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Optimal Sampling for Individual PK Models · Tutorial 61 of 497

Checking Local Design Dependence on Nominal Values

You will learn to reassess a locally optimized PK schedule across plausible parameter values and recognize when changes in sensitivity profiles make its apparent advantage unreliable.

Advanced 12 min read

What You'll Learn

  • Define local design dependence in terms of parameter-specific sensitivity profiles and information matrices.
  • Recalculate one-compartment PK sensitivities and determinants at alternative fixed parameter values.
  • Compare candidate schedules using determinant ratios and D-efficiency at the same parameter values.
  • Identify ranking reversals and diagnose weak or unstable local designs.
  • Distinguish parameter-value sensitivity from changes in assay precision or sampling constraints.
  • Use parameter grids and explicit robustness criteria to support design choices.

Why Recheck a Locally Optimized Schedule?

An individual PK schedule is often optimized using a specified set of nominal parameter values. The resulting times are locally optimal: they perform well for the model sensitivities evaluated at those particular values. If the true fixed parameters differ, the concentration-time curve and its sensitivities can change, and another schedule may be more informative. A design that looks excellent at one nominal point is not automatically reliable across a plausible range.

The practical question is not whether one can find a single schedule that is best for every possible parameter value. It is whether the proposed schedule remains sufficiently informative over the parameter values considered plausible for the design problem. Answering that requires recalculating sensitivities and design diagnostics at each value, rather than assuming that the nominal result carries over unchanged.

The calculations below use a one-compartment bolus model as a clear setting for checking local dependence. The same logic applies to other individual PK models: specify the model and error assumptions, evaluate the sensitivities at each fixed parameter vector, and compare candidate schedules on that common basis. This is a conditional, local assessment; it is not a claim that the unknown parameters have been estimated or averaged over a population.

Model, Sensitivities, and Information

Definition: A design is locally dependent on nominal values when its information or its ranking relative to other designs changes materially as the fixed parameter values used to calculate sensitivities change. A local design assessment evaluates the model derivatives at a specified parameter vector; checking dependence repeats that assessment at other plausible vectors.

Suppose a hypothetical individual receives an intravenous bolus dose \(D\), with concentration at time \(t\) described by \(C(t)=A e^{-kt}\), where \(A=D/V\), \(V\) is volume of distribution, and \(k\) is the elimination rate constant. Use the parameter vector \(\theta=(\log A,k)\). Assume observations at fixed times have independent, normally distributed additive errors with known variance \(\sigma^2\), the model is correct, and \(A\), \(k\), and \(\sigma\) are fixed when evaluating a local design.

$$ Y_j=C(t_j;\theta)+\epsilon_j,\qquad \epsilon_j\sim N(0,\sigma^2),\qquad C(t;\theta)=e^{\log A}e^{-kt}. $$

The sensitivity vector at time \(t_j\) is the gradient of the predicted concentration with respect to the parameters. For this parameterization, its components are concentration per unit change in \(\log A\), and concentration times hours per unit change in \(k\), respectively. With independent errors of common variance, the local Fisher information matrix is the sum of the weighted outer products of these vectors.

$$ g(t_j;\theta)= \begin{pmatrix} \frac{\partial C(t_j;\theta)}{\partial \log A}\\[2pt] \frac{\partial C(t_j;\theta)}{\partial k} \end{pmatrix} = \begin{pmatrix} C(t_j;\theta)\\ -t_jC(t_j;\theta) \end{pmatrix}, \qquad I(\theta;\mathcal{D})= \frac{1}{\sigma^2}\sum_{j=1}^{n}g(t_j;\theta)g(t_j;\theta)^{\mathsf T}. $$

For a two-parameter design with exactly two distinct sampling times \(t_1\) and \(t_2\), the determinant has a particularly useful form. A zero determinant means the two sensitivity vectors do not provide independent information about both parameters. A larger determinant indicates greater joint information for this parameterization at the fixed parameter values and under the stated error model.

Why the Determinant Changes

Write \(C_i=C(t_i;\theta)\). The two sensitivity vectors form the columns of a matrix whose rows are \((C_1,-t_1C_1)\) and \((C_2,-t_2C_2)\). The information matrix is the product of the transpose and the matrix, divided by \(\sigma^2\). Its determinant is therefore the squared determinant of that sensitivity matrix, divided by \(\sigma^4\):

$$ \det I(\theta;\{t_1,t_2\}) =\frac{\{C_1C_2(t_2-t_1)\}^2}{\sigma^4}. $$

This expression shows two sources of local design dependence. The time separation \(t_2-t_1\) helps distinguish the amplitude and elimination rate, while the concentrations \(C_1\) and \(C_2\) depend on the fixed values of \(A\) and \(k\). If elimination is faster, later concentrations can be much lower, changing the information contributed by late samples. Merely keeping the same sample times does not keep the sensitivity profiles or the information matrix fixed.

