Why Steady State Matters for Monitoring
A concentration measured after repeated doses reflects more than the most recent dose. Drug from previous doses may still be present, and each new dose adds to that residual amount. As a result, a concentration measured early in a regimen can differ from the value expected under the same regimen after accumulation has stabilized. For therapeutic drug monitoring, it matters whether a sample represents a repeating, stable dosing pattern or an evolving one.
Steady state does not mean that concentration is constant throughout each dosing interval. With intermittent dosing, concentration generally rises and falls after each dose. At steady state, that rise-and-fall pattern repeats from one interval to the next. A trough is therefore a recurring low point at a specified time relative to the next dose; a peak is a recurring high point or a concentration at a specified postdose time. The interpretation also depends on recording sample time relative to dosing, as covered in the earlier material on Recording Sample Time Relative to Dosing.
How Repeated Doses Approach Steady State
A useful estimate of the time to approach steady state follows from first-order elimination. Let \(k\) be the elimination rate constant and \(t_{1/2}\) the elimination half-life. Under first-order elimination, the fraction of a concentration remaining after elapsed time \(t\) is \(e^{-kt}\). Since \(t_{1/2}=\ln(2)/k\), this fraction can also be written \(2^{-t/t_{1/2}}\).
The following result applies when pharmacokinetics are linear and time-invariant, the regimen repeats at a fixed interval \(\tau\), the patient begins with no residual drug from earlier dosing, and the dose response at a matched phase is multiplied by \(e^{-k\tau}\) for each preceding interval. This holds, for example, with instantaneous bolus dosing in a one-compartment model with mono-exponential elimination. Doses and relevant conditions must remain unchanged during the approach. With delayed or first-order absorption, the approach fraction generally depends on the full dose-response model and its absorption and disposition rates.
One way to justify the result is to compare the accumulated dose contributions at a fixed phase. If each dose produces the same concentration-time contribution shifted by one interval, the contributions from the latest dose, the preceding dose, and earlier doses form a geometric series. The contribution from a dose one interval earlier is multiplied by \(r=e^{-k\tau}\); from two intervals earlier it is multiplied by \(r^2\), and so on. After \(n\) doses, the relative sum is \(1+r+\cdots+r^{n-1}\), while the steady-state sum is \(1+r+r^2+\cdots=1/(1-r)\). Their ratio is $$ \frac{1-r^n}{1-r}\,(1-r)=1-r^n=1-e^{-kn\tau}. $$ This explains why the fraction reached is the same at a matched phase in this mono-exponential bolus model, even though the absolute concentration at a peak and at a trough differs.
The result also gives a practical time estimate. To reach at least a chosen fraction \(q\) of steady state, require $$ 1-2^{-n\tau/t_{1/2}}\ge q \quad\Longleftrightarrow\quad n\tau\ge \frac{-\ln(1-q)}{k}. $$ Thus, reaching 90% takes about 3.322 half-lives; reaching 95% takes about 4.322 half-lives; and reaching 99% takes about 6.644 half-lives. These are approximate thresholds, not a sudden transition. Accumulation approaches steady state asymptotically, so the exact steady-state profile is not attained after a finite number of doses in this model.
Worked Example: Five Intervals With an 18-Hour Half-Life
A hypothetical patient starts a fixed regimen of instantaneous bolus doses with a 12-hour dosing interval. Assume a one-compartment model with first-order, linear, time-invariant pharmacokinetics, an elimination half-life of 18 hours, no drug remaining from prior treatment, and unchanged dosing. Estimate the fraction of steady state reached at the trough immediately before the next dose after five completed intervals.
First calculate the elapsed time as \(n\tau=5(12)=60\) hours. Apply the approach-to-steady-state formula:
After five intervals, the concentration at a matched point in the interval is about 90.08% of its steady-state value. This estimate does not mean that every concentration during the interval is 90.08% of every other concentration; it compares the same phase across intervals. The elapsed time is 3.333 half-lives, consistent with reaching just over 90% by that time.
Worked Example: A Shorter Interval Relative to Half-Life
Consider a different hypothetical regimen of instantaneous bolus doses with a 12-hour interval and a 36-hour half-life. Assume a one-compartment model with the same linear, first-order conditions and no residual drug at treatment initiation. How many complete intervals are needed to reach at least 95% of steady state?
Solve the threshold inequality for elapsed time. A 95% fraction requires at least 4.322 half-lives:
Since a complete interval is required, round up to 13 intervals. At 13 intervals, elapsed time is \(13(12)=156\) hours, or \(156/36=4.333\) half-lives. Substituting directly checks the result:
The estimated fraction is about 95.04%, just above the requested threshold. The interval-to-half-life ratio here is \(12/36=1/3\), which is shorter than the ratio \(12/18=2/3\) in the preceding example. Because the interval is shorter relative to the half-life, more intervals are needed to span the same elapsed time in half-lives.
What the Estimate Means for Peak and Trough Samples
At steady state, a concentration measured at a consistent postdose time can be compared with the expected concentration at that same time under the repeating profile. A trough sample is typically drawn just before the next scheduled dose. A postdose sample should be described by its actual time after dosing; for an oral drug, a sample at a selected postdose time is not automatically the maximum concentration. The earlier material on trough concentrations and peak concentrations distinguishes these monitoring targets.
