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Therapeutic Drug Monitoring and Individual Predictions · Tutorial 546 of 599

Using Below-Quantification Results in Individual Forecasts

Represent below-quantification observations as censored events in an individual’s likelihood, then see how that choice can change patient-specific forecasts.

Advanced 12 min read

What You'll Learn

  • Express a below-quantification result as a probability under the observation model.
  • Construct individual posterior weights from censored and quantified observations.
  • Compare censored-likelihood forecasts with forecasts based on fixed-value substitution.
  • Check the censoring threshold, residual model, and conditional-independence assumptions.
  • Recognize why substitution can distort patient-specific forecasts.
  • Assess practical limitations when several observations are below quantification.

Why a Below-Quantification Result Still Contains Information

A concentration reported as below the assay’s quantification limit is not an exact concentration of zero, nor is it an exact concentration equal to the limit. It tells us that the unobserved assay result fell below a known threshold. That event can still distinguish between individual parameter values: a model predicting a low concentration may assign it a higher probability than a model predicting a high one.

The key is to use the probability of the reported event, rather than the probability density at an invented replacement value. This matters when an individual forecast combines observed concentrations with a population-based prior. If a below-quantification result is treated as an exact number, the likelihood—and therefore the balance between patient data and prior information—can change.

Definition: A below-quantification observation is a censored observation: the exact concentration is not available, but it is known to be below a specified quantification limit \(L\). If \(Y\) is the assay result, its likelihood contribution under an individual parameter value \(\theta\) is \(P(Y<L\mid\theta)\), not a density evaluated at \(L\), at \(L/2\), or at zero.

Constructing the Censored Likelihood

Suppose the observation model for a positive concentration is lognormal: \(\log Y\mid\theta\sim N(\log m(\theta),\sigma^2)\), where \(m(\theta)\) is the model-predicted median concentration and \(\sigma\) is the residual standard deviation on the log scale. This assumes that the log concentration is normally distributed around the log model prediction, with the stated residual variability. The resulting probability of a below-limit result is

$$ P(Y<L\mid\theta) = P\left(\frac{\log Y-\log m(\theta)}{\sigma} < \frac{\log L-\log m(\theta)}{\sigma} \;\middle|\;\theta\right) = \Phi\left(\frac{\log(L/m(\theta))}{\sigma}\right). $$

Here \(\Phi\) is the standard normal cumulative distribution function. The formula follows by standardizing \(\log Y\), which has a normal distribution with mean \(\log m(\theta)\) and standard deviation \(\sigma\). It applies when the recorded result means that the assay result was below \(L\), and the lognormal observation model is appropriate. If the assay or reporting rule implies a different event or observation distribution, the probability must be adapted to that rule and model.

For comparison, if an exact positive result \(y\) is reported under the same model, its likelihood contribution is a density:

$$ f(y\mid\theta) = \frac{1}{y\sigma\sqrt{2\pi}} \exp\left[ -\frac{1}{2} \left(\frac{\log(y/m(\theta))}{\sigma}\right)^2 \right]. $$

A density is appropriate for an observed exact value; a probability is appropriate for an observed interval or event. With conditionally independent observations given \(\theta\), multiply the contributions for all observations. Thus, for a set containing both exact results and below-limit results,

$$ L(\theta) = \prod_{j\in E} f(y_j\mid\theta) \prod_{j\in C} P(Y_j<L_j\mid\theta), $$

where \(E\) indexes exact observations and \(C\) indexes censored observations. Conditional independence means the observation errors are independent given the individual parameters and the model; it should not be assumed if the observation process or residual structure implies dependence.

In an individual Bayesian fit, the posterior is proportional to the prior multiplied by this likelihood. For a finite set of candidate parameter states \(\theta_k\), the normalized posterior weight is

$$ P(\theta_k\mid\text{data}) = \frac{P(\theta_k)L(\theta_k)} {\sum_r P(\theta_r)L(\theta_r)}. $$

A forecast for a future concentration \(Y_{\mathrm{new}}\) averages over these posterior parameter values and the future observation model. In particular, if \(\mu_k\) is the conditional mean future concentration under state \(\theta_k\), the posterior predictive mean is \(\sum_k P(\theta_k\mid\text{data})\mu_k\). This average reflects both the evidence from the patient’s observations and the prior weights.

