28 but experience one later. The DLT criteria, observation window, and rules for assigning outcomes should therefore be specified consistently before assembling the likelihood.
From Patient Outcomes to a Bernoulli Likelihood
Suppose the observed outcomes at one dose level are \(y_1,\ldots,y_n\), each equal to zero or one. If the patients’ outcomes are conditionally independent given the common dose-specific probability \(p\), the joint probability of this particular labeled sequence is the product of the individual Bernoulli probabilities. As a function of \(p\), that joint probability is the likelihood.
The product form follows because \(p^{y_i}(1-p)^{1-y_i}\) equals \(p\) for an observed DLT and \(1-p\) for an observed non-DLT. Multiplying across patients gives one factor of \(p\) for each of the \(y\) DLTs and one factor of \(1-p\) for each of the \(n-y\) non-DLTs. A likelihood is a function of the unknown parameter for the data that were observed; it is not a probability distribution over possible values of that parameter.
Worked Example: Four Patient-Level Outcomes at One Dose
Suppose four hypothetical patients receive the same dose and all complete the assessment window. Their outcomes, in patient order, are \(1,0,1,0\). Find the likelihood for \(p\), and evaluate it at \(p=0.25\).
The two DLT outcomes contribute \(p^2\), and the two non-DLT outcomes contribute \((1-p)^2\). Thus the likelihood of this labeled sequence is
At \(p=0.25\), the likelihood is
This value is the probability of this particular ordered sequence under \(p=0.25\). If the data are recorded only as “two DLTs among four patients,” there are \(\binom{4}{2}=6\) possible labeled sequences with that count. The probability of the count is therefore \(6(0.03515625)=0.2109375\). The factor of 6 does not depend on \(p\), so using the count likelihood or the labeled-sequence likelihood gives the same relative support for different values of \(p\).
Aggregating Outcomes by Dose
At dose level \(j\), let \(n_j\) be the number of patients with classifiable binary outcomes and let \(y_j\) be the number of those patients with DLTs. Under conditional independence and a common probability \(p_j\) for patients at that dose, the count has a binomial distribution. Its probability mass includes a combinatorial coefficient because it counts all possible patient-level arrangements with \(y_j\) DLTs.
For several dose levels, if patient outcomes are conditionally independent given their dose-specific probabilities, the likelihood for the observed counts is
Here \(\boldsymbol{p}\) denotes the collection of dose-specific probabilities. For parameter estimation or comparing values of \(\boldsymbol{p}\), the coefficients \(\binom{n_j}{y_j}\) can be omitted when they are constant across the parameter values being considered. They must be retained when the goal is the probability of the observed count itself. The distinction is between the probability of a count and the probability of one specific labeled sequence, not between two different Bernoulli assumptions.
Worked Example: Likelihood From Dose-Specific Counts
Consider a hypothetical trial with three dose levels. Among patients with complete outcome assessments, dose 1 has 1 DLT among 6 patients, dose 2 has 2 among 5, and dose 3 has 3 among 4. Assume conditional independence and a common DLT probability within each dose level. Write the likelihood and evaluate its parameter-dependent part at \(p_1=0.20\), \(p_2=0.35\), and \(p_3=0.65\).
The likelihood for the counts, including count coefficients, is
The parameter-dependent part omits the coefficients \(6\), \(10\), and \(4\). Substitution gives
This product is the parameter-dependent likelihood, not the probability of the three observed counts. To obtain that probability at these values, multiply by \(6\times10\times4=240\), giving approximately \(0.05086\). The values \(p_1,p_2,p_3\) were evaluated separately; this calculation does not impose a trend or other relationship across doses.
Why the Count Likelihood Has This Form
The binomial likelihood can be justified directly from patient-level outcomes. For any one specific arrangement with \(y\) DLTs and \(n-y\) non-DLTs, independence gives probability \(p^y(1-p)^{n-y}\). There are \(\binom{n}{y}\) distinct arrangements of \(y\) DLTs among \(n\) labeled patients. These arrangements are mutually exclusive and each has the same probability, so summing their probabilities gives the binomial probability of the count.
A useful related result is that the likelihood for one dose is maximized at the observed DLT proportion when the count is strictly between zero and \(n\). To see this, take the logarithm of the likelihood without its parameter-independent count coefficient:
For \(0<y<n\), differentiating and setting the derivative to zero gives
The second derivative, \(-y/p^2-(n-y)/(1-p)^2\), is negative for \(0<p<1\), so this stationary point is a maximum. If \(y=0\), the likelihood is maximized at \(p=0\); if \(y=n\), it is maximized at \(p=1\). These boundary estimates describe the maximum of this dose-specific likelihood. They do not by themselves establish that the underlying toxicity probability is known precisely, particularly when \(n\) is small.
