Infusion Creates Two Linked Time Courses
During a constant-rate infusion, plasma concentration rises toward a plateau rather than jumping immediately to that level. The effect-site concentration follows with its own delay: it is driven by plasma concentration, but does not equilibrate instantaneously. When the infusion stops, plasma concentration declines, while effect-site concentration may initially continue to rise if it is still below plasma concentration. These trajectories matter when interpreting the timing of drug effects, even when the effect is determined by a concentration-response relationship already specified elsewhere in the model.
The calculations below use a one-compartment plasma model with first-order elimination and a first-order effect compartment. The infusion begins at time zero, and both plasma and effect-site concentrations are initially zero. The solution during infusion applies while the infusion rate remains constant; the washout solution begins when that infusion is stopped.
During a Constant-Rate Infusion
For a constant infusion beginning at zero concentration, the plasma balance is \(dC_p/dt=R_0/V-kC_p\). Its solution is \(C_p(t)=C_{ss}(1-e^{-kt})\): plasma concentration approaches \(C_{ss}\) asymptotically. The effect compartment is driven by this rising plasma concentration, so its trajectory is not simply the plasma curve multiplied by a fixed delay.
To obtain the effect-site solution, use the integrating factor \(e^{k_{e0}t}\) in the effect-compartment equation. Applying the initial condition gives the convolution integral below. Substituting the plasma infusion curve and integrating yields the closed form for unequal rate constants.
The result approaches \(C_{ss}\) as time increases, but initially \(C_e\) rises more slowly because it integrates the preceding plasma exposure. When \(k_{e0}=k\), the displayed expression has a zero denominator and must not be evaluated by direct substitution. Integrating the same convolution with equal rates gives its continuous limiting form.
Worked Example: Infusion With Unequal Rate Constants
Suppose a hypothetical drug is infused at a constant rate that gives \(C_{ss}=10.0\) mg/L. Let \(k=0.200\) h\(^{-1}\), \(k_{e0}=0.500\) h\(^{-1}\), and let the infusion run for 4.00 h. Calculate the plasma and effect-site concentrations at the end of infusion.
Because \(k_{e0}\ne k\), use the unequal-rate expressions. First calculate plasma concentration:
Then calculate the effect-site concentration:
At 4.00 h, the effect-site concentration is below the plasma concentration: 3.413 mg/L versus 5.507 mg/L. The infusion has not necessarily lasted long enough for either concentration to reach steady state.
After Infusion Cessation
Let \(T\) be the time the infusion stops, and write \(\tau=t-T\) for elapsed time since cessation. The plasma concentration at the stopping time is \(C_p(T)\). With no further input and first-order elimination, plasma concentration is \(C_p(T)e^{-k\tau}\). The effect compartment then responds to this declining plasma concentration while also retaining the concentration \(C_e(T)\) present at cessation.
Solving the effect-compartment equation from the initial value \(C_e(T)\), with \(C_p(T)e^{-k\tau}\) as its driving input, gives the following washout expression. The two terms have distinct roles: the first carries forward the existing effect-site concentration, and the second reflects continued equilibration with plasma after the infusion stops.
If the rates are equal, the corresponding limit is:
Worked Example: Effect-Site Washout After the Infusion Stops
Continue the hypothetical infusion in the first example, stopped at \(T=4.00\) h. At cessation, \(C_p(T)=5.507\) mg/L and \(C_e(T)=3.413\) mg/L. Find the effect-site concentration 2.00 h after stopping.
Here \(\tau=2.00\) h and the rate constants differ, so substitute in the unequal-rate washout equation:
Thus, the effect-site concentration 2.00 h after cessation is about 4.031 mg/L, greater than its 3.413 mg/L value at cessation. This is consistent with the initial post-infusion rate of change, \(k_{e0}[C_p(T)-C_e(T)]=0.500(5.507-3.413)=1.047\) mg/L/h, which is positive. Plasma is falling, but it is initially still above the effect-site concentration and continues to drive equilibration.
Worked Example: Equal Rates During Infusion and Washout
Suppose a hypothetical infusion has \(C_{ss}=6.00\) mg/L and \(k=k_{e0}=0.500\) h\(^{-1}\). It runs for 1.00 h, then stops. Calculate the effect-site concentration at cessation and 1.00 h later.
