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Dose Regimens and Titration Algorithms · Tutorial 247 of 497

Deriving Loading and Maintenance Dose Schedules

Derive loading doses that attain a chosen concentration promptly and maintenance doses that sustain a target average, peak, trough, or continuous-infusion concentration.

Advanced 11 min read

What You'll Learn

  • State the one-compartment assumptions needed for loading- and maintenance-dose calculations.
  • Derive maintenance bolus doses from a target average steady-state concentration.
  • Calculate a loading bolus to match either an initial target concentration or a steady-state peak.
  • Derive maintenance and loading amounts for continuous infusion.
  • Distinguish target average concentration from target peak or trough.
  • Diagnose unit, bioavailability, and regimen-matching errors.

Why Separate Loading and Maintenance Doses?

A maintenance regimen determines the long-run concentration pattern, but with repeated dosing it can take several elimination half-lives to approach that pattern. A loading dose is an initial dose chosen to bring concentration closer to a specified target sooner. The maintenance regimen then replaces drug eliminated over time and determines the continuing concentration profile.

These are related but distinct design tasks. A maintenance dose is set by the rate of drug input needed to balance elimination. A loading dose is set by the amount of drug needed in the body at a particular time. The appropriate loading amount therefore depends on which concentration is intended to be attained: an initial concentration, a steady-state peak, or a steady-state trough are not interchangeable targets.

Definition: A maintenance dose is a repeated dose, or a continuous input rate, selected to sustain a desired long-run concentration or concentration profile. A loading dose is an initial dose selected to establish a specified concentration promptly. In the equations below, \(V\) is the apparent volume of distribution, \(CL\) is clearance, \(k=CL/V\) is the first-order elimination rate constant, \(F\) is the fraction of an administered dose reaching systemic circulation, and \(\tau\) is the interval between bolus doses.

Model and Assumptions

The derivations use a one-compartment model with instantaneous mixing and linear, first-order elimination. The drug amount in the compartment is \(A(t)\), and concentration is \(C(t)=A(t)/V\). Elimination is \(kA(t)\), where \(k=CL/V\). Assume that \(V\), \(CL\), and \(F\) are constant over the period considered; that doses are administered as specified; and that there is no additional absorption delay or distribution phase.

For an administered bolus dose \(D\), systemic input is \(FD\). This notation allows for bioavailability below one; for an intravenous bolus, \(F=1\). For an infusion administered at rate \(R_0\), systemic input rate is \(FR_0\). The concentration targets must be clinically and mathematically defined: a target average concentration over a dosing interval is different from a target immediately after a dose or immediately before the next dose.

These assumptions are useful for deriving schedules, not guarantees that a real patient follows the model exactly. Changes in clearance, incomplete adherence, nonlinear elimination, or distribution into multiple compartments can make the calculated schedule inaccurate. The equations should therefore be interpreted as model-based predictions.

Repeated Bolus Doses: Maintenance and Loading

With repeated bolus doses \(D\) every \(\tau\) hours, each dose raises concentration by \(FD/V\), and elimination reduces concentration exponentially between doses. Let \(C_{\max,ss}\) denote the concentration just after a dose at steady state, and \(C_{\min,ss}\) the concentration just before the next dose.

$$ C_{\min,ss}=C_{\max,ss}e^{-k\tau}, \qquad C_{\max,ss}=\frac{FD}{V(1-e^{-k\tau})}. $$

The average steady-state concentration over an interval follows from mass balance. At steady state, the systemic amount entering during each interval, \(FD\), equals the amount eliminated during that interval. Since elimination rate is \(CL\,C(t)\), the amount eliminated over the interval is \(CL\int_0^\tau C(t)\,dt\). Dividing by \(CL\tau\) gives the interval-average concentration.

$$ FD=CL\int_0^\tau C(t)\,dt \quad\Longrightarrow\quad C_{\mathrm{ss,avg}}=\frac{1}{\tau}\int_0^\tau C(t)\,dt =\frac{FD}{CL\,\tau}. $$

Thus, if the desired target is the average steady-state concentration \(C_{\mathrm{target}}\), the maintenance dose is

$$ D_{\mathrm{maint}}=\frac{CL\,\tau\,C_{\mathrm{target}}}{F}. $$

A simple loading bolus that establishes concentration \(C_{\mathrm{target}}\) immediately is obtained by setting the initial amount \(FD_{\mathrm{load}}\) equal to \(V C_{\mathrm{target}}\). This does not mean that the later steady-state peak will equal that target. If instead the goal is to start at the steady-state peak produced by the maintenance regimen, the loading dose must replace the accumulated amount that would otherwise be present at that point.

$$ D_{\mathrm{load,peak}} =\frac{V C_{\max,ss}}{F} =\frac{D_{\mathrm{maint}}}{1-e^{-k\tau}}. $$

This result follows because a steady-state peak includes the surviving contribution from the current dose and from all earlier doses. If the concentration just after the loading dose is \(C_{\max,ss}\), then after \(\tau\) hours it decays to \(C_{\min,ss}\). Giving the maintenance dose at that time raises the concentration back to \(C_{\max,ss}\), reproducing the steady-state cycle.

