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Optimal Sampling for Individual PK Models · Tutorial 58 of 497

c-Optimal Sampling for Clearance or Half-Life

Learn how the target parameter changes the optimal sampling-time allocation, and why a schedule that is efficient for clearance or half-life need not be D-optimal.

Advanced 12 min read

What You'll Learn

  • Define c-optimality as minimizing the approximate variance of a specified parameter target.
  • Derive endpoint allocations for log clearance and log half-life in a one-compartment IV model.
  • Calculate target variances and standard errors for locally optimal and D-optimal schedules.
  • Explain why half-life and clearance can favor different sampling allocations.
  • Identify assumptions, diagnostics, and practical constraints that can invalidate a simple endpoint schedule.
  • Distinguish target-specific c-optimality from the broader information objective of D-optimality.

Why the Target Changes the Sampling Schedule

A sampling schedule is not “optimal” in the abstract. It is optimal relative to an objective. A schedule designed to estimate several model parameters jointly can differ from one designed to estimate a single clinically relevant quantity, such as clearance or terminal half-life. The distinction matters when the number of samples is limited: allocating observations to improve one target can leave other parameters less precisely estimated.

This tutorial derives that distinction for a one-compartment IV bolus model. The derivation is local: it uses sensitivities and an approximate covariance matrix evaluated at nominal parameter values. It assumes that the observed log concentrations follow a linear terminal profile with independent, constant-variance errors. These assumptions make the target-specific allocation explicit; more complex models require their own sensitivity calculations.

Definition: For a parameter vector \(\theta\), a scalar target \(g(\theta)\), and a design with Fisher information matrix \(I(\theta)\), the local c-optimal design minimizes \(c^\mathsf{T}I(\theta)^{-1}c\), where \(c=\nabla_\theta g(\theta)\), among the candidate designs being considered. This quantity approximates the variance of the estimated target. The design is local because the information and gradient are evaluated at specified nominal parameter values.

Model and Derivation of the Endpoint Allocation

Suppose a dose \(D\) is administered as an IV bolus to a one-compartment model. The concentration at time \(t\) is \(C(t)=(D/V)e^{-kt}\), where \(V\) is volume and \(k=CL/V\) is the elimination rate constant. Write the log-concentration model as \(Y(t)=\log C(t)=a+bt+\varepsilon(t)\), with \(a=\log(D/V)\), \(b=-k\), and \(\varepsilon(t)\sim N(0,\sigma^2)\). Assume errors are independent across sampling times, \(\sigma^2\) is constant, the dose is known, and \(b<0\). The model is appropriate only when the one-compartment exponential adequately describes the observed profile over the design window.

Consider \(n\) observations at times 0 and \(T\), with proportion \(p\) at time 0 and \(q=1-p\) at time \(T\). For the linear parameter vector \((a,b)\), the approximate covariance of the estimates is determined by the information matrix. Equivalently, the fitted endpoint means are \(a\) and \(a+bT\), with variances \(\sigma^2/(np)\) and \(\sigma^2/(nq)\), respectively. For any differentiable target \(g(a,b)\), let \(g_a\) and \(g_b\) denote its derivatives at the nominal values. Since \(b\) is the difference of the endpoint means divided by \(T\), the delta-method variance is

$$ \operatorname{Var}\{\widehat{g}\}\approx \frac{\sigma^2}{n}\left[ \frac{(g_a-g_b/T)^2}{p} +\frac{(g_b/T)^2}{q} \right]. $$

The terms in brackets show how the target combines information from the two endpoints. Define \(A=g_a-g_b/T\) and \(B=g_b/T\). For nonzero \(A\) and \(B\), minimizing \(A^2/p+B^2/(1-p)\) gives \(p=|A|/(|A|+|B|)\). One justification is the Cauchy–Schwarz inequality:

$$ \frac{A^2}{p}+\frac{B^2}{q} \geq \frac{(|A|+|B|)^2}{p+q} =(|A|+|B|)^2, $$

with equality when \(p:q=|A|:|B|\). This is a target-specific allocation, not a universal rule. If one coefficient is zero, the formal minimum puts all observations at the endpoint associated with the nonzero coefficient; that boundary design may not estimate both model parameters. In practice, a positive minimum allocation or another constraint may be needed to retain parameter identifiability.