Since \(kt=0.500(1.00)=0.500\), use the equal-rate infusion formula:
For the first hour after cessation, \(\tau=1.00\) h. Apply the equal-rate washout expression with \(C_e(T)=0.541224\) mg/L and \(C_p(T)=2.360816\) mg/L:
The effect-site concentration remains below plasma concentration at cessation, so it continues to rise during this first hour of washout. The calculations use the equal-rate formulas; substituting \(k_{e0}=k\) into a formula with denominator \(k_{e0}-k\) would be undefined.
Interpreting the Trajectories and Checking the Model
During infusion, both concentrations approach \(C_{ss}\), but their rates of approach depend on different constants. A larger \(k\) means plasma approaches its infusion plateau more rapidly; a larger \(k_{e0}\) means the effect compartment equilibrates with the current plasma concentration more rapidly. These statements concern the modeled concentration trajectories, not a claim that the effect compartment is a directly measured anatomical space.
After cessation, plasma concentration must decline under the stated elimination model. The effect-site trajectory need not decline immediately: its instantaneous slope is \(k_{e0}[C_p-C_e]\). It rises when \(C_p>C_e\), is momentarily flat when \(C_p=C_e\), and declines when \(C_p<C_e\). This sign check is a useful diagnostic for detecting arithmetic or interpretation errors in a washout calculation.
The solution also has boundary checks. At \(t=0\), both infusion formulas give \(C_e(0)=0\). At long infusion times, \(e^{-kt}\) and \(e^{-k_{e0}t}\) vanish, so \(C_p\) and \(C_e\) both tend to \(C_{ss}\). At washout onset, setting \(\tau=0\) returns \(C_e(T)\); as \(\tau\) increases, both exponential terms ultimately vanish, so \(C_e\) tends to zero. A computed value that violates these checks warrants review of units, parameter substitution, or the selected equal-rate formula.
These closed forms are useful when the infusion rate and model parameters are constant over the interval being analyzed. They are not appropriate without modification if the plasma input follows a different time course, clearance is nonlinear or time-varying, the starting concentrations are not both zero, or the effect compartment feeds back on plasma pharmacokinetics. A general changing plasma profile requires solving the effect-compartment equation using that profile as its input. In practice, compare predicted plasma and effect-site trajectories with observations and inspect whether the assumed infusion timing, rate constants, and initial conditions are credible. A poor fit should not be repaired simply by interpreting an implausible \(k_{e0}\) as a physiological delay.
The main alternative is numerical integration of the differential equations. Numerical methods can accommodate more complicated inputs and models, but a closed-form solution is especially valuable for checking implementation and understanding parameter effects. For the constant-rate infusion and first-order washout considered here, the analytic formulas are direct and provide transparent checks on a numerical solution.
Check Your Understanding
Answer each question, then compare with the concise solutions below.
- For \(C_{ss}=8.00\) mg/L and \(k=0.250\) h\(^{-1}\), what is \(C_p\) after 2.00 h of constant infusion from zero?
- When \(k=k_{e0}=0.500\) h\(^{-1}\), \(C_{ss}=6.00\) mg/L, and infusion time is 1.00 h, calculate \(C_e\) at cessation.
- At infusion cessation, \(C_p=4.00\) mg/L and \(C_e=5.00\) mg/L. Is \(C_e\) initially rising or falling after cessation if \(k_{e0}=0.300\) h\(^{-1}\)? Give its initial rate.
- Why can the unequal-rate infusion formula not be evaluated by direct substitution when \(k_{e0}=k\)?
- Name two assumptions that would make the closed-form infusion or washout solutions inappropriate if they were violated.
Solutions. (1) \(C_p=8.00(1-e^{-0.250(2.00)})=8.00(1-e^{-0.500})=3.148\) mg/L. (2) \(C_e=6.00[1-(1+0.500)e^{-0.500}]=0.541224\) mg/L. (3) \(dC_e/dt=0.300(4.00-5.00)=-0.300\) mg/L/h, so it is initially falling. (4) The expression has denominator \(k_{e0}-k=0\); use the equal-rate limit instead. (5) Examples include nonlinear or time-varying clearance, a nonconstant infusion rate, nonzero initial concentrations when using the zero-start infusion formula, and feedback from the effect compartment into plasma pharmacokinetics.