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Compartmental Absorption and Transit Models · Tutorial 226 of 799

Regional Contributions to Cumulative Absorption

Convert simulated regional fluxes into absorbed amounts and fractions, and interpret how each gut region contributes to cumulative absorption.

Intermediate 11 min read

What You'll Learn

  • Define regional cumulative absorbed amount by integrating its flux over time.
  • Calculate each region’s share of total absorption at a specified time.
  • Approximate cumulative amounts from flux values on a time grid.
  • Distinguish regional contribution from fraction of the oral dose absorbed.
  • Diagnose incomplete integration, inconsistent units, and misleading flux comparisons.

From Simulated Flux to Regional Contribution

A segmental absorption model can report an absorption flux for each gut region at every time point. A flux is an instantaneous rate, not an amount: a region with a large flux for a short interval may contribute less total absorbed drug than a region with a smaller flux that persists longer. To compare regions over a simulation, convert each flux into its cumulative absorbed amount, then express that amount relative to the total across regions.

The calculations describe absorption across the boundary represented by the model’s flux. They do not, by themselves, establish how much drug reaches systemic circulation: subsequent processes such as gut-wall metabolism or hepatic first-pass extraction are outside this regional accounting unless explicitly included in the flux definition.

Definition: For \(m\) gut regions, let \(J_i(t)\) be the nonnegative absorption flux from region \(i\) at time \(t\), measured in amount per unit time. If cumulative absorption is zero at \(t=0\), the cumulative absorbed amount from region \(i\) by time \(T\) is \(A_i(T)=\int_0^T J_i(t)\,dt\). The total cumulative absorbed amount is \(A_{\mathrm{tot}}(T)=\sum_{i=1}^{m} A_i(T)\). When \(A_{\mathrm{tot}}(T)>0\), the regional contribution fraction is \(F_i(T)=A_i(T)/A_{\mathrm{tot}}(T)\).

Amounts have units of mass, such as mg, while fractions are dimensionless. At a fixed time \(T\), the regional contribution fractions sum to one, provided the listed regions exhaust the fluxes included in the total:

$$ \sum_{i=1}^{m} F_i(T) = \frac{\sum_{i=1}^{m} A_i(T)}{A_{\mathrm{tot}}(T)} =1. $$

This fraction answers, “What share of the absorption represented in this model by time \(T\) came from region \(i\)?” It is not the same as the fraction of the administered dose absorbed. If the oral dose is \(D\), then \(A_i(T)/D\) is the fraction of that dose absorbed through region \(i\) by time \(T\), and \(A_{\mathrm{tot}}(T)/D\) is the total fraction absorbed by that time. These dose-based fractions sum to \(A_{\mathrm{tot}}(T)/D\), which may be below one.

Why Integration Gives Cumulative Absorption

The amount absorbed over a short interval is approximately flux multiplied by interval duration. Summing those contributions over time and taking the limit as the intervals become small gives the integral of flux. The result relies on the flux being integrable over the time interval; piecewise-continuous fluxes commonly used in simulations satisfy this condition.

$$ A_i(T)=\int_0^T J_i(t)\,dt, \qquad A_{\mathrm{tot}}(T)=\sum_{i=1}^{m}\int_0^T J_i(t)\,dt =\int_0^T \sum_{i=1}^{m}J_i(t)\,dt. $$

The cumulative amount \(A_i(t)\) is absolutely continuous when \(J_i(t)\) is integrable. Its derivative equals \(J_i(t)\) almost everywhere, not necessarily at every time point. For a continuous flux, the derivative identity holds at every point of continuity. The integral identity for cumulative amount remains valid even when the flux has jumps.

This distinction matters when interpreting simulated profiles. If a flux jumps at a time boundary, the cumulative amount remains continuous, but its left and right slopes can differ. For example, if \(J_i(t)=3\) mg/h before 2 h and \(J_i(t)=1\) mg/h after 2 h, the cumulative amount has left slope 3 mg/h and right slope 1 mg/h at 2 h; its derivative at exactly 2 h is not defined. Integration across the intervals is still well-defined.

Worked Example: Integrating Piecewise-Constant Regional Fluxes

Suppose a hypothetical simulation reports three regional fluxes from 0 to 5 h. Region A has flux 3 mg/h from 0 to 2 h and 1 mg/h from 2 to 5 h. Region B has flux 1 mg/h from 0 to 1 h, 2 mg/h from 1 to 3 h, and 0.5 mg/h from 3 to 5 h. Region C has flux 0.5 mg/h from 0 to 4 h and 0 mg/h from 4 to 5 h. Calculate the amounts and their contributions at 5 h.