Clearance and Half-Life Have Different Targets

In the \((a,b)\) parameterization, clearance is \(CL=Dk/V\), so \(\log CL=\log D-a+\log(-b)\). Terminal half-life is \(t_{1/2}=\log(2)/k\), so \(\log t_{1/2}=\log\{\log(2)\}-\log(-b)\). The delta-method gradients are therefore different:

$$ \nabla\log CL=\left(-1,\frac{1}{b}\right) =\left(-1,-\frac{1}{k}\right), \qquad \nabla\log t_{1/2}=\left(0,-\frac{1}{b}\right) =\left(0,\frac{1}{k}\right). $$

For log clearance, the endpoint coefficients are \(A=-1+1/(kT)\) and \(B=-1/(kT)\). Thus the locally optimal proportion at time 0 is \(p^*=\lvert-1+1/(kT)\rvert/\{\lvert-1+1/(kT)\rvert+\lvert1/(kT)\rvert\}\), with the remainder at \(T\). For log half-life, \(A=-1/(kT)\) and \(B=1/(kT)\), so the optimum is balanced: half the observations at each endpoint. These formulas assume both endpoints are feasible and that their errors have the same variance.

For comparison, the determinant of the information matrix for estimating \((a,b)\) is proportional to \(pqT^2\). At fixed \(n\) and fixed endpoints, this determinant is largest when \(p=q=1/2\). D-optimality therefore balances the endpoints for this model, regardless of whether the scientific target is clearance or half-life. The half-life schedule happens to agree with that D-optimal allocation under these assumptions; the clearance schedule need not.

Worked Example: Clearance-Targeted Times for a Nominal Elimination Rate

Suppose the hypothetical nominal elimination rate is \(k=0.40\ \mathrm{h}^{-1}\), the feasible endpoints are 0 and \(T=10\ \mathrm{h}\), and \(n=12\) log-concentration observations are planned. Assume the stated model and equal log-scale residual variance at both endpoints. Here \(kT=4\), so for log clearance \(A=-1+1/4=-0.75\) and \(B=-1/4=-0.25\). The c-optimal allocation is \(p=0.75/(0.75+0.25)=0.75\): nine observations at 0 h and three at 10 h.

For the half-life target, the endpoint coefficients have equal absolute value, so its c-optimal allocation is six observations at each endpoint. That is also the D-optimal allocation for estimating \((a,b)\). To compare precision, use the variance formula with \(\sigma=0.10\) log-concentration units. For log clearance under the 75:25 schedule:

$$ \operatorname{Var}(\widehat{\log CL}) \approx \frac{0.10^2}{12} \left(\frac{0.75^2}{0.75}+\frac{0.25^2}{0.25}\right) =\frac{0.01}{12}(0.75+0.25) =0.0008333, \qquad SE\approx 0.02887. $$

Under the balanced schedule, the corresponding variance is \(\frac{0.01}{12}(0.75^2/0.50+0.25^2/0.50) =\frac{0.01}{12}(1.125+0.125)=0.0010417\), giving \(SE\approx0.03227\). The clearance-targeted allocation is more precise for log clearance in this local calculation. Because this is a log-scale target, the standard error is in log units and can be interpreted approximately as relative uncertainty on the original clearance scale.

Worked Example: Precision for Half-Life Under Two Allocations

Continue with \(k=0.40\ \mathrm{h}^{-1}\), \(T=10\ \mathrm{h}\), \(n=12\), and \(\sigma=0.10\). For log half-life, \(A=-1/(kT)=-0.25\) and \(B=0.25\). The balanced schedule gives:

$$ \operatorname{Var}(\widehat{\log t_{1/2}}) \approx \frac{0.01}{12} \left(\frac{0.25^2}{0.50}+\frac{0.25^2}{0.50}\right) =\frac{0.01}{12}(0.25) =0.0002083, \qquad SE\approx0.01443. $$

If the 12 observations instead use the 75:25 clearance allocation, then the variance is \(\frac{0.01}{12}(0.25^2/0.75+0.25^2/0.25) =\frac{0.01}{12}(0.08333+0.25)=0.0002778\), and \(SE\approx0.01667\). The balanced design is more precise for log half-life, although both designs estimate it. These are approximate standard errors in log units; they are not exact confidence intervals or guarantees about an individual estimate.

Checking Candidate-Design Calculations

A target variance is obtained from the target gradient and the inverse information matrix, not from the determinant alone. The following arithmetic illustrates how a target-specific comparison should be checked. Suppose a hypothetical local calculation reports \(c^\mathsf{T}I^{-1}c=12/48\) for a three-to-one allocation and \(20/64\) for a balanced allocation, with log-scale residual SD \(\sigma=0.10\). If these quantities are the design factors before multiplication by \(\sigma^2\), the variances are:

$$ 0.10^2\left(\frac{12}{48}\right) =0.01(0.25)=0.0025, \qquad SE=\sqrt{0.0025}=0.05, $$

and

$$ 0.10^2\left(\frac{20}{64}\right) =0.01(0.3125)=0.003125, \qquad SE=\sqrt{0.003125}\approx0.05590. $$

The three-to-one allocation has the smaller variance for this specified target, even if the balanced design has the larger information determinant. The comparison is valid only if both design factors were computed for the same target, parameterization, nominal values, and residual-error assumptions.