Steady-state status and sample timing are separate requirements. A sample may be collected at the correct time for a trough but before accumulation is sufficiently close to steady state. Conversely, a patient may be at steady state while a sample drawn several hours away from the intended trough cannot be treated as that trough. Even a small timing difference can matter when concentration changes rapidly.
Worked Example: A Trough and a Later Sample
Suppose a hypothetical drug is given as a rapid intravenous bolus every 12 hours. Assume a one-compartment model, first-order elimination, linear kinetics, and a 12-hour half-life. The dose is 500 mg and the apparent volume of distribution is 50 L. Ignore any infusion or absorption phase.
The concentration increment immediately after a bolus is dose divided by volume: \(500\ \text{mg}/50\ \text{L}=10\ \text{mg/L}\). In this model, the fraction remaining over one interval is \(2^{-12/12}=0.5\). At steady state, the postdose concentration is the sum of the current increment and the residual contributions from prior doses:
The steady-state trough, 12 hours after the postdose concentration, is \(20(0.5)=10\ \text{mg/L}\). A sample drawn exactly at that trough time can be interpreted against the steady-state trough under the stated assumptions. If instead the sample is drawn 10 hours after the dose, the predicted concentration is
That value is about 1.23 mg/L, or 12.3%, higher than the 12-hour trough. It is a concentration at 10 hours postdose, not the trough. After five elapsed intervals from a drug-free start, the trough immediately before the next dose has reached \(1-2^{-5}=0.96875\), or 96.875%, of its steady-state value. Immediately after the dose at that time, the fraction is \(1-2^{-6}=0.984375\), or 98.4375%; the same fraction applies at the 10-hour postdose phase. Thus the 10-hour sample would still require both its actual timing and its approach-to-steady-state status to be considered.
Checking Assumptions and Recognizing Failure Modes
The half-life calculation is a planning estimate, not proof that a patient is at steady state. It assumes the relevant elimination process is adequately represented by a stable half-life and that the dose, interval, and pharmacokinetic conditions have not changed. It also assumes proportional accumulation: each dose contributes a concentration profile that can be added to those from earlier doses. Under these conditions the approach fraction is independent of dose size, although the absolute steady-state concentrations depend on dose and disposition.
Check the estimate against the clinical and dosing record. A recent dose change resets the approach to the new regimen; a missed or delayed dose disrupts the repeating pattern. A half-life estimated for a different patient or condition may not describe the current patient. Multiple disposition phases, delayed absorption, or a terminal process slower than the half-life used for the calculation can make a simple estimate misleading. For a complex profile, model-based predictions or repeated measurements at matched dose-relative times may be more informative than a single half-life rule. A value that varies across matched samples can signal a changed regimen, changing conditions, timing errors, or measurement variability; it should prompt review rather than an automatic declaration of steady state.
A common shortcut is to say that steady state is reached after exactly five half-lives. Under the stated first-order model, five half-lives correspond to \(1-2^{-5}=0.96875\), or 96.875% of steady state—not 100%. Whether that is close enough depends on the purpose and the clinical context. Another mistake is to count dosing intervals without considering their length relative to the half-life: 13 short intervals can represent fewer half-lives of elapsed time than five longer intervals.
A calendar rule is convenient when the kinetic assumptions are reasonable and an approximate threshold is sufficient. A model-based estimate can account for the actual interval and a specified fraction threshold more explicitly, but depends on the model and its parameter estimates. Repeated, consistently timed concentrations can provide evidence of a stable pattern, though apparent similarity across a small number of samples does not prove that all assumptions hold. No approach removes the need to verify the dosing history and sample timing.
Check Your Understanding
Answer each question using the stated assumptions; for questions 1, 2, and 4, assume instantaneous bolus dosing in a one-compartment model with first-order elimination. Brief solutions follow the questions.
- A hypothetical regimen has a 24-hour interval and a 24-hour half-life. Starting with no residual drug, what fraction of steady state is reached after four intervals?
- For a 48-hour half-life, approximately how many hours are required to reach at least 90% of steady state under a fixed regimen?
- Why does a concentration at 8 hours after a dose not automatically represent a trough, even if the patient is at steady state?
- A patient has received a fixed regimen for five half-lives. Is the concentration exactly at steady state under the first-order model? State the estimated fraction reached.
Solutions. For question 1, \(n\tau=4(24)=96\) hours, so \(f_4=1-2^{-96/24}=1-2^{-4}=0.9375\). The estimate is 93.75% of steady state at a matched phase. For question 2, 90% requires \(-\ln(0.10)/k=3.3219\) half-lives, so the elapsed time is \(3.3219(48)\approx159.5\) hours. For question 3, a trough is defined by its position in the interval, usually just before the next dose; an 8-hour sample is a concentration at 8 hours postdose unless that time is specifically the regimen's trough time. For question 4, no. After five half-lives the fraction is \(1-2^{-5}=0.96875\), or 96.875%; the profile is close to but not exactly at steady state in this model.