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Binding and Blood-to-Plasma Ratio · Tutorial 141 of 799

Fraction Unbound In Plasma And Binding Equilibria

Learn to interpret plasma fraction unbound and binding affinity, and calculate free and bound drug concentrations under linear or saturable equilibrium binding.

Intermediate 10 min read

What You'll Learn

  • Define plasma fraction unbound and bound fraction using free, bound, and total plasma concentrations.
  • Relate dissociation and association constants to binding affinity at equilibrium.
  • Derive the single-class binding equation from mass action and binding-site conservation.
  • Calculate free and bound concentrations from total concentration and fraction unbound.
  • Calculate concentration-dependent binding when a finite number of sites can saturate.
  • Recognize when a constant fraction-unbound approximation is inappropriate.

Why distinguish free and bound drug?

A plasma concentration reported as “total” combines drug that is free in plasma with drug bound to plasma constituents. The distinction matters in PBPK because the free concentration is the concentration available to move independently of those binding interactions. A fraction unbound is therefore not another concentration: it is a dimensionless ratio that relates free concentration to total concentration under specified conditions.

The introductory material on unbound fractions as inputs to Kp methods establishes why an unbound fraction can enter partition predictions. Here the focus is the plasma quantity itself: its definition, its relation to binding at equilibrium, and how to calculate free and bound concentrations. The binding equations below describe an idealized equilibrium model; they do not identify which plasma constituent is responsible for binding.

Definition: Let \(C_{p,\mathrm{tot}}\) be the total plasma drug concentration, \(C_{u,p}\) the free (unbound) plasma concentration, and \(C_{b,p}\) the bound plasma concentration, all expressed in the same concentration units. If these are the only two forms being counted, then \(C_{p,\mathrm{tot}}=C_{u,p}+C_{b,p}\). The plasma fraction unbound is \(f_{u,p}=C_{u,p}/C_{p,\mathrm{tot}}\), and the bound fraction is \(f_{b,p}=C_{b,p}/C_{p,\mathrm{tot}}\). Thus \(f_{u,p}+f_{b,p}=1\).

Both fractions are dimensionless and range from 0 to 1. A small \(f_{u,p}\) means a large proportion of the measured total concentration is bound; it does not, by itself, say that the free concentration is small in absolute units. That also depends on \(C_{p,\mathrm{tot}}\). When a fraction is known, the corresponding concentrations follow directly:

$$ C_{u,p}=f_{u,p}C_{p,\mathrm{tot}}, \qquad C_{b,p}=(1-f_{u,p})C_{p,\mathrm{tot}}=f_{b,p}C_{p,\mathrm{tot}}. $$

Equilibrium affinity and a finite set of binding sites

A simple mechanistic model treats free drug, \(D\), as reversibly binding to an available site, \(S\), to form a drug–site complex, \(DS\). At equilibrium, the association and dissociation processes balance. The dissociation constant \(K_d\) is the ratio of free drug and free site concentrations to complex concentration. A smaller \(K_d\) indicates greater binding affinity in this model. The association constant \(K_a\) is its reciprocal.

Definition: For the equilibrium \(D+S\rightleftharpoons DS\), \(K_d=[D][S]/[DS]\) and \(K_a=[DS]/([D][S])=1/K_d\). Here \([D]\) is the free drug concentration, \([S]\) the unoccupied-site concentration, and \([DS]\) the bound drug concentration. \(K_d\) has concentration units; \(K_a\) has reciprocal concentration units. A low \(K_d\) means that, at a given free drug concentration, binding-site occupancy is relatively high.

For one class of independent, equivalent sites, let \(B_{\max}\) be the total concentration of binding sites, including both occupied and unoccupied sites. The model assumes reversible binding has reached equilibrium, each site binds at most one drug molecule, and the sites have the same affinity. It also assumes concentrations can be used in the mass-action relationship, as is standard for this simplified treatment. These assumptions give a useful model, not a claim that plasma binding always follows one homogeneous site class.

$$ B_{\max}=[S]+[DS], \qquad K_d=\frac{C_{u,p}[S]}{C_{b,p}}. $$

The fraction of sites occupied is \(\theta=[DS]/B_{\max}\). Solving the equilibrium relationship shows how occupancy depends on the free, not the total, drug concentration:

$$ [S]=B_{\max}-[DS], \qquad K_d=\frac{C_{u,p}(B_{\max}-[DS])}{[DS]}. $$

Rearrange the last equation to collect the terms involving \([DS]\):

$$ K_d[DS]+C_{u,p}[DS]=C_{u,p}B_{\max}, \qquad [DS]=B_{\max}\frac{C_{u,p}}{K_d+C_{u,p}}. $$

Because \([DS]=C_{b,p}\) in this model, the bound concentration is \(C_{b,p}=B_{\max}C_{u,p}/(K_d+C_{u,p})\), and \(\theta=C_{u,p}/(K_d+C_{u,p})\). Total concentration is then free plus bound. This derivation also explains why the same \(f_{u,p}\) need not apply at every concentration: the bound concentration does not increase proportionally without limit when sites can become occupied.