Worked Example: Combining Cohorts and Incomplete Assessment
At a hypothetical dose, a first cohort of three patients has outcomes \(0,1,0\), with all three assessment windows complete. A second cohort of three has outcomes \(1,0,0\), also complete. In a third cohort, three additional patients have been enrolled: two complete their windows, with outcomes \(0,1\), while the third has not completed the window and has no observed DLT so far. Construct the binary DLT likelihood from the information currently classifiable.
Among patients with classifiable outcomes, there are \(n=8\) patients and \(y=3\) DLTs: two in the first two cohorts combined and one in the completed part of the third cohort. The patient with an incomplete window and no DLT observed so far cannot yet be classified as a non-DLT for the full window. The likelihood for the currently classifiable outcomes is therefore
At \(p=0.30\), its value for the observed labeled outcomes is
If the incomplete patient later completes the window without a DLT, the updated likelihood is \(p^3(1-p)^6\). If a DLT is observed before the window ends, that patient’s binary outcome is already determined as 1, and the updated likelihood is \(p^4(1-p)^5\). Cohort membership changes how the data are organized, but it does not change the Bernoulli contribution of a classifiable patient.
Assumptions, Diagnostics, and Alternatives
The basic likelihood is appropriate only when its assumptions match the data and endpoint. In particular, the analysis should make clear which DLT definition and time window apply, which patients have classifiable outcomes, and why a common probability is reasonable within each dose level. Conditional independence means that, given the dose-specific probability, one patient’s binary outcome does not provide additional dependence information about another patient’s outcome. If outcomes are clustered or otherwise dependent, the simple product likelihood may understate uncertainty.
Escalation trials often assign later patients’ doses using earlier outcomes. This adaptive allocation does not automatically invalidate a likelihood for the observed outcomes. When the allocation rule is based on recorded trial history and its assignment probabilities do not involve the unknown toxicity probabilities beyond that history, the outcome likelihood is constructed conditional on the assigned doses and observed history. The dose assignment rule still matters for the design and interpretation of the trial; it is not an extra Bernoulli DLT factor.
Useful checks include verifying that every included patient has a defined dose and a consistent outcome window, that \(0\leq y_j\leq n_j\), and that the total number of classifiable outcomes agrees with the patient records. Compare the patient-level outcome list with the dose-level counts; a count that does not equal the sum of the indicators signals a data or coding error. Also inspect whether a zero DLT count means all patients completed the window without DLT, or instead includes patients whose follow-up is still pending. Those are not equivalent data states.
The simple binary likelihood does not use the timing of DLTs within the window. It also does not, by itself, model differences between patients, dependence, or partially observed follow-up. A time-to-event approach can use event times and handle censoring under its own assumptions; it is an alternative when follow-up timing is central, not a reason to label an incomplete patient as a non-DLT. A dose-response model can relate probabilities across ordered doses, whereas separate dose-specific Bernoulli likelihoods leave each \(p_j\) unrestricted. The latter is transparent but may be imprecise when there are few patients per dose. The logistic dose-toxicity model is treated separately in the next topic.
The main practical advantage of an explicit Bernoulli likelihood is that each factor has a clear interpretation and the aggregated count form is easy to verify. Its limitations are equally direct: the binary summary discards event timing, a small count can leave substantial uncertainty about \(p_j\), and an unrestricted set of dose-specific probabilities does not borrow information across doses. The appropriate likelihood is therefore determined by the endpoint, follow-up, and assumptions—not by which formula is easiest to compute.
Check Your Understanding
Answer each question, then compare your reasoning with the solutions.
- At one dose, 2 of 7 patients complete the assessment window with DLTs. Write the likelihood for \(p\), omitting any parameter-independent coefficient.
- For 3 DLTs among 5 patients, explain why the probability of the count differs from the probability of one specified patient-level sequence.
- At a dose, 1 of 4 patients has a DLT and three complete their windows without DLT. A fifth patient has not completed the window and has no DLT observed so far. What \(n\), \(y\), and likelihood should be used for the currently classifiable binary outcomes?
- Under the dose-specific Bernoulli model, what is the maximum-likelihood estimate of \(p\) for 4 DLTs among 10 patients, and what assumption supports that calculation?
Solutions. (1) There are 2 DLTs and 5 non-DLTs, so \(L(p)=p^2(1-p)^5\). (2) A specified sequence has probability \(p^3(1-p)^2\); the count has \(\binom{5}{3}=10\) possible sequences, so its probability is \(10p^3(1-p)^2\). (3) Use the four completed outcomes: \(n=4\), \(y=1\), and \(L(p)=p(1-p)^3\). The pending patient is not yet a completed-window non-DLT. (4) The estimate is \(\widehat{p}=4/10=0.400\). This follows from the binomial likelihood when outcomes are conditionally independent and share a common DLT probability at that dose.