Worked Forecast Comparisons

Worked Example: One Below-Limit Result and Two Individual States

Hypothetical data. A patient has one result reported below \(L=0.50\) mg/L. Consider two candidate individual states, A and B, with equal prior probabilities. At the sampling time, their model-predicted median concentrations are \(m_A=1.50\) mg/L and \(m_B=0.50\) mg/L. Assume lognormal residual error with \(\sigma=0.50\), and assume the reported result means \(Y<L\).

Under A, the standardized log threshold is \(z_A=\log(0.50/1.50)/0.50=-2.1972\). Therefore, the censored likelihood contribution is \(\Phi(-2.1972)\approx0.0140\). Under B, \(z_B=\log(0.50/0.50)/0.50=0\), so the contribution is \(\Phi(0)=0.5000\). With equal prior weights, the posterior probability of A is

$$ P(A\mid Y<L) = \frac{0.0140}{0.0140+0.5000} \approx 0.0272. $$

The below-limit result therefore favors B, whose predicted concentration is lower. Suppose the model’s conditional mean future concentrations are 4.00 mg/L under A and 1.00 mg/L under B. The posterior predictive mean is \(0.0272(4.00)+0.9728(1.00)=1.082\) mg/L.

Now substitute \(0.50\) mg/L for the censored result and incorrectly treat it as an exact observation. The ratio of the exact-value densities under A and B is

$$ \frac{f(0.50\mid A)}{f(0.50\mid B)} = \exp\left[ -\frac{1}{2} \left\{ \left(\frac{\log(0.50/1.50)}{0.50}\right)^2 - \left(\frac{\log(0.50/0.50)}{0.50}\right)^2 \right\} \right] = \exp(-2.4139) \approx 0.0895. $$

The common density factor cancels in the ratio. With equal prior probabilities, substitution gives \(P(A\mid\text{substituted value})=0.0895/(1+0.0895)\approx0.0822\). The corresponding forecast mean is \(0.0822(4.00)+0.9178(1.00)=1.246\) mg/L. The result is higher than the censored-likelihood forecast of 1.082 mg/L because the substituted exact value supplies different evidence from the event \(Y<0.50\).

Worked Example: Multiplying Contributions From Two Censored Samples

Hypothetical data. Two samples from the same patient are both reported below \(L=1.00\) mg/L. Use the same lognormal model with \(\sigma=0.40\), assume conditionally independent residual errors, and give candidate states A and B equal prior probabilities. At the first sample time, let the predicted medians be \(m_A=1.50\) and \(m_B=0.80\) mg/L. At the second, let them be \(m_A=0.80\) and \(m_B=0.40\) mg/L.

For A, the first standardized threshold is \(\log(1/1.50)/0.40=-1.0137\), giving probability approximately \(0.1554\). The second is \(\log(1/0.80)/0.40=0.5579\), giving probability approximately \(0.7116\). The combined likelihood is \(0.1554(0.7116)\approx0.1106\). For B, the corresponding probabilities are approximately \(0.7116\) and \(0.9890\), so the combined likelihood is \(0.7116(0.9890)\approx0.7038\).

With equal priors, the posterior probability of A is \(0.1106/(0.1106+0.7038)\approx0.1358\). If the conditional mean future concentrations are 5.00 mg/L under A and 2.00 mg/L under B, the posterior predictive mean is \(0.1358(5.00)+0.8642(2.00)\approx2.407\) mg/L. Each censored result contributes its own event probability; multiplying the two is justified here by the stated conditional-independence assumption.

Worked Example: Combining an Exact Result With a Censored Result

Hypothetical data. A patient has an exact result of \(0.80\) mg/L at one time and a result below \(0.50\) mg/L at another. Candidate states A and B have equal prior probabilities, and \(\sigma=0.50\). At the exact sample time, their predicted medians are \(m_A=1.00\) and \(m_B=0.70\) mg/L. At the censored sample time, they are \(m_A=1.50\) and \(m_B=0.50\) mg/L. Assume the two residual errors are conditionally independent.