Worked Example: Converting a Fraction Unbound to Concentrations

Suppose a hypothetical plasma sample has \(C_{p,\mathrm{tot}}=12.0\) mg/L and \(f_{u,p}=0.080\). Assume free and bound drug account for all the total concentration. Calculate the free and bound concentrations.

Use the fraction definitions and the complement relation:

$$ C_{u,p}=f_{u,p}C_{p,\mathrm{tot}} =(0.080)(12.0\ \mathrm{mg/L})=0.960\ \mathrm{mg/L}. $$

The bound fraction is \(f_{b,p}=1-0.080=0.920\). Therefore,

$$ C_{b,p}=f_{b,p}C_{p,\mathrm{tot}} =(0.920)(12.0\ \mathrm{mg/L})=11.04\ \mathrm{mg/L}. $$

The check is \(0.960+11.04=12.00\) mg/L, matching the stated total. The fraction unbound is 0.080, or 8.0%; the free concentration is 0.960 mg/L. These are different kinds of quantities and should not be interchanged.

Using equilibrium parameters to calculate binding

When \(B_{\max}\) and \(K_d\) are given, the binding equation calculates bound concentration from free concentration. If instead total concentration is given, first use the mass balance \(C_{p,\mathrm{tot}}=C_{u,p}+C_{b,p}\). Substitution produces an equation for \(C_{u,p}\). In the one-site model, this equation can be solved algebraically. The physically meaningful solution must be nonnegative and cannot exceed the total concentration.

Worked Example: Calculating Bound Concentration at a Given Free Concentration

Consider a hypothetical one-site system with \(B_{\max}=30.0\) μmol/L and \(K_d=2.00\) μmol/L. At \(C_{u,p}=1.00\) μmol/L, calculate occupancy, bound concentration, total concentration, and the resulting fraction unbound.

First calculate the occupied fraction of sites:

$$ \theta=\frac{C_{u,p}}{K_d+C_{u,p}} =\frac{1.00}{2.00+1.00}=\frac{1}{3}=0.333. $$

The bound concentration is total site concentration multiplied by occupancy:

$$ C_{b,p}=B_{\max}\theta =(30.0\ \mathrm{\mu mol/L})(0.3333)=10.0\ \mathrm{\mu mol/L}. $$

Thus \(C_{p,\mathrm{tot}}=1.00+10.0=11.0\) μmol/L, and

$$ f_{u,p}=\frac{1.00}{11.0}=0.0909. $$

The units are consistent: \(B_{\max}\), \(K_d\), and each concentration are in μmol/L, while occupancy and fraction unbound are dimensionless. The result is specific to the stated free concentration and model parameters.

Worked Example: Solving for Free Concentration From Total Concentration

For a hypothetical compound, suppose \(C_{p,\mathrm{tot}}=10.0\) μmol/L, \(B_{\max}=20.0\) μmol/L, and \(K_d=4.00\) μmol/L. Under the one-site equilibrium model, find \(C_{u,p}\), \(C_{b,p}\), and \(f_{u,p}\).

Substitute the binding equation into the total-concentration balance:

$$ 10.0=C_{u,p}+\frac{20.0C_{u,p}}{4.00+C_{u,p}}. $$

All concentrations in this equation are in μmol/L. Multiplying by \(4.00+C_{u,p}\) and collecting terms gives

$$ 10.0(4.00+C_{u,p})=C_{u,p}(4.00+C_{u,p})+20.0C_{u,p}, $$
$$ C_{u,p}^{\,2}+14.0C_{u,p}-40.0=0. $$

The quadratic formula gives \(C_{u,p}=(-14.0\pm\sqrt{14.0^2+4(40.0)})/2\), or approximately 2.434 and \(-16.43\) μmol/L. A negative concentration is not physically possible, so retain only \(C_{u,p}=2.434\) μmol/L. Then

$$ C_{b,p}=10.0-2.434=7.566\ \mathrm{\mu mol/L}, \qquad f_{u,p}=\frac{2.434}{10.0}=0.2434. $$

The check \(2.434+7.566=10.000\) μmol/L satisfies the mass balance. The rejected root is an algebraic solution, not a valid concentration.

When is fraction unbound constant?

