Why Repeat Concentrations Need a Variability Model
A concentration measured in the same patient can differ from one occasion to another even when the prescribed dose and the patient's underlying exposure have not persistently changed. Variation can arise from biological fluctuations, imperfectly matched sampling times, dose-taking patterns, and residual analytical error. A difference between two results is therefore not, by itself, proof of a durable exposure change.
The task here is to describe the variation expected when conditions are stable, then compare an observed difference with that expectation. This requires comparable samples: for example, concentrations collected at the same point in the dosing interval under a stable regimen. The earlier material on The Minimum Metadata for Interpreting a Sample is relevant because dose, sampling time, and other context determine whether two concentrations can reasonably be compared.
Concentrations often vary multiplicatively: a fluctuation of a given percentage is more plausible than a fixed number of concentration units across a wide range of levels. A natural-log model represents this pattern and keeps fitted concentrations positive. Let \(C_{ij}\) be the concentration for patient \(i\) on occasion \(j\), and let \(Y_{ij}=\log(C_{ij})\), with concentration expressed in a fixed unit. For one patient observed in a stable period, a simple model is
Here, \(\mu\) is the patient's typical log concentration under the specified conditions, and \(\sigma_w\) is the within-patient standard deviation on the log scale. The model assumes that the occasions are comparable, errors have mean zero and a common variance, and errors are independent and approximately normal on the log scale. These are modeling assumptions, not guarantees supplied by having repeat results.
From Log-Scale Variation to Concentration Variation
The log-scale standard deviation is often easier to interpret after conversion to a geometric coefficient of variation (CV). Under the lognormal model, if \(Y\sim N(\mu,\sigma_w^2)\), then \(C=\exp(Y)\). Its mean is \(\exp(\mu+\sigma_w^2/2)\), and its variance is \(\exp(2\mu+\sigma_w^2)\{\exp(\sigma_w^2)-1\}\). Dividing the variance by the squared mean and taking the square root gives the CV.
This is the geometric CV: it describes multiplicative spread and does not depend on the typical concentration level. For modest \(\sigma_w\), the approximation \(100\sigma_w\%\) can be useful, but the exact expression is preferable when reporting a CV. In this tutorial, ratios and differences on the log scale are used to describe fluctuations; they are not interchangeable with additive differences in concentration units.
Worked Example: Converting Within-Patient Variation to a Geometric CV
Suppose a hypothetical set of comparable concentrations from one patient has an estimated within-patient log-scale standard deviation of \(\sigma_w=0.20\). Quantify the variation as a geometric CV.
Calculation. Substitute the standard deviation into the conversion:
Thus the estimated geometric CV is about 20.2%. This summarizes relative within-patient spread around the stable typical level; it does not mean every result will lie within 20.2% of that level. A CV alone also does not identify the source of variation, such as biology, sampling, or analysis.
How Much Can Two Stable Measurements Differ?
If two independent measurements are made under the same stable conditions, their log-scale difference is \(\varepsilon_2-\varepsilon_1\). Independence gives variance \(\sigma_w^2+\sigma_w^2=2\sigma_w^2\), so the difference has standard deviation \(\sqrt{2}\sigma_w\). Exponentiating that difference gives the ratio of the two concentrations. Consequently, even with no persistent shift, two single measurements can differ substantially.
The range is a model-based prediction for the ratio of two single measurements under stable conditions, not a confidence interval for a persistent shift. It is centered at ratio 1 on the log scale. Its width grows with within-patient variability, so a given observed ratio is less surprising when ordinary fluctuation is large.
Worked Example: Assessing a Difference Between Two Single Results
Assume, hypothetically, that a patient has \(\sigma_w=0.20\), estimated from comparable stable measurements. Two later standardized concentrations are 8.0 mg/L and 12.0 mg/L. Is this ratio unusually large under the stable model?
Stable spread. The standard deviation of the log ratio is \(\sqrt{2}(0.20)=0.2828\). The central 95% range for a stable ratio is
Observed difference. The observed ratio is \(12.0/8.0=1.500\), and the log ratio is \(\log(1.500)=0.4055\). Its standardized value under the stable model is
A two-sided normal-tail probability is approximately \(0.152\). The observed ratio lies inside the model's central 95% stable range, and this calculation does not provide strong evidence against stable exposure. It does not establish that exposure was unchanged: the result is a comparison with a variability model, whose assumptions and estimate of \(\sigma_w\) matter.
Replicates Help Separate a Shift from Fluctuation
A more informative comparison uses several comparable measurements in each of two periods. Let \(Y_{1j}\) and \(Y_{2j}\) be log concentrations in periods 1 and 2. Suppose each period has a stable typical log level, \(\mu_1\) or \(\mu_2\), and independent within-period errors with variance \(\sigma_w^2\). The quantity of interest is the shift \(\Delta=\mu_2-\mu_1\). Its exponentiation, \(\exp(\Delta)\), is the ratio of the periods' typical concentrations on the geometric scale.
