Why Multiple Endpoints Need a Common Enrollment Plan
A sample-size update is often driven by a prespecified primary endpoint, while the same participants also contribute information about secondary endpoints. The primary endpoint may require a certain sample size to achieve planned power; a secondary endpoint may instead have a planned confidence-interval width. These are different design goals, even though both depend on enrollment.
The re-estimation must preserve the primary question and its planned decision rule. Secondary endpoints should be checked against their stated goals at the revised sample size, not assumed to be adequately supported just because the primary calculation is satisfied. Conversely, a precision target for a secondary endpoint does not automatically make that endpoint a confirmatory test or change the trial’s success criterion.
Primary-Endpoint Requirement and Its Assumptions
For a simple illustration, suppose the primary endpoint is continuous, participants are independently randomized in equal numbers to two groups, outcomes are fully observed, and the outcome has the same standard deviation \(\sigma\) in both groups. Let \(\Delta\) be the prespecified treatment difference the design aims to detect. The standard error of the difference in sample means, with \(n\) participants per group, is \(\sigma\sqrt{2/n}\).
For a two-sided test at level \(\alpha\), the usual normal-approximation planning formula for power \(1-\beta\) is:
Here \(z_q\) is the \(q\)-quantile of the standard normal distribution. This is a planning approximation, including when \(\sigma\) is known; it is not an exact two-sided normal-theory power solution. Under the alternative, the standardized mean has noncentrality \(\lambda=\Delta/(\sigma\sqrt{2/n})\). Exact power for the two-sided z-test is \( \Phi(-z_{1-\alpha/2}-\lambda)+1-\Phi(z_{1-\alpha/2}-\lambda)\). The displayed planning formula uses the upper-tail target and does not solve that full equation exactly. If exact normal-theory power is required, solve the full expression for \(n\).
In a re-estimation, an updated nuisance-parameter estimate, such as an interim estimate of \(\sigma\), may be substituted into the prespecified planning rule. The target difference \(\Delta\), significance level, power target, allocation, and update rule should remain prespecified. The resulting continuous value of \(n\) is rounded upward to a whole participant per group. If the protocol sets a minimum or maximum, apply those bounds as written; do not silently replace the primary design target with an observed interim treatment effect.
Worked Example: Updating the Primary Requirement
Suppose a hypothetical equal-allocation trial has a continuous primary endpoint. It plans a two-sided test with \(\alpha=0.05\), power \(1-\beta=0.90\), and target difference \(\Delta=4\) endpoint units. At an interim review, the prespecified variance update gives a common standard-deviation estimate of 12 units. Assume the simple model above is appropriate, outcomes are independent across participants, and there is no loss of endpoint data for this calculation.
The normal quantiles are \(z_{0.975}=1.960\) and \(z_{0.90}=1.2816\). Substituting into the planning formula gives:
Rounding upward gives a target of 190 participants per group, or 380 in total under equal allocation. This is a normal-approximation planning target, not a claim that the exact two-sided power is precisely 90.0%. If 70 participants per group have already been randomized and the target refers to total randomized enrollment, 120 more per group would be needed. If the target instead refers to participants with observed outcomes, expected missingness must be addressed separately under the protocol’s prespecified rule.
Translate Secondary Precision Goals Into Enrollment
For a continuous secondary endpoint with standard deviation \(\sigma_S\), equal allocation, and independent participants, the standard error of the difference between group means is \(\sigma_S\sqrt{2/n}\). A two-sided normal-based confidence interval with individual confidence level \(1-\alpha_S\) has half-width \(z_{1-\alpha_S/2}\sigma_S\sqrt{2/n}\). To keep that half-width no larger than a planned value \(h\), solve the inequality for \(n\):
The calculation depends on the endpoint’s scale and variability, the interval’s confidence level, and the desired half-width. It does not depend on the endpoint’s treatment effect. If the endpoint is binary or time-to-event, its standard error and information requirements are different; the continuous-outcome formula must not be applied to those endpoints.
Worked Example: Checking One Secondary Endpoint
Continue the hypothetical trial, and suppose a continuous secondary endpoint has standard deviation 15 units in each group. The protocol seeks an individual two-sided 95% confidence interval for the group difference with half-width no greater than 3.5 units. Assume the endpoint is measured on the same participants and the equal-allocation normal approximation is suitable.
Using \(z_{0.975}=1.960\), the required sample size per group is:
Rounding upward gives 142 participants per group. The primary requirement of 190 per group is larger, so it also meets this secondary endpoint’s individual 95% precision target under the stated assumptions. At \(n=190\), the secondary interval half-width is:
Thus the expected interval width is about \(2(3.016)=6.03\) units, narrower than the planned maximum width of 7 units. This is a precision calculation; it does not establish that the endpoint has adequate power for a particular hypothesis test.
Combine Requirements Without Changing the Primary Question
When all endpoints use the same participants and allocation, calculate the required sample size for each design goal on a consistent basis. If the protocol requires primary power and specified secondary precision, the common per-group target is the largest of those requirements, subject to any prespecified enrollment bounds. If secondary endpoints are descriptive only and no precision goal was committed to, their calculated precision can still be reported, but it need not determine enrollment.
This maximum rule assumes that each requirement is expressed for the same unit of enrollment and that the endpoints are available from the same randomized participants. It does not mean that all requirements are automatically met if endpoints have different analysis populations, different missing-data rates, or different allocation or follow-up needs. Those differences require their own prespecified adjustments.
