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Food Effects and Gastric Emptying · Tutorial 290 of 799

Gastric Emptying Effects on Tmax and Cmax

Use a simplified gastric-input and disposition model to calculate Tmax and Cmax and understand when slower emptying changes the concentration profile without changing total exposure.

Advanced 10 min read

What You'll Learn

  • Derive the concentration-time profile after first-order gastric delivery.
  • Calculate Tmax and Cmax, including the limiting case when gastric emptying and elimination rates are equal.
  • Explain why slower emptying delays and lowers the peak under the stated model.
  • Derive the conditions under which AUC is independent of gastric emptying.
  • Recognize model assumptions and signs that the simplified prediction may not apply.

Why Emptying Can Change the Peak Without Changing Total Exposure

A meal can slow the delivery of an oral dose from the stomach. Even if the same total amount eventually reaches systemic circulation, changing the timing of that delivery changes the concentration-time profile: the peak may occur later and be lower. This distinction matters in PBPK interpretation because a change in \(C_{\max}\) does not, by itself, imply a change in total systemic exposure.

This tutorial uses a deliberately simplified model to isolate that timing effect. Gastric emptying is first order, and material reaching the systemic circulation is treated as entering a one-compartment disposition model immediately. The model is not a complete description of intestinal absorption. Instead, it makes explicit how the rate of gastric delivery interacts with elimination to shape \(T_{\max}\) and \(C_{\max}\).

Definition: \(D\) is the dose initially in the stomach, \(k_g\) is the first-order gastric emptying rate constant, \(F\) is the fraction of the dose that ultimately reaches systemic circulation, \(V\) is the apparent volume of distribution, and \(k_e\) is the first-order elimination rate constant. The amount reaching systemic circulation is \(FD\). In this model, \(F\) accounts for any presystemic loss; there is no additional loss from the gastric compartment. \(T_{\max}\) is the time of the maximum concentration, and \(C_{\max}\) is that maximum concentration.

Model and Assumptions

The amount remaining in the stomach, \(G(t)\), follows first-order emptying. The systemic input rate is the gastric emptying rate multiplied by \(F\). Once in the systemic compartment, drug is eliminated by first-order elimination. With \(C(0)=0\), the model is

$$ \frac{dG}{dt}=-k_gG,\qquad G(0)=D, \qquad R_{\mathrm{sys}}(t)=F k_gG(t), \qquad \frac{dC}{dt}=\frac{R_{\mathrm{sys}}(t)}{V}-k_eC(t). $$

The assumptions are that \(k_g\), \(F\), \(V\), and \(k_e\) are constant over time; gastric emptying is complete eventually; the disposition is linear and time invariant; and there are no other input pathways. The model treats the fraction \(F\) as fixed when \(k_g\) changes. In particular, a slower \(k_g\) does not itself reduce the eventual amount entering systemic circulation. There is no separate intestinal absorption step here, so interpreting \(k_g\) as the only rate controlling delivery is an approximation.

1
Find gastric amount.
Solving the gastric equation gives \(G(t)=D e^{-k_gt}\).
2
Write systemic input.
Substitution gives \(R_{\mathrm{sys}}(t)=FDk_g e^{-k_gt}\), with total systemic input \(\int_0^\infty R_{\mathrm{sys}}(t)\,dt=FD\).
3
Combine input and elimination.
Solving the concentration equation yields the profile used to locate \(T_{\max}\) and \(C_{\max}\).

For \(k_g\ne k_e\), solving the concentration equation gives

$$ C(t)=\frac{FD}{V}\frac{k_g}{k_g-k_e} \left(e^{-k_et}-e^{-k_gt}\right),\qquad t\geq 0. $$

The formula is positive for either ordering of the two rate constants: the sign of \(e^{-k_et}-e^{-k_gt}\) changes along with the sign of \(k_g-k_e\). It describes a rise as input accumulates relative to elimination, followed by a decline as gastric input wanes.

Deriving the Peak Time and Peak Concentration

Differentiate the concentration profile and set its derivative equal to zero. For positive \(k_g\) and \(k_e\), the interior maximum satisfies

$$ \frac{dC}{dt} = \frac{FD}{V}\frac{k_g}{k_g-k_e} \left(-k_e e^{-k_et}+k_g e^{-k_gt}\right)=0, \qquad k_g e^{-k_gT_{\max}}=k_e e^{-k_eT_{\max}}. $$

Taking logarithms and rearranging gives the peak time. Substituting the peak condition into the concentration expression gives a convenient form for the peak height.

$$ T_{\max}=\frac{\ln(k_g/k_e)}{k_g-k_e}, \qquad C_{\max}=\frac{FD}{V}e^{-k_eT_{\max}} =\frac{FD}{V} \left(\frac{k_g}{k_e}\right)^{-k_e/(k_g-k_e)}. $$

Both expressions have well-defined limits when the rates are equal. If \(k_g=k_e=k\), the concentration profile is \(C(t)=(FD/V)kt e^{-kt}\), so \(T_{\max}=1/k\) and \(C_{\max}=(FD/V)e^{-1}\). The apparent singularities in the unequal-rate formulas are therefore removable, not biological discontinuities.