A constant \(f_{u,p}\) is a useful approximation when binding behaves linearly over the concentration range of interest. In the one-site equation, if free concentration is much smaller than \(K_d\), then \(K_d+C_{u,p}\) is approximately \(K_d\). Consequently,

$$ C_{b,p}\approx\frac{B_{\max}}{K_d}C_{u,p}, \qquad f_{u,p}\approx\frac{1}{1+B_{\max}/K_d}. $$

This approximation follows from the model’s low-occupancy condition, \(C_{u,p}\ll K_d\); it is not a universal property of plasma binding. As sites become occupied, the bound concentration approaches \(B_{\max}\), while free concentration can continue increasing. The total-to-free relationship then becomes nonlinear and \(f_{u,p}=C_{u,p}/C_{p,\mathrm{tot}}\) generally changes with concentration. Binding affinity and capacity have distinct roles: \(K_d\) sets the concentration scale for occupancy, while \(B_{\max}\) sets the maximum bound concentration for the site class.

Checks, alternatives, and limitations

A sound calculation begins by identifying which concentration is supplied. If \(f_{u,p}\) is supplied, multiply it by total concentration to obtain free concentration. If free concentration and equilibrium binding parameters are supplied, use the binding equation to obtain bound concentration. If only total concentration and \(B_{\max}\) and \(K_d\) are supplied, combine the binding equation with the mass balance and solve for the physically meaningful free concentration.

  • Check the mass balance. Under the stated two-form definition, \(C_{u,p}+C_{b,p}\) must equal \(C_{p,\mathrm{tot}}\), apart from rounding.
  • Check bounds and units. Fractions must lie between 0 and 1; concentrations must be nonnegative and use compatible units. \(K_d\) must have concentration units, and \(B_{\max}\) must be a concentration.
  • Check the equilibrium assumptions. A single-site prediction may be inadequate if binding sites are heterogeneous, more than one binding process matters, or equilibrium is not a reasonable description.
  • Check concentration dependence. A fraction measured or assumed at one concentration should not automatically be treated as constant if binding may saturate over the range being modelled.

The simplest alternative to the explicit site model is to use a supplied or measured \(f_{u,p}\) directly. This is convenient when a constant fraction is an adequate representation in the relevant range, but it does not explain affinity or saturation. A mechanistic equilibrium model represents those features under stated assumptions, but its parameters and structure must be appropriate. Neither approach removes the need to define total and free concentrations consistently. In particular, a one-site equation cannot establish that real plasma binding consists of one uniform site class.

Common pitfall: Substituting total concentration into the occupancy equation \(\theta=C_{u,p}/(K_d+C_{u,p})\) because total concentration is the reported value. The equation is derived from equilibrium in terms of free drug concentration, not total drug concentration. First use the mass balance to determine \(C_{u,p}\), or solve the combined equation when total concentration is given.

A second frequent error is to call a small fraction unbound “a small free concentration.” For example, a fraction of 0.01 applied to a total concentration of 1,000 concentration units gives a free concentration of 10 units. The fraction describes a proportion; the absolute concentration depends on the total. For PBPK input selection, this distinction helps prevent a ratio from being mistaken for a concentration and makes the assumptions behind a constant unbound fraction explicit.

Check Your Understanding

Answer each question, then compare with the solutions below.

  1. If \(C_{p,\mathrm{tot}}=25.0\) mg/L and \(f_{u,p}=0.12\), calculate \(C_{u,p}\) and \(C_{b,p}\), assuming the total consists only of free and bound drug.
  2. In the one-site model, what does a smaller \(K_d\) indicate, and what units does \(K_d\) have?
  3. For \(B_{\max}=12.0\) μmol/L, \(K_d=3.00\) μmol/L, and \(C_{u,p}=1.00\) μmol/L, calculate occupancy and bound concentration.
  4. Why might a constant \(f_{u,p}\) fail when free concentration approaches or exceeds \(K_d\)?
  5. A calculation from a binding equation gives one positive and one negative free-concentration root. Which root is retained, and why?

Solutions. (1) \(C_{u,p}=(0.12)(25.0)=3.00\) mg/L and \(C_{b,p}=25.0-3.00=22.0\) mg/L. (2) A smaller \(K_d\) indicates greater affinity in the stated equilibrium model; \(K_d\) has concentration units. (3) \(\theta=1.00/(3.00+1.00)=0.250\), so \(C_{b,p}=(12.0)(0.250)=3.00\) μmol/L. (4) As sites become occupied, bound concentration no longer increases proportionally with free concentration, so the free-to-total ratio can change. (5) Retain the positive root because a concentration cannot be negative; verify it also satisfies the original mass balance.