With \(m_1\) and \(m_2\) independent observations in the periods, the difference of the sample log means estimates \(\Delta\). The variance of a sample mean of \(m\) independent observations is \(\sigma_w^2/m\). Since the two period means are independent, the variance of their difference is the sum of these variances:
If \(\sigma_w\) is known, a 95% interval for \(\Delta\) is \(\widehat{\Delta}\pm1.96\,\mathrm{SE}(\widehat{\Delta})\). Exponentiating both endpoints gives an interval for the ratio of typical concentrations. If the within-period variance is estimated from replicate data instead, its uncertainty must also be included; under the equal-variance normal model, a pooled within-period variance estimate leads to a \(t\) interval with the corresponding residual degrees of freedom. The known-\(\sigma_w\) calculation below is used to keep the example focused on the effect of replication.
Worked Example: Comparing Two Sets of Replicate Concentrations
In a hypothetical monitoring exercise, eight comparable concentrations are collected in each of two periods. Their geometric means are 8.00 mg/L in period 1 and 10.27 mg/L in period 2. Assume an independently established within-patient log standard deviation of \(\sigma_w=0.20\), with independent errors and stable conditions within each period. Estimate the typical exposure ratio and assess its uncertainty.
Estimate on the log scale. The log difference of geometric means is
The corresponding ratio estimate is \(\exp(0.250)=1.284\). Thus the period 2 geometric mean is estimated to be 1.284 times the period 1 geometric mean, or about 28.4% higher.
Standard error and interval. With \(m_1=m_2=8\),
The 95% interval on the log scale is \(0.250\pm1.96(0.100)\), or \([0.054,0.446]\). Exponentiating each endpoint gives
The interval excludes 1, so under the stated model the data support a difference between the periods' typical concentrations at the 5% two-sided level. Establishing that this difference is lasting requires additional evidence or follow-up. The estimated ratio is 1.284, with a 95% interval from 1.055 to 1.562. This conclusion concerns a difference in typical exposure under the comparison conditions; it does not establish why the shift occurred.
Assumptions, Diagnostics, and Alternatives
Replicate measurements improve precision only when they provide information about the intended source of variation. In the two-period calculation, the log errors must be independent across observations and periods, share the specified variance, and be reasonably normal. The underlying typical level should be stable within each period, and sampling conditions should be comparable across periods. If measurements are serially correlated, the variance of a mean is not generally \(\sigma_w^2/m\), so treating every observation as independent can make an interval too narrow.
Inspect the design and the log concentrations rather than relying on a formula alone. Check whether dose and sample timing were consistent, whether the regimen or clinical state changed within a period, and whether one unusually high or low value dominates the mean. A log-scale plot can reveal skewness or outliers; a sequence plot can reveal a gradual drift or clusters that contradict independence. If sample timing or dosing differs, the apparent shift may reflect those differences rather than a persistent change in typical exposure. Analytical uncertainty is another component of observed variation; it should not be counted twice if the estimate of \(\sigma_w\) already includes it.
| Approach | What it answers | Main caution |
|---|---|---|
| Compare two single results using the stable ratio range | Is this pair's difference surprising given expected within-patient variation? | It is imprecise and does not estimate a shift as reliably as replicates. |
| Compare replicate log means | How large is the estimated difference in typical concentration, and how uncertain is it? | Requires comparable, sufficiently independent observations and a defensible variance. |
| Use an additive-scale comparison | How many concentration units separate the results? | May not describe proportional variability well when concentration levels differ. |
These calculations have limits. A statistically detectable shift can be small in practical terms, while a wide interval can leave substantial uncertainty even when the point estimate is large. A stable-variance model may be inappropriate if variability changes with concentration, or if dosing, sampling, adherence, or physiology changes systematically between periods. Where repeated observations are correlated or the conditions are not comparable, a simple independent-error calculation is not adequate. The model supports interpretation of a difference; it does not identify its cause.
Common Pitfall
Wrong reasoning: “The second concentration is 50% higher, so the patient's exposure must have risen by 50%.” This treats two noisy observations as exact measures of typical exposure and ignores their expected within-patient spread.
Correction: Compare like with like, quantify expected variation, and use replicate measurements when available. A single ratio should be interpreted relative to the stable ratio range; a replicate-based ratio should be accompanied by an interval that accounts for within-patient uncertainty. Neither calculation excuses mismatched timing or other changes in conditions.
Check Your Understanding
Answer each question, then compare your reasoning with the solutions below.
- If \(\sigma_w=0.15\), what is the geometric CV, to three significant figures?
- For two independent stable measurements with \(\sigma_w=0.15\), what is the standard deviation of their log ratio?
- Two period geometric means are 5.0 mg/L and 6.0 mg/L. What is the estimated typical-concentration ratio?
- Why can serial correlation make a replicate-based interval too narrow if independence is assumed?
- Does a 95% interval for a typical-concentration ratio that includes 1 prove the periods are identical? Explain.
Solutions. (1) \(100\sqrt{\exp(0.15^2)-1}=100\sqrt{\exp(0.0225)-1}\approx15.1\%\). (2) The standard deviation is \(\sqrt{2}(0.15)=0.212\) log units. (3) The ratio is \(6.0/5.0=1.20\), so the second geometric mean is estimated to be 1.20 times the first. (4) Correlated measurements contain less independent information than the same number of independent observations; using \(\sigma_w^2/m\) then understates the variance of the mean difference and its standard error. (5) No. It means the data do not exclude a ratio of 1 at that interval level under the model; the interval may still include meaningful increases or decreases, so it does not establish equality.