For a constant flux over an interval, the absorbed amount is flux multiplied by interval duration. Thus:

$$ \begin{aligned} A_A(5)&=(3\ \mathrm{mg/h})(2\ \mathrm{h})+(1\ \mathrm{mg/h})(3\ \mathrm{h})=9\ \mathrm{mg},\\ A_B(5)&=(1\ \mathrm{mg/h})(1\ \mathrm{h})+(2\ \mathrm{mg/h})(2\ \mathrm{h})+(0.5\ \mathrm{mg/h})(2\ \mathrm{h})=6\ \mathrm{mg},\\ A_C(5)&=(0.5\ \mathrm{mg/h})(4\ \mathrm{h})+(0\ \mathrm{mg/h})(1\ \mathrm{h})=2\ \mathrm{mg}. \end{aligned} $$

The total is \(9+6+2=17\) mg. The contribution fractions are \(F_A(5)=9/17=0.5294\), \(F_B(5)=6/17=0.3529\), and \(F_C(5)=2/17=0.1176\). They sum to 1.000 to the displayed precision. Region A contributes the most cumulative absorption by 5 h, even though the comparison is based on the areas under the flux curves, not on a single flux value.

At 2 h, the amounts are \(A_A(2)=6\) mg, \(A_B(2)=1+2=3\) mg, and \(A_C(2)=1\) mg. The total is 10 mg, so the regional fractions at that time are 0.600, 0.300, and 0.100, respectively. The regional shares can therefore change over time.

Calculating Amounts from Simulated Time Grids

Simulation output is often available at discrete time points rather than as a symbolic flux function. If \(J_i(t_k)\) is reported at times \(t_0,\ldots,t_K\), a common approximation is the composite trapezoidal rule. Each adjacent pair of flux values is treated as the endpoints of a straight line, and the area of the resulting trapezoid approximates absorption over that interval.

$$ A_i(T)\approx \sum_{k=0}^{K-1} \frac{J_i(t_k)+J_i(t_{k+1})}{2} (t_{k+1}-t_k). $$

This approximation is most reliable when the time grid is fine enough to capture changes in flux. A large time step across a sharp peak, rapid transition, or discontinuity can miss substantial area. For a known piecewise-constant flux, integrating each constant interval directly is preferable to interpolating between output points as though the flux changed linearly.

Worked Example: Trapezoidal Integration of Sampled Fluxes

Suppose a hypothetical model outputs fluxes at 0, 1, 2, and 3 h. Region P has values 0, 2, 3, and 1 mg/h; region Q has values 0, 1, 2, and 2 mg/h. Use the trapezoidal rule on the 1 h intervals to estimate amounts by 3 h.

For region P, the three interval contributions are \((0+2)(1)/2=1\) mg, \((2+3)(1)/2=2.5\) mg, and \((3+1)(1)/2=2\) mg. Therefore \(A_P(3)\approx1+2.5+2=5.5\) mg.

For region Q, the interval contributions are \((0+1)(1)/2=0.5\) mg, \((1+2)(1)/2=1.5\) mg, and \((2+2)(1)/2=2\) mg. Therefore \(A_Q(3)\approx0.5+1.5+2=4.0\) mg. The estimated total is 9.5 mg, and the regional contribution fractions are \(5.5/9.5=0.579\) for P and \(4.0/9.5=0.421\) for Q.

If the hypothetical oral dose was 20 mg, the estimated fraction of dose absorbed by 3 h is \(9.5/20=0.475\), or 47.5%. This dose-based fraction is distinct from P’s 57.9% share of the amount absorbed by 3 h.

Time Patterns and Regional Ranking

A regional contribution is time-specific. A region can dominate early absorption without supplying the largest amount by the end of the simulation. The cumulative amount curve records the area accumulated so far; the cumulative fraction curve compares that area with the total accumulated across regions at the same time. Both curves can be useful when the question concerns not only the final amount but also when each region contributes.

Worked Example: A High Early Flux Does Not Guarantee the Largest Total

In a hypothetical simulation, proximal region P has flux 4 mg/h from 0 to 1 h and 0.5 mg/h from 1 to 5 h. Distal region D has flux 0.5 mg/h from 0 to 1 h and 1.5 mg/h from 1 to 5 h. Calculate the amounts and regional shares by 5 h.

For P, the amount is \((4)(1)+(0.5)(4)=6\) mg. For D, it is \((0.5)(1)+(1.5)(4)=6.5\) mg. The total is 12.5 mg, giving \(F_P(5)=6/12.5=0.480\) and \(F_D(5)=6.5/12.5=0.520\). Thus D contributes slightly more cumulative absorption by 5 h.

