From Intravenous Dose to Central-Compartment Input
Intravenous administration places drug directly into the systemic circulation, so the model does not need an absorption depot to represent delivery from the administration site. The input still has a time course: a bolus is treated as an instantaneous addition of amount, whereas an infusion delivers amount over time. In a PBPK model, that input enters the central compartment and is then acted on by distribution and elimination processes represented elsewhere in the model.
It is important to keep the route input separate from the rest of the pharmacokinetic model. The input function specifies when and how much drug is delivered; the central and tissue equations specify what happens to drug after delivery. For transparent concentration calculations below, a one-compartment model with first-order removal is used as an illustrative special case. Its concentration formulas are not a substitute for the full tissue-distribution equations in a PBPK model.
The central-compartment mass balance can be written in general form as
where \(G_c\) collects the non-input terms in the central-compartment balance. It may include elimination, transfer from the central compartment to tissues, and return from tissues. In a PBPK model, these terms depend on the particular organ and tissue model. The route-specific input functions derived here do not require a particular form for \(G_c\).
Three Intravenous Input Functions
Use time zero as the start of administration. Let \(D\) denote the delivered dose, \(R_0\) a constant infusion rate, and \(T\) the duration of a finite infusion. An indicator function is 1 when its condition is true and 0 otherwise. A bolus is represented mathematically by a Dirac delta input, whose integral over time is one.
The delta-function notation is a convenient way to express an instantaneous input in a differential equation. Its key property is that integrating the amount balance across time zero adds exactly \(D\) to the central amount. Equivalently, the bolus sets the initial condition \(A_c(0^+)=A_c(0^-)+D\). It is not a very large but finite infusion rate over an unspecified interval.
The constant-rate input is an idealization if it is allowed to continue indefinitely. It is useful for describing a maintained infusion or the portion of a longer infusion before it stops. A finite infusion is the constant-rate input switched off at \(T\). Since its delivered amount is the integral of the rate over the infusion interval,
This dose-conservation check is useful both when writing model code and when translating a prescribed dose into an infusion rate and duration.
Concentration Profiles in a One-Compartment Special Case
For explicit concentration-time calculations, suppose the central amount is the only modeled amount and is removed by a first-order process with rate constant \(k\), where \(k>0\) and units are inverse time. Assume \(V_c\) is constant, drug is instantaneously and completely available in the central compartment after a bolus, and the infusion rate is constant during administration. The mass balance is then \(dA_c/dt=R_{\mathrm{in}}(t)-kA_c\). These assumptions simplify the disposition model; they do not change the definitions of the intravenous inputs.
Between input events, multiplying the differential equation by the integrating factor \(e^{kt}\) gives
Integrating this expression from time zero to \(t\), with initial amount \(A_c(0)\), yields the general solution for this one-compartment case:
The integral shows how each small amount delivered at time \(\tau\) contributes to the amount remaining at time \(t\). An amount delivered earlier has more time to be removed. For a bolus, integration across time zero gives the initial amount \(D\), after which the amount declines exponentially. For an infusion, integrating the rate over the period when input is active gives the accumulation during dosing.
Worked Example: Concentration After an Intravenous Bolus
Suppose a hypothetical 100 mg bolus is given at time zero. In the one-compartment illustration, let \(V_c=20\) L and \(k=0.150\ \text{h}^{-1}\), with no drug present before dosing. The assumptions of instantaneous delivery, constant volume, and first-order removal are taken as part of this simplified example.
The bolus makes \(A_c(0^+)=100\) mg. There is no further input, so for \(t>0\), \(A_c(t)=100e^{-0.150t}\) mg and \(C_c(t)=A_c(t)/20\ \text{L}\). At four hours,
The units are consistent: the exponent is dimensionless, and amount divided by volume gives mg/L. The calculated concentration is the prediction of this illustrative one-compartment model, not a general PBPK bolus prediction.
For a constant-rate infusion that starts at zero with no initial amount, integrate the input \(R_0\) from zero to \(t\). Dividing the resulting amount by \(V_c\) gives the concentration during the infusion. For a finite infusion, the same expression applies only until the infusion stops; afterwards, the amount declines under the removal process without further input.
The post-infusion expression follows by taking the concentration at the stopping time, \(C_c(T)=\{R_0/(V_ck)\}(1-e^{-kT})\), and allowing that amount to decline for an additional \(t-T\) hours. Concentration is continuous at the stopping time in this model: evaluating either expression at \(t=T\) gives the same value. The input rate changes abruptly at \(T\), but the amount and concentration do not jump because no instantaneous dose is given at that time.
Worked Example: Concentration During a Constant-Rate Infusion
Consider a hypothetical infusion of \(12\) mg/h into a one-compartment model with \(V_c=24\) L and \(k=0.100\ \text{h}^{-1}\), starting from zero amount. The rate is constant through six hours, and the example assumes first-order removal and constant volume.