Worked Example: Two Secondary Endpoints and Simultaneous Precision
Consider a separate hypothetical trial with equal allocation. Its prespecified primary requirement is 110 participants per group. It also wants simultaneous 95% confidence coverage for the differences on two continuous secondary endpoints, with respective standard deviations of 10 and 14 units and desired half-widths of 3 and 4 units. Assume independent participants and use Bonferroni-adjusted normal intervals. Bonferroni does not require the endpoints to be independent.
For \(K=2\) intervals, set each interval’s two-sided noncoverage probability to \(\alpha_S=0.05/2=0.025\). Then \(z_{1-\alpha_S/2}=z_{0.9875}\approx2.2414\). For the first endpoint:
For the second endpoint:
The common target is \(\max(110,112,124)=124\) participants per group. At that enrollment, the Bonferroni half-widths are approximately \(2.846\) and \(3.985\) units, respectively, so both specified margins are met. Bonferroni guarantees at least 95% simultaneous coverage by ensuring each interval’s noncoverage probability is at most 0.025; it may be conservative. Had the protocol specified only individual 95% intervals, the unadjusted quantile \(z_{0.975}\) would be used instead, and the intervals would not thereby have 95% simultaneous coverage.
Justification, Diagnostics, and Failure Modes
The maximum rule follows directly from the meaning of each requirement. If \(n\) is smaller than any required value \(n_j\), then the corresponding design goal is not met by its calculation. If \(n\) is at least every \(n_j\), all the inequalities hold at once. Therefore the smallest common \(n\) satisfying all the requirements is their maximum:
A practical diagnostic is to recalculate each endpoint’s achieved quantity at the proposed enrollment: primary approximate power under its design assumptions, and secondary confidence-interval half-widths under their stated confidence levels. A table can make the bottleneck visible.
| Design goal | Check at proposed enrollment | Warning sign |
|---|---|---|
| Primary power | Re-evaluate the prespecified power calculation using the updated nuisance estimate | The primary requirement is below its target or depends on an unplanned effect-size change |
| Secondary precision | Calculate the expected interval half-width for each endpoint | Any width exceeds its planned margin |
| Simultaneous precision | Use the prespecified joint-coverage method or its adjusted quantiles | Individual intervals are described as jointly 95% without adjustment or justification |
| Common enrollment | Confirm that endpoint populations, allocation, and follow-up support the same \(n\) | An endpoint has additional missingness, a different analysis set, or incomplete measurement |
The calculations are only as credible as their assumptions. For the simple formulas, check whether the variance estimate is relevant to the endpoint and analysis population, whether the equal-allocation and common-variance assumptions are reasonable, and whether the endpoint is observed for the anticipated participants. If the updated variance is unstable or the endpoint’s missingness differs materially, a nominal increase in randomized enrollment may not deliver the intended precision. The resulting rule should state how rounding, lower and upper limits, and unavailable endpoint data are handled.
The main alternatives reflect different scientific goals. A precision-based plan specifies interval widths; a power-based plan specifies a detectable effect and a testing error rate. Confirmatory testing of several endpoints needs an explicit multiplicity strategy, such as a prespecified allocation of error or a gatekeeping procedure; simply increasing enrollment does not by itself control the familywise type I error rate. Co-primary endpoints are different again: trial success may require success on more than one endpoint, so their joint success rule must be part of the design rather than treated as secondary precision planning.
Endpoint correlation may inform more efficient joint precision methods, but it is not needed for Bonferroni’s simultaneous-coverage guarantee. A limitation of the maximum rule is that it can be conservative when endpoint requirements are not genuinely separate or when a carefully justified joint method is available. Another limitation is that a plug-in variance estimate does not eliminate uncertainty in that estimate. The update should therefore follow its prespecified rule and be interpreted as a design decision under uncertainty, not as proof that final power or precision is guaranteed.
Common Mistake
A frequent error is to say, “The updated sample size meets primary power, so the secondary endpoints are adequately powered and precise.” That conclusion does not follow: power for a secondary test and precision of its interval are distinct properties, and neither is implied merely by the primary calculation. The correction is to state each secondary goal, calculate its requirement or achieved interval width, and apply any multiplicity adjustment needed for simultaneous claims. A second error is to choose the largest observed interim effect among endpoints and use it to justify reducing enrollment. That changes the scientific target based on interim data; retain the prespecified primary endpoint and clinically meaningful target effect in the update.
Check Your Understanding
Answer the questions first, then compare your reasoning with the solutions below.
- A primary endpoint requires 160 participants per group. Two secondary precision calculations require 145 and 172 per group. What common target meets all three requirements?
- For a continuous secondary endpoint, \(\sigma_S=8\) units, \(h=2\) units, and an individual 95% interval are planned. Find the required participants per group using the normal approximation.
- Why does meeting the primary endpoint’s power target not establish 95% simultaneous coverage for several secondary intervals?
- What changes in the precision calculation if the protocol’s target is simultaneous 95% coverage for \(K\) secondary intervals using Bonferroni adjustment?
Solutions. (1) The common target is \(\max(160,145,172)=172\) participants per group. (2) \(n=2(1.960^2)(8^2)/2^2=2(3.8416)(64)/4=122.9312\), so round up to 123 participants per group. (3) Primary power concerns a specified primary hypothesis test; simultaneous coverage concerns the joint behavior of multiple intervals. One does not imply the other. (4) Set each interval’s noncoverage probability to \(0.05/K\), giving critical value \(z_{1-0.05/(2K)}\), and use that value in each endpoint’s half-width calculation. Bonferroni then guarantees at least 95% simultaneous coverage without requiring independence among endpoints.