The derivation relies on the stated assumptions: the predicted concentration is differentiable in the parameters, observation errors are independent with common known variance, and the design contains exactly two observations for the displayed two-time determinant. With more observations, the information is still the sum of weighted sensitivity outer products, but the two-time closed form does not generally apply. If the residual variance model changes with concentration, the weights must also be recalculated according to that model.

Worked Example: Recalculating Information at an Alternative Elimination Rate

Consider a hypothetical dose of \(100\) mg and fixed volume \(V=12\) L, so \(A=100/12=8.3333\) mg/L. Let the sample times be \(1\) h and \(5\) h, and let the additive residual standard deviation be \(\sigma=0.5\) mg/L. First evaluate the design at nominal \(k=0.125\) h\(^{-1}\).

The predicted concentrations are \(C_1=8.3333e^{-0.125(1)}\approx7.3541\) mg/L and \(C_2=8.3333e^{-0.125(5)}\approx4.4605\) mg/L. Substituting in the determinant formula gives:

$$ \det I =\frac{\{(7.3541)(4.4605)(5-1)\}^2}{(0.5)^4} \approx 2.755\times 10^5. $$

Now keep the same dose, volume, error model, and times, but evaluate at the plausible alternative \(k=0.150\) h\(^{-1}\). The determinant is proportional to \(e^{-2k(t_1+t_2)}\) when \(A\), \(\sigma\), and the times are fixed. Therefore its ratio to the nominal determinant is \(e^{-2(0.150-0.125)(1+5)}=e^{-0.3}\approx0.7408\). Thus the recalculated determinant is approximately \(204{,}073\), or \(2.041\times10^5\). The schedule retains substantial information, but its determinant is about \(25.9\%\) lower at the faster elimination rate. This comparison is conditional on the same parameterization and error assumptions at both evaluations.

Check Whether Design Rankings Persist

The determinant at one parameter value is not enough to establish that a schedule is robust. A useful check evaluates all candidate schedules at each fixed parameter vector using the same model, parameterization, and error assumptions. Then compare their information and determine whether their relative ranking changes. For two parameters, D-efficiency of a candidate design relative to a reference design at a given parameter vector is the square root of their determinant ratio. It is a relative measure of joint information, not a probability or a guarantee about estimation error in a particular dataset.

$$ \operatorname{D\text{-}eff}(\mathcal{D}_a\mid\mathcal{D}_b,\theta) = \left\{\frac{\det I(\theta;\mathcal{D}_a)} {\det I(\theta;\mathcal{D}_b)}\right\}^{1/2}. $$

The comparison is meaningful only when both determinants use the same parameterization and the same fixed parameter values. A parameterization change can change the numerical scale of a determinant. Likewise, comparing determinants computed under different error variances would mix parameter-value sensitivity with a change in the assumed observation precision.

Worked Example: A Candidate Schedule Ranking Reverses

Compare two hypothetical two-sample schedules under the same \(A=8.3333\) mg/L and \(\sigma=0.5\) mg/L: schedule \(a=\{1,5\}\) h and schedule \(b=\{1,4\}\) h. At any fixed \(k\), the common factors involving \(A\) and \(\sigma\) cancel in the determinant ratio. Using the two-time formula, the ratio is:

$$ \frac{\det I(\{1,5\})}{\det I(\{1,4\})} = \left\{\frac{4}{3}e^{-k(6-5)}\right\}^{2} = \frac{16}{9}e^{-2k}. $$

At \(k=0.10\) h\(^{-1}\), this ratio is \((16/9)e^{-0.20}\approx1.456\). The D-efficiency of schedule \(a\) relative to \(b\) is \(\sqrt{(16/9)e^{-0.20}}\approx1.206\), so schedule \(a\) has the larger determinant at this fixed value. At \(k=0.40\) h\(^{-1}\), the ratio is \((16/9)e^{-0.80}\approx0.799\), and the relative D-efficiency is \(\sqrt{0.799}\approx0.894\). The ranking has reversed: schedule \(b\) now has the larger determinant. The reversal occurs when \((16/9)e^{-2k}=1\), which gives \(k=\frac{1}{2}\log(16/9)\approx0.288\) h\(^{-1}\). This does not establish that either schedule is universally best; it demonstrates why candidate rankings should be checked over the plausible range of \(k\).

A Practical Reassessment Workflow

A useful assessment is systematic rather than based on a single alternative value. Specify a plausible set of fixed parameter vectors, recalculate the relevant sensitivities and information matrices at each vector, and report how the candidate schedules compare. The parameter values are held fixed for each calculation; the procedure does not assign probabilities to those values unless such probabilities are supplied as part of a separate design criterion.