At 1 h, P has absorbed 4 mg and D has absorbed 0.5 mg, so P has supplied \(4/(4+0.5)=0.889\), or 88.9%, of absorption by that time. The early regional ranking differs from the final ranking because D’s lower flux continues for a longer interval. Neither the largest instantaneous flux nor the largest early cumulative amount alone determines the final regional contribution.

Checks, Comparisons, and Limitations

Several checks help identify errors before interpreting regional shares. First, confirm that flux and time units are compatible: mg/h multiplied by h gives mg. Second, verify that all regions are included exactly once in the total. Third, check that nonnegative regional fluxes yield nondecreasing cumulative amounts. Finally, check that the regional amounts sum to the integrated total flux and that contribution fractions sum to one, apart from rounding.

If the model represents only some regions, the computed fractions describe shares within that represented set, not necessarily shares of all intestinal absorption. If the fluxes are net fluxes and can be negative, cumulative amounts need not be nondecreasing, and the resulting ratios may not behave like shares of nonnegative absorption. In that case, the sign convention and scientific meaning of the net flux must be stated; do not label a signed ratio an absorption contribution without justification. Likewise, a total of zero makes \(F_i(T)\) undefined, not zero.

There are two common calculation approaches. Direct integration of the model’s continuous or piecewise-defined flux is appropriate when its functional form is available. Numerical quadrature, such as the trapezoidal rule, is practical for time-grid output but introduces discretization error. Comparing refined-grid estimates is a useful diagnostic: if the estimated amounts change materially as the grid is refined, the original grid may not resolve the flux profile. Comparing regional peak fluxes is not an alternative calculation of contribution; it answers a different question about instantaneous rates.

Regional fractions also depend on the chosen endpoint \(T\). Fractions at an early time describe the composition of absorption accumulated so far; they need not equal eventual fractions. Conclusions should therefore state the integration interval and the flux boundary being counted. Regional amounts from a simulation are model-based quantities: they describe the specified model and inputs, and alone do not establish that the regional pattern has been identified from observed data.

Common pitfall: “Region A has the largest flux at the final time, so it must contribute the most absorption.” This reasoning confuses an instantaneous rate with an accumulated amount. The correction is to integrate every regional flux over the same interval, calculate \(A_i(T)\), and compare \(A_i(T)/A_{\mathrm{tot}}(T)\). Also, at a flux discontinuity, do not claim that the cumulative amount’s derivative equals the flux at every single time; the derivative identity holds almost everywhere for integrable fluxes.
1
Specify the interval and flux boundary.
State the start time, endpoint \(T\), and which modelled transfer into the absorbed pool each \(J_i(t)\) represents.
2
Integrate each region.
Use exact interval areas when available, or a stated numerical quadrature method for sampled output.
3
Check totals and units.
Confirm the regional amounts add to the total, the units are amounts, and the fractions are defined only when the total is positive.
4
Interpret the requested comparison.
Distinguish a region’s share of cumulative absorption from its fraction of the oral dose and from its instantaneous flux.

Check Your Understanding

Answer each question, then compare your reasoning with the solutions below.

  1. Two regions absorb 4 mg and 6 mg by 4 h. What are their regional contribution fractions by 4 h?
  2. A region has a constant flux of 2 mg/h from 0 to 3 h. What amount does it contribute, and what is the unit calculation?
  3. At time \(T\), total regional absorption is 12 mg from a 30 mg oral dose. What is the total fraction of dose absorbed, and why is it not a regional contribution fraction?
  4. Why can the cumulative amount be continuous at a flux jump even though its derivative may not exist at the jump?
  5. Fluxes are recorded only at widely spaced time points, and a narrow peak may occur between them. What diagnostic or remedy is appropriate?

Solutions. (1) The total is \(4+6=10\) mg, so the fractions are \(4/10=0.400\) and \(6/10=0.600\). (2) The amount is \((2\ \mathrm{mg/h})(3\ \mathrm{h})=6\) mg. (3) The dose fraction absorbed is \(12/30=0.400\), or 40.0%; it compares absorption with the administered dose, whereas a regional contribution fraction compares one region with total absorption. (4) The cumulative amount is the integral of the flux, so a finite jump in flux changes the slope on either side but does not create a jump in the accumulated area; the one-sided slopes can differ. (5) Refine the time grid or use output that resolves the peak, then compare integrated amounts across grids; a coarse trapezoidal estimate may miss area between samples.