At six hours, the concentration during infusion is
The infusion has delivered \(12\ \text{mg/h}\times6\ \text{h}=72\) mg by that time. The modeled central amount is \(24\ \text{L}\times2.256\ \text{mg/L}=54.14\) mg (using the unrounded concentration, \(54.14\) mg); the difference reflects drug removed during the infusion. The limiting concentration for an indefinitely maintained infusion under these assumptions is \(R_0/(V_ck)=5.000\) mg/L, which the six-hour concentration approaches but does not exceed.
Worked Example: Concentration After a Finite-Duration Infusion
Suppose a hypothetical infusion runs at \(120\) mg/h for \(1.50\) h, then stops. Use \(V_c=30\) L, \(k=0.200\ \text{h}^{-1}\), and zero initial amount. The total delivered dose is \(120\ \text{mg/h}\times1.50\ \text{h}=180\) mg. The one-compartment assumptions are constant volume, first-order removal, and an exact stop at \(T=1.50\) h.
The concentration at the end of infusion is
At \(3.50\) h, the infusion has been off for \(3.50-1.50=2.00\) h. The concentration therefore declines from its end-of-infusion value:
The exponent is dimensionless, and the concentration at \(3.50\) h is lower than at the end of infusion, as expected with no ongoing input and positive removal. The calculation uses the unrounded end-of-infusion value before rounding the final concentration.
Checks, Alternatives, and Common Failure Modes
In an implementation, verify that the input function has the intended units and integrates to the intended dose. A bolus is an amount, not a rate; an infusion rate has amount-per-time units. For a finite infusion, check \(R_0T=D\), confirm the input switches off at \(T\), and ensure that the concentration expression changes to the post-infusion form at the correct time. With nonzero initial amount, its contribution must also be included; the zero-initial-amount formulas above cannot be applied unchanged.
Record the bolus dose or the infusion rate and, for a finite infusion, its stop time. Check that rate multiplied by duration equals the intended infusion dose.
Use an instantaneous amount input for a bolus and a time-dependent rate for an infusion. Do not encode an infusion as a bolus simply because the total dose is known.
Add the input to the central-compartment mass balance, then use the specified central and tissue processes to predict concentration. The simple exponential formulas require the one-compartment assumptions stated above.
Confirm that delivered amount, timing, units, and behavior at start and stop times agree with the administration. In the finite-infusion example, concentration is continuous at the stop time but its rate of change changes.
A common mistake is to use \(D/V_c\) as the concentration throughout an infusion because \(D\) is the total dose. That calculation is the immediate concentration increment for a bolus in the one-compartment model, not the concentration during an infusion: drug is being delivered gradually while removal occurs. The correction is to use the rate-and-duration input and integrate it through the model, as in \(C_c(t)=\{R_0/(V_ck)\}(1-e^{-kt})\) during infusion.
Another useful comparison is between the input-function approach and a boundary or initial-condition implementation. A bolus can be implemented by adding \(D\) to \(A_c\) at time zero; an equivalent delta input represents the same jump. An infusion is naturally implemented as a rate term in the differential equation. These are alternative numerical representations of the same administered amount, not different pharmacokinetic mechanisms. A full PBPK model may require numerical solution of coupled organ equations; its concentration profile need not follow the single exponential expressions shown here. The limitation of the illustrative formulas is precisely that they replace tissue distribution with one central amount and a single first-order removal process.
Diagnostics for a failed profile include a total delivered amount that differs from the prescribed dose, a concentration that jumps when a finite infusion stops, an infusion that continues unintentionally after \(T\), or a result with incompatible units. Also check the timing convention: if an infusion starts at a time other than zero, shift its active interval rather than applying the zero-start expressions without adjustment. These checks address input implementation; disagreement with observed concentrations may additionally reflect an inadequate disposition model or incorrect parameter values.
Check Your Understanding
Answer each question, then compare with the solutions.
- A 60 mg bolus is administered directly into the central compartment. What amount jump does the bolus input represent?
- An infusion runs at 8 mg/h for 2.5 h. What is its total delivered dose, and what input rate applies after it stops?
- Under the one-compartment assumptions, explain why concentration does not jump when a finite infusion stops, even though the input rate does.
- For \(R_0=10\) mg/h, \(V_c=20\) L, and \(k=0.100\ \text{h}^{-1}\), calculate the concentration at 5 h if the infusion is still running from zero with no initial amount.
Solutions. (1) The central amount increases by exactly \(60\) mg at time zero. (2) The total is \(8\ \text{mg/h}\times2.5\ \text{h}=20\) mg; after the stop time, \(R_{\mathrm{in}}(t)=0\). (3) Stopping changes the derivative of amount by removing the input term, but an abrupt change in a finite rate does not add or remove an instantaneous amount. Therefore amount and concentration remain continuous. (4) \(C_c(5)=\{10/[(20)(0.100)]\}(1-e^{-0.500})=5.000(0.393469)=1.967\) mg/L. The rate is ongoing at 5 h, so the during-infusion expression applies.