Worked Example: Targeting an Average Concentration and a Steady-State Peak

Hypothetical data: A drug has \(V=40\) L, \(CL=4\) L/h, and oral bioavailability \(F=0.80\). Doses are given every \(\tau=12\) h. The target average steady-state concentration is \(5.0\) mg/L. Calculate the maintenance dose, the simple loading dose that initially gives 5.0 mg/L, and the loading dose that matches the steady-state peak.

The elimination rate constant is

$$ k=\frac{CL}{V}=\frac{4\ \mathrm{L/h}}{40\ \mathrm{L}}=0.100\ \mathrm{h}^{-1}. $$

Using the average-concentration target, the maintenance dose is

$$ D_{\mathrm{maint}} =\frac{CL\,\tau\,C_{\mathrm{target}}}{F} =\frac{(4\ \mathrm{L/h})(12\ \mathrm{h})(5.0\ \mathrm{mg/L})}{0.80} =300\ \mathrm{mg}. $$

A bolus that initially establishes \(5.0\) mg/L is

$$ D_{\mathrm{load}} =\frac{V C_{\mathrm{target}}}{F} =\frac{(40\ \mathrm{L})(5.0\ \mathrm{mg/L})}{0.80} =250\ \mathrm{mg}. $$

That loading dose is not the same as a dose that matches the maintenance regimen's steady-state peak. First calculate the peak for the 300 mg maintenance dose:

$$ C_{\max,ss} =\frac{(0.80)(300\ \mathrm{mg})} {(40\ \mathrm{L})(1-e^{-(0.100\ \mathrm{h}^{-1})(12\ \mathrm{h})})} =\frac{240\ \mathrm{mg}}{(40\ \mathrm{L})(0.6988)} =8.586\ \mathrm{mg/L}. $$

Therefore, the peak-matching loading dose is

$$ D_{\mathrm{load,peak}} =\frac{(40\ \mathrm{L})(8.586\ \mathrm{mg/L})}{0.80} =429.3\ \mathrm{mg}. $$

The 250 mg dose targets 5.0 mg/L at the start; the 429.3 mg dose targets the larger steady-state peak. Neither number is universally the correct loading dose: the choice depends on the concentration feature being targeted and on the desired initial profile.

When the Target Is a Trough

A target trough requires a different maintenance dose from a target average or peak. Since \(C_{\min,ss}=C_{\max,ss}e^{-k\tau}\), setting the trough to \(C_{\mathrm{target}}\) implies \(C_{\max,ss}=C_{\mathrm{target}}e^{k\tau}\). The maintenance dose that creates the required peak-to-trough decline is

$$ D_{\mathrm{maint,trough}} =\frac{V C_{\mathrm{target}}(e^{k\tau}-1)}{F}. $$

To begin at the matching steady-state peak, the loading dose is \(V C_{\max,ss}/F\), or \(V C_{\mathrm{target}}e^{k\tau}/F\). This dose is larger than a loading dose designed to establish the trough concentration at time zero. The distinction matters whenever the concentration changes appreciably between administrations.

Worked Example: Designing a Bolus Regimen for a Target Trough

Hypothetical data: For an intravenous drug, \(V=50\) L, \(CL=5\) L/h, and \(\tau=8\) h. The desired steady-state trough is \(4.0\) mg/L. Calculate the maintenance dose and a loading dose that starts at the steady-state peak.

Here \(F=1\), and \(k=CL/V=0.100\ \mathrm{h}^{-1}\). From the trough-target equation,

$$ D_{\mathrm{maint}} =(50\ \mathrm{L})(4.0\ \mathrm{mg/L})(e^{(0.100\ \mathrm{h}^{-1})(8\ \mathrm{h})}-1) =(200\ \mathrm{mg})(2.2255-1) =245.1\ \mathrm{mg}. $$

The required steady-state peak is

$$ C_{\max,ss}=4.0\ \mathrm{mg/L}\times e^{0.8}=8.902\ \mathrm{mg/L}. $$

Thus the loading bolus that establishes this peak is

$$ D_{\mathrm{load,peak}} =(50\ \mathrm{L})(8.902\ \mathrm{mg/L}) =445.1\ \mathrm{mg}. $$

After 8 h, that peak decays to \(8.902e^{-0.8}=4.000\) mg/L. Giving the 245.1 mg maintenance dose then raises concentration back to 8.902 mg/L, so the intended peak-trough pattern is reproduced.

Continuous Infusion

For a constant-rate infusion, the amount in the body changes according to input minus elimination: \(dA/dt=F R_0-kA\). Since \(A=VC\) and \(CL=kV\), the concentration approaches a steady state of \(FR_0/CL\). The maintenance rate required for a target steady-state concentration is therefore

$$ C_{\mathrm{ss}}=\frac{F R_0}{CL} \quad\Longrightarrow\quad R_{0,\mathrm{maint}}=\frac{CL\,C_{\mathrm{target}}}{F}. $$

If the infusion starts from zero concentration, it does not instantly create that target. Solving the differential equation gives \(C(t)=F R_0/CL+(C(0)-F R_0/CL)e^{-kt}\). An initial bolus can establish the target concentration at the start of the infusion. With a loading dose \(D_{\mathrm{load}}\), \(C(0)=FD_{\mathrm{load}}/V\); setting this to the infusion steady state yields \(D_{\mathrm{load}}=V C_{\mathrm{target}}/F\). When the maintenance infusion begins at the same time, its input exactly balances elimination at that concentration under the model.