Result: With \(F,D,V,k_e\) fixed, reducing \(k_g\) increases \(T_{\max}\) and decreases \(C_{\max}\) in this model. The amount reaching systemic circulation is unchanged, but it arrives over a longer period and is exposed to elimination while delivery continues.

The direction of these changes can be justified directly. Let \(x=k_g/k_e\), so that \(k_eT_{\max}=\ln(x)/(x-1)\). The derivative of this expression with respect to \(x\) is

$$ \frac{d}{dx}\left(\frac{\ln x}{x-1}\right) = \frac{(x-1)/x-\ln x}{(x-1)^2}<0 \quad (x\ne 1), $$

because \(\ln x>1-1/x\) for \(x>0\), \(x\ne1\). Thus \(T_{\max}\) decreases as \(k_g\) increases. Also, \(C_{\max}/(FD/V)=\exp[-\ln(x)/(x-1)]\), which increases with \(x\) because \(\ln(x)/(x-1)\) decreases. These monotonic conclusions apply to the stated model and fixed values of the other parameters; they are not universal claims about every oral absorption model.

Worked Example: Comparing Fast and Slow Gastric Delivery

Suppose a hypothetical 100 mg dose has \(F=0.80\), \(V=40\) L, and \(k_e=0.20\ \mathrm{h}^{-1}\). Compare \(k_g=0.80\ \mathrm{h}^{-1}\) with \(k_g=0.25\ \mathrm{h}^{-1}\). Assume the model’s other conditions hold.

The systemic amount is \(FD=0.80(100)=80\) mg, and \(FD/V=80/40=2.00\) mg/L. With fast emptying, \(T_{\max}=\ln(0.80/0.20)/(0.80-0.20)=\ln(4)/0.60=2.310\) h. Then \(C_{\max}=2.00e^{-0.20(2.310)}=1.260\) mg/L.

With slower emptying, \(T_{\max}=\ln(0.25/0.20)/(0.25-0.20)=\ln(1.25)/0.05=4.463\) h. The peak is \(C_{\max}=2.00e^{-0.20(4.463)}=0.8190\) mg/L.

The slower-emptying case therefore has a later, lower peak under these assumptions. The result does not mean that only \(0.8190/1.260\) of the dose reached the systemic circulation: \(FD=80\) mg in both cases. The peak is a concentration at one time, not a measure of the total amount delivered.

Why AUC Can Remain Unchanged

For this linear one-compartment model, integrating the concentration balance over time gives a simple mass-balance result. Assume \(C(0)=0\), \(C(t)\) eventually returns to zero, and the full gastric dose empties. Integrating \(dC/dt=R_{\mathrm{sys}}/V-k_eC\) from zero to infinity makes the net change in concentration zero:

$$ 0=\frac{1}{V}\int_0^\infty R_{\mathrm{sys}}(t)\,dt -k_e\int_0^\infty C(t)\,dt, \qquad \mathrm{AUC}_{0-\infty}=\frac{FD}{Vk_e} =\frac{FD}{CL}, \quad CL=Vk_e. $$

The total input is \(FD\) regardless of \(k_g\), so changing the emptying rate alone does not change \(\mathrm{AUC}_{0-\infty}\). This conclusion requires that \(F\), \(D\), and clearance remain fixed, that the full input is followed to infinity, and that disposition is linear. A change in presystemic availability, dose, clearance, or incomplete delivery can change AUC. If measurements stop before the delayed profile has finished, the observed partial AUC can differ even when the full AUC is the same.

Worked Example: Checking the AUC by Mass Balance

Use the hypothetical parameters in the previous example. Since \(CL=Vk_e=40(0.20)=8.00\) L/h, the full AUC is \(\mathrm{AUC}_{0-\infty}=FD/CL=80/8.00=10.0\ \mathrm{mg\cdot h/L}\), for either gastric emptying rate.

The same result follows from \(FD/(Vk_e)=80/[40(0.20)]=10.0\ \mathrm{mg\cdot h/L}\). The units are concentration multiplied by time. The peak changes between the two conditions, but the integrated concentration does not, provided the dose, systemic fraction, and clearance are unchanged and the entire profile is included.