For the exact result, the density ratio is

$$ \frac{f(0.80\mid A)}{f(0.80\mid B)} = \exp\left[ -\frac{1}{2} \left\{ \left(\frac{\log(0.80/1.00)}{0.50}\right)^2 - \left(\frac{\log(0.80/0.70)}{0.50}\right)^2 \right\} \right] \approx 0.9381. $$

For the below-limit result, the event probabilities are approximately \(0.0140\) under A and \(0.5000\) under B, so their likelihood ratio is \(0.0140/0.5000=0.0280\). Multiplying the independent contributions gives the combined likelihood ratio \(0.9381(0.0280)\approx0.02627\). Equal prior probabilities then give \(P(A\mid\text{data})=0.02627/(1+0.02627)\approx0.0256\). If the conditional mean future concentrations are 4.00 mg/L under A and 1.00 mg/L under B, the posterior predictive mean is \(0.0256(4.00)+0.9744(1.00)\approx1.077\) mg/L.

Assumptions, Diagnostics, and Alternatives

The likelihood calculation depends on more than the algebra. Check that \(L\) is the relevant limit for the particular sample and that the recorded category really means the result fell below it. Confirm that the residual distribution and its scale are plausible for the assay and concentration range. In the lognormal example, \(\sigma\) is on the log scale, not in concentration units. If residual error varies with concentration or the assay reports a different censoring interval, use an observation model that represents those features.

Useful diagnostics include checking whether the predicted below-limit probabilities are plausible at the observed sample times and whether the resulting posterior is highly sensitive to the assumed \(L\), residual error, or prior. A very small probability for a censored observation under every plausible individual state may indicate conflict between the data and the model, an incorrect threshold, or an observation-process problem. If nearly all candidate states assign probabilities close to zero or close to one, the data may provide little discrimination between those states. For several censored samples, inspect whether the conditional-independence assumption is defensible; shared assay effects or other dependence can make a product of marginal probabilities inappropriate.

Fixed-value substitution is sometimes used as a simple approximation, but it changes the evidence: it treats an interval event as though a particular exact concentration had been measured. Substituting \(L\), \(L/2\), or zero can produce different likelihoods and forecasts, and none is generally the censored likelihood. Deleting the result avoids inventing a value but discards the information that the result fell below \(L\). When the censoring threshold and observation model are available and adequate, using the event probability preserves that information directly.

Common pitfall: “The assay could not quantify the concentration, so I will enter the limit as the measured value.” The correction is that the data record an inequality, \(Y<L\), not an exact value \(Y=L\). Use \(P(Y<L\mid\theta)\) for that observation. Substitution is a different approximation and may shift the individual posterior and forecast.

Censored-likelihood forecasts are not automatically reliable if the underlying model is poor. They depend on a defensible observation model, known or appropriately represented thresholds, and a suitable prior and individual pharmacokinetic model. If all available observations are censored, or the candidate states predict similar event probabilities, the data may not identify the individual well; the posterior can remain largely determined by the prior. The likelihood handles what was observed, but it cannot create information that the assay did not provide.

Check Your Understanding

Try each question, then compare your reasoning with the solutions below.

  1. Under the lognormal model, what is the censored likelihood contribution when \(L=m(\theta)\)?
  2. If \(L=0.50\) mg/L, \(m(\theta)=1.00\) mg/L, and \(\sigma=0.50\), calculate \(P(Y<L\mid\theta)\) to about three significant figures.
  3. Two states have prior probabilities 0.30 and 0.70. Their likelihoods for a below-limit result are 0.10 and 0.60, respectively. What is the posterior probability of the first state?
  4. A patient’s posterior probability of state A is 0.20. The conditional mean future concentrations are 6.00 mg/L under A and 2.00 mg/L under state B. Find the posterior predictive mean.
  5. In one sentence, explain why entering \(L/2\) as an exact measured concentration is not the same as using a censored likelihood.

Solutions. (1) The standardized threshold is zero, so the contribution is \(\Phi(0)=0.500\). (2) The standardized threshold is \(\log(0.50/1.00)/0.50=-1.3863\), so the probability is \(\Phi(-1.3863)\approx0.08283\). (3) Normalize the prior-weighted likelihoods: \(0.30(0.10)/[0.30(0.10)+0.70(0.60)]=0.030/0.450=0.0667\). (4) The mean is \(0.20(6.00)+0.80(2.00)=2.80\) mg/L. (5) \(L/2\) is a chosen point treated as exact, whereas the censored likelihood uses the probability of the whole event \(Y<L\).

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