Worked Example: Loading and Maintenance for a Continuous Infusion

Hypothetical data: An intravenous drug has \(V=30\) L and \(CL=3.0\) L/h. The target concentration is \(2.5\) mg/L. Find the loading bolus and the continuous maintenance infusion rate.

Because the drug is intravenous, \(F=1\). The loading dose is

$$ D_{\mathrm{load}}=V C_{\mathrm{target}} =(30\ \mathrm{L})(2.5\ \mathrm{mg/L}) =75\ \mathrm{mg}. $$

The maintenance infusion rate is

$$ R_{0,\mathrm{maint}}=CL C_{\mathrm{target}} =(3.0\ \mathrm{L/h})(2.5\ \mathrm{mg/L}) =7.5\ \mathrm{mg/h}. $$

At the target, elimination is \(CL C=(3.0\ \mathrm{L/h})(2.5\ \mathrm{mg/L})=7.5\) mg/h, equal to the infusion input. The loading bolus supplies 75 mg, which corresponds to \(75/30=2.5\) mg/L in the compartment. Under the stated assumptions, the infusion then sustains that concentration.

Checks, Alternatives, and Limitations

Before using a calculated schedule, check that the target and dose refer to the same concentration feature. The average-concentration maintenance formula cannot by itself guarantee a desired peak or trough. Also check units: \(CL\tau C\) has units of amount, while \(CL C\) has units of amount per time. Include \(F\) when the administered route does not deliver the full dose systemically. For the loading dose, use the bioavailability of the loading route; if it differs from that of the maintenance route, do not assume one shared \(F\).

There are several reasonable approaches, but each answers a different question. A simple loading dose \(VC_{\mathrm{target}}/F\) establishes a specified initial concentration. A peak-matching load establishes the peak of a repeated-bolus steady-state profile. A trough-target design first determines the maintenance dose from the trough, then uses the corresponding peak if the intent is to begin on that profile. For continuous infusion, the loading amount establishes the target while the infusion rate maintains it. These approaches should not be substituted for one another without changing the target definition.

A loading dose changes how quickly the regimen reaches its intended concentration; it does not change the steady-state concentration produced by the maintenance regimen. Conversely, if the maintenance rate is wrong, a loading dose cannot correct the long-run mismatch. The calculations also do not ensure that a target is safe or effective, or that peak and trough concentrations both lie within a desired window. They depend on a specified, accurate model and parameter values.

A common mistake is to calculate \(D_{\mathrm{load}}=VC_{\mathrm{target}}/F\) and call the result the loading dose for any regimen. That reasoning silently treats the target as an initial concentration. If the intended target is the steady-state peak for repeated boluses, the correct load is \(D_{\mathrm{maint}}/(1-e^{-k\tau})\); if the target is a trough, the dose must account for the rise from trough to peak across the interval. State the target feature first, then derive the dose that establishes it.

1
Specify the target.
Decide whether the target is an initial concentration, average steady-state concentration, peak, trough, or continuous-infusion steady state.
2
Choose the maintenance regimen.
Use the target and the regimen structure to calculate the repeated dose or infusion rate, including bioavailability.
3
Match the loading dose to the intended starting point.
For a repeated-bolus peak, account for accumulation; for a continuous infusion, match the initial amount to the target concentration.
4
Check predictions and assumptions.
Verify units, the implied peak and trough when relevant, and whether the one-compartment linear model is plausible for the intended use.

Check Your Understanding

Answer each question, then compare with the brief solutions below.

  1. A hypothetical IV drug has \(CL=2\) L/h and a target continuous-infusion concentration of \(3\) mg/L. What maintenance rate is required?
  2. For a bolus regimen, why is a loading dose that initially gives the target average concentration generally not the same as one that matches the steady-state peak?
  3. A drug has \(V=20\) L, \(CL=2\) L/h, \(F=0.5\), and is dosed every 6 h. Calculate the maintenance dose for a target average steady-state concentration of \(2\) mg/L.
  4. True or false: increasing the loading dose can correct a maintenance regimen that produces a steady-state concentration below target. Explain.

Solutions. (1) \(R_0=CL C_{\mathrm{target}}=(2\ \mathrm{L/h})(3\ \mathrm{mg/L})=6\) mg/h. (2) The repeated-dose steady-state peak includes residual drug from previous doses, so it exceeds the average concentration when concentration fluctuates within the interval; the loading amount must match the peak if that is the intended starting point. (3) \(D_{\mathrm{maint}}=CL\tau C_{\mathrm{target}}/F=(2)(6)(2)/0.5=48\) mg. (4) False. The loading dose affects the initial concentration, whereas the maintenance regimen determines the long-run concentration; the maintenance dose or rate must be corrected.

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