Diagnostics, Limitations, and Alternatives

Before using an endpoint formula, check that the design and model support its assumptions. Plot or inspect the predicted and observed log concentrations over time: systematic curvature can indicate that the assumed exponential profile is inadequate. Check whether residual spread changes with concentration or time; unequal variances invalidate the equal-variance formulas and can change the optimal allocation. Verify that the nominal \(k\) is plausible, since the clearance allocation depends on \(kT\). A schedule highly sensitive to that nominal value may not perform well for the actual individual.

The formula also presumes that both endpoints are available and measurable. A nominal sample at time zero may be physically impossible after an IV bolus, and a late concentration may fall below quantification limits. If the earliest and latest feasible times are instead \(L\) and \(U\), use the model sensitivities at those times and recompute the target variance; do not simply assume the 0-to-\(T\) formula still applies. Minimum spacing, clinic windows, assay precision, and a requirement to estimate nuisance parameters can also alter the design.

In a two-compartment model, the terminal profile and its relation to clearance depend on more than one exponential component. The one-compartment derivation should not be transferred directly. For such a model, calculate the sensitivity of the chosen target to all relevant parameters and evaluate \(c^\mathsf{T}I^{-1}c\) for candidate schedules, respecting the residual-error model and feasibility constraints.

D-optimality is a natural alternative when joint estimation of the model parameters is the priority: it maximizes the information determinant, a measure of overall parameter information. c-optimality instead minimizes uncertainty for the stated scalar target. Neither criterion is universally superior. A D-optimal design may sacrifice precision for a particular target; a c-optimal design may leave some parameters poorly estimated or even fail to identify all parameters if it concentrates too heavily. A constrained c-optimal design can impose minimum sampling proportions or require a nonsingular information matrix when broader parameter estimation is also needed.

  • Common mistake: “D-optimal means best for clearance.” A large determinant summarizes joint information; it does not guarantee minimum variance for clearance. Calculate the target-specific variance.
  • Common mistake: using the allocation formula without naming the target. The coefficients \(A\) and \(B\) come from that target’s gradient. Derive them for log clearance or log half-life rather than reusing a schedule automatically.
  • Common mistake: treating a local result as universal. The schedule depends on nominal parameters, feasible times, and the assumed error model. Check sensitivity to those choices and compare candidate designs under realistic constraints.
Key takeaway: Under the stated one-compartment, equal-variance log-error model, half-life estimation favors balanced endpoint sampling, whereas clearance can favor an unequal allocation determined by \(kT\). The c-optimal choice is target-specific and should be checked against model adequacy, feasibility, and the need to estimate other parameters.

Check Your Understanding

Answer each question using the model and assumptions stated above. Short solutions follow the questions.

  1. For \(kT=2\), calculate the c-optimal proportion at time 0 for log clearance.
  2. Why is a balanced endpoint allocation D-optimal for the linear log-concentration model?
  3. With \(\sigma=0.08\) and \(n=16\), calculate the approximate variance and standard error of log half-life for a balanced endpoint design when \(kT=2\).
  4. What should be done if late samples have larger residual variance than early samples?
  5. Give one reason a formally c-optimal design might be undesirable when the goal includes estimating both model parameters.

Solutions. (1) Here \(A=-1+1/2=-0.5\) and \(B=-1/2=-0.5\), so \(p^*=0.5/(0.5+0.5)=0.50\). (2) The information determinant is proportional to \(pqT^2\); since \(p+q=1\), the product \(pq\) is maximized at \(p=q=0.50\). (3) For log half-life, \(|A|=|B|=1/(kT)=0.5\). Thus the variance is \(0.08^2/16\{0.5^2/0.5+0.5^2/0.5\}=0.0064/16(1)=0.000400\), and \(SE=\sqrt{0.000400}=0.0200\) log units. (4) Use the appropriate heteroscedastic residual-error model and recompute the information and target variance; equal-variance allocation formulas no longer apply. (5) The design may concentrate observations in a way that leaves the full information matrix singular or poorly conditioned, limiting estimation of nuisance or other model parameters.

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