1
Set the assessment conditions.
State the structural PK model, parameterization, residual error assumptions, candidate times, and plausible ranges for the fixed parameters. Keep the error model and parameterization consistent across comparisons.
2
Recalculate sensitivity profiles.
At each parameter vector, evaluate the concentration and its derivatives at every candidate sampling time. Inspect whether important sensitivities become small or whether different parameter sensitivities become difficult to distinguish.
3
Rebuild and compare information.
Form each local information matrix and calculate the chosen design diagnostic, such as a determinant or a target-specific criterion. Compare candidate schedules at the same parameter vector before interpreting their relative performance.
4
Summarize stability and limitations.
Report where rankings remain stable, where they reverse, and where information becomes weak or nearly singular. If the decision requires a single schedule, state the robustness criterion used to make that choice.

A parameter grid can include combinations at the low and high ends of plausible ranges, as well as intermediate values. Checking only one parameter at a time may miss important interactions: for example, a change in amplitude may affect concentration magnitudes while a change in elimination rate changes the relative contribution of early and late samples. For a small grid, reporting each result directly is transparent. For a larger grid, summarize the minimum relative efficiency or the range of each diagnostic, while retaining enough detail to identify where the worst performance occurs.

Diagnostics, Alternatives, and Limitations

Several diagnostics help identify a schedule that is fragile across nominal values. First, look for a large drop in determinant or target-specific information at plausible parameter values. Second, inspect whether candidate rankings reverse. Third, check for nearly linearly dependent sensitivity vectors or an information matrix with a very small eigenvalue; these indicate that some parameter combination is poorly distinguished locally. Parameter correlations from candidate designs can also flag near-confounding, but a correlation alone does not show how much information is available overall. These diagnostics should be interpreted together.

If the determinant remains positive but becomes very small, the design may technically identify both parameters in the local calculation while still providing weak information. A zero or nearly zero determinant can arise when sample times coincide, when sensitivities vanish, or when the sensitivity directions become indistinguishable. In the exponential example, very late samples at rapid elimination can have concentrations close to zero, making both sensitivity components small. Computational checks should also confirm that times respect the design constraints and that the model and units have been implemented consistently.

The main alternative to selecting the schedule optimized at one nominal vector is to adopt an explicit robustness criterion. One may choose a schedule that performs acceptably at every point on a prespecified grid, for example by maximizing the minimum relative efficiency over that grid, or compare a weighted average if justified weights over parameter values are available. These are different decision rules, not consequences of local D-optimality. A grid-based worst-case check is only as comprehensive as its grid and plausible parameter ranges.

A further limitation is that this assessment treats the fixed parameter values as known separately at each evaluation and uses local, model-based information. It does not account for between-subject variability, uncertainty in the residual model, model misspecification, or parameter distributions unless those features are explicitly included in the design calculation. Nor does a stable determinant guarantee that every parameter estimate will be accurate in a realized dataset. The method is a diagnostic of local information, not a substitute for checking model assumptions or practical feasibility.

Common Mistake

Common mistake: “The schedule was D-optimal at the nominal values, so it remains optimal throughout the plausible parameter range.” Correction: Local optimality is conditional on the parameter values used to calculate sensitivities. Recalculate the information for the candidate schedules at each plausible fixed value, compare them under a consistent criterion, and report any ranking reversals or weak-information regions.

Another frequent error is to change parameter values and then compare only concentration predictions. A design comparison concerns derivatives and the information they imply, not concentration fit alone. Conversely, if the model, variance, or parameterization changes between evaluations, an information difference cannot be attributed solely to nominal-value dependence.

Check Your Understanding

Answer each question using the stated model and assumptions. Brief solutions follow.

  1. In the one-compartment model, what does a zero determinant of the two-time information matrix indicate about local information for \(\log A\) and \(k\)?
  2. For times \(1\) h and \(5\) h, the determinant at \(k=0.125\) h\(^{-1}\) is approximately \(275{,}469\). What is its value at \(k=0.150\) h\(^{-1}\), with all other quantities fixed?
  3. At \(k=0.10\) h\(^{-1}\), the determinant ratio for schedules \(\{1,5\}\) and \(\{1,4\}\) is approximately \(1.456\). Which has the higher determinant, and what is the D-efficiency of the first relative to the second?
  4. Why must both candidate schedules be evaluated at the same fixed parameter vector when comparing their determinants?
  5. Name one reason that a grid-based robustness assessment might fail to represent performance over the full plausible parameter range.

Solutions. (1) The two sensitivity directions do not span two independent parameter directions, so the local information matrix is singular and both parameters cannot be locally distinguished from these observations. (2) The ratio is \(e^{-2(0.150-0.125)(1+5)}=e^{-0.3}\approx0.7408\), so the determinant is approximately \(204{,}073\). (3) Schedule \(\{1,5\}\) has the higher determinant; its relative D-efficiency is \(\sqrt{(16/9)e^{-0.20}}\approx1.206\). (4) The sensitivities depend on the parameter values, so different evaluation points would confound schedule differences with parameter-value differences. (5) The grid may omit an intermediate region or parameter combination where sensitivities weaken or candidate rankings reverse.

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