A Pure Lag and a More Detailed Absorption Model

A fixed lag time and slower first-order emptying are different input changes. If the entire systemic input profile is shifted by a fixed delay \(\tau\), then \(C_\tau(t)=0\) for \(t<\tau\) and \(C_\tau(t)=C(t-\tau)\) for \(t\geq\tau\). The peak height is unchanged, \(T_{\max}\) increases by \(\tau\), and the full AUC is unchanged. By contrast, changing \(k_g\) in the first-order model reshapes the input profile, which changes both peak timing and peak height.

A more detailed model can include a separate intestinal absorption rate. For example, drug may move from the stomach into an intestinal absorption compartment before entering systemic circulation. The concentration profile then reflects both gastric delivery and absorption, and \(T_{\max}\) is not generally given by the two-rate formula above. If all material is eventually absorbed with a fixed fraction \(F\), and disposition remains linear, the full AUC can still be independent of the timing of input. But the shape and peak must be derived from the added model; the simplified formula should not be applied as if gastric emptying were the only rate-limiting process.

Worked Example: When a Change in Availability Changes AUC

Suppose gastric emptying changes as in the first example, but a hypothetical food condition also changes the systemic fraction from \(F=0.80\) to \(F=0.60\). Keep \(D=100\) mg and \(CL=8.00\) L/h. The new systemic amount is \(FD=0.60(100)=60\) mg, so \(\mathrm{AUC}_{0-\infty}=60/8.00=7.500\ \mathrm{mg\cdot h/L}\).

This is lower than \(10.0\ \mathrm{mg\cdot h/L}\), not because of the emptying-rate change alone, but because the fraction reaching systemic circulation changed. AUC invariance with respect to \(k_g\) cannot be used to claim that every food-related change leaves AUC unchanged.

Diagnostics, Comparisons, and Limitations

Before interpreting a predicted peak shift, check whether the model’s assumptions are plausible for the question being asked. A first-order gastric process implies an exponentially declining gastric amount and a smoothly declining delivery rate. If the formulation has a distinct dissolution delay, if solid and liquid contents empty differently, or if the intestinal absorption process is slow, the single-rate input may not represent the relevant mechanism. In those cases, a model with explicit gastric and intestinal compartments, or an input distribution that represents variable transit times, is more appropriate.

Compare the model-predicted and observed profiles, not only their peak summaries. Warning signs include a predicted peak that is too early or too sharp, systematic residual patterns on the rising phase, a long observed tail not captured by the model, or a full AUC difference when the model assumes unchanged \(F\) and clearance. Such discrepancies do not identify a unique cause: altered absorption, presystemic loss, disposition, sampling, or model misspecification may contribute. The simplified equations describe consequences of assumptions; they do not establish that a measured food effect was caused by gastric emptying.

ApproachWhat it representsWhat it can establish
First-order gastric delivery used hereOne exponential delivery process followed by linear dispositionHow changing \(k_g\) alone shifts and reshapes the peak under fixed \(F\) and clearance
Fixed-lag inputThe same input profile translated in timeA delay in peak timing without changing peak height or full AUC
Explicit gastric and intestinal absorption compartmentsSeparate delivery and absorption ratesHow multiple sequential processes jointly shape the profile, at the cost of more parameters

The detailed alternatives can be more realistic, but they require more information to parameterize and may not be distinguishable from one concentration-time profile alone. The simplified model is useful for understanding direction and mass balance, not for deciding which mechanism is uniquely responsible for an observed clinical profile.

Common Mistake

A common error is to say, “The peak fell, so less drug reached the systemic circulation.” That conclusion does not follow. In the model, the peak falls when input is spread over more time, while the total amount reaching the systemic circulation remains \(FD\). Conversely, unchanged AUC does not prove that gastric emptying was the only process affected: different combinations of input and disposition changes can require further evaluation. State the assumptions behind the comparison, and distinguish peak concentration, full AUC, and systemic amount.

Check Your Understanding

Answer each question using the stated model unless the question specifies otherwise.

  1. If \(k_g\) is reduced while \(F,D,V,k_e\) stay fixed, what happens to \(T_{\max}\), \(C_{\max}\), and full AUC?
  2. For \(k_g=k_e=k\), write \(T_{\max}\) and \(C_{\max}\).
  3. Why can a fixed lag delay the peak without lowering it, whereas slower first-order emptying lowers the peak in this model?
  4. With \(FD=60\) mg and \(CL=12\) L/h, calculate the full AUC.

Solutions. (1) \(T_{\max}\) increases, \(C_{\max}\) decreases, and full AUC is unchanged, given the model assumptions. (2) \(T_{\max}=1/k\) and \(C_{\max}=(FD/V)e^{-1}\), from the equal-rate limiting profile. (3) A fixed lag translates the same concentration profile in time, preserving its height; slower first-order emptying spreads the input and allows elimination during ongoing delivery. (4) \(\mathrm{AUC}_{0-\infty}=FD/CL=60/12=5.000\ \mathrm{mg\cdot h/L}\).